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Are there any necessary conditions of the existence of a Hamiltonian cycle on directed graphs

I'm trying to prove that one concrete directed graph has no Hamiltonian cycle, but didn't seem to find any relevant theorems
Anđela Todorović's user avatar
2 votes
0 answers
116 views

Two more counterexamples to a conjecture from 1975 about hamiltonicity of digraphs

Question from 2013 gives one counterexample to Nash-Williams's conjecture 1975 about hamiltonicity of dense digraphs. In the linked answer, @LouisD "reverse engineered" the counterexample ...
joro's user avatar
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1 vote
1 answer
178 views

Is Hamiltonian cycle fixed parameter tractable with parameter clique cover?

Let $G$ be connected simple graph. Clique cover of graph $G$ is partition of the vertices of $G$ into $k$ disjoint cliques $D'_i$. Given $G$ and $k$-clique cover, can we solve Hamiltonian cycle in ...
joro's user avatar
  • 25.4k
0 votes
0 answers
64 views

Degree-constraints for the existence of vertex-disjoint directed cycle covers in digraphs

Given a digraph $G(E,V): (u,v)\in E\implies(v,u)\notin E$, what is known about lower bounds on the indegree and outdegree of the vertices that guarantee the existence of a vertex-disjoint directed ...
Manfred Weis's user avatar
  • 13.2k
4 votes
0 answers
230 views

Is this case of Barnette's Conjecture known?

Context: Barnette's Conjecture is that every bipartite cubic polyhedral graph is Hamiltonian. I have been interested by this problem for a long time, and I recently came up with a result. From my ...
Zach Hunter's user avatar
  • 3,499
4 votes
1 answer
109 views

Does 2-connectivity imply Hamiltoniancy for subgraphs of the rook graph

We say the rook graph, $R_n$, is the cartesian product of $K_n \times K_n$. Let $S$ be the set of graphs that are an induced subgraph of $R_n$ for some $n$. Does there exist some constant $c$ such ...
Zach Hunter's user avatar
  • 3,499
3 votes
1 answer
138 views

Edge colorability and Hamiltonicity of certain classes of cubic graphs (MO graphs)

Let $G$ be a simple cubic graph (that is, 3-regular). A dominating circuit of $G$ is a circuit $C$ such that each edge of $G$ has an endvertex in $C$. The circuit $C$ is chordless if no edge which is ...
EGME's user avatar
  • 1,018
6 votes
1 answer
299 views

Why is the number of Hamiltonian Cycles of n-octahedron equivalent to the number of Perfect Matching in specific family of Graphs?

In OEIS A003436, it is written that the number of inequivalent labeled Hamilton Cycles of an n-dimesnional Octahedron is the same as the number of Perfect Matchings in a the complement of the Cycle ...
Mario Krenn's user avatar
10 votes
2 answers
782 views

Graphs with many edges avoided by Hamiltonian cycles

Let $G$ be a $3$-connected Hamiltonian graph with at least one edge that belongs to each H-cycle of $G$. Some authors (e.g. in the link given here) call such an edge an a-edge and an edge that belongs ...
Wolfgang's user avatar
  • 13.4k
14 votes
1 answer
783 views

What was Smith's proof of Smith's theorem on Hamilton cycles in cubic graphs?

In a short 1946 paper "On Hamiltonian Circuits", Tutte proved the famous result that an edge in a cubic graph lies in an even number of Hamilton circuits. He attributed the result to his friend CAB ...
Gordon Royle's user avatar
  • 12.7k
10 votes
1 answer
513 views

What is the complexity of finding a third Hamilton Cycle in cubic graph?

According to Smith Theorem: if a cubic graph has a hamilton circuit then it must have a second one. SMITH : Given a Hamilton circuit in a 3-regular graph, find a second Hamilton circuit. It is known ...
user avatar
7 votes
1 answer
210 views

Grinberg's uniquely hamiltonian 3-connected graphs (Russian paper)

Many years ago, Grinberg found some uniquely-hamiltonian $3$-connected graphs, and published his results in a paper that has been cited several times as follows. E. Grinberg, Three-connected graphs ...
Gordon Royle's user avatar
  • 12.7k
9 votes
1 answer
399 views

Are bipartite Moore graphs Hamiltonian?

