Skip to main content

All Questions

Filter by
Sorted by
Tagged with
6 votes
0 answers
293 views

Representation-finiteness vs. $\tau$-tilting-finiteness

Setting: Throughout, $\Lambda$ is a finite dimensional associative algebra, $\operatorname{mod} \Lambda$ is the category of all finitely generated left $\Lambda$-modules, and all subcategories are ...
5 votes
1 answer
365 views

2TQFT and commutative Frobenius algebras

There is an equivalence between the category of commutative finite dimensional Frobenius algebras and 2 dimensional topological quantum field theories, see for example the book by Joachim Kock, which ...
4 votes
0 answers
273 views

Question on Han's conjecture

Let $A$ be a finite dimensional algebra with enveloping algebra $A^e$. A conjecture of Han states that the Hochschild homology $Tor_{A^e}^n(A,A) \cong DExt_{A^e}^n(A,D(A))$ is nonzero infinitely often ...
1 vote
0 answers
361 views

Property of the syzygy functor of $\operatorname{\underline{mod}} A$

Let $A$ be an artin algebra. We denote by $\operatorname{mod}A$ the category of finitely generated left $A$-modules. We denote by $[A]$ the ideal of morphisms between $A$-modules which factor through ...
2 votes
1 answer
207 views

Question on Ext for finite dimensional algebras

Given a finite dimensional non-Gorenstein algebra $A$, do we have $Ext^i(D(A),A) \neq 0$ for infinitely many $i$? (We can assume A is local or commutative if that helps). All I can show is that such ...
2 votes
0 answers
135 views

Ext over a certain commutative algebra

Let $A$ be the algebra $K[x,y]/(x^2,y^2,xy,yx)$. Then $A$ is a 3-dimensional commutative algebra and $Ext^i(M,A) \neq 0$ for any indecomposable non-projective module $M$ for some $i>0$. Namely: $...
1 vote
0 answers
63 views

Reference request for formula on global dimension

Given a finite dimensional algebra $A$ over an algebraically closed field $K$. Let $A^e=A^{op} \otimes_K A$ be the enveloping algebra of $A$. Who noted first that the global dimension of $A$ is equal ...
2 votes
0 answers
33 views

Bounds on global and dominant dimension of certain algebras

Algebras are always finite dimensional over a field $K$. Let $X_n$ be the set of representation-finite algebras over $K$ with $n$ simple modules. Define $g(X_n):= sup \{ gldim(A) | A \in X_n $ and $A$...
1 vote
0 answers
72 views

Question on Gorenstein projective modules

Call a finite dimensional algebra $A$ special in case the category of (finite dimensional) Gorenstein projective modules coincides with the category of finite dimensional modules $M$ such that $Ext^i(...
2 votes
0 answers
48 views

Special modules over symmetric algebras

Let $A$ be a symmetric connected finite dimensional algebra over a field $k$. Call a tuple of two modules $(X,M)$ (having no projective direct summands) cute in case $Ext^l(X,M) \neq 0$ for some $l \...
3 votes
0 answers
81 views

Number of generalised tilting modules

This question is a modification of Number of tilting modules and was suggested by a comment of Dag Madsen. I wondered about this question too some time ago, but did not do much with it since my ...
1 vote
1 answer
207 views

Tensor product of finite global dimension algebras

Given two finite dimensional connected algebras A and B over a field $K$ with finite global dimension. Their tensor product is not necessarily of finite global dimension when the field is not ...
3 votes
0 answers
417 views

Finitistic dimension of an algebra

The finitistic dimension of an algebra is defined as the supremum of all projective dimensions of modules having finite projective dimension. (we look here only at finite dimensional modules). It is ...
2 votes
0 answers
81 views

Characterisation of Frobenius algebras via sequences

Given a commutative Frobenius algebra, finite dimensional over a field $k$. We assume that the algebra is connected and in fact given by quiver and relations. Let $S$ be the unique simple modules of ...
6 votes
1 answer
505 views

Global dimension of quiver algebra

Given a representation-finite (finite dimensional over a field) quiver algebra of finite global dimension. Is $eAe$ isomorphic to the field for at least one primitive idempotent $e$? This is true for ...
2 votes
1 answer
77 views

Complexity one modules that are not periodic

Questions: Is there a module of complexity one that is not periodic over a selfinjective algebra over a finite field? Is there a module of complexity one that is not periodic over a symmetric algebra ...
15 votes
1 answer
961 views

Who conjectured the Cartan determinant conjecture

The Cartan determinant conjecture states that every finite dimensional algebra of finite global dimension has the property that the determinant of its Cartan matrix is equal to one. Who stated this ...
2 votes
0 answers
191 views

Global dimension of quiver algebras

Given a finite quiver $Q$, let $Y(Q)$ be the set of (isomorphism classes of) algebra $kQ/I$ (with admissible ideal $I$) that have finite global dimension. For example in case $Q$ is acyclic, all ...
0 votes
1 answer
153 views

