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A Banach space is a complete normed vector space: A vector space equipped with a norm such that every Cauchy sequence converges.

10 votes

Dual space of $\ell^\infty$

Let's recall a simple, elementary, and general fact that hasn't been explicitly mentioned: a dual Banach space is always a splitting subspace in the isometric embedding into its double dual. So $\el …
Pietro Majer's user avatar
  • 60.6k
1 vote
Accepted

Characterization of the dual of intersection of Banach spaces

In general, in order that the intersection be defined, we should assume that $(U,\|\cdot\|_U)$ and $(V,\|\cdot\|_V)$ are continuously embedded into an ambient Hausdorff TVS $E$. Then, $(U\cap V,\|\cdo …
Pietro Majer's user avatar
  • 60.6k
5 votes
Accepted

Is the image of a complemented subspace complemented?

For a counterexample, let $Y$ be a Banach space with a closed, non-complemented subspace $Z\subset Y$. Consider the restriction of the sum operation ${\bf +}:Y\times Y\to Y$ to the space $X:=Y\times …
Pietro Majer's user avatar
  • 60.6k
3 votes
Accepted

A variation of the Riesz Lemma

Let's denote $B$ the unit ball of $X$. Geometrically, we are asking if there is a line $\langle x\rangle$ such that the ball $\alpha B$ can be translated along $\langle x\rangle$ and pass through the …
Pietro Majer's user avatar
  • 60.6k
3 votes

Using the Stone-Weierstrass theorem to solve an integral limit

I understand the aim is an elementary proof; here is one. Let $\omega$ be a modulus of continuity for $f$ on $[0,c]$. Then, for all $0<t\le c-1$ $$\int_0^1|f(x+t)-f(x)|^2dx\le \omega(t)\int_0^1\big(f( …
Pietro Majer's user avatar
  • 60.6k
1 vote

Density of the set of convex polygons in the Banach-Mazur distance

Let $U\subset \mathbb R^2$ be a bounded open convex neighborhood of $0$. For every $\epsilon>0$ we have $\displaystyle \overline U=\bigcap_{H\supset U\atop H \text{ closed half-plane}} H \subset (1+\e …
Pietro Majer's user avatar
  • 60.6k
2 votes

When a quasinilpotent is nilpotent?

This is almost tautological, but suppose that the quasi-nilpotent operator $T$ has the property that, for some $p\in\mathbb N_+$, the equality $\|T^{np}\|=\|T^p\|^n$ holds for infinitely many $n\in\ma …
Pietro Majer's user avatar
  • 60.6k
14 votes
Accepted

Question about Schauder bases in C([0,1]).

I would say, monomials are not a Schauder basis for $C[0,1]$ because functions that admits a representation are analytic functions on the unit disc. Actually, $f(t)=\sum_k a_k t^k$ immediately implie …
Pietro Majer's user avatar
  • 60.6k
11 votes

Smooth Urysohn's lemma on Fréchet spaces

A bump function on a Banach space $X$ is a non-zero function with bounded support. Existence of a bump function of a given smooth regularity has, of course, strong immediate consequences --by translat …
Pietro Majer's user avatar
  • 60.6k
2 votes

Extension Operator for $W^{1,\infty}(U,X)$

Say $I:=[a,b]$. We may extend $u$ simply putting it constant for $t\ge b$ and $t\le a$, that is $Eu(t):=u((t\vee a)\wedge b)$. This defines a norm-$1$ linear extensor $E$.
Pietro Majer's user avatar
  • 60.6k
7 votes
Accepted

Is there a reflexive Banach space whose ball is not the convex hull of its extreme points?

I'd try $X:=\ell_2$ with an equivalent but non strictly convex norm. Let $(e_k)_{k\ge0}$ be the standard Hilbert basis of $\ell_2$. Consider the sets: $A:=\{0\}\cup\{2^{-k}e_k:k\ge 1\}$, $B$, the …
Fedor Petrov's user avatar
5 votes
Accepted

Subspaces of $\ell_\infty^3$

A funny isometry invariant to distinguish these normed spaces is: The space of spheres of radius $2$ in the unit sphere of $(X,\|\cdot\|_X)$ which are maximal by inclusion, as described below. It turn …
Pietro Majer's user avatar
  • 60.6k
3 votes

Direct limit of the sequence $E_{0} \hookrightarrow E_{1} \hookrightarrow \cdots$ in the cat...

The key point is "linear contraction" (which in this context I think means "operator norm not larger that $1$"). Let $(X,\|\;\|)$ be a Banach space and let $\{T_n:E_n\to X\}_{n\in\mathbb N}$ a famil …
Pietro Majer's user avatar
  • 60.6k
5 votes
Accepted

Implicit function theorem with continuous dependence on parameter

Assuming $P$ first countable, the standard contraction principle and elementary bounds are sufficient to conclude. You do not need higher regularity: Let $X$, $Y$ be Banach spaces, $P$ a topological …
Pietro Majer's user avatar
  • 60.6k
3 votes

Strong differentiability and the inverse function theorem in Banach spaces

Yes, it is true. This inverse function theorem is in a sense half-way between the Lipschitz and the $C^1$ setting. To be more precise let me review some classic results. (Invertibility of Lipschitz p …
Daniele Tampieri's user avatar

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