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Bases of Ideals With no Monomials

Let $K$ be an algebraically closed field and $K[\underline{x}]$ its ring of polynomials in $n$ variables $x_1,\cdots, x_n$. Let $J\leq K[\underline{x}]$ be an ideal such that there are no monomials in ...
Santiago's user avatar
  • 345
1 vote
0 answers
236 views

Terminology question - "Chern number"

I have seen the term Chern number used to refer to the first Hilbert-Samuel coefficient, $e_{1}(I)$, of an ideal $I$ in a local ring $(R, m)$. (Where the Hilbert-Samuel polynomial agrees with $\...
LAM's user avatar
  • 113
1 vote
0 answers
451 views

Proof of local structure theory for unramified morphisms [closed]

In Raynaud's "Anneaux locaux henseliens," a proof is given of the following fact: Let $R \to S$ be a finite type morphism of rings, $\mathfrak{q} \in \mathrm{Spec} S$, $\mathfrak{p} $ the inverse ...
Akhil Mathew's user avatar
  • 25.6k
1 vote
0 answers
276 views

Generalizations of divided-power algebras over finite fields

In Andrews, Askey, and Roy's Special Functions, the authors state that Gauß sums are finite field analogs of the $\Gamma$-function as Jacobi sums are to B-function. The $\Gamma$-function is well-...
Adam Hughes's user avatar
  • 1,049
1 vote
0 answers
351 views

Regularity and limits of smooth rational curves.

Fix integers $2 < d \leq n$. Suppose that $T$ is a smooth complex curve with marked point $0 \in T$, and $X$ is a closed subscheme of $\mathbb{P}^n_T$, flat over $T$ such that each fiber has ...
mdeland's user avatar
  • 1,990
1 vote
0 answers
169 views

Sum of two free o-submodules in a vector space over a local field

Let $V$ be a countably infinite dimensional $K$-vector space over a local field $K$ (nontrivially discretely valued with finite residue field). Let $o$ be the ring of integers of $K$. Given two free ...
Tiffy's user avatar
  • 107
1 vote
0 answers
538 views

Functoriality of a standard integral domain construction.

The evident forgetful functor from fields to integral domains has a left adjoint, namely the construction of the quotient field for a given integral domain. Another standard construction is taking the ...
Stines's user avatar
  • 21
1 vote
0 answers
198 views

Seek for good methods of computing the Krull dimension of a module?

Hi, everyone. Recently I am interested in computing the Krull dimensions of modules without using any software. However, it is not an easy job for me to do so only by its definition. Therefore, I ...
TmobiusX's user avatar
  • 1,207
1 vote
0 answers
238 views

relative flatness and torsion freeness

Hi. Question 1: let $f:X\rightarrow S$ be a proper and surjective morphism of complex reduced spaces with $X$ pure dimensional. Let $F$ be a $S$-flat coherent sheaf on $X$. Is it true that the two ...
kaddar's user avatar
  • 435
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2k views

Generators of ideals in polynomial rings over commutative rings.

This is my first question; I hope it worthy of this awesome forum and its members. Let $R$ be a commutative ring, perhaps with unit, perhaps not. As usual let $R[x]$ denote the ring of polynomials ...
drbobmeister's user avatar
1 vote
0 answers
534 views

Integral element in the quotient of a polynomial ring

Hello, I'm writting a "report" (to learn) on algebraic geometry, and was looking to write a proof for the following statement : Theorem : Let $K$ be an algebraically closed field and $C_1, C_2 \...
warsomekey's user avatar
1 vote
0 answers
268 views

Rational map defined over K leads to algebra question

Hello, Concrete algebraic question : Let $K$ be a perfect field, $\bar{K}$ a fixed algebraic closure and let $f \in \bar{K}[x_1,\ldots,x_n]$. I was wondering when there exists another polynomial (non-...
warsamekei's user avatar
1 vote
0 answers
2k views

Formal power series ring & completion

I encountered the following passage in Matsumura's Commutative Ring Theory : A a Noetherian ring, $B=A[[x]]$ a formal power series ring. $M\subset B$ a maximal ideal, $\mathfrak{m}=M\cap A$. Then $(...
ashpool's user avatar
  • 2,857
1 vote
1 answer
274 views

Coefficients of the monomials appearing in a Schubert polynomial

It is known that the coefficients of the monomials appearing in a Schubert polynomial are always positive. My question is: Is it always true that at least one such coefficient must be $1$? If that is ...
user avatar
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3 answers
1k views

non-associative but commutative algebra [closed]

Is it possible(or may be easier) to give an example of non associative algebra but commutative? At first sight, it seems possible to prove associativity from commutativity but later realised it may no ...
Sunny's user avatar
  • 629
0 votes
3 answers
565 views

Homology of koszul complex is finitely generated?

