Questions tagged [catalan-numbers]

The Catalan numbers form the sequence of numbers starting 1,1,2,5,14,42,... with explicit formula $\frac{1}{n+1}\binom{2n}{n}$. It counts many combinatorial objects like planar binary trees, triangulations, noncrossing partitions, Dyck paths, etc. See https://oeis.org/A000108

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Representations of $\mathrm{sl}(3,\mathbb{C})$ and Catalan-like paths

Background on representations of $\mathrm{sl}(3,\mathbb{C})$ In Chapter 6 of Brian C. Hall's book "Lie Groups, Lie Algebras, and Representations", he constructs the irreducible ...
Samuel Johnston's user avatar
8 votes
3 answers
718 views

Alternating Sum Involving Catalan Numbers

I was wondering if anyone knew how to obtain a simpler closed form of the following sum(or had any other insights regarding it): $$\sum_{k=0}^n (-1)^k{n \choose k} C_{2n-2-k} $$ Here $C_n = \frac{1}{n+...
interstice's user avatar
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Solving a Catalan-like recursion of polynomials, related to the KdV energies

I am working on a PDE problem. The goal is to connect the higher order energies of the Gross-Pitaevskii equation to those of the Korteweg-de-Vries equation. As these higher order energies are ...
Robert Wegner's user avatar
2 votes
0 answers
123 views

Lattice paths avoiding holes

Consider lattice paths from $(0,0)$ to $(2n,2n)$ with steps $N=(0,1)$ and $E=(1,0)$ avoiding the points $(2i-1,2i-1)$ for all $1\leq i\leq n$. There are Catalan many $C_{2n}=\frac1{2n+1}\binom{4n}{2n}$...
T. Amdeberhan's user avatar
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Yet, another generalization of Catalan determinants

The discussion on this page is motivated by Johann Cigler's MO question. My intention arose from a possible generalization of Cigler's matrix $$A_{n,m}=\left( \binom{2m}{j-i+m}-\binom{2m}{m-i-j-1} \...
T. Amdeberhan's user avatar
1 vote
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Super Catalan (super ballot) numbers

We refer to this article by Ira Gessel. In section 6, page 10, equation (28), the Super Catalan numbers are defined as $$S(m,n)=\frac{(2m)!(2n)!}{m!n!(m+n)!}.$$ On page 12, equation (31), there goes ...
T. Amdeberhan's user avatar
10 votes
2 answers
1k views

Proving an identity about Catalan numbers

$$C_{n} = \sum_{i=1}^n (-1)^{i-1} \binom{n-i+1}{i} C_{n-i}$$ Are there any good combinatorial proofs or algebraic proofs of this?
banana's user avatar
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Determinants of band matrices which are related to Hankel matrices of Catalan numbers

Let $A_{n,m}$ be the band matrix $$ A_{n,m}=\left( \binom{2m}{j-i+m}-\binom{2m}{m-i-j-1} \right)_{0\leq {i,j} \leq {n-1}}.$$ For example, $$A_{6,2}=\left ( \begin{matrix} 2 & 3 & 1& 0 &...
Johann Cigler's user avatar
1 vote
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72 views

Shifted Hankel determinants for convolutions of Catalan numbers

It is well known that for $m\in \mathbb N$ the Hankel determinants $$D_m(n)= \det\left(C_{i+j+m}\right)_{0\leq i,j\leq {n-1}}$$ satisfy $D_m(n)=p_m(n)$, where $p_m(n)=\prod_{1 \leq i \leq j \leq {m-1}}...
Johann Cigler's user avatar
6 votes
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224 views

Catalan numbers from matchings?

There are several examples of interpreting the Catalan numbers as non-nesting or non-crossing matchings of some graph. My question is: Is there a family of graphs $G_1,G_2,\dotsc$ with the number of ...
Per Alexandersson's user avatar
7 votes
0 answers
239 views

Hankel determinants for some convolutions of Catalan numbers

Let $c(x)=\frac{1-\sqrt{1-4x}}{2x}$ be the generating function of the Catalan numbers and let $$x^k c(x)^{2k}=(c(x)-1)^k =\sum_{n\geq0}c(k,n)x^n.$$ Consider the determinants $$D(k,n,m)= \det\left(c(k,...
Johann Cigler's user avatar
3 votes
1 answer
106 views

Why is this alternating sum involving Catalan numbers $\sum_{i=0}^{\lfloor t/2 \rfloor} (-1)^{i+1} \binom{t-i}{i} C_{t-i-1} = 0$ for all $t$?

