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34 votes
4 answers
5k views

What is the right definition of the Picard group of a commutative ring?

This is a rather technical question with no particular importance in any case of actual interest to me, but I've been writing up some notes on commutative algebra and flailing on this point for some ...
Pete L. Clark's user avatar
33 votes
0 answers
2k views

Is there a (discrete) monoid M injecting into its group completion G for which BM is not homotopy equivalent to BG?

For a (discrete) monoid $M$, the classifying space $BM$ is the geometric realization of the nerve of the one object category whose hom-set is $M$. (This definition gives the usual classfiying space ...
Omar Antolín-Camarena's user avatar
33 votes
2 answers
7k views

Noetherian rings of infinite Krull dimension?

Since Noetherian rings satisfy the ascending chain condition, every such ring must contain infinitely many chains of prime ideals s.t. the heights of these chains are unbounded. The only example I ...
moby's user avatar
  • 331
33 votes
5 answers
13k views

Atiyah-MacDonald, exercise 2.11

Let $A$ be a commutative ring with $1$ not equal to $0$. (The ring A is not necessarily a domain, and is not necessarily Noetherian.) Assume we have an injective map of free $A$-modules $A^m \to A^n$...
CJD's user avatar
  • 1,098
32 votes
5 answers
9k views

How many binary operations are associative?

Let $X$ be a finite set of $n$ elements, and consider a binary operation $\odot: X \times X \rightarrow X$. There are $n^{n^2}$ such binary operations, as the $n \times n$ table entries can each be ...
Joseph O'Rourke's user avatar
32 votes
4 answers
2k views

Do there exist non-PIDs in which every countably generated ideal is principal?

The title pretty much says it all: suppose $R$ is a commutative integral domain such that every countably generated ideal is principal. Must $R$ be a principal ideal domain? More generally: for ...
Pete L. Clark's user avatar
31 votes
2 answers
2k views

Should Krull dimension be a cardinal?

A totally ordered finite set $\quad \mathcal P_0 \varsubsetneq \mathcal P_1\varsubsetneq \dots \mathcal \varsubsetneq \mathcal P_n \quad$ of prime ideals of a ring $A$ is said to be a chain of ...
Georges Elencwajg's user avatar
31 votes
1 answer
2k views

Are Conway's omnific integers the Grothendieck group of the ordinals under commutative addition?

This is a question in two parts. Say that $\mathbf{On}$ is the proper class of all ordinal numbers in ZFC. We can define a binary operator over $\mathbf{On}$ which corresponds to the commutative ...
Mike Battaglia's user avatar
31 votes
8 answers
21k views

Reference book for commutative algebra

I'm looking for a good book in commutative algebra, so I ask here for some advice. My ideal book should be: More comprehensive than Atiyah–Macdonald More readable than Matsumura (maybe better ...
29 votes
2 answers
2k views

What are applications of commutativity theorems for rings?

Herstein's little book "Noncommutative Rings" has a chapter called Commutativity Theorems in which he proves results like Jacobson's theorem: if a ring (associative with identity, please) has the ...
KConrad's user avatar
  • 50.6k
28 votes
2 answers
2k views

A sum involving roots of unity

Let $n$ be a positive integer and $\zeta$ be a primitive $n$th root of unity. It is not hard to show that \begin{align*} \sum_{k=1}^{n-1}\frac{\zeta^k}{1-\zeta^k}=\frac{1-n}{2}. \end{align*} Since $\...
Chitsai Liu's user avatar
  • 2,183
28 votes
5 answers
9k views

Can a quotient ring R/J ever be flat over R?

If $R$ is a ring and $J\subset R$ is an ideal, can $R/J$ ever be a flat $R$-module? For algebraic geometers, the question is "can a closed immersion ever be flat?" The answer is yes: take $J=...
Anton Geraschenko's user avatar
27 votes
2 answers
2k views

Is every commutative ring a limit of noetherian rings?

Edit of Feb. 14, 2019. After Laurent Moret-Bailly's accepted answer, only Questions 4 and 5 remain open. I don't care that much about Question 4, but I'm very curious about Question 5, which is Do ...
Pierre-Yves Gaillard's user avatar
27 votes
5 answers
14k views

Flat module and torsion-free module

All rings in this question are integral. It is known that flat modules are torsion-free. Conversely, torsion-free modules over Prüfer domain (in particular, Dedekind domain) are flat, please see here. ...
Liu Hang's user avatar
  • 951
27 votes
5 answers
3k views

Algebraic description of compact smooth manifolds?

