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Questions on group theory which concern finite groups.

12 votes
Accepted

How quasirandom are the nonabelian finite simple groups?

Suppose $G$ is a finite simple group of order $n$ with a nontrivial representation of degree $d$. Then $G$ is isomorphic to a subgroup of $U(d)$. By Collins's sharp version of Jordan's theorem (https: …
Sean Eberhard's user avatar
9 votes
1 answer
411 views

When is there a unique perfect group of order $n$?

For which $n$ is there a unique perfect group of order $n$? Are there infinitely many such $n$? Some guesses for infinite sequences of such $n$: $|\mathrm{PSL}(2,p)|$, $|\mathrm{SL}(2,p)|$, $|A_m|$, …
Sean Eberhard's user avatar
9 votes

Nonisomorphic finite groups with isomorphic Sylow subgroups

Let $G_1$ and $G_2$ be nonisomorphic Sylow-isomorphic groups. For example let $G_1 = C_6$ and $G_2 = S_3$. Then for any finite group $H$, the groups $G_1 \times H$ and $G_2 \times H$ are nonisomorphic …
Sean Eberhard's user avatar
8 votes

Subgroup property stronger than being characteristic

There must be no other subgroup of $H$ isomorphic to $K$. Certainly this property implies your property, as $g^{-1}Kg$ is always isomorphic to $K$. Conversely if $K'\leq H$ is isomorphic to $K$ let $ …
Sean Eberhard's user avatar
8 votes

Bounds on the number of elements of a given order in a finite simple group

For $w$ a word in a free group $F_d$, we can consider the word map $\bar w : G^d \to G$. Let $P_w(G)$ denote the proportion of $d$-tuples $x \in G^d$ such that $\bar w (x) = 1$. Your notation is relat …
Sean Eberhard's user avatar
8 votes

When does $G\times G\times G$ admit a faithful group action on a set of size $|G|$?

This is more of an extended comment than an answer. I will determine all the abelian groups failing to act faithfully on at most $n/3$ points. Suppose $G$ is abelian, say $G = C_{q_1} \times C_{q_2} \ …
Sean Eberhard's user avatar
8 votes
Accepted

Order of abelian subgroup of the automorphism group of an abelian group

As Nick Gill points out, one can certainly have $|B| > |A|$ if you do not assume coprimality. If you assume coprimality then yes $|B| < |A|$. If $A_p$ is the Sylow $p$-subgroup of $A$ then $\DeclareMa …
Sean Eberhard's user avatar
8 votes

Why do these finite group Dedekind matrices seem to have integer spectrum when specialized t...

You can just compute the spectrum exactly using the formula mentioned by Benjamin Steinberg: $$\sum_g \operatorname{ord}(g) \frac{\chi(g)}{\chi(1)}.$$ There are two or four characters of degree $1$ ac …
Sean Eberhard's user avatar
7 votes
Accepted

Quadratic refinements of a bilinear form on finite abelian groups

By the classification of finite abelian groups we have $A \cong C_1 \oplus \cdots \oplus C_k$ for some cyclic groups $C_i = \langle g_i \rangle$ of prime power order $r_i$. Let $\chi: A \times A \to …
Sean Eberhard's user avatar
6 votes
1 answer
430 views

Kantor's Singer cycle theorem

I'm trying to understand the proof of Kantor's Singer cycle theorem, which asserts that if $G$ is a subgroup of $\operatorname{GL}(n,q)$ containing a Singer cycle then $\operatorname{GL}(n/s,q^s) \leq …
Sean Eberhard's user avatar
5 votes
Accepted

Minimal degree of primitive permutation group

You seem to be aware of the answer to your own question, since you give the reference to the paper of Guralnick and Magaard, which classifies groups of minimal degree $\leq n/2$. Therefore $n \leq 2m$ …
Sean Eberhard's user avatar
5 votes
Accepted

When are elements of a (perfect) semidirect product simple commutators?

Your general question seems too general. Here is a partial answer to your specific question. Let $V = \mathbb{F}^{2m}$ and $G = \mathrm{Sp}_{2m}(\mathbb{F})$. Consider some $vg \in VG$. We know that $ …
Sean Eberhard's user avatar
5 votes
1 answer
315 views

Embedding an icosahedron

A transitive set in $\mathbf{R}^n$ is a finite set with a transitive group of symmetries. I want to understand how subsets of a transitive set constrain the group. Let me start with the example of a t …
Sean Eberhard's user avatar
4 votes
Accepted

Is the free abstract group residually of rank d > 2?

No, there is not such a word, by the following two facts. The two elements $$A=\left(\begin{array}{cc}1&2\\0&1\end{array}\right),\quad B=\left(\begin{array}{cc}1&0\\2&1\end{array}\right)$$ of $\text …
Sean Eberhard's user avatar
4 votes
0 answers
105 views

Maximal abelian subgroups of the full collineation group $\mathrm{P\Gamma L}_3(q)$

Is there a convenient list of the maximal abelian subgroups of the projective semilinear group $\mathrm{P\Gamma L}_3(K) \cong \mathrm{PGL}_3(K) \rtimes \mathrm{Gal}(K)$ for $K$ a finite field? This is …
Sean Eberhard's user avatar

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