I need the result that for all $t$, $$\sum_{i=0}^{\lfloor t/2 \rfloor} (-1)^{i+1} \binom{t-i}{i} C_{t-i-1} = 0,$$ where $C_{t-i-1}$ is the $(t-i-1)$-th Catalan number. I've checked for $t$ up to ...
Aaron Li's user avatar
5 votes
1 answer
454 views

A polynomial identity related to Catalan numbers

Let $F_n^{(k)}(x)= \sum_j {\binom{n+(k-1)j}{kj} x^j}$ and $G_n^{(k)}(x)= \sum_j {\binom{n+j}{kj} x^j}.$ I am interested in the coefficients ${a_{n,k,j}}$ such that $$G_n^{(k)}(x)=\sum_{j\geq0 }{a_{n,...
Johann Cigler's user avatar
7 votes
2 answers
374 views

A sequence of polynomials related to Catalan numbers

The sequence of polynomials $$P_n=\sum_{k=0}^{\lfloor(2n-1)/3\rfloor} \frac{(2n-2k-1)!(2n-2k-2)!}{k!(n-k)!(n-k-1)!(2n-3k-1)!}x^k$$ satisfies apparently the identities $$0=\sum_{j=0}^nP_{n-j}(P_j-(-x)^...
Roland Bacher's user avatar
16 votes
1 answer
473 views

Conjecture on sum over permutations of products of Catalan numbers

Context In a recent paper involving entanglement in linear optics, we came across some summations involving Catalan numbers and permutations. In particular, these sums arise when doing integration ...
Joseph Iosue's user avatar
4 votes
0 answers
187 views

Non-crossing and crossing bijection in higher genus

This is a follow-up question of my SO post I'll briefly mention it here. So given a $n$ cycle say $(1,2,\ldots,n)$, what are the monotonic 2 -tuples, of the form $(a,b)(c,d)$, monotonicity in on the ...
GGT's user avatar
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2 votes
1 answer
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Counting monomials and $q$-Catalan polynomials

Define $N(F)$ to be the number of monomials of a multi-variable polynomial $F$. For example $N(x^2y+3xy-y^5)=3$. If $\mathbf{x}=(x_1,\dots,x_n)$ and $F_n(\mathbf{x})=\prod_{k=1}^n(x_1+\cdots+x_k)$ ...
T. Amdeberhan's user avatar
6 votes
0 answers
106 views

Bijection between forests and skew SYT + Cyclic sieving

Consider the two-row skew shape $\lambda_n = (2n+1,n)/(1)$. The number of standard Young tableaux of this shape is $\binom{3n}{n}-\binom{3n}{n-2}$ (since one can easily biject this to the set of non-...
Per Alexandersson's user avatar
4 votes
1 answer
186 views

Reference for a definition of Catalan numbers

The $l$-th Catalan number ${2l\choose l}\frac{1}{l+1}$ is equal to the number of sequences $s_0,\ldots,s_{l+1}$ of length $l+2$ with the following properties: (1) $s_0=s_{l+1}=1$ and $s_1,\ldots,s_l$ ...
Roland Bacher's user avatar
1 vote
1 answer
109 views

A big list of Narayana-enumerated objects

By a Narayana-enumerated object I mean an object whose count is given by the Narayana number $N(n,k)=\frac{1}{n} {n \choose k} {n \choose k-1}$. Can you give me a reference to some good big list of ...
Svjetlan Feretic's user avatar
5 votes
1 answer
328 views

Counting monomials and the Catalan numbers

Given a multi-variable polynomial $F$, denote the number of monomials by $N(F)$. Take for instance, \begin{align*}N(x(x+y)+(x+y)^2-(x-y)^2)=N(x^2+5xy)&=2 \qquad \text{and} \\ N((x+z)(x+y)^2)=N(x^3 ...
T. Amdeberhan's user avatar
2 votes
1 answer
190 views

Sequence of monotone tuples and permutation condition for rotation

I was doing some counting in $S_n$ symmetric group I encountered the following problem, which also someway related to central factorial number. So given a $n$ cycle say $(1,2,\ldots,n)$, what are the ...
GGT's user avatar
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0 votes
1 answer
139 views

What is this numerically-generated function?

This question is an "outgrowth" of https://math.stackexchange.com/questions/4380919/ which led to a numerically-generated two-parameter function $f_b(n)$, where $b$ is the number base $2,3,4,...
eigengrau's user avatar
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1 answer
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Hankel determinants for q-Catalan numbers where q is a root of unity?

