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Questions about the branch of algebra that deals with groups.
4
votes
1
answer
152
views
Do the class vector and character vector of a $p$-group determine each other?
To a finite $p$-group, we can associate two vectors $(v_0,v_1,\dotsc)$:
The class vector - $v_i$ is the number of conjugacy classes of order $p^i$.
The character vector - $v_i$ is the number of comp …
3
votes
The extension class of a finite Heisenberg group
I believe that your conjecture is equivalent to Theorem 3.5 in the paper Locally Compact Abelian Groups with Symplectic Self-duality, Advances in Mathematics, volume 225, pages 2429-2454, 2010.
9
votes
Accepted
Branching Rule for alternating groups
This is answered in Theorem 4 of my paper Comparison of Gelfand-Tsetlin Bases for Alternating and Symmetric Groups, with Geetha Thangavelu, which is published in Algebras and Representation Theory, an …
5
votes
Accepted
Induced representation of a Young subgroup
The answer is a special case of Young's rule. In my book, I give a very simple method for the slightly easier case where $r=0$. In that case we have:
$$
\mathrm{Ind}_{S_k\times S_l}^{S_n} = \bigoplus_ …
9
votes
Accepted
Can monomial representations induced from nonmonomial representations?
According to Djokovic and Maizan, the Specht module $V_{(3, 1, 1)}$ of $S_5$ is monomial. This is a representation of dimension $6$, induced from a representation of dimension $3$ of $A_5$. Since $A_5 …
4
votes
Accepted
subgroups of General linear group with two generators
You would have an answer to your question if you could classify pairs of elements in $GL_n(\mathbf F_q)$ up to simultaneous conjugacy. This is the notorious matrix pair problem, which is the quintesse …
13
votes
Automorphism group of a finite group
A nice set of generators for the automorphism group of a finite abelian group is described by Garrett Birkhoff in his paper titled "Subgroups of abelian groups", Proc. London Math. Soc., s2-38(1):385- …
3
votes
Accepted
A question on automorphisms of finite abelian groups
Here is an outline for odd order abelian $p$-groups:
The main point is that every non-zero element in a field with at least three elements is a sum of two non-zero elements. Using this, you can show …
2
votes
Decomposition of induced representations / Refinement of Mackey's criterion
The proof of Mackey's theorem on intertwiners actually tells you how to construct the endomorphism algebra of an induced representation, not just its dimension. So, if you work a little harder, you ma …
3
votes
What are the necessary and sufficient conditions for GL(n,Z/p^lZ) to be isomorphic to GL(n,F...
For $l=2$, the only cases where the extension splits are $n=2$ and $p=2,3$ and $n=3$ and $p=2$. In her PhD thesis, on page 3, Pooja Singla attributes this to [Chih Han Sah. Cohomology of split group e …
7
votes
Hall polynomial when the subgroup is cyclic?
Let's say you want to compute the Hall polynomial $g^\lambda_{(r),\mu}(p)$.
According to [Dutta and Prasad, Degenerations and orbits in finite abelian groups], the orbits under the automorphism group …
3
votes
Accepted
Non-split groups
Besides the basic definitions and examples, you will find a concise description of the vocabulary needed to talk about linear algebraic groups over fields that are not algebraically closed in T. A. Sp …
2
votes
Automorphisms of a matrix in Smith normal form?
If you have $P$, I think you can recover $Q$ as $(D^{-1}PD)^{-1}$.
Therefore, you are looking for invertible integer matrices $P$ such that $D^{-1}PD$ is also invertible (i.e., $P\in GL_n(\mathbf Z)\c …
10
votes
Accepted
Bruhat decomposition for G(R), R local ring or R=Z/p^r
Bruhat decomposition over $\mathbf Z/p^r\mathbf Z$ is precisely the problem we looked at in this paper. We defined several invariants of double cosets, and classified the pairs $(n,k)$ for which, when …
9
votes
Accepted
Conjugation orbits in the square matrices
For a field, this is given by the rational canonical form (see Section 7.2 of Hoffman and Kunze's Linear Algebra, for example). Even in this case, the trace and characteristic polynomial are quite wea …