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5 votes
1 answer
145 views

Mathematical strength of the statement "Heyting Arithmetic admits Markov's rule"

Consider the following theorem about Heyting arithmetic (HA): For every arithmetical formula $\phi$ whose only free variable is $n$, if $\text{HA} \vdash \forall n. \phi \lor \lnot \phi$ and $\text{...
Christopher King's user avatar
12 votes
0 answers
250 views
+50

Is there a decidable theory of arithmetic with a non-collapsing quantifier hierarchy?

This question is very close to this old MSE question of mine, which is still unanswered. Is there an (ideally reasonably-natural!) expansion of the structure $(\mathbb{N};+)$ in a finite language ...
Noah Schweber's user avatar
5 votes
1 answer
371 views

Are PA and Counting Theory synonymous\bi-interpretable?

The following question is whether $\sf PA$ is synonymous or even bi-interpretable with a theory about counting objects in finite sets. Counting Theory: $\textbf{Logic:}$ Bi-sorted first order logic ...
Zuhair Al-Johar's user avatar
-2 votes
1 answer
211 views

Can this theory interpret Peano arithmetic?

Logic: Bi-sorted first order logic with equality, first sort written in lower case range over natural numbers, the second sort written in upper case range over sets of naturals, "$=$" has no ...
Zuhair Al-Johar's user avatar
1 vote
0 answers
91 views

About synonymy relationships around these two theories?

The following question is about patterns of synonymy relationships around two theories, $T^+$ and $\sf PA$. For purposes of self inclusiveness I'll re-iterate $T$ and its extensions. $\textbf{Logic:}$ ...
Zuhair Al-Johar's user avatar
-4 votes
1 answer
173 views

To which arithmetic\set theory this theory is bi-interpretable?

$\textbf{Logic:}$ Mono-sorted first order logic with equality. $\textbf{Extralogical Primitives: } <, \in$ $ \textbf{Axioms:}$ $ \textbf{Order:} \ x < y < z \to x < z $ $ \textbf{...
Zuhair Al-Johar's user avatar
-4 votes
0 answers
135 views

Which arithmetic\set theory is synonymous with this theory?

$\textbf{Logic:}$ Mono-sorted first order logic with equality. $\textbf{Extralogical Primitives: } <, \in$ Define: $x > y \iff y < x$ Define: $x \leq y \iff x < y \lor x=y$ $ \textbf{...
Zuhair Al-Johar's user avatar
12 votes
4 answers
1k views

Is this theory synonymous with PA?

Language: Mono-sorted first order logic with equality. Extralogical Primitives: $<, \in$ Define: $x \leq y \iff x < y \lor x=y$ $\textbf{Well ordering: }\\\textit{Transitive:} \ x < y \land ...
Zuhair Al-Johar's user avatar
23 votes
1 answer
3k views

What is known about the theory of natural numbers with only 0, successor and max?

Consider the first-order theory whose intended/standard model is the natural numbers $\mathbb{N}$, with constant $0\in \mathbb{N}$, with an injective successor operation $s$ such that $0$ is not a ...
David Roberts's user avatar
  • 35.5k
6 votes
1 answer
197 views

Is there a 1-generic degree g such that Th(D(< g)) is more complicated than true arithmetic?

I am currently reading an article titled "Embedding and Coding Below a 1-Generic Degree" by Greenberg and Montalbán(link to a free source:https://pi.math.cornell.edu/~erlkonig/Papers/...
H.C Manu's user avatar
  • 893
6 votes
1 answer
743 views

Which part(s) of this proof of Goodstein's Theorem are not expressible in Peano arithmetic?

EDIT: Noah Schweber helpfully points out that $\mathsf{ACA}_0$ is a conservative extension of Peano arithmetic in which certain aspects of my proof not expressible in Peano arithmetic are expressible. ...
Julian Newman's user avatar
1 vote
2 answers
340 views

Heuristic interpretations of the PA-unprovability of Goodstein's Theorem

I've relatively recently learned about Goodstein's Theorem and its unprovability in Peano arithmetic (the Kirby-Paris Theorem). I do not have any real knowledge of formal logic; but I think I've seen ...
Julian Newman's user avatar
1 vote
1 answer
180 views

Natural functions outside $\sf PA$?

