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Questions tagged [set-theory]

forcing, large cardinals, descriptive set theory, infinite combinatorics, cardinal characteristics, forcing axioms, ultrapowers, measures, reflection, pcf theory, models of set theory, axioms of set theory, independence, axiom of choice, continuum hypothesis, determinacy, Borel equivalence relations, Boolean-valued models, embeddings, orders, relations, transfinite recursion, set theory as a foundation of mathematics, the philosophy of set theory.

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Do these ordinals exist?

Given an ordinal $\alpha$, I define $F_{n}(\alpha)$ as follows: $F_0(\alpha)=\alpha$ $F_{n+1}(\alpha)$ is the smallest $\beta$ such that no first-order $\phi$ in the language of $\{\in\}$ has $(\...
Zetapology's user avatar
6 votes
1 answer
423 views

Which model is the minimal pointwise definable model of $\sf ZFC$?

Is the minimal transitive model of $\sf ZFC$ pointwise definable? If not, then what is the minimal pointwise definable model of $\sf ZFC$? Can we define that using Hamkins result for existence of ...
Zuhair Al-Johar's user avatar
6 votes
1 answer
934 views

The universal algebra of a $\sigma$-algebra

I am searching for the 'dual' algebraic structure of a $\sigma$-algebra. The notion of duality is like in the case of the Boolean algebra and set algebra. If $X$ is a set, the complement and ...
zeh's user avatar
  • 191
6 votes
1 answer
333 views

Can we have this sequence where choice fails and returns?

Can we have a sequence of transitive sets $\langle\mathcal V_0, \mathcal V_1, \mathcal V_2,...\rangle$, all modeling $\sf ZF$, such that $\mathcal P(V_n) \subset \mathcal V_{n+1}$, and the cardinality ...
Zuhair Al-Johar's user avatar
6 votes
2 answers
512 views

Is strengthening Foundation in NBG sufficient to make it prove Con(ZFC)?

Can $\sf NBG$ class theory prove the foundation scheme: Foundation schema: if $\Phi(X)$ is a formula in which "$X$" occurs free and only free, and in which "$Y$" doesn't occur, ...
Zuhair Al-Johar's user avatar
6 votes
0 answers
274 views

Forcing Martin's Axiom without cardinal arithmetic

We know that if $\kappa>2^{\aleph_0}$ and $\kappa^{<\kappa}=\kappa$, then there is a c.c.c. forcing which forces $\sf MA+2^{\aleph_0}=\kappa$. Traditionally, we even start with $\sf GCH$, which ...
Asaf Karagila's user avatar
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6 votes
1 answer
505 views

Upward Löwenheim–Skolem theorem for well-ordered models with/without measurable cardinals

Consider a complete first order theory $T$ whose language contains a binary predicate $\leq$. Assume that $T$ has an uncountable model that is well-ordered by $\leq$ so that this question isn't stupid ...
James E Hanson's user avatar
6 votes
1 answer
229 views

Smallest ordinal $\mu$ not embeddable in ${\cal P}(\omega)$

The motivation for this question is the startling fact that there is an order-preserving injective map (embedding) from $\mathbb{R}$ into ${\cal P}(\omega)$. (Think Dedekind cuts.) I am wondering how &...
Dominic van der Zypen's user avatar
6 votes
2 answers
456 views

When are all greater cardinals sharply greater?

Makkai and Paré introduced the following binary relation on regular cardinals: given $\kappa$ and $\lambda$, $\kappa \vartriangleleft \lambda$ (read, $\kappa$ is sharply less than $\lambda$) when $\...
Zhen Lin's user avatar
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6 votes
1 answer
191 views

Steinhaus number of a group

$\newcommand\Sn{\mathit{Sn}}$A subset $A$ of a group $X$ is called algebraic if $A=\{x\in X: a_0xa_1x\dotsm xa_n=1\}$ for some elements $a_0,a_1,\dotsc,a_n\in X$. Let $\mathcal A_X$ be the family of ...
Taras Banakh's user avatar
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6 votes
1 answer
217 views

Is the statement that every convex complete metric space has midpoints equivalent to the axiom of dependent choice (DC)?

