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Mathematical methods in classical mechanics, classical and quantum field theory, quantum mechanics, statistical mechanics, condensed matter, nuclear and atomic physics.
2
votes
What structure does Rep(vertex algebra) have?
I suspect the expected structure of $Rep(V)$ common to all vertex algebras $V$ is something like "abelian pseudomonoidal category" and I don't think you can say much else. The abelian structure follo …
20
votes
Theoretical physics: Why not just $\mathbb{R}^4$?
I can answer your literal question. Not everyone studies exotic $\mathbb{R}^4$, because the universe of mathematical and theoretical physics is a big one with many interesting ideas, and there's no r …
1
vote
Number-theoretic congruences with geometry and topology?
I'm not an expert in this area, but I've heard that algebraic topologists run into congruences quite often. For example, the stable homotopy groups of spheres are almost always finite abelian groups, …
3
votes
GKO (or coset) construction - all possible highest weights $h$
The terminology is explained earlier on that page and the previous page in the paper.
On the same page, we see that they set $\mathfrak{g} = \mathfrak{su}(2) \times \mathfrak{su}(2)$, and let the suba …
4
votes
Accepted
Examples of simple vertex operator algebras (VOAs)
I expect there will never be a classification of simple VOAs, unless perhaps one is only sorting according to very rough criteria. This is because there are too many of them - even the rational case …
7
votes
Accepted
The use of Schur's lemma for Lie algebras in physics (CFT)
Let $\mathfrak{g}$ be a complex Lie algebra with a distinguished nonzero central element $x$, and let $V$ be an irreducible representation of $\mathfrak{g}$. The usual proof of Schur's lemma can be a …
9
votes
Physicists misuse the term "Kac Moody algebra". Does that bring problems?
I can't address all uses by all physicists, but in many contexts, they consider only representations at a fixed level that admit a well-behaved energy grading. That is, sometimes an energy grading is …
6
votes
Accepted
One particle irreducible Feynman diagrams
Section 5 of Borcherds, Barnard, Lectures on Quantum Field Theory is a discussion of the 0-dimensional spacetime case, which gives finite dimensional integrals.
3
votes
Accepted
Globalizing Feigin--Frenkel duality
The Feigin-Frenkel isomorphism is globalized by the global quantum geometric Langlands conjecture, proposed by Stoyanovsky, and refined by Gaitsgory and his collaborators. See Gaitsgory's 2016 collec …
4
votes
Accepted
Relationship between irreducible representations of the Schur covering group and elements of...
The answer to your question is Yes. Consider your covering group $C$ as a central extension:
$$1 \to N \to C \to G \to 1$$
and suppose it is given by a 2-cocycle $\alpha \in H^2(G, N)$. Then for any …
3
votes
Accepted
Some examples of vertex algebra modules
I don't know what paper you are reading, but you can find examples in most textbooks. For example, Frenkel and Ben-Zvi's book "Vertex algebras and algebraic curves" has a treatment of modules in chap …
5
votes
Phase transitions between Category Theories
In general, we expect field theories to be described by some higher categorical structures, where bulk models are assigned objects (also called 0-morphisms), domain walls are assigned morphisms (also …
8
votes
Accepted
What are braided vertex algebras?
For the case of vector spaces graded by an abelian group (with braiding determined by an abelian 3-cocycle following Joyal-Street), this was done by Dong and Lepowsky in their 1993 book "Generalized V …
9
votes
Where does a math person go to learn quantum mechanics?
I disagree (though not particularly strongly) with the comments claiming that you should learn classical mechanics first. You don't need much physics background to learn to do basic calculations with …
5
votes
Accepted
When two vertex (operator) algebras can be patched-up to a full CFT on a genus 0 surface?
If your VOA $V$ is not rational, then it is quite unlikely that its category of representations is a modular tensor category. That is, you can safely conclude that Theorem 3 contains an unstated assu …