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4 votes
0 answers
212 views

When does the canonical $t$-structure restrict to perfect complexes?

I am interested in non-Noetherian(!) rings such that the canonical $t$-structure on $D(R)$ (the derived category of left $R$-modules) restricts to perfect complexes i.e. to the subcategory of ...
Mikhail Bondarko's user avatar
2 votes
1 answer
640 views

Simple modules for direct sum of simple Lie algebras

I think that the following statement is true, but I do not know how to prove it. Let $\mathfrak{g}_1$ and $\mathfrak{g}_2$ be two real simple Lie algebras. If $M$ is a (infinite dimensional) complex ...
Hebe's user avatar
  • 951
2 votes
1 answer
143 views

A weak Schur's lemma for non-semisimple finite dimensional algebras

Let $B \subseteq C$ be an inclusion of finite dimensional (associative) algebras over a field $k$. Assume that $C$ is a free $B$-module. Let $\bigoplus_i U_i$ be a decomposition of $B$ into ...
Sebastien Palcoux's user avatar
1 vote
0 answers
66 views

To find $\dim(D^{\mu})=\dim\frac{S^{\mu}}{S^{\mu}\cap S^{\mu\perp}}$

Let $S_6$ be the symmetric group of degree $6$ and $F$ be any finite field of characteristic $2.$ Then $2$-regular partition of $6$ are $(5,1)$, $(4,2)$ and $(3,2,1)$ . I have to find $$\dim(D^{\mu})=\...
neelkanth's user avatar
  • 141
1 vote
1 answer
153 views

About locally finite condition in category $\mathcal{O}^\mathfrak{p}$

Denote by $\mathfrak{g}$ a complex semisimple Lie algebra and let $\mathfrak{h}$ be a Cartan subalgebra of $\mathfrak{g}$. Denote by $\Phi$ the root system of $(\mathfrak{g},\mathfrak{h})$ and ...
James Cheung's user avatar
  • 1,875
13 votes
1 answer
748 views

Tilting Objects in BGG Categories $\mathcal{O}$

Let $\mathcal{O}$ be the BGG category $\mathcal{O}$ with respect to a finite dimensional semisimple Lie algebra $\mathfrak{g}$ and its Borel subalgebra $\mathfrak{b}$ (as define in this book by ...
Zvi's user avatar
  • 295
1 vote
0 answers
77 views

n-Gorenstein algebras and tilting modules

Let $\Lambda$ be an artin algebra over a commutative artinian ring $R$. $\Lambda$ is said to be $n$-Gorenstein, for some natural number $n$, provided it have finite self-injective dimension at most $n$...
Xiaosong Peng's user avatar
3 votes
1 answer
252 views

Higher Extension Group Question

Suppose we have an associative unital ring $R$, and we have an $R$-module $M$ with a length 3 socle filtration, i.e. write $$soc(M) \text{ for the socle of } M,$$ $$soc^2(M) \text{ for the preimage ...
freeRmodule's user avatar
  • 1,077
5 votes
3 answers
903 views

Irreducible representations and invariant subspaces

Consider two invertible n-by-n matrices, $n>2$, $X$ and $Y$ over a finite field $k$ (say for simplicity $k=\mathbb Z/ \mathbb Z_2$). Is there any reasonable way to check that there is no proper ...
Serge Nikoforov's user avatar
1 vote
0 answers
77 views

Existence of a certain direct summand

Let $P$ be a cyclic group of order $p^n$. Let $M$ be a $\mathbb{Z}_p[P]$-module and $M_p :=\mathbb{Q}_p\otimes M$ be the associated $\mathbb{Q}_p[P]$-module. When will $M_p$ have a direct summand ...
debanjana's user avatar
  • 1,283
5 votes
1 answer
192 views

Given a representation-infinite algebra, when is every AR component infinite?

Let $A$ be a finite dimensional algebra over an algebraically closed field $K$. The Auslander-Reiten quiver $\Gamma_A$ of $A$ is a means of presenting the category of finitely generated right $A$-...
Iteraf's user avatar
  • 482
7 votes
1 answer
349 views

Is there a converse to the Brauer–Nesbitt theorem?

$\DeclareMathOperator\Tr{Tr}$Say that we have an algebra $R$ over $\mathbb{C}$. If, for two finitely generated (edit: and semisimple) $R$-modules $M, N$ we know that $\Tr_M(r)=\Tr_N(r)$ for all $r\in ...
Ioannis Zolas's user avatar
6 votes
3 answers
446 views

Is the category of symmetric bimodules over a commutative ring closed under extensions?

