Skip to main content

All Questions

Filter by
Sorted by
Tagged with
2 votes
0 answers
224 views

$(\mathfrak{g},K)$-modules and parabolic category $\mathcal{O}$

I am trying to get acquainted with various infinite dimensional representations of Lie groups. So a general reference would be appreciated. Right now I am trying to figure out the following question. ...
Vít Tuček's user avatar
  • 8,597
12 votes
0 answers
716 views

Lifting abelian varieties in (the closed fiber of) a fixed Neron model

Suppose that $R$ is a dvr with field of fractions $K$ and residue field $k$ and that $A_K$ is an abelian variety over $K$ with Neron model $A$ over $R$. Then the closed fiber $A_k$ is a smooth ...
B. Cais's user avatar
  • 1,609
3 votes
0 answers
234 views

Generators and relations for the enveloping algebra of a unipotent radical

Let $G$ be a semisimple algebraic group over an algebraically closed field $k$ of characteristic 0 and let $B \subseteq G$ be a Borel subgroup with unipotent radical $U$. Let $P \supseteq B$ be a ...
Chuck Hague's user avatar
  • 3,637
0 votes
0 answers
352 views

Liftability in positive characteristic

What clsses of algebraic varieties over field of positive characteristic can be lift to $W_2(k)$?
Universe's user avatar
3 votes
0 answers
359 views

Does Branching in the Weight Diagram affect an embedding?

All groups here are compact semisimple Lie groups. Out of laziness I will use $B_7$ to mean $Spin(15)$. Suppose that one has a group $H$ and a subgroup $G$. The embedding determines the decomposition ...
ARupinski's user avatar
  • 5,191
0 votes
1 answer
175 views

An inseparable lift of a regular variety.

Let $X$ be a variety over an (imperfect) field $k$, that is regular as a scheme. Let $k'/k$ be an algebraic inseparable extension (I am interested in $k'$ being the perfection or the algebraic closure ...
Mikhail Bondarko's user avatar
4 votes
1 answer
270 views

Invariant forms

Is there a classification of pairs $(\mathfrak g,V)$, with $\mathfrak g$ a Lie algebra and $V$ a $\mathfrak g$-module, such that $(\Lambda^3V)^{\mathfrak g}\neq0$?
Mariano Suárez-Álvarez's user avatar
6 votes
0 answers
524 views

Approximating the radical of a Lie algebra by Killing radicals

The following question might be filed under "idle curiosity", but I'm hoping some expert on Lie algebras can answer it. Background One of the fundamental structural results about Lie algebras is the ...
José Figueroa-O'Farrill's user avatar
3 votes
0 answers
281 views

What would be a characteristic-$p$ analogue for $C^{\infty}$-fiber bundles?

I'd like to know a notion for a morphism between algebraic varieties in characteristic $p$ that plays the role of a $C^{\infty}$-fiber bundle. It should be, in particular, flat. I'm not assuming the ...
shenghao's user avatar
  • 4,265
1 vote
0 answers
189 views

Exotic Chains for Group Homology of a Complex Lie Group

Related Question: Exotic Chains for Group Cohomology of a Complex Lie Group Let's take the group homology of a affine algebraic group over $\mathbb C$ (with its discrete topology). The natural free ...
John Pardon's user avatar
  • 18.7k
4 votes
0 answers
184 views

Exotic Chains for Group Cohomology of a Complex Lie Group

Related Question: Exotic Chains for Group Homology of a Complex Lie Group Let's take the group cohomology of a affine algebraic group over $\mathbb C$ (with its discrete topology). The natural free ...
John Pardon's user avatar
  • 18.7k
4 votes
0 answers
537 views

Working with quadratic Lie algebras

A quadratic Lie algebra is a Lie algebra with an invariant inner product and the main examples are semisimple Lie algebras. This definition then makes sense in any linear symmetric monoidal category. ...
Bruce Westbury's user avatar
4 votes
0 answers
534 views

Why are Lie Algebras/ Lie Groups so much like crossed modules, and not?

A crossed module consists of a pair of groups $G$ and $H$ with a group homomorphism, $t:H \rightarrow G$, and $\alpha: G \times H \rightarrow H$ that defines an action of $G$ on $H$, $\tilde{\alpha}$: ...
Scott Carter's user avatar
  • 5,264
4 votes
1 answer
282 views

Adjoint orbits of small subspaces in Lie algebras

I've been studying isometric quotients (by compact Lie groups) of compact simply connected homogeneous spaces $G/H$ and their inherited curvature. One of the issues that continually arises is the ...
Jason DeVito - on hiatus's user avatar
1 vote
0 answers
75 views

Is it possible to compute the Iwahori Decomposition using the Chavalley Commutator Formulas?

Ideally, I would like a constructive, algorithmic proof of this fact. I have convinced myself that it is true, but my "proof" is not pretty. I would like to know if a more attractive or intuitive ...
Nitalynn's user avatar
7 votes
0 answers
491 views

Alterations of regular varieties

Let $X$ be a regular quasi-projective variety over a perfect field $k$. The existence of a "good compactification" of $X$, i.e. a regular projective variety $\bar{X}$ with an embedding $X\...
Lars's user avatar
  • 4,450
3 votes
1 answer
121 views

Lower bound on the degree of a product of elements in a hyperalgebra/enveloping algebra

Background: Fix a linear algebraic group $G$ over an algebraically closed field $k$ of arbitrary characteristic and let $B \subseteq G$ be a Borel subgroup with unipotent radical $N$. Let $\Delta^+$ ...
Chuck Hague's user avatar
  • 3,637
1 vote
0 answers
269 views

exactness of n homology functor

Let $G$ be a real reductive group, $P=MN$ a parabolic subgroup with its Levi decomposition, let $\mathfrak{n}$ be the nilpotent Lie algebra of $N$. Now given a smooth representation $(\pi,V)$ of $G$, ...
user1832's user avatar
  • 2,709
5 votes
0 answers
234 views

Modular reduction of exceptional complex reflection groups

I am interested in reducing reflection representations of complex reflection groups modulo a prime $p$. For the infinite family $G(m,r,n)$, it is straightforward to get "good reduction" provided that $...
Steven Sam's user avatar
  • 10.7k
3 votes
1 answer
139 views

What's the name of an algebra? is it isomorphic to $w_\infty \times w_\infty$?

