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10 votes
1 answer
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Clebsch–Gordan decomposition formula for algebraic groups

$\DeclareMathOperator\SL{SL}$There is a well-known Clebsch–Gordan decomposition formula for irreducible representations of $\SL_2$. If $V_n$ denotes the unique $n+1$-dimensional irreducible ...
dm82424's user avatar
  • 370
8 votes
1 answer
704 views

Kazhdan-Lusztig theorem for composition factors of Verma modules

The Kazhdan-Lusztig Conjecture (which is actually a theorem) gives the character of some irreducible modules of a (say) simple complex Lie algebra $\mathfrak{g}$ in terms of characters of Verma ...
Antoine's user avatar
  • 457
8 votes
1 answer
1k views

Maximal Submodule of a Verma Module

Let $\mathfrak{h}$ be a Cartan subalgebra of a $\mathbb{C}$-semi simple Lie algebra $\mathfrak{g}$. Given $\lambda \in \mathfrak{h}^*$, $M(\lambda)$ the Verma module of highest weight $\lambda$ and $N(...
Bib's user avatar
  • 83
7 votes
1 answer
456 views

Hopfian modules

My question is slightly motivated by basic results in linear algebra, for example, that if $F$ is a field then a surjective linear map $F^n \rightarrow F^n$ is injective. More generally, any ...
Mark Wildon's user avatar
  • 11.2k
6 votes
1 answer
361 views

How to check whether a module is an n-th syzygy

Given a finite dimensional algebra $A$, define $\Omega^{n}(mod-A)$ (modules here are always finite dimensional) to be the full subcategory of projective modules or modules $M$ such that $M \cong \...
Mare's user avatar
  • 26.5k
3 votes
1 answer
339 views

If the Hom-space of finite length modules is generated by single elements, must the elements be conjugate?

Let $A$ be an Artin $k$-algebra for a commutative artinian ring $k$ (e.g. $A$ is a finite dimensional algebra over a field $k$). Let $X,Y$ be finite length left $A$-modules. If $\text{Hom}_A(X,Y)$ is ...
kevkev1695's user avatar
3 votes
1 answer
240 views

Split monomorphisms of modules - does the finite case imply the infinite case?

Let $k$ be a field, $A$ a finite dimensional $k$-algebra, $X$ a finite dimensional indecomposable (left) $A$-module and $M$ an infinite dimensional (left) $A$-module. Further $X\subseteq M$ and for ...
kevkev1695's user avatar
3 votes
1 answer
173 views

$M$ is finitely generated as $A$-module iff $M/A_{>0}M$ is finitely generated as $A$ module?

Let $A$ be a nonnegatively graded algebra and $M$ a nonnegatively graded $A$-module. Then, $A_{>0}M$ is a graded $A$-submodule of $M$. (Here, given a nonnegatively graded algebra $A$, we've ...
Jakob W's user avatar
  • 349