Given a compact smooth manifold $M$, it's relatively well known that $C^\infty(M)$ determines $M$ up to diffeomorphism. That is, if $M$ and $N$ are two smooth manifolds and there is an $\mathbb{R}$-...
Jason DeVito - on hiatus's user avatar
26 votes
5 answers
3k views

Given a polynomial f, can there be more than one constant c such that every root of f(x)-c is repeated?

The question Let $f$ be a nonconstant polynomial over $\mathbb{C}$. Let's say that a point $c \in \mathbb{C}$ is unusual for $f$ if every root $x$ of $f(x) - c$ is repeated. Can $f$ have more than ...
Tom Leinster's user avatar
  • 27.7k
26 votes
4 answers
3k views

Is a domain all of whose localizations are noetherian itself noetherian ?

Is a domain $D$, all of whose localizations $D_P$ for $P \in Spec(D)$ are noetherian, itself noetherian ? The question is motivated by proposition 11.5 of Neukirch's Algebraic Number Theory: Let ...
KBuck's user avatar
  • 558
26 votes
2 answers
4k views

Why are injective modules more complicated than projective modules?

For beginners in homological algebra, it is a fact of life that injective modules seems to be more mysterious than projective modules. For example, for finitely generated modules over a noetherian ...
temp's user avatar
  • 2,040
25 votes
7 answers
3k views

When can we prove constructively that a ring with unity has a maximal ideal?

Many commutative algebra textbooks establish that every ideal of a ring is contained in a maximal ideal by appealing to Zorn's lemma, which I dislike on grounds of non-constructivity. For Noetherian ...
Qiaochu Yuan's user avatar
25 votes
1 answer
5k views

The Rabinowitz Trick

The recent question about problems which are solved by generalizations got me thinking about the Rabinowitz trick, which is used to prove a statement of Hilbert's Nullstellensatz, specifically, the ...
Grant Rotskoff's user avatar
25 votes
3 answers
1k views

What spaces $X$ do have $\text{End}(X) \cong \text{End}(\mathbb{R})$?

This is a follow-up on the following question. Let $\text{End}(X)$ denote the endomorphism monoid of a topological space $X$ (that is, the collection of all continuous maps $f:X\to X$ with composition)...
Dominic van der Zypen's user avatar
24 votes
5 answers
2k views

Lie groups vs Lie monoids

Does there exist a well developed theory of a class of objects which might rightfully be called Lie monoids? By this I mean with axioms similar to those of Lie groups, but with the axiomatic existence ...
Benjamin's user avatar
  • 2,099
24 votes
6 answers
5k views

Pythagorean 5-tuples

What is the solution of the equation $x^2+y^2+z^2+t^2=w^2$ in polynomials over C ("Pythagorean 5-tuples")? There are simple formulas describing Pythagorean n-tuples for n=3,4,6: n=3. The formula ...
mikhail skopenkov's user avatar
24 votes
3 answers
1k views

Is $\widehat{\mathbb{Z}}[[t]]\cong\widehat{\mathbb{Z}}[[\widehat{\mathbb{Z}}]]$?

Let $\widehat{\mathbb{Z}}[[\widehat{\mathbb{Z}}]] := \varprojlim_{n,m}(\mathbb{Z}/n)[x]/(x^m-1)$ be the complete group algebra of the profinite free group of rank 1. In Corollary 5.9.2 of Ribes-...
stupid_question_bot's user avatar
24 votes
3 answers
3k views

Non-abelian Grothendieck group

By general nonsense the forgetful functor from groups to monoids has a left adjoint. It maps a monoid $(X,\cdot,1)$ to the free group on $\{\underline{x} : x \in X\}$ modulo the relations $\underline{...
Martin Brandenburg's user avatar
23 votes
2 answers
910 views

How slowly can a power of an ideal grow?