This is motivated by a computer-generated conjecture that bipartite distance-regular graphs are hamiltonian. I decided to check the case of Moore graphs first. The cycles and complete bipartite graphs ...
LeechLattice's user avatar
  • 9,501
4 votes
3 answers
506 views

Does every finite bridgeless cubic planar simple undirected graph admit a 2-factorization with at most two components each of which has even order?

Consider simple bridgeless cubic planar graphs. Does each such graph admit a 2-factorization with $\leq 2$ components each of which has even order? If not, does anyone know of an counterexample? ...
Jimmy Dillies's user avatar
6 votes
1 answer
335 views

What is the complexity of counting Hamiltonian cycles of a graph?

Since deciding whether a graph contains a Hamiltonian cycle is $NP$-complete, the counting problem which counts the number of such cycles of a graph is $NP$-hard. Is it also $PP$-hard in the sense ...
T. D. Nguyen's user avatar
2 votes
1 answer
85 views

The number of Hamiltonian circuits on a convex polytope embedded in $\mathbb{R}^N$

Recently I wondered whether there might be a natural topological complexity measure for convex polytopes embedded in $\mathbb{R}^N$. After some reflection it occurred to me that the number of distinct ...
Aidan Rocke's user avatar
  • 3,871
1 vote
3 answers
883 views

Hamiltonian paths in bipartite graphs with 2 sets of "almost" same cardinality

Suppose we have two finite disjoint sets $A, B \neq \emptyset$ such that $|A|$ and $|B|$ differ by at most $1$, and let $\Gamma = (A\cup B, E)$ where $E\subseteq \big\{\{a,b\}: a\in A, b\in B\big\}$ ...
Dominic van der Zypen's user avatar
11 votes
1 answer
328 views

How many edges can be added to two circles before the graph becomes Hamiltonian?

Start with two $n$-circles $(v_1\cdots v_n)$ and $(w_1\cdots w_n)$ of vertice sets $V$ and $W$, where $n\ge 5$. Add a number of vertex-disjoint edges between $V$ and $W$ (thus no chords) in a way ...
Wolfgang's user avatar
  • 13.4k
5 votes
1 answer
1k views

How many hamiltonian cycles can be removed from a complete directed graph before it becomes disconnected?

The question started from a problem brought home by a friend's 5th grader: "How many ways can you seat 5 people around a round table so that the people sitting to the left of any person is different ...
Michael's user avatar
  • 2,205
1 vote
2 answers
321 views

Hamiltonicity and minimal degree in bipartite graphs

Given an integer $k>1$, is there a connected bipartite graph $\Gamma = (A, B, E)$ where $A\cap B = \emptyset$ and $E \subseteq \big\{\{a, b\}:a\in A, b\in B\big\}$ such that $|A| = |B|$, $\text{...
Dominic van der Zypen's user avatar
3 votes
2 answers
123 views

Number Associated with Straight-line Drawings of Hamiltonian Graphs

Is there anything known about the maximum number of simple-polygonal Hamilton cycles that a straight-line drawing of a Hamiltonian graph can have? Put differently, if the vertices of a Hamilton ...
Manfred Weis's user avatar
  • 13.2k
16 votes
1 answer
696 views

A counterexample to a conjecture of Nash-Williams about hamiltonicity of digraphs?

Maybe I am missing something, but found potential counterexample to a conjecture of Nash-Williams. According to HAMILTONIAN DEGREE SEQUENCES IN DIGRAPHS The outdegree and indegree sequences of ...
joro's user avatar
  • 25.4k
1 vote
2 answers
603 views

Graph classes where Hamiltonian Cycle and Hamiltonian Path problems have different complexity

While searching The information System on Graph Classes and their Inclusions, I stumbled on several graph classes for which the Hamiltonian Cycle problem is $NP$-complete while the complexity of ...
Mohammad Al-Turkistany's user avatar
6 votes
0 answers
73 views

Normal colorings of bridgeless cubic graphs

Definition (informal) A normal edge-5-coloring of a bridgeless cubic graph $G$ is a proper 5 coloring of the edges of the graph, so that for each edge $e\in E(G)$, either $e$ and the four edges ...
EGME's user avatar
  • 1,018
4 votes
0 answers
143 views

Halin Graphs with Highest Number of Hamilton Cycles

Halin graphs contain a Hamilton cycle and have the interesting property, that, also in the case of arbitrary real edge weights, it is possible to report one of the shortest contained Hamilton cycles ...
Manfred Weis's user avatar
  • 13.2k
8 votes
2 answers
2k views

How to efficiently find a Hamiltonian cycle in a graph whose closure is complete?