Let ${C_n}(q)$ be the weight of the Dyck paths of semilength $n$ where the upsteps have weight $1$ and the downsteps which end on height $i$ have weight $q^i$. They satisfy ${C_n}(q) = \sum\limits_{j ...
Johann Cigler's user avatar
6 votes
1 answer
262 views

Another generalization of parity of Catalan numbers

Recently, a question by T. Amdeberhan gathered up many enjoyable proofs that a Catalan number $C_n$ is odd if and only if $n=2^r-1$. Noam D. Elkies' answer considered $F=\sum_{n=0}^\infty C_n x^{n+1}$....
user196574's user avatar
3 votes
1 answer
163 views

Sequences that sums up to second differences of Bell and Catalan numbers

Let $f(n)$ be A007814, the exponent of the highest power of $2$ dividing $n$, a.k.a. the binary carry sequence, the ruler sequence, or the $2$-adic valuation of $n$. Let $g(n)$ be A025480, $g(2n) = n$...
Notamathematician's user avatar
4 votes
1 answer
354 views

Generating functions for Hankel determinants of Catalan numbers

The Hankel determinants of the Catalan numbers are well known and can be written as $d(k,n)= \det \left( C_{k + i + j} \right)_{i,j = 0}^{n - 1}=\prod_{i=1}^{k-1}\frac{\binom{2n+2j}{j}}{\binom{2j}{j}}$...
Johann Cigler's user avatar
11 votes
2 answers
338 views

Kernel of a matrix and the Catalan numbers

Let $B_n$ denote the Boolean lattice of a set with $n \geq 2$ elements and $C_n$ the matrix with entries $c_{i,j}=1$ if $i \leq j$ and $c_{i,j}=0$ else, where $i,j\in B_n$. Let $M_n:=C_n+C_n^T$ (this ...
Mare's user avatar
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4 votes
1 answer
252 views

Generalization of Catalan numbers

Some time ago I was trying to find a closed form formula for the number of tuples $(a_k)_{k=1}^{n+s}$ of non-negative integers satisfying following conditions: $\sum_{k=1}^{n+s} a_k = n$, $\forall m \...
Kacper Kurowski's user avatar
2 votes
0 answers
180 views

Does this question have anything to do with Catalan numbers?

I think this question has something to do with Catalan numbers but I'm not really sure. I want to find out the number of strings that consist of $n$ $L$'s and $n$ $R$'s, under the constraint that for ...
Tuhin Mukherjee's user avatar
0 votes
1 answer
231 views

Dyck words and Catalan numbers

One of the many applications of the $n$th Catalan number is to calculate the number of strings consisting of $n$ $X$'s and $n$ $Y$'s, such that any prefix of the string will contain at least as many $...
Tuhin Mukherjee's user avatar
6 votes
0 answers
300 views

Reference request: colored Motzkin path interpretation of Catalan numbers

Recall that a Dyck path of length $2n$ is a lattice path in $\mathbb{Z}^2$ from $(0,0)$ to $(2n,0)$ consisting of $n$ up steps $U=(1,1)$ and $n$ down steps $D=(1,-1)$ which never goes below the $x$-...
Sam Hopkins's user avatar
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5 votes
1 answer
377 views

Reference request: recurrence relation for Catalan numbers

I would like to know if the following recurrence relation for Catalan numbers (see mathoverflow.net/questions/191524 and also math.stackexchange.com/questions/2113830) has appeared in a paper or a ...
egunawan's user avatar
10 votes
0 answers
333 views

A bijective proof for the odd companion to Shapiro's Catalan convolution

Shapiro's Catalan convolution is the following formula (where $C_n$ is the $n$th Catalan number): $$ \sum_{k=0}^{n}{C_{2k}C_{2(n-k)}}=4^nC_n. $$ In other words, letting $C(z)=\sum_{n=0}^{\infty}{C_nz^...
Alexander Burstein's user avatar
6 votes
1 answer
317 views

Are the “generalized Catalan numbers” of Dumitrescu–Mulase the "moments" of some "multivariate Wigner semicircle distribution"?

The classical Catalan numbers $$ C_n = \frac{1}{n+1} \binom{2n}{n}, $$ well-known for their numerous combinatorial interpretations (the second volume of Stanley's Enumerative Combinatorics famously ...
mlbaker's user avatar
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6 votes
0 answers
150 views

Upper bounds for a sequence of integers

Given $\alpha\geq0$ we consider the sequence $$ C_k=k^\alpha\sum_{j=0}^{k-1}C_jC_{k-1-j} $$ with $C_0=1$. I'm interested in upper bounds (in terms of $\alpha$) for such a sequence. I know that when $\...
guacho's user avatar
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6 votes
0 answers
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Looking for a combinatorial proof for an identity involving $q$-Catalan triangles

Let $C_n=\frac1{n+1}\binom{2n}n$ be the Catalan numbers. Following my earlier post on MO, one fine colleague asked me if there is a $q$-analogue of the identity formed by the so-called Shapiro's ...
T. Amdeberhan's user avatar
13 votes
5 answers
2k views