Strange modules part II

Let $A$ be a finite dimensional symmetric algebra over a field (we can also assume that it is connected). Call a non-projective indecomposable module $M$ strange in case $Ext^i(M,M)=0$ for all but ...
3 votes
0 answers
111 views

Strange modules over symmetric algebras

Let $A$ be a symmetric algebra (finite dimensional and connected) and define $\psi_M:=sup \{ i \geq 1 | Ext^{i}(M,M) \neq 0 \}$ (infinite if this Ext is nonzero infinitely often) for an indecomposable ...
2 votes
0 answers
86 views

Testing the Cartan determinant conjecture via Gorenstein algebras

Let $A$ be a Gorenstein algebra (of infinite global dimension) with finitely many indecomposable Gorenstein projective modules and $X$ the basic direct sum of all indecomposable Gorenstein projective ...
1 vote
0 answers
68 views

Ext in Gorenstein algebras

My computer suggests that the following is true for Nakayama algebra (it also found not counterexample for arbitrary algebras): Let $A$ be an algebra of finite Gorenstein dimension $g \geq 1$, then ...
5 votes
1 answer
577 views

When is the category of Gorenstein projective $R$-modules Frobenius?

Let $R$ be a ring (associative with unit, but not necessarily commutative, and definitely not necessarily Noetherian.) Then the category $\operatorname{GP}(R)$ consists of those $R$-modules having a ...
6 votes
1 answer
448 views

Hochschild cohomology of certain local algebras

Let $K$ be a field and $A$ the algebra $K\langle x_1,...,x_n\rangle/J^m$ for $n \geq 1$ and $m \geq 2$, where $K\langle x_1,...,x_n\rangle$ is the non-commutative polynomial ring in $n$ variables over ...
3 votes
0 answers
144 views

Computation of nearby cycles, monodromy action and action of $sl_{2}$ on $\operatorname{gr}(Ψ)$ for Picard-Lefshetz family

Let $f: \mathbb{A}^{2} \rightarrow \mathbb{A}^{1}$ be a map that sends $(x,y)$ to $xy$. Let $U \hookrightarrow \mathbb{A}^{2}$ be the preimage $f^{-1}(\mathbb{A}^{2} \setminus \{0\})$ and $X:=f^{−1}(0)...
1 vote
0 answers
46 views

Ext in selfinjective algebras

Is there a selfinjective finite dimensional algebra $A$ with a non-projective module $M$ such that $Ext^{i}(M,M)=0$ for all $i=1,2,...,2n-1$ when $n$ denotes the number of simple module of that ...
3 votes
0 answers
197 views

Questions on syzygies and Gorenstein algebras

Questions are about this paper: http://users.uoi.gr/abeligia/gorenstein.pdf and all algebras are finite dimensional Question 1: In corollary 6.21 (2) there is a proof of the direction (e) implies (a):...
3 votes
0 answers
60 views

Number of syzygy closed Nakayama algebras

Let $A$ be the algebra of $n \times n$ upper triangular matrices over a field $K$ and $J$ its Jacobson radical. Call an ideal $I$ of $A$ admissible in case $I \subseteq J^2$. Let $X$ be the set of ...
3 votes
1 answer
354 views

Who are the compact generators in the derived category of $\mathcal{D}_X$-modules?

Let $X$ be a smooth affine variety over $\mathbb{C}$ and let $\mathcal{D}_X$ be its algebra of differential operators. Consider $\mathcal{C}=\mathcal{D}_X$-$\text{mod}$, the stable $\infty$ category ...
1 vote
0 answers
71 views

Non-Gorenstein projective maximal Cohen-Macaulay module

In http://s.web.umkc.edu/segal/papers/refl.pdf the authors gave the first example of a maximal Cohen-Macaulay module $M$ (that is a module over an algebra A with $Ext^{i}(M,A)=0$ for all $i \geq 1$) ...
2 votes
1 answer
257 views

First Hochschild cohomology of $A=K[x]/(x^n)$

Given the algebra $A=K[x]/(x^n)$ for some field $K$ and natural number $n \geq 2$ with enveloping algebra $A^e=A \otimes_K A$. It is easy to see that the 1. Hochschild cohomology of $A$ is nonzero ...
0 votes
1 answer
98 views

Algebra with all modules non-rigid 2

Given a finite dimensional connected algebra $A$ with $Ext^{1}(M,M) \neq 0$ for any non-projective and non-injective indecomposable module $M$, with the condition that at least one such module exists....
1 vote
1 answer
133 views

Algebra with all modules non-rigid

Given a finite dimensional connected algebra $A$ with $Ext^{1}(M,M) \neq 0$ for any non-projective and non-injective module $M$. Is $A$ selfinjective? Is $A$ local?
5 votes
2 answers
224 views

Properties of right rejective subcategories

I am reading this paper finiteness of representation dimension, on page 1012 there is a place I don't understand: Why $\mathcal{C}(, \mathbb{F}(X)) \rightarrow [\mathcal{C'}](,X)$ is an isomorphism? ...
4 votes
0 answers
127 views

Injective dimension is infinite?