A graph whose closure is the complete graph is Hamiltonian by the Bondy-Chvátal theorem, but I haven't found a polynomial algorithm for finding a Hamiltonian cycle in such a graph. Is there one that ...
Alejandro Erickson's user avatar
3 votes
0 answers
145 views

Hamiltonian cycle polytope for the hypercube graph

Let $Q_n$ denote the $n$ dimensional hypercube graph (i.e., graph formed from the vertices and edges of an n-dimensional hypercube). Denote the set of edges and vertices of $Q_n$ by $E_n$ and $V_n$ ...
Ozzy's user avatar
  • 393
3 votes
0 answers
107 views

Reference request: Bipartite symmetric graphs are hamiltonian

Does anyone know whether bipartite symmetric graphs are hamiltonian? I'm not sure whether anyone have proved it before, but a nonhamiltonian symmetric bipartite graph would lead to a counterexample to ...
LeechLattice's user avatar
  • 9,501
4 votes
2 answers
349 views

Can we find 3 disjoint directed Hamiltonian cycles in the cube?

Let $D$ be the digraph on $2^d$ vertices with $d2^d$ edges that we obtain by directing each edge of the $d$-dimensional hypercube in both directions. Can we partition the edges of $D$ into $d$ ...
domotorp's user avatar
  • 19.1k
7 votes
1 answer
736 views

Refinement of Dirac's theorem on Hamiltonian graphs

Dirac's theorem states that if degree of each vertex of a graph $G=(V,E)$ is not less than $|V|/2$, then it has Hamiltonian cycle. It is less known, but still known and not so hard to prove (though I ...
Fedor Petrov's user avatar
1 vote
0 answers
147 views

Properties of graphs with Hankel-like adjacency matrix

I am having undirected graphs with adjacency matrices which have a regular Hankel-like form, e.g., $$A=\begin{pmatrix}0 & 0 & 1 & 0 & 0 & 0 & 0 & 1 & (6\times 0 \text{ ...
pisoir's user avatar
  • 243
3 votes
1 answer
266 views

What is the densest bipartite graph with unique Hamiltonian cycle?

In a prior post regarding perfect matching, it was stated that the densest graph with a unique perfect matching cannot have more than $n^2$ edges, if graph has $2n$ vertices. Analogously, what is the ...
Turbo's user avatar
  • 13.9k
9 votes
0 answers
245 views

Heuristic arguments regarding Sheehan's conjecture?

Sheehan conjectured that there are no 4-regular graphs that are uniquely hamiltonian (i.e. have exactly one hamilton cycle). Evidence that might be loosely seen to be in favour of this conjecture is: ...
Gordon Royle's user avatar
  • 12.7k
0 votes
1 answer
1k views

Does this graph contain at least two Hamiltonian cycles?

Let $G$ be a simple graph which is a $2n$-cycle together with $n$ chords such that $G$ is $3$-regular. In other words, the set of $n$ chords is a perfect matching of $G$. I conjecture that for every ...
user40096's user avatar
  • 421
2 votes
1 answer
606 views

Simple decomposition of $K_{2n}-I$ into hamiltonian cycles

http://mathworld.wolfram.com/HamiltonDecomposition.html In the 1890s, Walecki showed that complete graphs K_n admit a Hamilton decomposition for odd n, and decompositions into Hamiltonian cycles ...
Mohemnist's user avatar
  • 400
0 votes
1 answer
149 views

degG(x) + degG(y) >= n, show that the graph is hamiltonian [closed]

I'm trying to show that a connected graph which has order >=3, and having the following inequality is Hamiltonian: ...
KevinZ's user avatar
  • 3
6 votes
0 answers
129 views

Minimum number of hamilton cycles in a 4-connected planar triangulation?

I am currently interested in hamilton cycles (i.e. a cycle through every vertex) in planar triangulations (i.e. planar graphs with every face a triangle). There are non-hamiltonian planar ...
Gordon Royle's user avatar
  • 12.7k
8 votes
0 answers
123 views

Is there a non-bipartite hamiltonian cubic graph on $n$ vertices with no $(n-1)$-cycle?

