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A Sobolev space is a vector space of functions equipped with a norm that is a combination of Lp-norms of the function itself and its derivatives up to a given order.

18 votes
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Research topics in distribution theory

While I do not know much about current development of the general theory of distributions, I can say something about the current research topics in a special class of distributions, the theory of Sobo …
Piotr Hajlasz's user avatar
14 votes
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Is the intersection of two Caccioppoli (i.e. finite perimeter) sets Caccioppoli?

That is true. Caccioppoli sets are also known as sets of finite perimeter. Theorem. Suppose $f\in L^1(\mathbb{R}^n)$ vanishes outside the unit cube $[0,1]^n$. For $i=1,2,\ldots,n$ consider the fu …
Piotr Hajlasz's user avatar
14 votes
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Is there any nontrivial characterization of weakly differentiable functions?

Definition. If $U\subset\mathbb{R}$ is open, we say that $u\in {AC}(U)$ if $u$ is absolutely continuous on every compact interval in $U$. Let $\Omega\subset\mathbb{R}^n$. We say that $u$ is absolutely …
Piotr Hajlasz's user avatar
10 votes

Books about capacity theory

I think the best treatment of basic facts about capacity from the perspective of Sobolev spaces is in Chapter 4 of L. C. Evans, R. F. Gariepy, Measure theory and fine properties of functions. Revised …
Piotr Hajlasz's user avatar
9 votes
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Is $C^{\infty}(M)$ dense in weighted Sobolev space $W_{X}^{1}(M)$?

The density result is true for any family of vector fields with Lipschitz coefficients. Theorem. Let $X_1,\ldots,X_k$ be a system of vector fields with Lipschitz coefficient on a compact Riemanni …
Piotr Hajlasz's user avatar
8 votes
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Sobolev functions on $\mathbb{R}^N$ cannot be discontinuous on a $(N-1)$-dimensional submani...

Any function in $W^{1,p}$, $p>N$, has a continuous representative by the Sobolev embedding theorem so there is no issue here. However: Proposition. There is a function $f\in W^{1,p}$, $p\leq N$, …
Piotr Hajlasz's user avatar
8 votes

discontinuous functions on the Sobolev borderline

There are plenty of examples of discontinuous Sobolev function in $W^{1,n}(\mathbb{R}^n)$. For example $f(x)=\log|\log|x||$ defined in a neighborhood of zero. Now take $n=2$ and restrict the function …
Piotr Hajlasz's user avatar
8 votes
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Extending Sobolev function on Riemannian manifold

If the annulus is small, then it is basically an Euclidean annulus and there is an extension operator for Sobolev spaces. However, if the annulus is large is may happen that it goes around a "neck" in …
Piotr Hajlasz's user avatar
7 votes
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Bounded deformation vs bounded variation

Example 7.7 in L. Ambrosio, A. Coscia, Alessandra, G. Dal Maso, Fine properties of functions with bounded deformation. Arch. Rational Mech. Anal. 139 (1997), no. 3, 201–238.
Piotr Hajlasz's user avatar
7 votes

Do non-continuous Sobolev maps pull back closed forms to weakly closed forms?

This is I guess Lemma 4.1 in https://arxiv.org/pdf/1301.4978.pdf which I state below. The assumptions might be a bit different than yours, but it might be useful. I guess the assumptions in Lemma 4.1 …
Piotr Hajlasz's user avatar
7 votes

Weak Hessian of the distance function

The following result is due to Asplund [A, p.235]. Theorem. If $\varnothing\neq E\subset\mathbb{R}^n$ is closed, and $d(x)=\operatorname{dist}(x,E)$, then $f:\mathbb{R}^n\to\mathbb{R}$ defined by $f( …
Piotr Hajlasz's user avatar
7 votes
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Is the support of a Sobolev function a varifold?

Yes if you choose a suitable representative of a Sobolev function. Lemma. Let $f\in W^{1,p}(\mathbb{R}^n)$, $1\leq p<\infty$. Then for every $\epsilon>0$, there is a Lipschitz function $g:\mathbb{R}^n …
Piotr Hajlasz's user avatar
6 votes
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Is $L^1$ strong convergence of Jacobians valid for maps between manifolds?

You actually do not need to assume that the mappings are Lipschitz as it is true for general $W^{1,n}$ mappings Theorem. If $\mathcal{M}$ and $\mathcal{N}$ are smooth compact and oriented manifolds, …
Piotr Hajlasz's user avatar
6 votes
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Does anyone know what is the right reference for the following simple lemma from harmonic an...

The lemma is due to: J. O. Strömberg, and A. Torchinsky. Weights, sharp maximal functions and Hardy spaces. Bull. Amer. Math. Soc. (N.S.) 3 (1980), no. 3, 1053–1056. The lemma is stated there with …
Piotr Hajlasz's user avatar
5 votes
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Estimate of the difference quotients in terms of an $L^{1,\infty}$ function

The property (P) indeed characterizes the Sobolev space $W^{1,p}$. Theorem 1. $f\in W^{1,p}(\mathbb{R}^n)$, $1<p\leq\infty$ if and only if $f\in L^p$ and there is $0\leq g\in L^p$ such that $$ | …
Piotr Hajlasz's user avatar

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