We say that a point $m$ is between points $p$ and $q$ of a metric space $(M, d)$ if $d(p, q) = d(p, m) + d(m, q)$ and $p ≠ m ≠ q$. Furthermore, if the equality $d(p, m) = d(m, q)$ holds for $m$, we ...
Juan Atacama's user avatar
6 votes
1 answer
1k views

Some questions about Ackermann set theory

In a comment on this site Andreas Blass stated: "To fit this situation into my philosophical point of view, I'd say that what Ackermann's theory calls proper classes are really certain sets. That ...
Victor Makarov's user avatar
6 votes
1 answer
309 views

Failure of Cantor-Bernstein for the Levy Collapse

Related to this question, is it possible to give an example of the failure of Cantor-Bernstein for complete embeddings of forcing notions involving the Levy Collapse $Col(\omega,<\kappa)$? Suppose ...
Monroe Eskew's user avatar
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6 votes
1 answer
571 views

Parameter-free effective cardinals

In the paper "Effective cardinals and determinacy in third order arithmetic" by Juan Aguilera, effective cardinals is defined. I'm curious about its little variation, parameter-free ...
Reflecting_Ordinal's user avatar
6 votes
2 answers
629 views

Independence over ZFC + CH

Acknowledging Woodin's result on $\Sigma^2_1$-absoluteness for forcing-models satisfying the continuum hypothesis (CH), it is natural to ask: Are there examples of statements $\phi$ in "the usual ...
Tool's user avatar
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6 votes
1 answer
482 views

Permutation on $\omega$ and Ramsey ultrafilter

let $\pi:\omega\to\omega$ be permutation and $\mathcal{F}$ is Ramsey selective ultrafilter on $\omega$. There are uncountable many increasing subsequences of $\pi$. Can one proof that one of them has ...
ar.grig's user avatar
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5 votes
1 answer
432 views

Is there a class choice principle over MK that is equivalent to class well ordering over MK?

$\sf MKCWO$ is the theory obtained by adding a new primitive binary relation $\prec$ to the signature of $\sf MK$ and axiomatize that $\prec$ is a well order on classes, that is: $\textbf{Transitive:}...
Zuhair Al-Johar's user avatar
5 votes
1 answer
610 views

Injection of the proper class of ordinals in every proper class

Is it possible to prove in the set theory NBG (with local choice but without global choice) that the proper class of ordinals injects in every proper class ?
Gérard Lang's user avatar
  • 2,655
5 votes
1 answer
286 views

Is there an oracle that can compute something iff it is computable in every countable model that is equivalent to $(V, \in)$?

Let us work in Kelly-morse set theory, so we can talk about $V$. For some model $M=(\mathbb N, \in_M)$ that is elementary equivalent $(V, \in)$, we can have an oracle that corresponds to $(\mathbb N, \...
Christopher King's user avatar
5 votes
1 answer
316 views

Is this set theory used by Gandy first-order with signature $(\in, \lambda)$?

In On the Axiom of Extensionality, Part II, The Journal of Symbolic Logic, Vol. 24, No. 4 (Dec., 1959), https://doi.org/10.2307/2963897, pp. 287-300, R. O. Gandy shows that a class theory X ...
Frode Alfson Bjørdal's user avatar
5 votes
1 answer
213 views

Relation between ultrafilters ${\scr U}$ and ${\scr U} \otimes {\scr U}$ [closed]

If ${\scr U}$ and ${\scr V}$ are ultrafilters on non-empty sets $A$ and $B$ respectively, then the tensor product ${\scr U}\otimes{\scr V}$ is the following ultrafilter on $A\times B$: $$\big\{X\...
Dominic van der Zypen's user avatar
5 votes
1 answer
470 views

Large cardinals and mild extensions

It is known that for many large cardinals $\kappa$ (like weakly compact, measurable,...) , $\kappa$ remains large of the same type after forcings of size $<\kappa$. Now the questions are: Question ...
user avatar
5 votes
2 answers
528 views

Cardinality of a set of countable connected Hausdorff spaces

It is a non-trivial result that there is a countable connected Hausdorff space. Let ${\cal T}$ be a set of connected Hausdorff topologies on $\omega$ such that whenever $\tau_1\neq\tau_2\in {\cal T}$ ...
Dominic van der Zypen's user avatar
5 votes
2 answers
655 views

$C^n$ And Forcing: Reading a Recent Paper By Kunen

While reading a recent paper by Kunen arxiv.org/abs/0912.3733, which deals with PFA and the existence of certain differentiable functions, (defined on all of $\mathbb{R}$) which map certain $\aleph_1$-...
Not Mike's user avatar
  • 1,615
5 votes
4 answers
2k views

Subsystems of Peano arithmetic and incompleteness theorem

I think everyone is familiar with Goedel's incompleteness theorems. In particular they imply that PA (Peano arithmetic) can not prove its own consistency. Now my question is what is the largest ...
Najdorf's user avatar
  • 741
5 votes
2 answers
401 views