Is there a cubic (3-regular) graph $G$ on $n$ vertices such that: $G$ is hamiltonian $G$ has no $(n-1)$-cycles $G$ is not bipartite My computer tells me that there are none on up to $24$ vertices.
Gordon Royle's user avatar
  • 12.7k
4 votes
0 answers
258 views

When is an induced subgraph of a Johnson graph hamilton-connected?

The Johnson graph $J(n,k)$ has as its vertices the $k$-subsets of $\{1, 2, \dots, n\}$ where two vertices are adjacent iff their intersection has size $k-1$. A graph is Hamilton-connected if every two ...
jamisans's user avatar
  • 393
1 vote
1 answer
78 views

Graph gadget related to uniquely hamiltionian regular graphs (question #2)

Related to uniquely hamiltionian graphs. For natural numbers $a,b$ define $(a,b)$ gadget $G$: $G$ is finite simple graph. Two vertices $u,v$ are of degree $b$ and the rest of the vertices are of ...
joro's user avatar
  • 25.4k
4 votes
1 answer
724 views

Minimum distance between Hamiltonian cycles in cubic Hamiltonian graph

It is $NP$-hard to find constant factor approximation of longest cycle in cubic Hamiltonian graphs. Therefore, finding a Hamiltonian cycle in a cubic Hamiltonian graph is NP-hard. By Smith's theorem, ...
Mohammad Al-Turkistany's user avatar
5 votes
0 answers
99 views

Graph gadget related to uniquely hamiltionian regular graphs

A graph is uniquely hamiltonian if it has exactly one hamiltonian cycle. According to a conjecture there are no $r$-regular uniquely hamiltonian graphs for $r > 2$ and of special interest is the ...
joro's user avatar
  • 25.4k
6 votes
0 answers
108 views

Localizing Bondy's metaconjecture on hamiltonicity

Definitions: Let $G$ be a graph on $n$ vertices. $G$ is Hamiltonian provided $G$ has a cycle of length $n$. $G$ is pancyclic provided $G$ has a cycle of length $\ell$ for every $3 \leq \ell \leq n$. ...
D. Ror.'s user avatar
  • 399
5 votes
1 answer
224 views

Reconstructing the number of Hamiltonian cycles

As is common terminology in graph reconstruction, given a graph $G$, we call a vertex deleted subgraph of $G$, a card, and call the multiset of all cards, the deck of $G$. The graph reconstruction ...
Gjergji Zaimi's user avatar
6 votes
0 answers
76 views

Cage graphs and even cycles

Let $G$ be a $(\nu,g)$-cage graph of degree $\nu$ with girth $g$ and $n=n(\nu,g)$ vertices. Based on the known examples, I am wondering if the following can be proved/disproved: Is it true that ...
Wolfgang's user avatar
  • 13.4k
6 votes
1 answer
243 views

Hamiltonicity criteria for sparse graphs

Given a sparse graph, how can one go about proving that it is Hamiltonian? (Assuming it actually is, of course). There are three main classes of criteria for Hamiltonicity that I am aware of: Dirac-...
Felix Goldberg's user avatar
5 votes
0 answers
295 views

A digraph related to permutations

A finite sequence of distinct real numbers of length $n$ determines a linear order of $\{1,\ldots,n\}$, by mapping position to rank; call this the permutation of the sequence. Consider the following ...
David Feldman's user avatar
3 votes
1 answer
117 views

Hamiltonicity of random graphs with high girth

We say that $G\sim G_{n,f}$ (for $f=f(n)$) if $G$ is chosen uniformly at random from all graphs on $n$ vertices with girth $g(G)\ge f(n)$. Is there any threshold function $F(n)$ such that when $f\ll F$...
Bach's user avatar
  • 221
3 votes
1 answer
219 views

Regular graphs with $a$ and $b$ Hamiltonian edges

Special case of this question. Let $G$ be $r$-regular Hamiltonian graph. An $a$ edge is an edge which is on every Hamiltonian cycle. A $b$ edge is an edge which is on no Hamiltonian cycle. $a(G)$ ...
joro's user avatar
  • 25.4k
6 votes
1 answer
344 views

Hamiltonian cycles in power-graphs

I've stumbled across a short note from 1993 where a nice question was asked: Suppose you take a graph with vertices $\{1,2,\ldots,n\}$ and connect $i,j$ by an edge if and only if $i+j$ is a $k$th ...
Felix Goldberg's user avatar