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Topology of cell complexes and manifolds, classification of manifolds (e.g. smoothing, surgery), low dimensional topology (e.g. knot theory, invariants of 4-manifolds), embedding theory, combinatorial and PL topology, geometric group theory, infinite dimensional topology (e.g. Hilbert cube manifolds, theory of retracts).

9 votes

$\mathrm{GL}_n(\mathbb{Z}_2)=\mathrm{Out}(F_n)/\langle\langle \epsilon_1,\dots,\epsilon_n\ra...

$\DeclareMathOperator{Out}{Out} \DeclareMathOperator{Aut}{Aut} \DeclareMathOperator{IA}{IA}$ The key thing that is missing is that the Torelli subgroup of $\Out(F_n)$ is contained in the normal closur …
Andy Putman's user avatar
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5 votes
Accepted

Extending diffeomorphisms between surfaces

The way you phrased this makes it sound harder than it is. Your two surfaces are diffeomorphic, so we can identify them both with a single surface $M$. Do this in a way that reflects the identificat …
Andy Putman's user avatar
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3 votes

Finite normal subgroup of mapping class group

When the genus of the surface is at least 3, Lanier-Margalit proved something much stronger than the fact that there are no finite normal subgroups: aside from the hyperelliptic involution, the normal …
Andy Putman's user avatar
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8 votes
Accepted

Linking number and intersection number

$\DeclareMathOperator\tX{\widetilde{X}}\DeclareMathOperator\tB{\widetilde{B}}\DeclareMathOperator\tD{\widetilde{D}}\DeclareMathOperator\Z{\mathbb{Z}}$ In fact, $B$ must intersect $D$ at least $|\text{ …
Andy Putman's user avatar
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12 votes
Accepted

If the universal cover has three boundary components, does it have infinitely many?

Let $M$ be a compact connected 3-manifold with nonempty boundary such that $\pi_1(M)$ is infinite and the universal cover $\tilde{M}$ has finitely many boundary components. I will prove that $\tilde{ …
Andy Putman's user avatar
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8 votes

Proof of Giroux's correspondence

I haven't read it carefully, but the new paper here by Licata-Vértesi appears to be (finally) a complete proof, albeit one that is different from the original. EDIT: As the comments pointed out, the …
Andy Putman's user avatar
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7 votes
Accepted

Dualizing module for $\operatorname{Aut}(F_n)$

In our paper here, Himes, Miller, Nariman, and myself prove that Hatcher-Vogtmann’s question has a negative answer, at least for $n=5$. It also probably has a negative answer for larger $n$, but our i …
Andy Putman's user avatar
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3 votes

Fibration of hyperbolic 3-manifold

This isn't true. Here's one easy construction. For some $g \geq 2$, let $\Sigma_g$ be a closed oriented genus $g$ surface and let $f\colon \Sigma_g \rightarrow \Sigma_g$ be a homeomorphism represent …
Andy Putman's user avatar
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8 votes
Accepted

Generate $\mathrm{Mod}(S_g)$ by two Dehn twists

In Humphries, Stephen P. Generators for the mapping class group. Topology of low-dimensional manifolds (Proc. Second Sussex Conf., Chelwood Gate, 1977), pp. 44–47, Lecture Notes in Math., 722, Springe …
Andy Putman's user avatar
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8 votes

How to prove that Lie group framing on S^1 represents the Hopf map in framed cobordism

I wrote out careful proofs of all of this and more in my note "Homotopy groups of spheres and low-dimensional topology", available here.
Andy Putman's user avatar
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3 votes
Accepted

Do taut foliations leafwise branch covering S^2 yield foliations by circles?

To see what is going on, I think it is helpful to carefully work out an explicit example. In Section 2.1 of Calegari's paper, he explains how to deal with 3-manifolds that fiber over the circle. Her …
Andy Putman's user avatar
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4 votes
Accepted

Two details from Stallings's proof of the sphere theorem

What you need for your second question is that $H^1_c(\tilde{M})$ is a free abelian group. As you noted, this is isomorphic to $H_2(\tilde{M})$. Now, $\tilde{M}$ is a connected non-compact 3-manifol …
Andy Putman's user avatar
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5 votes

Is there a simple formula to compute the Casson invariant of an homology $3$-sphere from its...

I don’t know a nice recipe from a Heegaard diagram, but every Heegaard splitting of a homology 3-sphere is equivalent to one whose gluing map lies in the Torelli subgroup of the mapping class group (i …
Andy Putman's user avatar
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7 votes

Index of the mapping class group $\Gamma_{g,n}$ inside $\text{Out}(\Pi_{g,n})$

It only has finite index in very low-complexity degenerate cases. Here's a proof that it always has infinite index for $\Sigma_{g,1}$ with $g \geq 2$. This proof generalizes in an obvious way to deal …
Andy Putman's user avatar
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8 votes

Generators for commutator subgroup of surface group

Before I answer this old question, a confession: the user "Linda" is actually me! I asked this basically to make sure that something I proved was not already known. This is such a classical subject …
Andy Putman's user avatar
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