Let $A$ be a commutative ring, and consider the category of bimodules over $A$. An $A$-bimodule $M$ is called symmetric if $a\cdot m = m \cdot a$ for all $a \in A$, $m \in M$. Is the category of ...
Symmetric's user avatar
10 votes
2 answers
503 views

A diagram for understanding action/coaction compatibility in a Yetter-Drinfeld module

For a Hopf algebra $H$ with antipode $S$, let $M$ be a left $H$-module with the action $h \otimes m \mapsto \rho(h,m)$, and also a left $H$-comodule with coaction $\delta \colon m \mapsto m^{(-1)} \...
Mike Pierce's user avatar
  • 1,161
5 votes
0 answers
856 views

Dual of representation is irreducible implies the representation is irreducible?

Suppose $V$ is an infinite dimensional $\mathbb{Q}_p$-representation of Lie algebra $\mathfrak{g}$ over $\mathbb{Q}_p$. If its dual representation $V^{\prime}$ is irreducible then, is it always true ...
MathStudent's user avatar
4 votes
1 answer
419 views

Weights of BGG dual of Verma module

Consider the Verma module $M(\lambda)=\oplus_{\mu \in \mathfrak{h}^{\star}} M(\lambda)_{\mu}$. Denote its BGG dual by $M(\lambda)^{\vee}=\oplus_{\mu \in \mathfrak{h}^{\star}} M(\lambda)^{\star}_{\mu}$ ...
MathStudent's user avatar
5 votes
1 answer
243 views

G-modules and ideals of secant varieties

Consider the action of $G = SL(n+1)$ on $\mathbb{P}^N$, and embed $\mathbb{P}^n$ in $\mathbb{P}^N$ via the degree two Veronese embedding. Let $V\subset\mathbb{P}^N$ be the corresponding Veronese ...
user avatar
1 vote
1 answer
149 views

Finding modules to check for finite global dimension

Given a finite dimensional algebra $A$ and a generator-cogenerator $M$ and let $B:=End_A(M)$. $B$ has finite global dimension iff every $A$-module has finite $add(M)$-resolution dimension, which is ...
Mare's user avatar
  • 26.5k
1 vote
2 answers
337 views

Finding all submodules

Given a finite dimensional local commutative algebra over a finite field $K$ and a finite dimensional module $M$. What is the fastest/best way to obtain all submodule from $M$ using a Computer algebra ...
Mare's user avatar
  • 26.5k
3 votes
1 answer
247 views

Kazhdan-Lusztig Theorem for a special class of integral weights

This question may be seen as a follow up of this one. Let $\mathfrak{g}$ be a rank $r$ simple complex Lie algebra, and let $\mathfrak{h}$ be a Cartan subalgebra of $\mathfrak{g}$. We call $\alpha_i$ ...
Antoine's user avatar
  • 457
8 votes
1 answer
704 views

Kazhdan-Lusztig theorem for composition factors of Verma modules

The Kazhdan-Lusztig Conjecture (which is actually a theorem) gives the character of some irreducible modules of a (say) simple complex Lie algebra $\mathfrak{g}$ in terms of characters of Verma ...
Antoine's user avatar
  • 457
6 votes
1 answer
302 views

Endomorphism ring of bimodules

Given an algebra $A$ with a right $A$-module $M$ with $End_A(M) \cong A$. Then we can view $M$ as a natural $A$-bimodule. When is $M$ as a bimodule indecomposable and what is its endomorphism ring as ...
Mare's user avatar
  • 26.5k
3 votes
1 answer
286 views

Why we study Endo-Trivial Modules?

I made the exact same question on MSE some days ago and there wasn't any response whatsoever so far, so thought probably I have to ask here to get an answer. So the question goes as follows: Recently ...
mayer_vietoris's user avatar
4 votes
2 answers
288 views

The explicit indecomposable representations of (any) Euclidean quiver of type E

It is known that for any quiver $Q$ that is an orientation of $\tilde{\mathbb{E}}_8$, the hereditary path algebra $KQ$ ($K$ being an algebraically closed field) is tame (but not finite). That is, in ...
Iteraf's user avatar
  • 482
1 vote
0 answers
360 views

Property of the syzygy functor of $\operatorname{\underline{mod}} A$

Let $A$ be an artin algebra. We denote by $\operatorname{mod}A$ the category of finitely generated left $A$-modules. We denote by $[A]$ the ideal of morphisms between $A$-modules which factor through ...
Xiaosong Peng's user avatar
3 votes
1 answer
361 views

Whether hom functor and socle (radical) are commutative?