Natural examples of $\bf\Sigma^0_3$ equivalence relations

I have been reading about Borel equivalence relations and I have noticed that while $\bf\Sigma^0_3$ equivalence relations are mentioned, there is a conspicuous absence of natural examples (other than $...
Francis Adams's user avatar
5 votes
1 answer
649 views

Showing a filter with a certain property on the power set of $\mathbb{Z}$ is a one point filter

Let $\mathcal{P}_0(X)$ the Power set of $X$ without the empty set and let $\dot{x}:=\{A\subseteq X: x \in A\}$ the one point filter generated by $x$. Furthermore let $$ \mathcal{A} := \{ f \in X^{\...
Dominic Michaelis's user avatar
5 votes
2 answers
1k views

Large cardinals without the ambient set theory?

In an attempt to understand a bit better large cardinals, I have been thinking along the following lines, which could be summarized under the slogan Talk about cardinals without the (ambient) ...
Mirco A. Mannucci's user avatar
5 votes
1 answer
770 views

If $0^{\sharp}$ exists, then every uncountable cardinal in $V$ is as large as it can be in $L$.

According to Wikipedia, if $0^{\sharp}$ exists, then every uncountable cardinal in $V$ satisfies every large cardinal property in $L$ that can be realized in $L$, e.g. weak compactness, total ...
Amit Kumar Gupta's user avatar
5 votes
1 answer
422 views

What is the relationship between non-existence of those kinds of singular sets and AC?

Let's say a set $A$ is super-singular, if and only if, there exists a set $x$ such that $|A|=|\bigcup x|$ and $| A| > |x|$, and for each $y \in x$ we have: $ |y| \not > |x|$ . A set $A$ is ...
Zuhair Al-Johar's user avatar
5 votes
1 answer
1k views

How many well-orders of reals are there?

It's commonly known that the cardinality of the set of all well-orders on $\aleph_0$ is the continuum (correct me if I'm wrong plz). What about that of all well-orders on $\mathbb{R}$? Is there a ...
Edouard Ji's user avatar
5 votes
1 answer
149 views

Does there exist a section of $\mathcal{P}(\kappa)\to\mathcal{P}(\kappa)/(\text{fin})$ that is "nearly Boolean"?

The following might be a somewhat esoteric question: Does there exist an infinite cardinal $\kappa$ and a section $f$ of the quotient map $\pi:\mathcal{P}(\kappa)\to\mathcal{P}(\kappa)/(\text{fin})$ (...
David Gao's user avatar
  • 2,830
5 votes
0 answers
162 views

Strong chains of uncountable functions and cardinal characteristics

A family of functions $\langle f_\alpha:\alpha<\kappa\rangle$ from $\omega_1$ to $\omega_1$ is called a strong chain if $\alpha<\beta<\kappa\Longrightarrow \{\xi<\omega_1: f_\beta(\xi)\leq ...
Todd Eisworth's user avatar
5 votes
1 answer
524 views

A topologically transitive dynamical system without dense orbits

By a dynamical system I understand a pair $(K,G)$ consisting a compact Hausdorff space and a subgroup $G$ of the homeomorphism group of $K$. We say that a dynamical system $(K,G)$ $\bullet$ is ...
Taras Banakh's user avatar
  • 41.9k
5 votes
2 answers
2k views

Are all models of ZF + DC + "All set of reals are lebesgue measurable" also models of CH? [duplicate]

Possible Duplicate: Lebesgue Measurability and Weak CH I have studied a little set theory and I found that Solovay constructed a model of ZF+DC+"All set of reals are Lebesgue measurable" and I ...
Iván Ongay Valverde's user avatar
5 votes
1 answer
356 views

Calculate the $\downarrow$, $\downarrow\uparrow$ and $\uparrow\downarrow$ cofinalities of the poset of nontrivial finitary partitions of $\omega$

Let $(P,\le)$ be a poset. For a point $x\in P$ let $${\downarrow}x=\{p\in P:p\le x\}\quad\text{and}\quad{\uparrow}x=\{p\in P:x\le p\}$$be the lower and upper sets of the point $x$, and for a subset $...
Taras Banakh's user avatar
  • 41.9k
5 votes
0 answers
1k views

Mathias forcing with Ramsey ultrafilters, and Cohen reals [closed]

Edit/update: One reason this question never received an answer is because it was founded on a faulty premise! The Blaszczyk-Shelah paper I mentioned below does not prove that Mathias forcing with a ...
Justin Palumbo's user avatar
5 votes
1 answer
471 views

Comparability implies well-orderability?