Can theories stronger than $\sf PA$ manage to define functions from the naturals to the naturals, that $\sf PA$ cannot? If so, what are examples of those functions?
Zuhair Al-Johar's user avatar
1 vote
1 answer
146 views

Can PA define functions related to higher theories?

Working in $\sf ZFC$ we can define a function $F$ from naturals to naturals such that $F(0) = \, ^\circ\ulcorner r({\sf Z}) \urcorner$, where $r({\sf Z})$ is the Rosser sentence of Zermelo set theory $...
Zuhair Al-Johar's user avatar
7 votes
1 answer
334 views

Why include $0$ and $1$ in the signature of Presburger arithmetic?

I recently became interested in some problems concerning decidability of extensions of Presburger arithmetic. However, being a number-theorist rather than a logician, I am confused by some notational ...
Jakub Konieczny's user avatar
2 votes
1 answer
154 views

The Dirichlet principle and arithmetical induction

Let us consider the Dirichlet principle as follows: for all natural numbers $n > k > 0$, there is no injection from $\{0, \dots, n-1\}$ into $\{0, \dots, k-1\}$. Is it true that in some non-...
Nikolay Kazimirov's user avatar
2 votes
0 answers
100 views

Realizing arithmetic hierarchy in algebraic number theory

Is it possible to realize arithmetic hierarchy in algebraic number theory? For example, consider a $\Pi^0_4$ statement of the form $\forall x \exists y \forall z \exists w \phi(x,y,z,w)=0$ where $\phi$...
0x11111's user avatar
  • 593
15 votes
5 answers
3k views

How is it possible for PA+¬Con(PA) to be consistent?

I'm having some trouble understanding how a certain first-order theory isn't just straight-up inconsistent. Let $PA$ be the axioms of (first-order) Peano arithmetic and let $C$ be the following ...
E8 Heterotic's user avatar
15 votes
5 answers
2k views

In what sense does the sentence $\operatorname{con}(\mathsf{PA})$ "say" that $\mathsf{PA}$ is consistent?

It seems common amongst logicians to think of "truth" as being relative to a particular structure. Consider, for instance, the first-order theory of groups. The sentence $\forall x\forall y(...
Joe Lamond's user avatar
4 votes
1 answer
269 views

Does Peano's axioms prove $\alpha$-induction for primitive recursive sequences for every concrete $\alpha < \varepsilon_0$?

It is well-known that Peano's axioms (PA) cannot prove $\varepsilon_0$-induction for primitive recursive sequences (PRWO($\varepsilon_0$)), because PA + PRWO($\varepsilon_0$) proves the consistency of ...
Imperishable Night's user avatar
7 votes
4 answers
574 views

A conservative extension of Peano Arithmetic

Ulrich Kohlenbach makes the following intriguing comment here: "In the 70s S. Feferman introduced a mathematically strong system S=restricted(PA^omega)+QF-AC+mu for classical mathematics (and in ...
Mikhail Katz's user avatar
  • 16.6k
4 votes
1 answer
193 views

Further research on relevant realizability etc

I just read Dunn's 1979 paper Relevant Robinson's Arithmetic, and the end especially caught my interest. Following the surprising role of constant functions in collapsing "relevant Q with zero&...
Noah Schweber's user avatar
14 votes
1 answer
526 views

Is there a theory between HA and PA that doesn't have Markov's rule?

A theory $T$ admits Markov's rule when For every formula $\phi(n)$, if $$T \vdash \forall n \in \mathbb N. \phi(n) \lor \lnot \phi(n)$$ and $$T \vdash \lnot \lnot \exists n \in \mathbb N. \phi(n)$$ ...
Christopher King's user avatar
5 votes
0 answers
109 views

Computational complexity of arithmetic sentences over classical theories

Below, I use the term "tracker" rather than "realizer" since I'm not requiring the relevant objects to be computable. Define the relation "$f$ tracks $\varphi$" for $f:\...
Noah Schweber's user avatar
5 votes
2 answers
433 views

Models of second-order arithmetic closed under relative constructibility

I know little to nothing about second-order arithmetic and its subsystems. However, I would like to understand when a model of (a subsystem of) second-order arithmetic ($\mathsf{Z}_2$) is downward ...
Lorenzo's user avatar
  • 2,286
4 votes
1 answer
515 views

Truth Values of Statements in non-standard models

Excuse me, if the question sounds too naive. Non-standard models of PA will have statements of non-standard lengths, basically infinite. And it is also true that every statement of a theory will have ...
Amiren's user avatar
  • 1
8 votes
1 answer
588 views

Con(PA) via non-well-foundedness?