$A$ a local ring and $a_{1}$, ..., $a_{n}$ elements in its maximal ideal, $M$ a finitely generated $A$-module. In this case apparently the homologies from the Koszul complex are finitely generated as $...
ashpool's user avatar
  • 2,857
0 votes
2 answers
232 views

Commutation of $GL_{n}$ with projective limits

Let $A$ denote a unital commutative ring. Given a system of ideals $(I_p)_{p\in P}$ indexed by a partially ordered set $P$ such that if $p \leq q$, then $I_p$ is contained in $I_q$, when is $$GL_n ...
Nic Palmero's user avatar
0 votes
1 answer
630 views

Useless question on rank

What is the rank of $A^{n}$ if A is the zero ring? It's clearly not $n$ as many careless authors claim, since it's not even invariant. I don't think it's 0 either because it does have a linearly ...
ashpool's user avatar
  • 2,857
0 votes
2 answers
754 views

On reducible polynomials with positive coefficients, $1$ as constant coefficient and certain bounds on coefficients

Given $a \in \mathbb{Z}$ with $a > 1$. Let $g(x) \in \mathbb{Z}[x]$ be a polynomial with $g(a)=\pm 1$. Let $h(x) \in \mathbb{Z}[x]$ be a polynomial with $h(a)= p$, a prime. Let $g(x)$ and $h(x)$ ...
0 votes
2 answers
316 views

Tensor powers of an algebra all isomorphic

Let $k$ be a commutative ring with total quotient ring $K$, and let $A$ be a commutative $k$-algebra such that the multiplication map $A \otimes_k A \longrightarrow A$ is an isomorphism. EDIT: Assume ...
Jesse Elliott's user avatar
0 votes
1 answer
327 views

Can we generalise groupoids to monoid-oids? [closed]

Groups correspond to one object categories where every morphism is an isomorphism. Monoids correspond to one object categories. Groupoids correspond to small categories where every morphism is an ...
Diego de la Paz's user avatar
0 votes
2 answers
388 views

$\mathbb{Z}_p[\zeta]$ is Local Ring

Let consider the ring $\mathbb{Z}_p$ and $\zeta$ be a $p$-th root of unity. Especially $\zeta \not \in \mathbb{Z}_p$. Denote with $\Phi _p(x)$ the cyclotomical polynomial in $p$. Since $p$ is a prime ...
user267839's user avatar
  • 6,038
0 votes
2 answers
768 views

Tor independence

Let $R$ be a ring. Take the polynomial ring over $R$ $$R[x_1,\dots, x_n]$$ nonzerodivisors $f,g\in R[x_1,\dots, x_n]$ such that $f$ is a polynomial in the first $k$ indeterminates, $g$ a polynomial ...
user avatar
0 votes
1 answer
187 views

Which finite cyclic groups can be characterized by Lattice isomorphism and isomorphism between their automorphism groups?

Given a finite cyclic group $G$, we denote by $L(G)$ the lattice of its subgroups, and by $\mathop{\rm Aut}(G)$ the automorphism group of $G$. Let $H$ be any group. Assume that $L(G)\cong L(H)$ and $...
R. Shhaied's user avatar
0 votes
3 answers
186 views

Behavior of duality under pull-back

I have a technical question on commutative algebra. I am not an expert in the subject, and I would like to know if there are "typical conditions" making the following possible. Let $\varphi:R\to S$ ...
Tommaso Centeleghe's user avatar
0 votes
1 answer
964 views

Determinants over commutative rings [closed]

Hello, I am preparing a paper on determinants in commutative rings. Someone can give me examples of applications of determinants in commutative rings to other areas of mathematics or physics. Thank ...
Miguel's user avatar
  • 545
0 votes
1 answer
2k views

Are Chow groups a birational invariant?