Just as we know, $w_\infty$:=span {${z^\alpha }\partial _z^\beta|\alpha,\beta\in\mathbb{Z}, \beta\geq0$ }. But, what's the name of the following algebra, span {$\{{z^{\alpha_1}}{y^{\alpha_2}}\partial ...
Jack Cheng's user avatar
3 votes
0 answers
487 views

Is the Cartan matrix a complete invariant of a Kac-Moody algebra?

In chapter 1 of Kac's book "Infinite dimensional Lie algebras" it is mentioned that two Kac-Moody algebras are isomorphic if and only if their Cartan matrices are isomorphic (i.e. they are the same up ...
user717's user avatar
  • 5,243
6 votes
0 answers
456 views

On periods of algebraic integers modulo rational primes

I run, somewhat indirectly, into the following problem and I have no hints where to look in the literature in search for answers or clues. Let $K$ be a number field, which we may assume Galois if it ...
Andrea Mori's user avatar
2 votes
0 answers
321 views

Dimension of fibres of moment maps in characteristic $p$

Suppose $G$ is a connected semisimple linear algebraic group with Lie algebra $\mathfrak{g}$ and $X$ is a homogeneous $G$-space with isotropy subgroup $H$ (associated Lie algebra $\mathfrak{h}$) that ...
Simon Wadsley's user avatar
0 votes
0 answers
289 views

Good and/or standard notation for the abelianization of a Lie algebra

I'd like to solicit good notations for the abelianization of a Lie algebra $\mathfrak g$. One could write $\mathfrak g/[\mathfrak g,\mathfrak g]$, or even $H_1(\mathfrak g)$ but I'd like something ...
Jim Conant's user avatar
  • 4,898
0 votes
0 answers
105 views

approximation in Lie algebras

Let $x_{1}$, $x_{2}$, $x_{3}$ three disctinct closed points of a curve $X$ over an algebraically closed field k. Let G a connected reductive group and $\mathfrak{g}$ his Lie algebra. I fix a Borel $...
prochet's user avatar
  • 3,472
3 votes
0 answers
264 views

Is it possible to construct category $\mathcal{O}^{\mathfrak{p}}$ with non-standard parabolic subalgebra

The usual definition of the parabolic category $\mathcal{O}^{\mathfrak{p}}$ is the following. We consider Lie algebra $\mathfrak{g}$ of the rank $r$ with the root system $\Delta$ and the set of ...
Anton Nazarov's user avatar
4 votes
0 answers
287 views

Characters of Kac-Moody algebra from orbifold

In a Wess–Zumino–Witten model on some Lie group G, the character of a particular integrable representation is the same as the specialized character from the corresponding Kac-Moody algebra. Suppose ...
Moduli's user avatar
  • 248
3 votes
1 answer
298 views

In what way do exact sequences of Lie ideals integrate to the category of groups?

Please excuse, very naive question: Suppose $g$ is a topological Lie algebra over Q and $G$ = $exp(g)$ the associated group (take free group on formal symbols $exp(X)$, X $\in$ $G$, and impose all ...
dh35jvn's user avatar
  • 934
2 votes
1 answer
197 views

Polytopes related to the conjugation action of a Lie group on multiple copies of itself?

Let G be a finite dimensional real Lie group. As I understand it, the quotient space of G acting on itself by conjugation is a well studied polytope which can be identified with the fundamental alcove ...
Chris Schommer-Pries's user avatar
1 vote
0 answers
124 views

Approximated characters

Is it possible to construct series of groups $G_i, |G_i|\mapsto \infty$ and functions $f_i:G_i\mapsto$ {$ 1,0,-1$} such that $f_i(1)=0$, $f_i(g) \in ${$-1,1$} for $g\neq 1$ such that dimension of $C[...
Klim Efremenko's user avatar
0 votes
0 answers
23 views

Existence of a subregular element with abelian centralizer in a quadratic Lie algebra

All Lie algebras here will be finite dimensionnal complex Lie algebra. We say that such an Lie algebra $\mathfrak{g}$ is quadratic if there exist a skew-symetric, non-degenerate bilinear form or ...
Hugo MTV's user avatar
  • 188
0 votes
0 answers
61 views

Representation and Laplacian on the Heisenberg group

Let $\pi_{\lambda}$ be the the Schrödinger representations of the Heisenberg group $H=\mathbb C\times \mathbb R$. For $\varphi\in L^2(\mathbb R)$, we have $$\pi_{\lambda} (z,t)\varphi(\xi)=e^{i\...
Z. Alfata's user avatar
  • 650
0 votes
0 answers
90 views

Some details about Kirillov-Kostant Poisson bracket

Let $G$ be a finite dimensional Lie group with Lie algebra $\mathfrak{g}$. The Kirillov-Kostant Poisson bracket on $\mathfrak{g}^*$ is defined as $$\{\cdot ,\cdot \} :C^{\infty}(\mathfrak{g}^*)\times ...
Mahtab's user avatar
  • 287

1
49 50 51 52
53