Skip to main content

All Questions

Filter by
Sorted by
Tagged with
4 votes
0 answers
177 views

Basis of topology on space of properly embedded smooth manifolds

In A Short Exposition of the Madsen-Weiss Theorem, Hatcher discusses (starting at p.6) a basis for a topology on the space $\mathcal{C}^n$, the space of all smooth oriented $d$-dimensional ...
jasnee's user avatar
  • 141
25 votes
1 answer
582 views

Does every oriented $3$-dimensional submanifold of $\mathbb{R}^6$ bound an oriented $4$-dimensional submanifold?

In my recent research, I encountered the following problem about embeddings. Let $M^3$ be a closed compact oriented smooth $3$-dimensional submanifold of $\mathbb{R}^6$. Does there exist a compact ...
Zhenhua Liu's user avatar
6 votes
1 answer
206 views

A stable splitting of linear surjections

Some computations I've been doing in Weiss calculus predict the following stable splitting of the space of linear surjections: $\Sigma^\infty_+ \mathrm{Sur}(\mathbb{R}^n,\mathbb{R}^{m_1+m_2})$ as the ...
Connor Malin's user avatar
  • 5,839
5 votes
1 answer
380 views

Proving the Cork Theorem

I am reading Kirby's paper paper "Akbulut's corks and h-cobordisms of smooth simply connected 4-manifolds" and I have a question about how to actually prove the cork theorem from the results ...
failedentertainment's user avatar
14 votes
0 answers
326 views

When can we extend a diffeomorphism from a surface to its neighborhood as identity?

Let $M$ be a closed and simply-connected 4-manifold and let $f: M^4 \to M^4$ be a diffeomorphism such that $f^*: H^*(M;\mathbb{Z})\to H^*(M;\mathbb{Z})$ is the identity map. Moreover, let $\Sigma \...
Anubhav Mukherjee's user avatar
1 vote
0 answers
57 views

extendability of fibre bundles on manifolds with same dimensions

Let $M$ be an $m$-manifold. Let $M'\subseteq M$, where $M'$ is also an $m$-manifold. Let $N$ be an $n$-manifold. Let $N'\subseteq N$, where $N'$ is also an $n$-manifold. Suppose there is fibre ...
Shiquan Ren's user avatar
0 votes
1 answer
135 views

Local embedding and disk in domain perturbation

Consider say $M=(\mathbb{S}^1\times\dotsb\times \mathbb{S}^1)-q$ ($n$-times). Assume that $B$ is an $n$ disk in $M$ (for instance, thinking of $\mathbb{S}^1$ as gluing $-1$ and $1$, the cube $B=[-\...
monoidaltransform's user avatar
5 votes
1 answer
429 views

Linking number and intersection number

Consider a disjoint union of two circles $A$ and $B$ smoothly embedded in $\mathbb{R}^3$ with linking number more than $1$. Suppose we know that there exists a disc $D$ in $\mathbb{R}^3$ such that $\...
user429294's user avatar
3 votes
1 answer
200 views

Does the group of compactly supported diffeomorphisms have the homotopy type of a CW complex?

It is known that the group of diffeomorphisms of a compact manifold with the natural $C^{\infty}$ topology has the homotopy type of a countable CW complex. See for instance this thread: Is the space ...
Yasha's user avatar
  • 491
5 votes
0 answers
158 views

Representing some odd multiples of integral homology classes by embedded submanifolds

Consider an $m$-dimensional compact closed orientable smooth manifold $M$ and an $n$-dimensional integral homology class $[\Sigma]$ on $M$, with $1 \le n \le m-1$. Then does there exist an odd integer ...
Zhenhua Liu's user avatar
13 votes
1 answer
518 views

Impossibility of realizing codimension 1 homology classes by embedded non-orientable hypersurfaces

Suppose we have an $n+1$-dimensional compact closed oriented manifold $M$ and an $n$-dimensional integral homology class $[\Sigma]\in H_n(M,\mathbb{Z})$ on $M.$ Then is it true that $[\Sigma]$ mod $2$ ...
Zhenhua Liu's user avatar
4 votes
0 answers
206 views

Reference for a folklore theorem about h-cobordisms

I've seen referenced here that if $M$ and $N$ are closed topological $n$-manifolds and $f: \mathbb{R}\times M \to \mathbb{R}\times N$ is a homeomorphism, then $M$ and $N$ are h-cobordant. I know that ...
nick5435's user avatar
0 votes
1 answer
376 views