Let us work in the category of smooth, projective varieties (say, over an algebraically closed field $k$). If $X$ and $X'$ are birational, then do they have the same Chow groups? Is there at least a ...
Adam's user avatar
  • 179
0 votes
2 answers
511 views

When are seminormal rings Cohen-Macaulay?

I know that not every local seminormal ring is Cohen-Macaulay. But are 1-dimensional local seminormal rings Cohen-Macaulay?
Adam's user avatar
  • 179
0 votes
1 answer
556 views

Is the multiplication between even numbers an associative algebra? [closed]

We were discussing about the possibility of having an algebra over a field which is associative but has not the unity. Does it exist? It has been proposed as a counterexample the set of even numbers. ...
MicAndDim's user avatar
0 votes
3 answers
1k views

When is the radical of the extension of a prime ideal prime?

(All rings assumed to be commutative and unital) Given a ring $R$, a prime ideal $\mathfrak{p}$ of $R$, and an extension ring $S$ (the algebra map $R\to S$ is injective), are there any nontrivial ...
0 votes
1 answer
152 views

Name for a monoid on the basis of a vector space?

Is there a name for the structure of a vector space with a monoid defined on its basis? Given a vector space V over a field F, we can choose a basis and define a monoid on it. Now we can use each ...
Spencer Woolfson's user avatar
0 votes
1 answer
162 views

$\mathbb{C}(u(x,y),v(x,y),f(x)+g(y))=\mathbb{C}(x,y)$ implies $\mathbb{C}(u(x,y),v(x,y))=\mathbb{C}(x,y)$?

The following question is a direct continuation of this question: Let $u,v \in \mathbb{C}[x,y]$. Assume that for every $f \in \mathbb{C}[x]$ and every $g \in \mathbb{C}[y]$ (excluding the cases where $...
user237522's user avatar
  • 2,837
0 votes
1 answer
181 views

Factor $\sum_{n=1}^{N} x^n$ [closed]

I am attempting to factor an $N^{\text{th}}$ degree polynomial with coefficients strictly equal to $1$ given by the equation $$\sum_{n=1}^{N} x^n$$ Although the Galois group for anything beyond a ...
Talmsmen's user avatar
  • 547
0 votes
1 answer
426 views

Generators of $SL(n,\mathbb F_2)$? [closed]

Consider the invertible matrices in $\mathbb F_2^{n\times n}$ which are a multiplicative group structure. Is there a finite set of $2k$ (at a $k\in\mathbb Z_{\geq1}$ independent of $n$) generators for ...
Turbo's user avatar
  • 13.9k
0 votes
1 answer
176 views

When can one infer degrees of generators of a ring from its hilbert series

I know that for a noetherian ring, it's hilbert series can be written as $$HS(t)=\frac{P(t)}{\prod_{i=1}^d{(1-t^{d_i})}}$$ where $P(t)$ is polynomial, and there are $d$ generators of degrees $d_1,\...
batconjurer's user avatar
0 votes
2 answers
240 views

Using group presentation for its corresponding semigroup?

Somewhere Colin M. Campbell noted: If $A$ is a semigroup defined as $$A=Sg(\pi)=\langle a_1,\cdots, a_d\mid u_1=v_1,\cdots,u_e=v_e\rangle $$ then the same generators with the same relations can ...
Mikasa's user avatar
  • 233
0 votes
2 answers
357 views

Rank of a $ \mathbb{Z}_{p}[[T]] $ module

Let $p$ be a prime and $M$ is a finitely generated $ \mathbb{Z}_{p}[[T]] $ module. Suppose $M[p]$ denotes the $p$-torsion of $M$. Then $M[p]$ and $M/(p)$ are both $ F_{p}$ vector spaces. So we can ...
Suman's user avatar
  • 1,209
0 votes
2 answers
1k views

What is the localization of Q[x]/(x) at 0

Q is a rational field. Q[x] is polynomial ring over Q 。(x) is maximal ideal of Q[x]. Take Q[x]/(x) as a module over Q[x]. Then what is Q[x]-module Q[x]/(x) localize at 0?? I think the result is Q[x]/...
MAJIA's user avatar
  • 25
0 votes
2 answers
389 views