Lumsdaine made the following interesting comment: if Con(PA) fails in a non-standard model, it means it contains a “proof of non-standard length” of a contradiction from PA. With a little work, one ...
Mikhail Katz's user avatar
  • 16.6k
4 votes
1 answer
155 views

Does this hierarchy of fragments of $I \Sigma_1$ collapse?

Does anyone know whether the following hierarchy of fragments of $\mathrm{I} \Sigma_1$ (or rather $\mathrm{I} \Pi_1$) collapses or not? Let $\Sigma^b_n$ denote formulas in the language of arithmetic ...
Lukas Holter Melgaard's user avatar
1 vote
0 answers
123 views

Is possibile to define transfinite sum and product recursively? [closed]

On mathstackexchange a few days ago I published the following question where I asked about "transfinite" sum and products but actually nobody answered or gave an opinion with a comment: thus ...
Antonio Maria Di Mauro's user avatar
14 votes
1 answer
646 views

Extensions of $PA+\neg Con(PA)$ with large consistency strength

There is a large hierarchy of theories strengthening $PA$ eg $PA+Con(PA)$, $PA+Con(PA+Con(PA))$,..., second-order arithmetic and $ZFC$, ordered by consistency strength. Is there an extension of $PA+\...
Tom Bouley's user avatar
3 votes
1 answer
135 views

$\Pi^0_1$ sentences modulo "schematic entailment"

Let $\mathfrak{P}$ be the preorder of $\Delta^0_0$ (= only bounded quantifiers) formulas with one free variable in the language of arithmetic, under the relation $\alpha(x)\le\beta(x)$ iff there is a ...
Noah Schweber's user avatar
4 votes
1 answer
258 views

What is the theory of statements with a provably *bounded* realizer (according to PA)?

$\let\T\mathrm\def\kr{\mathrel{\mathbf r}}$This is a follow up to Kleene realizability in Peano arithmetic. We can summarize the results from Emil Jeřábek's answer as follows: \begin{gather*} T_1 = \{ ...
Christopher King's user avatar
10 votes
2 answers
436 views

The additive structure of clusters of nonstandard models of arithmetic

Given $\frak M$ a countable nonstandard model of $\sf PA$ and let $a\in M$ be a nonstandard element. A "cluster around $a$" is the set of successors and predecessors of $a$, a cluster is a ...
Holo's user avatar
  • 1,676
29 votes
10 answers
4k views

Defining the standard model of PA so that a space alien could understand

First, some context. In one of the comments to an answer to the recent question Why not adopt the constructibility axiom V=L? I was directed to some papers of Nik Weaver at this link, on ...
Pace Nielsen's user avatar
  • 18.7k
10 votes
5 answers
2k views

What is the canonical way to extend Peano's axioms to the set of all integers?

My first idea on how to do this would be: $0\in\mathbf Z$ $\forall x\in\mathbf Z,Sx\in\mathbf Z\land Px\in\mathbf Z$ $P$ and $S$ are injective $\forall x\in\mathbf Z,PSx=SPx=x$ some induction axiom ...
user avatar
1 vote
1 answer
313 views

What is the set theory synonymous with this order-set theory?

Let $ T$ be a theory written in Mono-sorted first order logic with equality, with extralogical primitives: $<, \in$. Define: $x \leq y \iff x < y \lor x=y$ Axioms: $\textbf{Well ordering: }\\\...
Zuhair Al-Johar's user avatar
32 votes
2 answers
3k views

Do we expect that sufficiently large computable ordinals settle every question of arithmetic?

