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Search options answers only not deleted not community wiki created 2010-09-28 - 2011-09-28
9 votes
Accepted

Positivity of a rational function

The answer is yes. This was already proved in Gabor Szegö's original paper from 1933: G. Szegö, Über gewisse Potenzreihen mit lauter positiven Koeffizienten, Mathematische Zeitschrift, Volume 37, Nu …
Andreas Thom's user avatar
  • 25.5k
4 votes
Accepted

minimal diameter of full preimage of torus

The second claim is false for $n=3$. Choose $\varepsilon$ small and $\delta\ll\varepsilon$. Let $A$ be the set of all points $(x,y,z)\in\mathbb R^3$ satisfying the following inequalities: $$ \begin{c …
Sergei Ivanov's user avatar
35 votes
Accepted

The Hardy Z-function and failure of the Riemann hypothesis

This doesn't quite sound like the right conjecture here, because Z is known to go to infinity on the average, by Selberg's central limit theorem (see my blog post on this topic). But this is easy to …
Terry Tao's user avatar
  • 114k
2 votes

Reference for two facts about perverse sheaves on G/B

A couple of things (I meant to just have this as a comment but it got too long): I think with regard to the first fact, a lot of people realised it all around the same time — the article by Springer w …
Kevin McGerty's user avatar
4 votes

What is special about polylogarithms that leads to so many interesting identities and applic...

Polylogarithms have interesting connections in the Theory of Partitions. This is mainly because a class of generating functions for bivariate partition statistics can be approximated by polylogarithm …
Daniel Parry's user avatar
  • 1,306
3 votes
Accepted

Maximal clique intersection graphs

$T$ is called the clique graph of $G$, see https://link.springer.com/chapter/10.1007/0-387-22444-0_5
rvf0068's user avatar
  • 266
8 votes

Automorphism group of a scheme

This is a partial answer to THC's question about a "direct" way to do this. Let $X$ be a smooth projective variety such that $\omega_X$ is ample. Then there is some $m\in\mathbb N$ such that $\mathsc …
Sándor Kovács's user avatar
39 votes

What is the intuition behind the Freudenthal suspension theorem?

Maybe this differential topologic way of thinking the Freudenthal suspension is much more intuitive. By Pontrjagin's contruction you can identify $\pi_{n+k}(S^n)$ with equivalence classes of framed su …
Francesco Lin's user avatar
14 votes

When is a Banach space a Hilbert space?

More characterisations are in the book of Haim Brezis (Analyse fonctionnelle), at the appendix of Chapter 5. I will copy two of these below, toghether with the references: If $ \dim(E)\geq 2 $ and e …
Garrisi Daniele's user avatar
2 votes

Maximal clique intersection graphs

Hi, I have been working with clique graphs for the last 10 years. My doctoral tesis was about clique graphs. Recently we have proved that recognizing clique graphs is an NP-complete problem. See Th …
liliana's user avatar
  • 21
3 votes

Computing squaring operations in the Adams spectral sequence

This is an answer Bob's question after my previous answer. It doesn't fit in a comment. As a spectrum, $\mathrm{End}(H\mathbb{Z}/2)$ is known to be a product of Eilenberg-MacLane spectra, so it is th …
Fernando Muro's user avatar
18 votes
Accepted

Cardinality of connected manifolds

A connected Hausdorff manifold with more than one point has cardinality $2^{\aleph_0}$. Here's a proof sketch. For each point $x$ of the manifold, let $U_x$ be an open Euclidean neighbourhood of $x$ …
Stephen S's user avatar
  • 981
9 votes

Is the Leopoldt conjecture almost always true?

I think that not much is known. For example I don't think that we are any closer to prove Leopoldt's conjecture for a given $F$ for infinitely many $p$ than to prove it for all $p$. Here is a result …
Joël's user avatar
  • 26k
21 votes

Is the Leopoldt conjecture almost always true?

Olivier and all, If you trust your own minds, you should better try directly and read version 2 of the proof for only CM fields, which I posted in June this years. The rest is hot wind - people may …
Preda's user avatar
  • 375
1 vote
Accepted

Associativity of polar decomposition

Ah, (quite) some fiddling with Mathematica gave a counterexample. In the notation of anon's answer, take $$ A' = \begin{pmatrix} 1 & 1 & 1 & 1 \\\\ 1 & 1 & 1 & 0 \end{pmatrix}, \qquad B = \begin{ …
Chris Heunen's user avatar
  • 3,937

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