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for questions about sequences and series, e.g. convergence, closed form expressions, etc. Note that there is a different tag for spectral sequences, and also note that MathOverflow is not for homework. Please consider consulting the online encyclopedia for integer sequences, if you are trying to identify a given sequence that you have found in your research.

5 votes

5 different ways to define the same family of integer sequences

Here is a proof that $a_1(n, p, q) = a_2(n,p,q)$. The generating function for the Stirling numbers of the second kind is $$\sum_{n=i}^\infty {n\brace i}\frac{x^n}{n!}= \frac{(e^x-1)^i}{i!}.$$ Also $$\ …
Ira Gessel's user avatar
6 votes
Accepted

Closed form for the A110501 (unsigned Genocchi numbers (of first kind) of even index)

This is a known result. To quote from Richard Stanley's Enumerative Combinatorics, Volume 2, second edition, solution to problem 8(e) of Chapter 5, page 115: This is equivalent to a conjecture of J. M …
Ira Gessel's user avatar
7 votes
Accepted

$R$-recursion for the A143017

We proceed by "guessing" a generating function for $R(n,q)$ and verifying that it has the right properties. According to https://oeis.org/A143017, the generating function $G= \sum_{n=1}^\infty a(n) x^ …
Ira Gessel's user avatar
4 votes
Accepted

$R$-recursion for the A307389

Let \begin{equation*} A(x,q) = e^{qx}A(x)=e^{(q+1)x+(e^x-1)^2/2} \end{equation*} and define $a(n,q)$ by \begin{equation*} A(x,q) = \sum_{n=0}^\infty a(n,q) \frac{x^n}{n!}. \end{equation*} Then $a(n,0) …
Ira Gessel's user avatar
4 votes
Accepted

General case of the some $R$-recursions

Let $$ A(x,q)=\sum_{i=0}^{\infty}\frac{x^i}{\prod\limits_{j=0}^{i}(1-f(q+j)x)}, $$ so that $A(x) = A(x,0)$. Define $a(n,q)$ by $$A(x,q) = \sum_{n=0}^\infty a(n,q) x^n,$$ so that $a(n) = a(n,0)$. I wil …
Ira Gessel's user avatar
7 votes

Recreation with Catalan

Here's a sketch of a generating function proof. Recall that \begin{equation*} \sum_{m=0}^\infty \binom{2m+k}{m} x^m =\frac{c(x)^k}{\sqrt{1-4x}}, \end{equation*} where $c(x) = \sum_{n=0}^\infty C_n x^n …
Ira Gessel's user avatar
1 vote

Evaluating a sinusoidal series

Here's a formula for $A_{nk}$: $$A_{nk} = (-1)^{n-k}2^{k-2n} \frac{(2n-k)!}{k!\,(n-k)!}.$$ This can be proved by standard methods for proving binomial coefficient identities.
Ira Gessel's user avatar
8 votes
Accepted

Infinite sum of Laguerre polynomials: is $\sum_{k=0}^{\infty}\frac{n!}{(k+n)!}x^kL_n^k(x)^2=...

Everything becomes simpler if add some parameters and start the sum at $k=-n$ instead of $k=0$. Note that if $k$ is a negative integer with $-n\le k \le -1$ then $L_n^k(x)$ is a polynomial in $x$ divi …
Ira Gessel's user avatar
4 votes

Integrality of a sequence formed by sums

Here is another proof, inspired by Tewodros Amdeberhan's. We represent the sum as a constant term in a power series. To represent $(7k+8) \frac{(3k+1)!}{k!\,(2k+3)!}$ as a constant term, we need to ex …
Ira Gessel's user avatar
32 votes
Accepted

Integrality of a sequence formed by sums

Let $A(x) = \sum_{n=1}^\infty a_n x^n$ and let $$S(x) = \sum_{k=0}^\infty (7k+8)\frac{(3k+1)!}{k!\,(2k+3)!} x^k.$$ Then the formula for $a_n$ gives $A(x) = R(x)S(x)$, where $$R(x) = \frac{1}{3}\biggl( …
Ira Gessel's user avatar
2 votes

Upper bound for an infinite series of Pochhammer Symbol

The sum is $r/(1-\alpha)^{(1+r/\alpha)}$ by the binomial theorem.
Ira Gessel's user avatar
9 votes

Method to evaluate an infinite sum of ratio of Gamma functions (how does Mathematica do it?)

This is a special case of Watson's Theorem $$\def\h{\frac{1}{2}} \def\g#1{\Gamma(#1)\,} {}_3F_2\left({a,\ b,\ c\atop\h a+\h b+\h, 2c }\biggm| 1 \right) =\frac{\g\h\g{c+\h}\g{\h a+\h b +\h}\g{c+\h -\ …
Ira Gessel's user avatar
5 votes

Non-arithmetic proof of the integrality of a rational expression

The integrality of the coefficients of $(1-k^2x)^{-1/k}$ follows from the integrality of the coefficients of the generalized Catalan number generating function $$c_k(x)=\frac{1-(1-k^2 x)^{1/k}}{kx},$$ …
Ira Gessel's user avatar
2 votes

Bilinear recurrence relation between even Bernoulli numbers

Here's a simple proof of the identity. Let $$B(x) = \frac{x}{e^x-1} = \sum_{n} B_n \frac{x^n}{n!}.$$ Then $$\sum_n (2^n-1) B_n \frac{x^n}{n!} = B(2x) - B(x) = -\frac{x}{e^x+1}$$ and $$\bigl(B(2x) -B …
Ira Gessel's user avatar
50 votes
Accepted

New binomial coefficient identity?

In terms of hypergeometric series, the sum is $_3F_2(-n, 1+n, 1/2;1,3/2;1)$ and the identity is a special case of Saalschütz's theorem (also called the Pfaff-Saalschütz theorem), one of the standard h …
Ira Gessel's user avatar

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