Relation between trivial tangent bundle $\Leftrightarrow$ certain characteristic classes of tangent bundle vanish [closed]

We know that framing structure means the trivialization of tangent bundle of manifold $M$. string structure means the trivialization of Stiefel-Whitney class $w_1$, $w_2$ and half of the first ...
zeta's user avatar
  • 447
2 votes
0 answers
147 views

Extension of isotopies

In what follows $M$ will be a manifold (without boundary, for simplicity) and $C\subseteq M$ will denote a compact subset. In the paper Deformations of spaces of imbeddings Edwards and Kirby prove the ...
Tommaso Rossi's user avatar
0 votes
0 answers
120 views

Topological transversality by dimension

We know that to achieve transverality in the topological category, for example to make a continuous map into a manifold transverse to a topological submanifold, we need the existence of micro normal ...
UVIR's user avatar
  • 803
4 votes
1 answer
192 views

Version of pseudo-isotopy $\neq$ isotopy for $(n+1)$-framings

Let $M$ be a closed $n$-manifold and $\varphi$ be a self-diffeomorphisms of $M$. There is a bordism from $M$ to itself given by $M\times [0,1]$ with the identification $M \cong M \times \{0\}$ induced ...
Daniel Bruegmann's user avatar
16 votes
0 answers
425 views

Is the oriented bordism ring generated by homogeneous spaces?

I am trying to find a Riemannian geometrically well-understood set of generators of the oriented bordism ring, including the torsion parts. By a set of generators, I mean that the set generates the ...
Zhenhua Liu's user avatar
6 votes
0 answers
209 views

"Inclusion" between higher categories of framed bordisms?

Let $\mathrm{Bord}_n$ be the bordism $(\infty, n)$-category of unoriented manifolds. It can be viewed as an $(\infty, n+1)$-category whose $n+1$-morphisms are equivalences. If $n$ is large enough, ...
Daniel Bruegmann's user avatar
1 vote
0 answers
160 views

Higher dimensional Seifert surfaces and link numbers of higher knots

In 3-manifold topology, the notion of Seifert surface is well known. It is then used to define link numbers of knots. Question: Consider embedding $N^n \rightarrow M^{2n+1}$ of n-dimensional manifold $...
0x11111's user avatar
  • 593
2 votes
0 answers
146 views

Explicit S-duality map

$\DeclareMathOperator{\Th}{Th}$ The Thom space of a closed manifold $M$ ($\Th(M)$) is the $S$-dual to $M_+ (=M \cup \{pt\})$. Let $M$ be embedded in $\mathbf R^{n+k}$. I found the duality map from $S^...
Sagnik Biswas ma20d013's user avatar
13 votes
1 answer
386 views

Realizing integral homology classes on non-orientable manifolds by embedded orientable submanifolds

Let $M^m$ denote a compact, non-orientable smooth manifold and $\nu$ an integral homology class of dimension $n$. I am interested in understanding the representability of $\nu$ by embedded, orientable ...
Zhenhua Liu's user avatar
11 votes
1 answer
331 views

Embedded 2-tori in $S^1\times S^4$

I am interested in understanding the smooth isotopy class of embedded 2-tori in $S^1\times S^4$. Is it true that every two homotopic embedded 2-tori in $S^1\times S^4$ are smoothly isotopic? It would ...
Dmitrii Ivanov's user avatar
20 votes
2 answers
901 views

Integral homology classes that can be represented by immersed submanifolds but not embedded submanifolds

Let $M$ be an $m$-dimensional compact closed smooth manifold and $z\in H_n(M,\mathbb{Z})$ an $n$-dimensional integral homology class, with $m>n.$ Does there exist a pair of $M$ and $z$ so that $z$ ...
Zhenhua Liu's user avatar
1 vote
1 answer
256 views

Reference request and prerequisites for understanding the Sphere Theorem and the Loop Theorem in 3-manifold theory

As part of my directed studies project, my advisor has suggested that I completely understand the proof of the Sphere Theorem and the Loop Theorem in 3-manifold theory and explain it to him. I have ...
ZSMJ's user avatar
  • 131
8 votes
1 answer
217 views

Integral homology classes of which no multiples admit embedded representatives with trivial normal bundle

Let $M$ be a closed smooth manifold of dimension $n$ and $z\in H_l(M,\mathbb{Z})$ a $k$-dimensional integral homology class. Theorem II.4 of Thom's classical 1954 paper states that for $l< n/2$ or $...
Zhenhua Liu's user avatar
13 votes
1 answer
459 views

