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forcing, large cardinals, descriptive set theory, infinite combinatorics, cardinal characteristics, forcing axioms, ultrapowers, measures, reflection, pcf theory, models of set theory, axioms of set theory, independence, axiom of choice, continuum hypothesis, determinacy, Borel equivalence relations, Boolean-valued models, embeddings, orders, relations, transfinite recursion, set theory as a foundation of mathematics, the philosophy of set theory.

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"Very $L$-like" models, part 1: large cardinals

(The original version of this question was much narrower and less natural; but see the edit history if interested.) Say that a good logic is a regular logic $\mathcal{L}$ containing $\mathsf{FOL}$ ...
Noah Schweber's user avatar
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1 answer
2k views

There are no abstract categories

$\newcommand\Set{\mathbf{Set}}\newcommand\Ob{\mathbf{Ob}}\newcommand\Hom{\mathbf{Hom}}$Work in a foundation that admits a countable hierarchy of notions of ‘set’, and say that a category is $n$-small ...
Alec Rhea's user avatar
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0 answers
265 views

How strong is this "modal definability principle"?

Throughout, we work in the class theory $\mathsf{MK}$ (although I'm open to tweaking this), "logic" means "set-sized logic whose semantics is definable over $V$," and "$\...
Noah Schweber's user avatar
5 votes
1 answer
183 views

Fragility of large cardinals with respect to transitive end extensions

To motivate things, let me start with a special case of the question I'm interested in. Let $\mathsf{In}(x)\equiv$ "$x$ is an inaccessible cardinal." Question 1: Is it consistent with the ...
Noah Schweber's user avatar
5 votes
2 answers
1k views

Large cardinals without the ambient set theory?

In an attempt to understand a bit better large cardinals, I have been thinking along the following lines, which could be summarized under the slogan Talk about cardinals without the (ambient) ...
Mirco A. Mannucci's user avatar
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1 answer
158 views

(Weakly) minimal subcovers of linear covers

Motivation. The starting point of this question is the trivial observation that if we cover $\mathbb{N}$ with $$\big\{\{0,\ldots n\}: n\in \mathbb{N}\big\},$$ then this cover doesn't have a minimal ...
Dominic van der Zypen's user avatar
5 votes
1 answer
1k views

How many well-orders of reals are there?

It's commonly known that the cardinality of the set of all well-orders on $\aleph_0$ is the continuum (correct me if I'm wrong plz). What about that of all well-orders on $\mathbb{R}$? Is there a ...
Edouard Ji's user avatar
5 votes
1 answer
422 views

What is the relationship between non-existence of those kinds of singular sets and AC?

Let's say a set $A$ is super-singular, if and only if, there exists a set $x$ such that $|A|=|\bigcup x|$ and $| A| > |x|$, and for each $y \in x$ we have: $ |y| \not > |x|$ . A set $A$ is ...
Zuhair Al-Johar's user avatar
5 votes
1 answer
149 views

Does there exist a section of $\mathcal{P}(\kappa)\to\mathcal{P}(\kappa)/(\text{fin})$ that is "nearly Boolean"?

The following might be a somewhat esoteric question: Does there exist an infinite cardinal $\kappa$ and a section $f$ of the quotient map $\pi:\mathcal{P}(\kappa)\to\mathcal{P}(\kappa)/(\text{fin})$ (...
David Gao's user avatar
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How to study formal logic without formally using the notion of a set?

I have recently begun curious in set theory, and when I researched this subject I saw that all axiomatizations of set theory, such as ZFC and NBG, are expressed in the language of first order logic. ...
Shthephathord23's user avatar
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1 answer
286 views

Is there an oracle that can compute something iff it is computable in every countable model that is equivalent to $(V, \in)$?

Let us work in Kelly-morse set theory, so we can talk about $V$. For some model $M=(\mathbb N, \in_M)$ that is elementary equivalent $(V, \in)$, we can have an oracle that corresponds to $(\mathbb N, \...
Christopher King's user avatar
5 votes
1 answer
471 views

Comparability implies well-orderability?

I am trying to prove a small proposition that got me completely stumped, and I cannot find a single counterexample. (ZF) Suppose that $E$ is such that for every $A\subseteq\mathcal P(E)$ either $|...
Asaf Karagila's user avatar
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Mathias forcing with Ramsey ultrafilters, and Cohen reals [closed]

Edit/update: One reason this question never received an answer is because it was founded on a faulty premise! The Blaszczyk-Shelah paper I mentioned below does not prove that Mathias forcing with a ...
Justin Palumbo's user avatar
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0 answers
449 views

How many Dedekind-finite sets can $\mathbb{R}$ be partitioned into?