For a polynomial ideal $I\subset \mathbb{C}[x_1,x_2]$, let $D(I)$ be the smallest degree of any polynomial in $I$. How slowly can $D(I^n)$ grow as a function of $n$? For example, if $D(I^n)\leq 1....
Boris Bukh's user avatar
  • 7,836
23 votes
1 answer
2k views

Examples of Noetherian overkill

I have read in many places that the noetherian hypothesis is often overkill - both in commutative algebra and in ($\overset?=$) algebraic geometry. In particular, I've read that coherence and finite ...
Arrow's user avatar
  • 10.5k
23 votes
1 answer
3k views

Modules and Square Zero Extensions

Let $R$ be a commutative ring, $RMod$ its category of modules and $CRing$ the category of commutative rings. There's an embedding $RMod \rightarrow CRing/R$ that sends an $R$-module $M$ to the ring ...
Eric Finster's user avatar
  • 1,484
23 votes
3 answers
4k views

What are the units in the ring of Laurent polynomials?

What are the units in $R[X,X^{-1}]$, where $R$ is a commutative ring with $1$? I know that the question for polynomial rings is a standard textbook exercise. However, I couldn't find a reference for ...
Seb's user avatar
  • 323
22 votes
2 answers
2k views

Anything special (historical?) about surface $x\cdot y\cdot z\ +\ x+y+z=0$?

QUESTION I wanted to introduce and develop the complex logarithm from scratch. As the result I've arrived a couple of months ago at the following identity after which the road to complex logarithm is ...
Włodzimierz Holsztyński's user avatar
22 votes
6 answers
6k views

When is a blow-up non-singular?

Suppose that $X$ is a non-singular variety and $Z \subset X$ is a closed subscheme. When is the blow-up $\operatorname{Bl}_{Z}(X)$ non-singular? The blow-up of a non-singular variety along a non-...
jlk's user avatar
  • 3,284
22 votes
2 answers
5k views

affine open subset of affine scheme

Let $X=Spec(A)$ be an affine scheme and $U=Spec(R)$ be an affine open subset of $X$. Is it true that $R$ is an localization of $A$, i.e. $R=S^{-1}A$ for some closed multiplication subset $S\subset A$ ?...
vdm123's user avatar
  • 427
22 votes
3 answers
2k views

Nice algebraic statements independent from ZF + V=L (constructibility)

Background and motivation I've always been fascinated about algebraic statements independent from ZFC set theory. One such fascinating example comes from considering $\rm{Ext}^1_\mathbb{Z}(A,\mathbb{Z}...
user avatar
22 votes
3 answers
3k views

Which rings are subrings of matrix rings?

In this question, all rings are commutative with a $1$, unless we explicitly say so, and all morphisms of rings send $1$ to $1$. Let $A$ be a Noetherian local integral domain. Let $T$ be a non-zero $...
Kevin Buzzard's user avatar
21 votes
2 answers
3k views

Standard reduction to the artinian local case?

Where can I find a clear exposé of the so called "standard reduction to the local artinian (with algebraically closed residue field", a sentence I read everywhere but that is never completely unfold? ...
Workitout's user avatar
  • 411
21 votes
1 answer
2k views

Does formally etale imply flat for noetherian schemes?

This is a followup to an earlier question I asked: Does formally etale imply flat? After some remarks I received on MO I noticed that this was answered to the negative by an answer to an earlier ...
mabli's user avatar
  • 705
21 votes
2 answers
2k views

What is the dimension of the product ring $\prod \mathbb Z/2^n\mathbb Z$ ?

In an anwswer to a question on our sister site here I mentioned that a reduced commutative ring $R$ has zero Krull dimension if and only if it is von Neumann regular i.e. if and only if for any $r\...
Georges Elencwajg's user avatar
21 votes
2 answers
1k views

If a polynomial ring is finite free over a subring, is the subring polynomial?