Let $A$ be a non-selfinjective finite dimensional algebra and $M$ a nonprojective module with $Ext^{i}(M,A)=0$ for all $i \geq 1$. It is easy to see that $M$ has infinite projective dimension. Does $M$...
9 votes
1 answer
736 views

Strange boundary-like map on tensor algebra: what is its kernel?

Let $k$ be a commutative ring and $L$ a $k$-module. The tensor algebra $\otimes L$ is $\mathbb{Z}$-graded and $\mathbb{Z}_2$-graded (an element of $L^{\otimes n}$ has degree $n$ and $\mathbb{Z}_2$-...
7 votes
0 answers
433 views

What is the endomorphism cooperad?

In Loday and Vallette's book on algebraic operads, they use the "Endomorphism cooperad $End^c_{s\mathbb{K}}$", where $s\mathbb{K}$ is the base field, shifted into (homological) degree one. This is an ...
5 votes
1 answer
261 views

Some questions on division algebras

Given a field $K$, is there a finite dimensional quiver algebra, such that any finite dimensional division algebra is isomorphic to End(M)/rad(End(M)) for some indecomposable finite dimensional module ...
2 votes
0 answers
102 views

Ext in a selfinjective algebra

Given a finite dimensional selfinjective algebra $A$ and an indecomposable module $M$, which is not projective. Let $v=DHom(-,A)$ be the Nakayama functor. In case $Ext^{i}(v(M),M) \neq 0$ for some i, ...
4 votes
1 answer
423 views

Alternating sum of symmetric and exterior powers vanishes

Let $V$ be a vector space with some extra structure (maybe to be general, an object of an abelian tensor category?), where we can form tensor products and exterior powers $\Lambda^i V$ and symmetric ...
0 votes
0 answers
112 views

Some places I can't understand in the paper "Gendo-symmetric algebras, dominant dimensions and Gorenstein homological algebra"

I am reading the paper "Gendo-symmetric algebras, dominant dimensions and Gorenstein homological algebra", the link is here: https://arxiv.org/pdf/1608.04212.pdf There are some places I can't ...
5 votes
0 answers
120 views

Ext$^1(D(A),A)$ for hereditary algebras

Let $A$ be a hereditary (non-semisimple) finite-dimensional algebra over a field $K$. Let $M:={\rm Ext}^{1}_A(D(A),A)$ ($ \cong D(\tau((D(A)))$ as left modules) and let $A^e$ be the enveloping algebra ...
2 votes
1 answer
119 views

How to get that $\Omega^2_{\Lambda}(N) \cong \textrm{Hom}_A(M,Y)$?

Let $A$ be an algebra over a field k. A module $_AM$ is called a generator if $\textrm{add}(A) \subseteq \textrm{add}(M)$, a cogenerator if $\textrm{add}\big(D(A)\big) \subseteq \textrm{add}(M)$. $M$ ...
2 votes
1 answer
959 views

homology under exact functors

Let $\mathcal{A}$ be an Abelian category, $X$ be a complex, $F$ be a contravariant exact functor. I am wondering whether F preserves the homology of X, that means whether $H^{i}(FX)=F(H^{-i}(X)),\ \...
1 vote
1 answer
158 views

How to get that one module is tilting iff the other one is?

Let $A$ be an algebra over a field k. $D$ is the standard duality functor. A module $_AM$ is called a generator if $add(A) \subseteq add(M)$, a cogenerator if $add(D(A)) \subseteq add(M)$. $M$ is n-...
5 votes
0 answers
303 views

Recovering an A-infinity structure on an Ext-algebra from a quiver presentation

Let $A=KQ/I$ be a basic finite dimensional algebra given by a quiver with relations. Let $S$ denote the direct sum of the corresponding simple modules. According to [Keller: A-infinity algebras in ...
1 vote
2 answers
157 views

On some modules with bounded syzygies

Let A be a finite dimensional algebra. Call an indecomposable module M cool in case $\Omega^{i}(M)$ is nonzero and indecomposable for every $i \geq 1$ and $dim(\Omega^{i}(M))$ is bounded. Questions: ...
2 votes
0 answers
148 views

Algebras where all indecomposable modules are rigid

Is there a classification of selfinjective algebras having $Ext^{1}(X,X)=0$ for every indecomposable module X? Examples include trivial extensions of representation-finite hereditary algebras. One ...
5 votes
1 answer
374 views

Tachikawa conjecture for commutative algebras proven?

The Tachikawa conjecture states that $Ext^i(M,M) \neq 0$ for some $i \geq 1$ for every non-projective module $M$ over a selfinjective finite dimensional algebra. In theorem 4.6. of http://maths.nju....
3 votes
0 answers
205 views

Finitistic dimension via tilting modules

is the following true (all algebras and modules are assumed to be finite dimensional): The finitistic dimension of an algebra is equal to the supremum of projective dimensions of tilting modules? It ...

1
6 7
8
9 10