Let $A$ be an algebra. We know that $Soc M =\oplus _A Soc M_{\alpha}$ and $Rad M =\oplus _A Rad M_{\alpha}$ if $M= \oplus _A M_{\alpha}$ as $A$-modules. Now let $M,N$ be $A$-modules, $\Lambda:=End_A(...
Xiaosong Peng's user avatar
2 votes
1 answer
119 views

How to get that $\Omega^2_{\Lambda}(N) \cong \textrm{Hom}_A(M,Y)$?

Let $A$ be an algebra over a field k. A module $_AM$ is called a generator if $\textrm{add}(A) \subseteq \textrm{add}(M)$, a cogenerator if $\textrm{add}\big(D(A)\big) \subseteq \textrm{add}(M)$. $M$ ...
Xiaosong Peng's user avatar
4 votes
1 answer
382 views

Non-existence of projective covers

I didn't get the argument of Example 7.3.11, page 123, from the representation theory book of Peter Webb, available also online at: http://www-users.math.umn.edu/~webb/RepBook/RepBookLatex.pdf In ...
user103474's user avatar
4 votes
1 answer
241 views

Questions in the paper "The category of good modules over a quasi-hereditary algebra has almost split sequences"

I am reading the paper "The category of good modules over a quasi-hereditary algebra has almost split sequences", the link is here:https://pub.uni-bielefeld.de/publication/1780235. In the paper, $A$ ...
Xiaosong Peng's user avatar
3 votes
1 answer
777 views

Long exact sequence of free modules and rank inequality

Given a long exact sequence of free (left) modules $M_i$ of finite rank $k_i$ over possibly non-commutative ring $R$: $\dots \to M_{i-1}\to M_i \to M_{i+1}\to \dots$ What is the condition on $R$ ...
RAG's user avatar
  • 31
8 votes
1 answer
351 views

Irreducible $S_n$-modules and $S_n$-actions on projective spaces

Let $V$ be an $(N+1)$-dimensional vector space with an action of the symmetric group $S_n$, such that $V$ is an irreducible $S_n$ -module. Let $\{p_1,...,p_h\}\in \mathbb{P}(V)$ be $h\geq N+2$ ...
user avatar
0 votes
1 answer
235 views

Questions about Lowey length

Let $\Lambda$ be an artin algebra. If $M$ is a finitely generated $\Lambda$-module with Loewy length 2 and finite projective dimension. How to get the exact sequence $$0 \rightarrow A \rightarrow P/...
Xiaosong Peng's user avatar
6 votes
1 answer
361 views

How to check whether a module is an n-th syzygy

Given a finite dimensional algebra $A$, define $\Omega^{n}(mod-A)$ (modules here are always finite dimensional) to be the full subcategory of projective modules or modules $M$ such that $M \cong \...
Mare's user avatar
  • 26.5k
1 vote
0 answers
33 views

How to get that $add(E)=add(\nu(E))$ equivalent to $add(soc(E))\cong add(top(E))$?

Let $A$ be a finite dimensional algebra over a field K. $E$ is an injective $A$ module. $\nu=DHom_A(-,A)$ is the Nakayama functor. $add(E)$ is the full subcategory of $A$-module consisting of all ...
Xiaosong Peng's user avatar
2 votes
0 answers
105 views

Why $T'$ dosen't have projective direct summand?

Let $A$ be a k-algebra, where k is a fixed field. Let $S$ be a simple, non-injective $A$-module such that $Ext^{i}_{A}(S,S)=0$ for $1 \leq i \leq n$. Let $P(S)$ be the projective cover of $S$, and let ...
Xiaosong Peng's user avatar
2 votes
1 answer
263 views

Nonnegatively graded algebra $A$ finitely generated as $k$-algebra iff $A_0$ finitely generated, $A_{>0}$ finitely generated as $A$-module?

This is related to my question here. My question is as follows. How do I see that a nonnegatively graded algebra $A$ is finitely generated as a $k$-algebra if and only if $A_0$ is finitely generated ...
Jakob W's user avatar
  • 349
3 votes
1 answer
173 views

$M$ is finitely generated as $A$-module iff $M/A_{>0}M$ is finitely generated as $A$ module?

Let $A$ be a nonnegatively graded algebra and $M$ a nonnegatively graded $A$-module. Then, $A_{>0}M$ is a graded $A$-submodule of $M$. (Here, given a nonnegatively graded algebra $A$, we've ...
Jakob W's user avatar
  • 349
0 votes
0 answers
68 views

Is there a simple module $S$ satisfies the following conditions?