Building off Asaf Karagila's answer to my previous question (Can $\mathbb{R}$ be partitioned into dedekind-finite sets?) on partitioning $\mathbb{R}$ into strictly Dedekind-finite sets: (1) What ...
Noah Schweber's user avatar
5 votes
2 answers
528 views

Cardinality of a set of countable connected Hausdorff spaces

It is a non-trivial result that there is a countable connected Hausdorff space. Let ${\cal T}$ be a set of connected Hausdorff topologies on $\omega$ such that whenever $\tau_1\neq\tau_2\in {\cal T}$ ...
Dominic van der Zypen's user avatar
5 votes
1 answer
432 views

Is there a class choice principle over MK that is equivalent to class well ordering over MK?

$\sf MKCWO$ is the theory obtained by adding a new primitive binary relation $\prec$ to the signature of $\sf MK$ and axiomatize that $\prec$ is a well order on classes, that is: $\textbf{Transitive:}...
Zuhair Al-Johar's user avatar
5 votes
1 answer
327 views

$\Sigma_n$ version of HOD

Fix a natural number, $n \geq 1$. Consider the class, M, of all sets hereditarily ordinal-definable using some $\Sigma_n$ formula. Since there is a universal $\Sigma_n$ formula, M is definable. Is M ...
Norman Lewis Perlmutter's user avatar
5 votes
1 answer
421 views

Large cardinal axioms and the perfect set property

It is known that if there is a measurable cardinal then every $\Pi_1^1$ set has the perfect set property (i.e it is either countable or contains a copy of $2^{\omega}$). Also if we have $\Pi_1^1$-...
Rachid Atmai's user avatar
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5 votes
2 answers
407 views

What's the consistency strength of this form of reflection?

Working in mono-sorted first order logic with equality $``="$ and membership $``\in"$: Define: $set(x) \equiv_{df} \exists y \, (x \in y)$ Axiomatize: Extensionality: $( a \subseteq b \land b \...
Zuhair Al-Johar's user avatar
5 votes
1 answer
493 views

Subcountability

In these slides of a talk Giovanni Curi shows that the generalized uniformity principle follows from Troesltra’s uniformity principle and from the subcountability of all sets, which are both claimed ...
ToucanIan's user avatar
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0 answers
472 views

The surreal numbers under a change of universe

Suppose we start with a model $\mathcal{M}$ of $ZFC$ (or $GBC$ or $MK$ if you prefer), and let $N_0^\mathcal{M}$ denote the surreals in $\mathcal{M}$. If we add some large cardinal assumptions $\{\...
Alec Rhea's user avatar
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5 votes
1 answer
489 views

Simplest non-constructible set of integers compatible with the nonexistence of $0^\sharp$?

What is the simplest non-constructible set of integers (say, in the analytical hierarchy) that is compatible with the nonexistence of $0^\sharp$? In particular, can there still be a non-constructible $...
Jesse Elliott's user avatar
5 votes
1 answer
627 views

Can there be no "surprisingly averageable" second-order sentences?

Say that a second-order sentence $\varphi$ is averageable iff there exists some infinite cardinal $\kappa$ and some nonprincipal ultrafilter $\mathcal{U}$ on $\kappa$ such that for every $\kappa$-...
Noah Schweber's user avatar
5 votes
3 answers
884 views

"name" for the ground model

I am a beginner of forcing, often I read from some articles something like "$p \Vdash \dot{G}$ is $P$-generic over $\check{M}$" (where $M$ is a countable transitive model, for instance). Q1. I ...
sonicyouth's user avatar
5 votes
1 answer
694 views

What are examples of non-equivalent virtualizations of a large cardinal?

