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A Banach space is a complete normed vector space: A vector space equipped with a norm such that every Cauchy sequence converges.
10
votes
Dual space of $\ell^\infty$
Let's recall a simple, elementary, and general fact that hasn't been explicitly mentioned: a dual Banach space is always a splitting subspace in the isometric embedding into its double dual. So $\el …
1
vote
Accepted
Characterization of the dual of intersection of Banach spaces
In general, in order that the intersection be defined, we should assume that $(U,\|\cdot\|_U)$ and $(V,\|\cdot\|_V)$ are continuously embedded into an ambient Hausdorff TVS $E$. Then, $(U\cap V,\|\cdo …
5
votes
Accepted
Is the image of a complemented subspace complemented?
For a counterexample, let $Y$ be a Banach space with a closed, non-complemented subspace $Z\subset Y$. Consider the restriction of the sum operation ${\bf +}:Y\times Y\to Y$ to the space $X:=Y\times …
3
votes
Accepted
A variation of the Riesz Lemma
Let's denote $B$ the unit ball of $X$. Geometrically, we are asking if there is a line $\langle x\rangle$ such that the ball $\alpha B$ can be translated along $\langle x\rangle$ and pass through the …
3
votes
Using the Stone-Weierstrass theorem to solve an integral limit
I understand the aim is an elementary proof; here is one.
Let $\omega$ be a modulus of continuity for $f$ on $[0,c]$. Then, for all $0<t\le c-1$
$$\int_0^1|f(x+t)-f(x)|^2dx\le \omega(t)\int_0^1\big(f( …
1
vote
Density of the set of convex polygons in the Banach-Mazur distance
Let $U\subset \mathbb R^2$ be a bounded open convex neighborhood of $0$. For every $\epsilon>0$ we have $\displaystyle \overline U=\bigcap_{H\supset U\atop H \text{ closed half-plane}} H \subset (1+\e …
2
votes
When a quasinilpotent is nilpotent?
This is almost tautological, but suppose that the quasi-nilpotent operator $T$ has the property that, for some $p\in\mathbb N_+$, the equality $\|T^{np}\|=\|T^p\|^n$ holds for infinitely many $n\in\ma …
14
votes
Accepted
Question about Schauder bases in C([0,1]).
I would say, monomials are not a Schauder basis for $C[0,1]$ because functions that admits a representation are analytic functions on the unit disc. Actually, $f(t)=\sum_k a_k t^k$ immediately implie …
11
votes
Smooth Urysohn's lemma on Fréchet spaces
A bump function on a Banach space $X$ is a non-zero function with bounded support. Existence of a bump function of a given smooth regularity has, of course, strong immediate consequences --by translat …
2
votes
Extension Operator for $W^{1,\infty}(U,X)$
Say $I:=[a,b]$. We may extend $u$ simply putting it constant for $t\ge b$ and $t\le a$, that is $Eu(t):=u((t\vee a)\wedge b)$. This defines a norm-$1$ linear extensor $E$.
7
votes
Accepted
Is there a reflexive Banach space whose ball is not the convex hull of its extreme points?
I'd try $X:=\ell_2$ with an equivalent but non strictly convex norm.
Let $(e_k)_{k\ge0}$ be the standard Hilbert basis of $\ell_2$. Consider the sets:
$A:=\{0\}\cup\{2^{-k}e_k:k\ge 1\}$,
$B$, the …
5
votes
Accepted
Subspaces of $\ell_\infty^3$
A funny isometry invariant to distinguish these normed spaces is: The space of spheres of radius $2$ in the unit sphere of $(X,\|\cdot\|_X)$ which are maximal by inclusion, as described below. It turn …
3
votes
Direct limit of the sequence $E_{0} \hookrightarrow E_{1} \hookrightarrow \cdots$ in the cat...
The key point is "linear contraction" (which in this context I think means "operator norm not larger that $1$"). Let $(X,\|\;\|)$ be a Banach space and let $\{T_n:E_n\to X\}_{n\in\mathbb N}$ a famil …
5
votes
Accepted
Implicit function theorem with continuous dependence on parameter
Assuming $P$ first countable, the standard contraction principle and elementary bounds are sufficient to conclude. You do not need higher regularity:
Let $X$, $Y$ be Banach spaces, $P$ a topological …
3
votes
Strong differentiability and the inverse function theorem in Banach spaces
Yes, it is true. This inverse function theorem is in a sense half-way between the Lipschitz and the $C^1$ setting. To be more precise let me review some classic results.
(Invertibility of Lipschitz p …