I came across a post by Ron Maimon on physics.SE that makes what seems to me to be a very interesting conjecture I've never seen before about what it would take to settle every question of arithmetic. ...
Qiaochu Yuan's user avatar
2 votes
0 answers
192 views

Can PA be acyclically complete?

Any formula $\phi$ in the first order language of arithmetic is to be called acyclic if and only if we can associate with it an acyclic undirected graph whose nodes are the variable symbols occurring ...
Zuhair Al-Johar's user avatar
3 votes
1 answer
169 views

Would this alteration of $T$ affect its synonymy with PA?

If we replace the single axiom "Emergence" in the axiomatic system $T$ presented at posting [What is the set theory synonymous with this order-set theory], by the following schema. Would the ...
Zuhair Al-Johar's user avatar
1 vote
1 answer
221 views

Seeking clarification of ultrapower nonstandard model of arithmetic

I've read that one nonstandard model of arithmetic is: take $\mathbb{N}^\mathbb{N}$, the set of countably infinite sequences of natural numbers take a quotent that gives the ultrapower: identify ...
Dave Pritchard's user avatar
-2 votes
1 answer
416 views

Defining the set of natural numbers in the first order Peano arithmetic [closed]

The question seems simple, but I'm not sure: let's consider a first order Peano Arithmetic and its standard model $N = \{ 0,1,2,3,... \}$ of natural numbers. A question: how can we define the whole ...
Viipuri's user avatar
  • 19
-3 votes
1 answer
638 views

Analysis I, simpler proof of Tao's construction of the integers [closed]

In chapter 4 of Analysis I by Terence Tao, we have the following note about the set theoretic construction of the integers: In the language of set theory, what we are doing here is starting with the ...
HJE's user avatar
  • 23
33 votes
2 answers
3k views

Can we interpret arithmetic in set theory, with exactly PA as the ZFC provable consequences?

There are many interpretations of arithmetic in set theory. The Zermelo interpretation, for example, begins with the empty set and applies the singleton operator as successor: $$0=\{\ \}$$ $$1=\{0\}$$ ...
Joel David Hamkins's user avatar
8 votes
3 answers
1k views

Dedekind-Peano axioms, but numbers have at most one successor

One can consider a variant of the Dedekind-Peano axioms in which one replaces the assumption that every number has exactly one successor by the assumption that every number has at most one successor, ...
James Propp's user avatar
  • 19.7k
11 votes
2 answers
379 views

Can singular long models require less than PA?

Say that a long model is an $\mathfrak{A}\models\mathsf{I\Sigma_1}$ such that $\mathfrak{A}$ has strictly greater cardinality than each of its proper initial segments (in the case $\vert\mathfrak{A}\...
Noah Schweber's user avatar
10 votes
2 answers
600 views

Is diamond consistent with 2nd order PA?

If $T$ is a theorem of ZF which says something only about reals, then one may want to prove $T$ using a theory like 2nd order PA or related theories like ZFC$^-$ or GBC$^-$ (minus accounts for the ...
Vladimir Kanovei's user avatar
12 votes
1 answer
482 views

Is there a useful measure of density of decidable sentences in PA?

Essential undecidability of PA says every complete extension of PA includes a non r.e. set of new "axioms," all undecidable in PA.  In that sense lots of sentences of PA are undecidable in ...
Colin McLarty's user avatar
-2 votes
1 answer
211 views

Would this alteration safeguard the resulting theory from inconsistency?

If we replace "Emergence" axiom in the theory $T$ presented at posting "What is the set theory synonymous with this order-set theory?" with the following axiom, call the resulting ...
Zuhair Al-Johar's user avatar
2 votes
1 answer
329 views

Can set theory be interpreted in infinite arithmetic?

Is the following system of infinite arithmetic consistent? If so, can it interpret $\sf ZFC$? Language: first order logic Primitives: $\operatorname{Card}, <, + , \times,\text{^}$ where $\...
Zuhair Al-Johar's user avatar
3 votes
1 answer
123 views

Kleene normal form theorem for r.e. relations proven in arithmetical theories

After reading the relevant chapters of Classical Recursion Theory (freely available from here), I have the following questions concerning Theorem II.1.10 (Normal form theorem) and Theorem IV.1.9 (...
CBuch's user avatar
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