Compact closed aspherical manifolds with vanishing second homology in all the covering spaces

I wonder if there exists a compact closed smooth aspherical manifold $M$ of dimension at least $4$, so that for any covering space $\tilde{M}$ over $M,$ we always have $H_2(\tilde{M},\mathbb{Z})=0$ ...
Zhenhua Liu's user avatar
3 votes
1 answer
235 views

Example of a non $\pi_1$-injective, degree one, self-map of a three-manifold

All manifolds will be assumed to be closed, oriented, and connected. Let $f\colon M\to M$ be a map of degree $\pm 1$. It is not hard to show that $\pi_1(f)$ is surjective. What is an example of a non ...
Random's user avatar
  • 1,097
11 votes
3 answers
1k views

Computation on characteristic classes

I am organizing a reading seminar on characteristic classes. The audience in the seminar is interested in symplectic and contact manifolds. I work in categorification and would like to compute some ...
Monkey.D.Luffy's user avatar
2 votes
0 answers
105 views

Vanishing of Goldman bracket requires simple-closed representative?

Let $\Sigma$ be a connected oriented surface, and $[-,-]\colon \Bbb Z\big[\widehat\pi(\Sigma)\big]\times Z\big[\widehat\pi(\Sigma)\big]\to Z\big[\widehat\pi(\Sigma)\big]$ be the Goldman Bracket. Note ...
Random's user avatar
  • 1,097
2 votes
1 answer
267 views

on second cohomology of $S^1$-manifold

Let $M$ be a closed oriented real manifold with a free smooth circle action. Denote $BS^1$ to be the classifying space of principal circle bundles and $ES^1\rightarrow BS^1$ to be the universal ...
user1568940's user avatar
6 votes
1 answer
414 views

Do $h$-cobordism groups arise from a 'Thom-like' spectrum?

Not thinking about $h$-cobordism, one usually defines a cobordism between manifolds, realizes it is an equivalence relation, chooses an appropriate class of structured manifolds (framed, unoriented, ...
Matthew Niemiro's user avatar
8 votes
1 answer
429 views

Gluing of orbifolds

Suppose that $P$ and $Q$ are $n$-dimensional orbifolds, with boundaries. Suppose also that there is an isomorphism $f \colon \partial P \rightarrow \partial Q$ (as orbifolds). Is there a way to glue $...
Hao Yu's user avatar
  • 781
2 votes
1 answer
130 views

Gluing isotopic smoothings

Let $M$ be a topological manifold which can be written as $M = U \cup V$ where $U$ and $V$ are open. Suppose both $U$ and $V$ admit smooth structures. Also assume that on the overlap $U \cap V$ the ...
UVIR's user avatar
  • 803
30 votes
1 answer
1k views

Are homeomorphic representations isomorphic?

Let $G$ be a finite group. Let $V_1, V_2$ be two finite-dimensional real representations. Suppose $f: V_1 \to V_2$ is a $G$-equivariant homeomorphism. Can one conclude that $V_1$ and $V_2$ are ...
UVIR's user avatar
  • 803
1 vote
1 answer
147 views

Transversal pre-image of a small enough trivial tubular neighborhood contains a trivial tubular neighborhood

A similar post on MSE without answer. Let $f\colon M'\to M$ be a smooth map between two orientable closed smooth manifolds and $S$ be a smoothly embedded closed orientable submanifold of $M$ of co-...
Random's user avatar
  • 1,097
6 votes
0 answers
162 views

Uniqueness of normal microbundle of a smooth embedding

Suppose $M$ is a topological manifold and $\iota: N\hookrightarrow M$ be a submanifold. A normal microbundle of $N$ consists of an open neighborhood $U$ of $N$ and a retraction $\pi: U \to N$ such ...
UVIR's user avatar
  • 803
8 votes
0 answers
267 views

$\mathbb RP^n$ bundles over the circle, II

EDIT: I fixed the issue pointed out by Nicholas Tholozan, thanks for sheding light on this! This question is written as a follow-up to this one. Both answers there are great, but my impression is ...
Jens Reinhold's user avatar
2 votes
1 answer
295 views

In which dimensions is it true that every topological ball embedded by a smoothly embedded sphere is a smoothly embedded ball?