I am trying to prove a small proposition that got me completely stumped, and I cannot find a single counterexample. (ZF) Suppose that $E$ is such that for every $A\subseteq\mathcal P(E)$ either $|...
Asaf Karagila's user avatar
  • 39.8k
5 votes
1 answer
1k views

Can the Knaster-Tarski theorem be proved using the Schroeder-Bernstein theorem?

The reverse can be done easily and the proof is well known I am wondering if the exact same argument can be used to prove reverse as well.
user10122's user avatar
5 votes
1 answer
362 views

Sequences of projecta in the constructible hierarchy

For $n$ a natural number, $\alpha$ an ordinal, let $\rho(n,\alpha)$ be the $n$-th projectum of $J_\alpha$, where $J$ is the Jensen hierarchy for $L$. Call a finite sequence $s:=(x_1,\dots,x_m)$ of ...
M Carl's user avatar
  • 521
5 votes
0 answers
449 views

How many Dedekind-finite sets can $\mathbb{R}$ be partitioned into?

Building off Asaf Karagila's answer to my previous question (Can $\mathbb{R}$ be partitioned into dedekind-finite sets?) on partitioning $\mathbb{R}$ into strictly Dedekind-finite sets: (1) What ...
Noah Schweber's user avatar
5 votes
1 answer
309 views

Universally Baire Tree Representation of Projective Sets

In Feng, Magidor, and Woodin "Universally Baire Sets of Reals", they show that if $A$ is a $\mathbf{\Pi}_2^1$ set and $U$ and $V$ are any pair of trees witnessing the universal baireness of $A$, then ...
William's user avatar
  • 1,750
5 votes
1 answer
158 views

(Weakly) minimal subcovers of linear covers

Motivation. The starting point of this question is the trivial observation that if we cover $\mathbb{N}$ with $$\big\{\{0,\ldots n\}: n\in \mathbb{N}\big\},$$ then this cover doesn't have a minimal ...
Dominic van der Zypen's user avatar
5 votes
0 answers
276 views

Absoluteness and the scale property for $Π^2_2$ or $Σ^2_2$

Under the diamond principle $◊$ and large cardinal axioms, which of the two pointclasses $Π^2_2$ or $Σ^2_2$ is expected to have the scale property? Because conditional $Σ^2_2$ absoluteness under $◊$ ...
Dmytro Taranovsky's user avatar
5 votes
3 answers
1k views

Are there first-order statements that second order PA proves that first order PA does not?

Are there first-order statements that second order PA proves that first order PA does not? Is this known one way or the other? Could you share an example? (edit: to clarify, by 'second order PA' I don'...
pathway's user avatar
  • 117
5 votes
1 answer
367 views

"Intersection number" of a cardinal

Let $\kappa$ be an infinite cardinal. We call a cardinal $\lambda \leq 2^\kappa$ intersecting if there is ${\cal C}\subseteq {\cal P}(\kappa)$ such that for every $A\in {\cal C}$ we have $|A|=\kappa$,...
Dominic van der Zypen's user avatar
5 votes
2 answers
361 views

Stationary sets and $\kappa$-complete normal ultrafilters

Let $\kappa$ be a measurable cardinal, and let $u$ be a normal $\kappa$-complete ultrafilter over $\kappa$. It is a standard easy fact that every closed unbounded set must belong to $u$ (notice that ...
David Fernandez-Breton's user avatar
5 votes
3 answers
521 views

A question about Mitchell/Steel Fine Structure and Iteration Trees

In chapter 8 of Mitchell's and Steel's FSIT, they prove a central fine structural result, which basically states that if $\mathcal{M}$ is 1-small, $k$-sound, $k$-iterable premouse then the $k+1$-...
Rachid Atmai's user avatar
  • 3,804
5 votes
1 answer
627 views

Can there be no "surprisingly averageable" second-order sentences?

Say that a second-order sentence $\varphi$ is averageable iff there exists some infinite cardinal $\kappa$ and some nonprincipal ultrafilter $\mathcal{U}$ on $\kappa$ such that for every $\kappa$-...
Noah Schweber's user avatar
5 votes
3 answers
884 views

"name" for the ground model

I am a beginner of forcing, often I read from some articles something like "$p \Vdash \dot{G}$ is $P$-generic over $\check{M}$" (where $M$ is a countable transitive model, for instance). Q1. I ...
sonicyouth's user avatar

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