This is a follow up to my previous question concerning virtual large cardinals, that are generally weaker axioms of infinity obtained from ordinary large cardinals through the so-called virtualization ...
Morteza Azad's user avatar
5 votes
1 answer
320 views

Bounds for a small cardinal

$\newcommand{\w}{\omega}\newcommand{\F}{\mathcal F}\newcommand{\I}{\mathcal I}\newcommand{\J}{\mathcal J}\newcommand{\M}{\mathcal M}\newcommand{\N}{\mathcal N}\newcommand{\x}{\mathfrak x}\newcommand{\...
Alex Ravsky's user avatar
  • 5,409
4 votes
2 answers
883 views

Group & modules of arbitrary cardinality [closed]

How do I see that there is a group of an arbitrary cardinality? Is this also true for abelian groups? Also, given a commutative ring $R\neq 0$ how do I see that there is an $R$-module of arbitrary ...
ashpool's user avatar
  • 2,857
4 votes
1 answer
302 views

Presaturated ideals

In this paper, Gitik and Shelah make the following claim (part of Proposition 1.5): Claim (Gitik-Shelah): Suppose $\kappa < \lambda$ are regular, $2^\lambda = \lambda^+$, and $D$ is a normal ...
Monroe Eskew's user avatar
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4 votes
1 answer
309 views

Unbounded set in $V[G]$ has an unbounded subset in $V$?

This is a repost of the same question on math.SE, which received several comments but no answers/comments on the first question. Suppose $\kappa$ is a cardinal preserved in the generic extension $V[G]...
Clement Yung's user avatar
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4 votes
1 answer
318 views

Bad subforcings of nice forcing notions

Let $\mathbb{P}$ and $\mathbb{Q}$ be two forcing notions. Recall that we say $\mathbb{Q}$ is a subforcing of $\mathbb{P}$ if there exists a regular embedding $\mathbb{Q} \to \text{r.o.}(\mathbb{P}).$ ...
Mohammad Golshani's user avatar
4 votes
1 answer
425 views

Perfect set property implies $\omega_1$ is a limit cardinal in $L$

Specker proved in 1957 that if in $V$ every set of real numbers has the perfect set property, than in $L$, $\omega_1^V$ is actually a limit cardinal. The original proof is in German, and I've been ...
Asaf Karagila's user avatar
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4 votes
0 answers
233 views

How distributive are the bad Laver tables?

Suppose that $n\in\omega\setminus\{0\}$. Then define $(S_{n},*)$ to be the algebra where $S_{n}=\{1,...,n\}$ and $*$ is the unique operation on $S_{n}$ where $n*x=x$ $x*1=x+1\,\text{mod}\, n$ and if $...
Joseph Van Name's user avatar
4 votes
0 answers
241 views

Is the lowenheim-skolem number of nth order logic larger than the corresponding number for 2nd order logic

According to this paper, by Vaananen, the $LS$ number for $2^{nd}$ order logic is given by "the supremum of $Π_{2}$-definable ordinals", where "The Lowenheim-Skolem number $LS(L)$ of $L$ is the ...
Andy's user avatar
  • 95
4 votes
1 answer
143 views

Injective choice function for infinite complete linear hypergraphs

A hypergraph $H=(V,E)$ is said to be complete and linear if whenever $e_1\neq e_2\in E$ then $|e_1\cap e_2|=1$, and for $v,w\in V$ there is $e\in E$ such that $\{v,w\}\subseteq e$. Assuming that $V$ ...
Dominic van der Zypen's user avatar
4 votes
0 answers
172 views

Ultracoproducts of C(X)-algebras

Let $X$ be a metrizable compact topological space, let $\mathcal U$ be an ultrafilter, and denote by $X^{\mathcal U}$ the ultracopower of $X$ with respect to $\mathcal U$. As a C$^*$-algebraist, I ...
Aaron Tikuisis's user avatar
4 votes
1 answer
718 views

Is every element of $\omega_1$ the rank of some Borel set?

It is well known that we can obtain the $\sigma$-algebra of Borel subsets of $2^{\omega}$ in the following way: Let $B_0$ be the collection of all open subsets of $2^{\omega}$. For $\alpha=\beta+1$, ...
Hannes Jakob's user avatar
  • 1,799
4 votes
1 answer
151 views

Comparing bornologies for domination/escaping

Consider the following bornologies $\mathbb{D},\mathbb{E}$ on the set $\mathcal{N}$ of all functions from $\mathbb{N}$ to $\mathbb{N}$: $\mathbb{D}=\{A: \exists f\in\mathcal{N}\forall g\in A\exists m\...
Noah Schweber's user avatar
4 votes
3 answers
828 views

Impact of the axiom of replacement on finite sets

The axiom of replacement is usually used to prove the existence of large sets, to provide a reflection principle, for transfinite recursion… However, I am wondering how it affects finite sets. Let me ...
The User's user avatar
  • 2,442
4 votes
1 answer
260 views

Is ${\cal P}(\omega)/\text{(fin)}$ a fractal poset?