Let $R = k[x_1, \ldots, x_n]$ for $k$ a field of characteristic zero and let $S \subset R$ be a graded sub-$k$-algebra (for the standard grading: $\deg x_i = 1$) such that $R$ is a free $S$-module of ...
David E Speyer's user avatar
21 votes
1 answer
584 views

Existence of a polynomial $Q$ of degree $\geq (p-1)/4$ in $\mathbb F_p[x]$ such that $QQ'$ factorizes into distinct linear factors

For all primes up to $p=89$ there exists a product $Q=\prod_{j=1}^d(x-a_j)$ involving $d\geq (p-1)/4$ distinct linear factors $x-a_j$ in $\mathbb F_p[x]$ such that $Q'$ has all its roots in $\mathbb ...
Roland Bacher's user avatar
21 votes
2 answers
2k views

Stability of real polynomials with positive coefficients

Say that a polynomial in an indeterminate $x$ with real coefficients of degree $d$ has positive coefficients if each of the coefficients of $x^d,\ldots,x^1,x^0$ is (strictly) positive. For $f$ a ...
user avatar
21 votes
1 answer
2k views

Two conjectures by Gabber on Brauer and Picard groups

In a paper I need to make reference to two conjectures by Gabber, from Ofer Gabber, On purity for the Brauer group, in: Arithmetic Algebraic Geometry, MFO Report No. 37/2004, doi:10.14760/OWR-2004-37 ...
Hailong Dao's user avatar
  • 30.5k
21 votes
4 answers
4k views

Why are finitely generated modules over principal artin local rings direct sums of cyclic modules?

I am looking for a proof of the following fact: If $R$ is a principal artin local ring and $M$ a finitely generated $R$-module, then $M$ is a direct sum of cyclic $R$-modules. (Apparently such rings $...
Keenan Kidwell's user avatar
21 votes
6 answers
3k views

A ring such that all projectives are stably free but not all projectives are free?

This question is motivated by this recent question. Suppose $R$ is commutative, Noetherian ring and $M$ a finitely generated $R$-module. Let $FD(M)$ and $PD(M)$ be the shortest length of free and ...
Hailong Dao's user avatar
  • 30.5k
20 votes
1 answer
2k views

Joyal's construction of the spectrum of a commutative ring

I am trying to understand bits and pieces of Lawvere's article Continuously Variable Sets; Algebraic Geometry = Geometric Logic. I'm not doing very well. I know this is a lot to ask, but basically, I ...
Arrow's user avatar
  • 10.5k
20 votes
3 answers
2k views

Simple example of a ring which is normal but not CM

I try to keep a list of standard ring examples in my head to test commutative algebra conjectures against. I would therefore like to have an example of a ring which is normal but not Cohen-Macaulay. I'...
David E Speyer's user avatar
20 votes
1 answer
2k views

How is a descent datum the same as a comodule structure?

For a homomorphism of commutative rings $f:R\to S$, there are at least two notions of a descent datum for this map. One of these is to be an $S$-module $M$, with an isomorphism $M\otimes_R S\cong S\...
Jonathan Beardsley's user avatar
20 votes
1 answer
1k views

Does the ring $R = \mathbb{Z}[X^{\pm1}]$ of Laurent polynomials over $\mathbb{Z}$ satisfy $SL_2(R) = E_2(R)$?

Let $R = \mathbb{Z}[X^{\pm1}]$ be the ring of Laurent polynomials on one indeterminate over $\mathbb{Z}$. Let $E_2(R)$ be the subgroup of $GL_2(R)$ generated by the matrices that differ from the ...
Luc Guyot's user avatar
  • 7,893
20 votes
3 answers
2k views

Is every integral epimorphism of commutative rings surjective?

That's the question. Recall that a morphism $f\colon A\to B$ of commutative rings is integral if every element in $B$ is the root of a monic polynomial with coefficients in the image of $A$ and that $...
JBorger's user avatar
  • 9,408
20 votes
5 answers
2k views

Constructively, is the unit of the “free abelian group” monad on sets injective?

Classically, we can explicitly construct the free Abelian group $\newcommand{\Z}{\mathbb{Z}}\Z[X]$ on a set $X$ as the set of finitely-supported functions $X \to \Z$, and so easily see that the unit ...
Peter LeFanu Lumsdaine's user avatar
19 votes
2 answers
5k views

Are morphisms from affine schemes to arbitrary schemes affine morphisms?

To put this question in precise language, let $X$ be an affine scheme, and $Y$ be an arbitrary scheme, and $f : X \rightarrow Y$ a morphism from $X$ to $Y$. Does it follow that $f$ is an affine ...
Erick Knight's user avatar

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