Let $A$ be a k-algebra,where k is a fixed field. {$x_1,x_2, \cdots,x_n $} is a complete set of primitive orthogonal idempotents of $A$. $M$ is a left $A$-module such that $x_iM=0$ for $i=1,2,\cdots,n-...
Xiaosong Peng's user avatar
2 votes
1 answer
450 views

The definitions of a generator module?

Recently I have seen two definition of a generator module: 1) A generator for a category $C$ is an object $G$ such that for any two parallel morphisms $f,g:X \rightarrow Y$ with $f \neq g$, then ...
Xiaosong Peng's user avatar
5 votes
1 answer
394 views

Classification of indecomposable modules in tame hereditary algebras

An algebra $A$ is said to be tame if the isomorphism classes of indecomposable $A$-modules in each dimension occur in a finite number of 1-parameter families. $A$ is said to be of finite ...
Iteraf's user avatar
  • 482
1 vote
1 answer
126 views

Action is determined by a braiding

Let $H$ be a bialgebra over $\mathbb{C}$. Suppose that $V$ is a left $H$-comodule and $W$ is an $H$-module. Then we can defined map $\Psi$ by \begin{align} & \Psi: V \otimes W \to W \otimes V, \\ &...
Jianrong Li's user avatar
  • 6,201
1 vote
1 answer
271 views

Rank of a locally free $\mathbb Z[G]$-module

This is a basic question. Let $G$ be a finite group, $M$ a finitely generated $\mathbb Z[G]$-module so that the $\mathbb Z_p[G]$-module $M_p$ is free for all prime numbers $p$, i.e. is locally free. ...
eddie's user avatar
  • 255
3 votes
1 answer
151 views

Unclear asymmetry in Lie-algebra module structure on space of linear transformations Hom(V,W)

Let $L$ be a (finite dimensional) Lie-algebra. Let $V, W$ be finite-dimensional vector spaces. If $V,\; W$ are in addition $L$-modules (see, e.g., 6.1 in Humphreys Introduction to Lie Algebras), then ...
Shlomi A's user avatar
  • 583
7 votes
1 answer
455 views

Hopfian modules

My question is slightly motivated by basic results in linear algebra, for example, that if $F$ is a field then a surjective linear map $F^n \rightarrow F^n$ is injective. More generally, any ...
Mark Wildon's user avatar
  • 11.2k
2 votes
0 answers
202 views

Could Partial Tiltings be studied as Almost Complete Tiltings?

The first part of what follows is a brief recap of the definitions, setting and motivations for my questions. Experts can find the questions at the end. Here $k$ denotes an algebraically closed field,...
Kaveh's user avatar
  • 493
9 votes
1 answer
472 views

Why do we want $p$-permutation modules in splendid equivalences?

First Rickard (in Splendid Equivalences: Derived Categories and Permutation Modules ) and then Rouquier (Block theory via stable and Rickard equivalences, Appendix A.1) define splendid equivalences ...
AnalysisStudent0414's user avatar
1 vote
0 answers
120 views

Irreducible representations of quantum affine algebras

The finite dimensional simple modules of quantum affine algebras are parameterized by Drinfeld polynomials. Some other modules of quantum affine algebras are studied in the paper. Some infinite ...
Jianrong Li's user avatar
  • 6,201
8 votes
1 answer
387 views

Jordan-Hölder-like statements for modules with $\Delta$-filtrations over a quasihereditary algebra

Definitions Let $A$ be an Artin algebra (for instance, take $A$ to be a finite dimensional algebra over some field) and label the isomorphism classes of simple $A$-modules by the elements of a ...
3 A's's user avatar
  • 425
2 votes
1 answer
268 views

Constructing a simple $A$-module

Let $n \ge 2$, and let $A$ be the (unital and associative, but noncommutative) $\mathbb{C}$-algebra with generators $x_1, \dots, x_n$ and relations $x_ix_j + x_j x_i = 2\delta_{ij}$. What is a ...
Indranil Banik's user avatar
2 votes
1 answer
395 views

Projectivity of torsion-free modules over integral group rings

Let $G$ be a torsion-free group and assume that the integral group ring $\mathbb{Z}G$ is torsion-free as well. Let $M$ be a torsion-free, finitely generated module over $\mathbb{Z}G$. If we assume ...
AlexE's user avatar
  • 2,998