If $(P,\leq)$ is a partially ordered set and $a,b\in P$ we set $[a,b]:=\{x\in P: a\leq x\leq b\}$. We say that $P$ is fractal if whenever $a,b\in P$ and $[a,b]$ contains more than one element, then $[...
Dominic van der Zypen's user avatar
4 votes
1 answer
746 views

Can all uncountable (but small) families of sets with positive measure have an uncountable subfamily with an intersection of positive measure?

My general question was is it consistent that any uncountable family of less than $\mathrm{non}(\mathcal{N})$ sets, each with positive measure, has an uncountable subfamily $\mathcal{F}$ s.t. $\bigcap ...
mtg's user avatar
  • 135
4 votes
1 answer
236 views

How can I collapse all cardinals of ground model except one of them?

Let $\kappa$ be an uncountable cardinal of a c.t.m $M$ of $ZFC$. Is there a generic extension of $M$ like $M[G]$ such that all uncountable cardinals of ground model collapse except $\kappa$?
user avatar
4 votes
0 answers
139 views

Simple $(\alpha+1)$-recursive well-orders with order type $|\alpha\text{-recursive}|$

In the following, $L_\alpha$ is the $\alpha$-th level of the constructible hierarchy, $\alpha$-recursive means definable in $L_\alpha$ by a $\Delta_1$ formula. $|\alpha\text{-recursive}|$ is the ...
Racheline's user avatar
  • 148
4 votes
1 answer
221 views

Comparing bornologies for cardinal characteristics via Borel maps

This question is "take 2" of this older one, following a suggestion of Francois Dorais. Consider the following bornologies $\mathbb{D},\mathbb{E}$ on the set $\mathcal{N}$ of all functions ...
Noah Schweber's user avatar
4 votes
2 answers
326 views

Infinite graph with no minimal vertex cover

If $G=(V,E)$ is a simple, undirected graph, then $C\subseteq V$ is said to be a vertex cover if $C\cap e\neq \varnothing$ for all $e\in E$. Is there an infinite graph $G=(V,E)$ such that for any ...
Dominic van der Zypen's user avatar
4 votes
1 answer
943 views

A question about "local" versus "global" large cardinal axioms

The terms "local" and "global" when applied to large cardinal axioms seem to have a well understood intuitive meaning, although a formalized definition of them in (a meta-language for)ZFC might be ...
Garabed Gulbenkian's user avatar
4 votes
1 answer
888 views

About the relationship between the generalized continuum hypothesis and the axiom of choice

I was trying to get a short, intuitive proof of Sierpinski’s theorem (gch implies axiom of choice) and I could but only by using the following gch2 for the generalized continuum hypothesis gch. gch: ...
M. Solomon's user avatar
4 votes
0 answers
297 views

Is there some absoluteness between the Boolean valued universe $V^{B}$ and $V$?

It is well known that if $\phi$ is a $\Delta_{1}$-formula and $x_{1},..,x_{n}$ in $V$ and $V[G]$ is a forcing extension, then $V\models\phi(x_{1},...,x_{n})$ if and only if $V[G]\models\phi(x_{1},...,...
Joseph Van Name's user avatar
4 votes
1 answer
556 views

the choice of representing formulas and Gödel's second incompleteness theorem

In Rautenberg's book (A Concise Introduction to Mathematical Logic, Universitext, Springer 2006), Gödel's second incompleteness theorem is stated: Theorem 3.2 (Second incompleteness theorem). PA ...
user40921's user avatar
  • 143
4 votes
2 answers
448 views

Number of torsion-free abelian groups

Let $\mathfrak{c}$ be the cardinality of the continuum. How much Choice, if any, is needed to prove that there are $2^{\mathfrak{c}}$ distinct (mutually nonisomorphic) torsion-free abelian groups of ...
Bruce Blackadar's user avatar
4 votes
2 answers
503 views

"Potentially club" filters on $\omega_2$

Short version: what can we say about subsets of $\omega_2$ which - in a generic extension where $\omega_2$ is the new $\omega_1$ - contain a club? We could of course generalize beyond $\omega_2$, but ...
Noah Schweber's user avatar

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