I asked a question on MSE with no answer. Here is my question in the generalized version. Question 1: Suppose we are given a connected three-manifold $M$ (possibly non-compact, or non-orientable) and ...
Random's user avatar
  • 1,097
1 vote
0 answers
284 views

A question on existence of gradient vector field on manifold with boundary

Let $M$ be a compact manifold with smooth boundary $\partial M$. Does $M$ admit a gradient vector field $\nabla u$, which has no zeros, i.e. $\nabla u(x)\neq 0$, $\forall x\in M\cup\partial M$? Thanks ...
yuan's user avatar
  • 51
6 votes
1 answer
222 views

Stable smoothing of topological manifolds relative to an embedding

Let $M$ be a topological manifold. We know that $M$ is stably smoothable if and only its tangent microbundle, up to stabilization, admits a reduction to vector bundle. Now I wonder if there is a ...
UVIR's user avatar
  • 803
17 votes
1 answer
898 views

Does there exist a closed manifold with vanishing reduced rational cohomology but nonvanishing odd torsion cohomology?

Question: Let $p$ be an odd prime. Does there exist a closed manifold $M$ with $\widetilde H^\ast(M; \mathbb Q) = 0$ but $\widetilde H^\ast(M; \mathbb F_p) \neq 0$? When $p = 2$, an example is given ...
Tim Campion's user avatar
  • 63.9k
0 votes
0 answers
266 views

Define a characteristic class on a simplicial complex (non-manifold)

Given a simplicial complex with only triangulation and only branching structure, is it enough to define Stiefel–Whitney class? (Please provide Yes or No answers, and reasonings.) Given a fixed ...
wonderich's user avatar
  • 10.5k
9 votes
1 answer
588 views

Oriented bordism in higher dimensions (e.g. $12 \leq d \leq 28$)

The classification of oriented compact smooth manifolds up to oriented cobordism is one of the landmarks of 20th century topology. The techniques used there form the part of the foundations of ...
wonderich's user avatar
  • 10.5k
11 votes
0 answers
335 views

Isotopy on embedded 3-manifolds in 4-manifolds

Suppose that $X$ be an oriented, closed four-manifold. Suppose that $Y$ is an oriented, closed three-manifold smoothly embedded in $X$. Suppose also that $f:X \to X$ is a diffeomorphism that fixes $Y$...
Anubhav Mukherjee's user avatar
40 votes
2 answers
2k views

Can the nth projective space be covered by n charts?

That is, is there an open cover of $\mathbb{R}P^n$ by $n$ sets homeomorphic to $\mathbb{R}^n$? I came up with this question a few years ago and I´ve thought about it from time to time, but I haven´t ...
Saúl RM's user avatar
  • 10.6k
0 votes
1 answer
154 views

Why does $X_0\times S^1\simeq X-X_0$? [closed]

Let $X$ be an $n$-dimensional connected smooth manifold, and let $X_0$ be an embedded $(n-2)$-dimensional compact submanifold of $X$ with the trivial normal bundle. How do we get inclusion? $$X_0\...
Radeha Longa's user avatar
0 votes
1 answer
284 views

Künneth formula and induced map in homologies

Let $X,Y,Z$ be smooth connected manifolds and $f \colon X \times Y \rightarrow Z$ a smooth map. Suppose that we have $H_{*}(X \times Y; \mathbb{Z})$ is isomorphic to $\bigoplus_{p+q=*}(H_{p}(X; \...
Math1016's user avatar
  • 369
8 votes
0 answers
222 views

Representing the fundamental class of an aspherical manifold in the bar complex

Suppose $M$ is a compact orientable aspherical manifold and $G$ its fundamental group. Is there a nice description of representatives of the fundamental class of $M$ and its dual in the (homogenous) ...
ThorbenK's user avatar
  • 1,174
1 vote
0 answers
102 views

DA structure of a Dehn twist

I am trying to find the DA bordered homology structure of a Dehn twist.In https://arxiv.org/pdf/0810.0687v6.pdf page 255 bottom the authors tabulate the differentials of the right module(A side) of ...
user123090's user avatar
8 votes
0 answers
219 views

Computation of the 3-dimensional $\mathbb{Z}/m$-equivariant spin cobordism group (with possibly non-empty fixed-point set)?

$\newcommand{\odd}{\mathrm{odd}}\newcommand{\ev}{\mathrm{ev}}$Consider tuples of the form $(Y,\mathfrak{s},\widehat{\sigma})$ where: $Y$ is a closed oriented 3-manifold, $\mathfrak{s}$ is a spin ...
Ian Montague's user avatar