Looking for a combinatorial proof for a Catalan identity

Let $C_n=\frac1{n+1}\binom{2n}n$ be the familiar Catalan numbers. QUESTION. Is there a combinatorial or conceptual justification for this identity? $$\sum_{k=1}^n\left[\frac{k}n\binom{2n}{n-k}\right]^...
T. Amdeberhan's user avatar
15 votes
1 answer
228 views

A formula for this generating function that is similar to the $qt$-Catalan numbers

I came up with the following conjecture: $$ \sum_{n \ge 0} z^n \sum_{\mu \vdash n} \frac{ t^{\sum l}q^{\sum a}}{\prod (q^a - t^{l+1})(t^l - q^{a+1})} = \exp\left(\sum_{n \ge 1} \frac{z^n}{n(q^n-1)(t^n-...
Drew's user avatar
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5 votes
0 answers
147 views

A conjecture about sums over partitions arising from Hilbert scheme of points

$\DeclareMathOperator{\leg}{\operatorname{leg}}\DeclareMathOperator{\arm}{\operatorname{arm}}$The following situation arose from the study of some localization computations on Hilbert schemes of ...
Drew's user avatar
  • 1,471
7 votes
1 answer
578 views

Reciprocity for fans of bounded Dyck paths

This is a continuation of some questions asked by Johann Cigler: Number of bounded Dyck paths with "negative length" and Number of bounded Dyck paths with negative length as Hankel ...
Sam Hopkins's user avatar
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12 votes
1 answer
444 views

What's the dimension of the Lie algebra generated by transpositions on $n$ objects?

Define a Lie bracket on the group algebra of the permutation group $S_n$ in the following way: $$[\sigma, \tau] = \sigma\circ\tau - \tau\circ\sigma,$$ where $\sigma, \tau \in S_n$, and the ...
WunderNatur's user avatar
4 votes
1 answer
336 views

A generalisation of the Catalan numbers

Let $n$ be a nonnegative integer. It is well-known that the number of lattice paths from $(0, 0)$ to $(n, n)$ with steps $(0, 1)$ and $(1, 0)$ that are never rising above the line $y=x$ is given by ...
Fikilis's user avatar
  • 155
17 votes
1 answer
828 views

Proof of certain $q$-identity for $q$-Catalan numbers

Let us use the standard notation for $q$-integers, $q$-binomials, and the $q$-analog $$ \operatorname{Cat}_q(n) := \frac{1}{[n+1]_q} \left[\matrix{2n \\ n}\right]_q. $$ I want to prove that for all ...
Per Alexandersson's user avatar
3 votes
0 answers
109 views

Seeking bijective proof of a recurrence for generalized Narayana numbers

Consider lattice paths in $d$ dimensions with the steps $X_1\mathrel{:=}(1,0,\dotsc,0)$, $X_2\mathrel{:=} (0,1,\dotsc,0)$,…, $X_d\mathrel{:=} (0,0,\dotsc,1)$. Let $\mathcal C(d, n)$ denote the set of ...
Tri's user avatar
  • 1,198
5 votes
1 answer
352 views

Non-nesting matchings and Catalan numbers

It is well-known that the number of non-nesting perfect matchings on $2n$ points is given by the Catalan number $C_n$; see part (a) of the figure below. This is item e^5 in Stanley's list (http://www-...
Torsten Mütze's user avatar
-1 votes
1 answer
85 views

Domination relationship between generalized Dyck Paths

In short, we are seeking an injection between generalized Dyck paths that end at a certain height into the set of paths of the same length that end at a lower height such that the image path stays ...
Matthew Junge's user avatar
4 votes
0 answers
267 views

Dyck paths weighted by height profile

We are interested in a question concerning a weight function on Dyck paths that penalizes visits to higher heights. Let $\rho$ be a parameter. Let $D_k$ be the set of all nearest neighbor random walk ...
Matthew Junge's user avatar
1 vote
1 answer
230 views

A divisibility problem involving Catalan numbers

The Catalan numbers in combinatorics are given by $$C_n=\frac1{n+1}\binom{2n}n=\binom{2n}n-\binom{2n}{n+1}\ \ (n=0,1,2,\ldots).$$ In 2014 I formulated the following conjecture. Conjecture. For each $...
Zhi-Wei Sun's user avatar
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13 votes
1 answer
537 views

Coincidences between average Catalan tableaux

There are Catalan number $C_n$ of standard Young tableaux of shape $(n,n)$, which we view as $2\times n$ matrices. Denote by $P_n$ the average of these matrices: $$ P_n \, := \, \frac{1}{C_n} \, \...
Igor Pak's user avatar
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