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Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.
46
votes
4
answers
9k
views
What are "good" examples of spin manifolds?
I'm trying to get a grasp on what it means for a manifold to be spin. My question is, roughly:
What are some "good" (in the sense of illustrating the concept) examples of manifolds which are spin …
21
votes
Geometric picture of scalar curvature
I'll add a few things which I've found helpful to get intuition to what Renato's already written.
Scalar curvature has the very simple geometric interpretation as the volume defect of small balls (as …
19
votes
1
answer
505
views
Smooth curve in $\mathbb{R}^3$ not contained in real analytic surface?
Is there a $C^\infty$-smooth embedding $\gamma : I \to \mathbb{R}^3$ so that there is no real analytic $2$-dimensional submanifold $M \subset \mathbb{R}^3$ with $\gamma(I)\subset M$?
16
votes
Intuition for mean curvature
Perhaps a more geometric way of viewing mean curvature (at least for a hypersurface) is as follows:
If $\varphi: \Sigma^n\hookrightarrow (M^{n+1},g)$ is an embedded (oriented) hypersurface, then we …
14
votes
Dimension of eigenspaces of Laplacian on a compact Riemannian manifold
In dimension $n\geq 3$, there cannot be any sort of bound on the multiplicities which does not depend on some geometric input. This is because it is a theorem of Colin de Verdière (mathscinet and arti …
13
votes
Are there some other notions of "curvature" which measure how space curves?
An interesting "curvature" which has recently received much interest is the "Ma--Trudinger--Wang" (MTW) tensor, which arose in the study of when optimal transport maps are smooth on a Riemannian manif …
12
votes
2
answers
1k
views
Converse to Bishop-Gromov Inequality
Is the converse to the Bishop-Gromov Inequality true?
In other words, if, for a complete $n$-dimensional Riemannian manifold $M$, there is $k \in \mathbb{R}$, such that defining $V_k(R)$ to be the s …
11
votes
Ricci flow and isometry group
The answer is yes (I'm assuming you are asking about closed manifolds, non-compactness allows for all sort of crazy things to happen, you can check out the work of Topping and collaborators).
Kotsch …
10
votes
Compact surface with arbitrarily large eigenvalue
Yang and Yau proved that for a surface of genus $\gamma$, $\Sigma$ with a metric $g$, the first eigenvalue satisfies
$$
\lambda_1(g) Area(g) \leq 8\pi (1+\gamma).
$$
So, the answer to your first ques …
9
votes
Accepted
minimal surfaces in $S^n$
Without embeddedness, the Choi--Schoen theorem is false.
For example, there is a huge family of rotationally symmetric immersed tori in $\mathbb{S}^3$ (the only embedded one is the Clifford torus, b …
8
votes
1
answer
239
views
Poincare's argument for maximizing the Coulomb energy
For $\Omega\subset \mathbb{R}^3$ a region with $|\Omega| = |B_1|$, let
$$
C(\Omega) = \int_\Omega\int_\Omega \frac{dxdy}{|x-y|}
$$
denote the Coulomb (or gravitational, etc) energy.
Poincaré is cred …
8
votes
Accepted
the left hand side of the Ricci flow equation at the initial value
Misha's comment could be a bit misleading. In particular, it is not true that the Ricci flow should exist on a slightly bigger interval $(-\epsilon,T)$ with $g(0) = g_0$. One way to see this is by thi …
8
votes
Accepted
A general theory for local moduli space of minimal surface?
In general, asking whether or not all Jacobi fields on a minimal surface can be "integrated" to find a nearby minimal surface is a very difficult problem. For example, see Yau's remark here (page 246) …
7
votes
1
answer
366
views
Theory of surfaces in $\mathbb{R}^3$ as level sets
Is there a book that treats the classical theory of surfaces in $\mathbb{R}^3$ from the point of view of level sets of a function? I seem to remember someone telling me that such a book exists, but I …
7
votes
Can anyone give an example of Ricci flat Riemannian or Lorentzian Manifold that is not flat?
Your claim that "all solutions from general relativity are geodesically incomplete" is not true. The classical Schwarzschild/Kerr black hole solutions are geodesically incomplete, and along with Minko …