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7 votes
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Why are the medians of a triangle concurrent? In absolute geometry

There is such a proof given by Hjelmslev; it is based on a clever application of central symmetries (point-reflections). You can find it on pages 102-104 of Ф. Бахман, Построение геометрии на основе …
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10 votes
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submanifold of a hyperbolic manifold

The thing is that every compact Riemannian surface admits a $C^\infty$ isometric embedding in ${\mathbb E}^5$, see Michael Albanese's answer here; the result is a version of the Nash isometric embeddi …
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12 votes
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Hyperbolic 3 manifold with trivial deformation of flat conformal structures

Let $M$ be a compact hyperbolic 3-manifold and let $C(M)$ be the moduli space of flat conformal structures on $M$. The hyperbolic metric on $M$ defines a distinguished point $h\in C(M)$. One says tha …
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7 votes
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Geodesic representatives in the orbifold fundamental group

First of all, I would use a different name for what you call geodesics on $X$, let's call them regular geodesics. The reason is that geodesics in Riemannian geometry are curves satisfying the equation …
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1 vote

Are pseudo-Anosov foliations dense?

I am sure this was known earlier (check Ivanov's book, most likely, it is there), but you can refer to the following theorem of Lindenstraus and Mirzakhani (see their paper Ergodic theory of the space …
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10 votes

Hilbert 16th problem via hyperbolic geometry

This story is somewhat reminiscent of a (probably apocryphal) story of somebody writing a telegram to a mathematical research institute (Steklov Institute in Moscow, if I remember it correctly): "Sol …
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3 votes
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Subsets of the boundary of a surface group

You definition is closely related to the notion of the "cone type" introduced by Jim Cannon. As Yves noted, $U(x,y)$ is compact. It is also connected. Compactness part is immediate from the Arzela- …
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3 votes

Kleinian groups containing an isomorphic copy of itself

Let us say that an abstract group $\Gamma$ is self-contained (I just made up this terminology) if $\Gamma$ is isomorphic to its proper subgroup of finite index. Next, each discrete group of isometri …
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8 votes
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Dirichlet polyhedra for hyperbolic manifolds

B.Bowditch, Geometrical finiteness for hyperbolic groups. J. Funct. Anal. 113 (1993), no. 2, 245–317. The statement that you need is a corollary of his Proposition 5.6 in conjunction with finiteness …
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3 votes
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Does the Teichmüller space of the pair of pants admit a continuous global section?

Since the fiber is contractible, there is a global section. The details are in the papers Earle, Clifford J.; Eells, James, A fibre bundle description of Teichmüller theory. J. Differential Geometr …
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11 votes
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Representation varieties of 3-manifold groups in $\mathrm{SL}(n,\mathbb{C})$

These are difficult questions and very little in general is known about this. Mostly, what's known is ad hoc results for specific classes of manifolds (say, take some surgeries on 2-bridge knots...). …
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4 votes

Best known Margulis constants?

For Question 2: In addition to Kellerhals' lower bounds on $\epsilon(n)$, there is an absolute constant $C>0$ such that $$ \epsilon(n)\le \frac{C}{\sqrt{n}}, $$ see Proposition 5.2 in Belolipetsky, Mi …
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4 votes

Structures on open surfaces

I assume that $\varphi$ has finite order; a similar construction works in the infinite order case, just it is a bit harder. Consider $D$, the complement to the fixed point of $\varphi$. Then $S'=D/<\v …
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2 votes

Two questions on isometric embedding

For the second question the answer is obviously negative since distinct Euclidean lines cannot converge to each other (in the sense that the distance function goes to zero). For the first question, I …
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8 votes

Model of hyperbolic geometry with finite number of parallel line

Here is how you can define a hyperbolic plane over a finite field $F$, I do not know if it is sufficiently useful or interesting though. Let $V$ be a 3-dimensional vector space over $F$; let $Q$ be …
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