Torsion of modules

Given a left module $M$ over a domain $R$, I am interested in irreducible elements $r\in R$ such that $r\cdot m=0$ for some $m\in M-\{0\}.$ I think "torsors" would be perfect name for such $...
Adam's user avatar
  • 2,390
0 votes
1 answer
568 views

A confusion about power series and p-adic measures

In page 16 of these notes on $p$-adic $L$-functions, it makes the following claim: Let $\alpha$ be a $p$-adic measure on $\mathbf{Z}_p$ which corresponds to a power series $F_{\alpha}(T) \in \mathbf{...
Adithya Chakravarthy's user avatar
0 votes
1 answer
176 views

Annihilator of idempotent elements

Let $R $ be a commutative ring with 1 and $s $ a nonnilpotent element of $R $ such that for each idempotent $e $ of $R $ there exists a natural number $n_e $ such that either $s^{n_e}e=0$ or $s^{n_e}(...
arenna's user avatar
  • 9
0 votes
2 answers
2k views

Tensor products of two domains

Let $R$ be an integral noetherian regular local ring. Let $S$ be a noetherian integral domain such that $S/R$ is finite. That is, $R \subset S$ and the surjection $R^{\oplus n} \twoheadrightarrow S$ ...
Pierre MATSUMI's user avatar
0 votes
1 answer
571 views

Recursive Non-standard Models of Modular Arithmetic? [closed]

Any algebraically closed field (ACF) is a model of Modular arithmetic (MA). (MA) has the same axioms as first order Peano arithmetic (PA) except $\forall x(Sx \neq 0)$ is replaced with $\exists x(Sx=0)...
Russell Easterly's user avatar
0 votes
2 answers
681 views

Pontryagin dual

Suppose $M$ is a $Z_p[[T]]$-module and $\widehat{M}$(the Pontryagin dual of $M$) is a finitely generated torsion $Z_p[[T]]$-module. How to prove that $\widehat{M}$ has $\mu$-invariant zero $\...
Suman's user avatar
  • 1,209
0 votes
1 answer
453 views

The completion of a ring R is a domain then the ring R is a domain?

Let be R a commutative ring whit unit and let I a proper ideal of R. Let R' the completion of R respect to the ideal I (see Introduction to Commutative Algebra - M. F. Atiyah, I. G. MacDonald for the ...
Antonio's user avatar
0 votes
1 answer
403 views

When does a power semigroup have a zero, and what can the zero be?

Let $S$ be a semigroup. The power semigroup of $S$ is the set $P(S)=2^S\setminus\lbrace\varnothing\rbrace $ with the operation $$AB=\lbrace ab\ |\ a\in A,\ b\in B\rbrace.$$ This operation is ...
Michał Masny's user avatar
0 votes
1 answer
372 views

the algebraic closure of strict henselian DVR

Let $A$ be a strict henselian DVR, and $\hat A$ is completion of $A$, is $K(A)^{alg} \longrightarrow {K(\hat A)}^{alg}$ a isomorphism? where $K(A)$ and $K(\hat A)$ are quotient fields.
kiseki's user avatar
  • 1,921
0 votes
2 answers
617 views

An element in the product of schemes

Let $ f : X \to S, g : Y \to S$ be the scheme morphisms, and $ X \times_S Y$ be the product of shemes. Let $ z \in X \times_S Y$ , and $ x=p(z) , y=q(z) ,$ where $ p: X \times_S Y \to X, q: X \times_S ...
Li Zhan's user avatar
  • 95
0 votes
1 answer
183 views

Projectively splitting module

Is there a name for such class of modules $M$ such that $M\rightarrow N\rightarrow 0$ splits for every $N$?
ashpool's user avatar
  • 2,857
0 votes
2 answers
563 views

Primary decomposition of zero-dimensional modules

(I removed my motivation because it may be misleading :) ) Let $A$ be a noetherian commutative ring and let $M \neq 0$ be a finitely generated zero-dimensional (i.e. $\mathrm{dim} \ \mathrm{Supp}(M) ...
user717's user avatar
  • 5,243

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