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Riemann surfaces(Riemannian surfaces) is one dimensional complex manifold. For questions about classical examples in complex analysis, complex geometry, surface topology.
37
votes
Accepted
How did Riemann prove that the moduli space of compact Riemann surfaces of genus $g>1$ has d...
Riemann combines what is called Riemann-Roch and Riemann-Hurwitz nowadays.
He considers the dimension of the space of holomorphic maps of degree $d$ from the Riemann surface of genus $g$ to the sphere …
22
votes
Accepted
Poincaré metric on the Riemann sphere minus more than two points
Yes. The density of the Poincare metric with respect to the spherical metric is
a positive continuous function which tends to infinity at the punctures. Thus it
is bounded from below by some positive …
17
votes
Accepted
A "holomorphic" Peano curve?
Here it is:
MR0015154
Salem, R.; Zygmund, A.
Lacunary power series and Peano curves.
Duke Math. J. 12, (1945). 569–578.
16
votes
What is a branched Riemann surface with cuts?
There are two different things which are called "Riemann surface" in the literature.
The modern notion (introduced by Hermann Weyl): complex 1-dimensional manifold.
In older literature this is somet …
16
votes
Embed a bordered Riemann surface into punctured Riemann surfaces?
The answer is no. For $g=0$, the problem is equivalent to the following: is there a univalent function in the unit disk which takes given values at finitely many given points. It is well known that th …
15
votes
Are real-analytic functions in $\mathbb{R}^2$ holomorphic after suitable change of coordinates?
The answer is negative. For the non-injective case, the reason is that non-constant complex analytic functions are open, discrete maps, while real analytic functions can be neither open nor discrete ( …
13
votes
Accepted
Spicing up Riemann surfaces course (revised)
Forster just touches the Riemann-Hilbert problem and fiber bundles. Expansion on this can be interesting
I recommend the books of Bolibrukh.
Applications of compact Riemann surfaces to solitons ("Ex …
13
votes
Accepted
Gluing Riemann surfaces
The answer to the first question is "yes". This is called conformal gluing, and the proof is based on the following lemma due to Lavrentiev: Let $\phi$ be an increasing diffeomorphism of $[-1,1]$ onto …
9
votes
Accepted
Reference request: uniformization theorem
On a basic level:
W. Abikoff, The uniformization theorem, Amer. Math. Monthly 88 (1981), no. 8, 574–592.
L. Ahlfors, Conformal invariants, last chapter.
S. Donaldson, Riemann surfaces, Oxford, 2011. V …
9
votes
Accepted
Reference request: uniformization theorem proof by Borel
I suppose that Borel is mentioned in the text you refer to by mistake. I cannot prove this (Borel has 335 publications including 85 books according to Zentralblatt) but a large recent book on the unif …
8
votes
Explicit triples of isomorphic Riemann surfaces
There are indeed very few pairs (except spheres with 3 or 4 singularities, or tori, and what can be obtained from them by finite coverings, where correspondence 2)-3) is completely explicit. See:
H. P …
8
votes
Elementary proof of Riemann-Roch for compact Riemann surfaces
There are (at least) 2 kinds of proofs: analytic ones (which use the existence of Abelian differentials with certain properties) and algebraic ones.
The proofs of the first kind use powerful analytic …
8
votes
The existence of meromorphic functions on Riemann surfaces
This deep fact is essentially the same as the uniformization theorem. The problem is
how to construct at least one holomorphic or meromorphic form with prescribed singularity.
All known proofs use som …
7
votes
Accepted
searching for an elementary proof a complex analysis result
Let $L$ be your difference operator: $(Lf)(z)=f(z+1)-f(z)$.
Consider these polynomials
$$P_n(z)=\frac{1}{n!}z(z-1)\ldots(z-n+1),\quad n=0,1,2,\ldots.$$
Simple computation shows that $LP_n=P_{n-1}$. Po …
7
votes
Conformal Welding Reference
The gluing does not necessarily exist, neither it is unique when exists,
in such generality as stated. (I am not even speaking of what the "boundary" of a Riemann
surface could mean in general).
Even …