Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
Enumerative combinatorics, graph theory, order theory, posets, matroids, designs and other discrete structures. It also includes algebraic, analytic and probabilistic combinatorics.
2
votes
Accepted
Monotonicity of the sum of coefficients of a family of generating functions
Your conjecture is true. First, observe that
\begin{align*}
K_{w+1}(z)&=(1+z)\,K_w(z) & \mbox{ if } w \mbox{ is odd, }\\
K_{w+1}(z)&=(1+z)\,K_w(z) +\frac{1}{2}{w\choose \frac{w}{2}}z^{w/2}(1-z) & …
3
votes
Grouping lists together in a proportional election: image of a Dirichlet distribution by the...
Here is a way. Start from the exact form of your integral expression (i.e. supply the "Dirichlet factor" $\frac{\Gamma(\alpha_1+\ldots+\alpha_n)}{\Gamma(\alpha_1)\cdots\Gamma(\alpha_n)})$.
(1) Writing …
3
votes
Accepted
A polynomial identity related to Catalan numbers
These assertions can be proved using (formal) generating functions.
Using that for $j\geq 0, k\geq 1$
\begin{align*}
\sum_{n\geq 0} {n-j+kj \choose kj} t^n &=\frac{t^j}{(1-t)^{kj+1} }\;\;\mbox{ …
2
votes
Asking for a proof for a sum of products of binomials: an "interesting" identity?
A generating function proof.
As $\arcsin(z)=\sum_{k\geq 0} \frac{1}{2k+1} {2k \choose k} \frac{z^{2k+1}}{4^k}$ and $\frac{1}{\sqrt{1-z^2}}=\sum_{k\geq 0}{2k \choose k}\frac{z^{2k}}{4^k}$
we have that
…
5
votes
Accepted
Expected number of compositions needed to get constant function
This question was completely settled by J.A. Fill here:
https://citeseerx.ist.psu.edu/viewdoc/summary?doi=10.1.1.8.641
7
votes
Comparing two power-series
As in Timothy Budd's answer let $w=w(q)$ denote the (formal) solution of $q=\frac{w}{f(w)}$.
Let $p$ be another variable and consider the sum
\begin{align*}
S(p,q):=\sum_{n,m>0} \sum_{j>0} j[z^{n+j}]\ …
3
votes
Accepted
Bounding the max-loaded bin using${m \choose k} \|A\|_k^k$
The following inequality holds:
$$\mathbb{P}(C_k(m)\geq 1)\geq \mathbb{P}(\mathrm{Bin}(m, \lVert A\rVert_k)\geq k)$$
where here and in the sequel $\mathrm{Bin}(n,p)$ denotes a binomially distributed r …
7
votes
Alternative proofs sought after for a certain identity
One can also use the binomial transform.
(If $A(z)=\sum_{i\geq 0} a_i z^i$ is a (formal) power series, the (formal) power series $B(z):=\frac{1}{1-z}
A(\frac{z}{1-z})$ has coefficients $[z^n] B(z)=\su …
0
votes
Coupon collector targeting a collection among many
There a well known generating function methods (the ''symbolic method'' and ''Poissonization'') which can be used to deal with this kind of question.
However, I am unable to point to a reference for …
8
votes
Accepted
The number of ways to merge a permutation with itself
By @Max Alexeyev's solution above $N_{2k-1}^{\sigma}=tr(M_{k}(P_{\sigma}M_{k}P_{\sigma}^{-1}))$.
The eigenvalues and eigenvectors of $M_k$ are given here: Result attribution for eigenvalues of a matri …
4
votes
Quantifying the noninvertibility of a function
$\lambda(f):=\kappa_f-1$ is called "the coefficient of coalescence of $f$" here:
https://msp.org/pjm/1982/103-2/pjm-v103-n2-p03-p.pdf
(note the typo on p.269, the correct definition appears on p.27 …
4
votes
Accepted
Moments of a combinatorial ensemble of random variables
(You are considering the uniform distribution on a discrete simplex. I'm not aware of specific results in the literature,
and a brief internet search didn't reveal anything.)
A simple way is to use …
4
votes
Showing this formula counts these things
Here is a proof using (formal) generating functions.
The Lah number $L(n,m+1)$
$$L(n,m+1)=\frac{n!}{(m+1)!}[x^n] \bigg(\frac{x}{1-x}\bigg)^{m+1}$$
counts the number of unordered partitions of the se …
2
votes
Classification of algebras of finite global dimension via determinants of certain 0-1-matrices
(Not a solution, just a reformulation and a conjecture for $w=3$)
(1) Remark: the question above may equivalently be stated as follows:
Let $Z$ be the matrix of the cyclic shift (the companion matri …
3
votes
1
answer
378
views
Determinant of an "almost cyclic" matrix
Let $n\geq 3$, let $Z$ be the matrix of the cyclic shift (the companion matrix of $X^n-1$), and for $\mathbf{d}\in \mathbb{C}^n$ let
$\operatorname{diag}(\mathbf{d})$ be the diagonal matrix with $\ma …