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Topology of cell complexes and manifolds, classification of manifolds (e.g. smoothing, surgery), low dimensional topology (e.g. knot theory, invariants of 4-manifolds), embedding theory, combinatorial and PL topology, geometric group theory, infinite dimensional topology (e.g. Hilbert cube manifolds, theory of retracts).

1 vote

Fundamental group of the complement of a codimension two submanifold

As you suspect, in dimension 3 the answer to your first question should be "no". Indeed, if one deletes any collection of circles from $M$ then the complement is a 3-manifold with toroidal boundary. S …
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8 votes

Finite two-relator groups and quotients of knot groups

Question 1: As mentioned in comments, presentations with the same number of generators and relations are called balanced. The triviality problem for balanced presentations appears to be a question of …
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10 votes

Fundamental group of a generalized connected sum

This basic question is unfortunately not well explained anywhere in the literature that I know of, although the answer is well known to lots of people. When $\pi_1(S)$ embeds into $\pi_1(M)$ and $\pi_ …
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7 votes
Accepted

Existence of a surface group ensures the existence of a $\pi_1$-injective immersed surface

This fact doesn’t need $M$ to be hyperbolic. It just needs one general theorem about 3-manifold topology, namely the Scott core theorem. Let $N\to M$ be the covering space corresponding to the subgrou …
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5 votes

Residual finiteness of hyperbolic 3-manifold groups

Sam Nead's answer does it, but perhaps I can offer a slightly different perspective on Question 1. No complicated hyperbolic gluing results are needed. I assume we are satisfied with the characterisat …
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6 votes
Accepted

Order of a loop around a cone point

As mentioned in comments, the answer is "yes" and there are many ways to see it. I would refer you to §2 of Peter Scott's survey paper "The geometries of 3-manifolds", in which he discusses 2-dimensio …
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9 votes
Accepted

Is every automorphism of $\mathrm{Aut}^+(F_2)$ induced by conjugation inside $\mathrm{Aut}(F...

$\DeclareMathOperator\Aut{Aut}\DeclareMathOperator\Out{Out}$If I have chased through the literature correctly, I think the answer to your question is "yes". Specifically: Dyer–Formanek–Grossman showed …
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9 votes

Amalgamated product acting on CAT(0) cube complex

To extend the gluing result from Bridson--Haefliger to non-positively curved cube complexes, it is important to work in the correct category. If we want the result to also be a non-positively curved c …
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2 votes

Identifying a curve on a closed surface of genus 4

As mentioned in comments, your picture is not entirely accurate. But perhaps this is what you're looking for? (Note that, if you had chosen a different gluing pattern for your once-punctured genus-tw …
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4 votes

Elevator pitch for the Virtual Fibering Theorem

The Virtual Fibring theorem provides the topological classification of closed 3-manifolds. Very roughly, after passing to finite covers, we can build 3-manifolds by gluing together simpler pieces that …
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7 votes

Generate $\mathrm{Mod}(S_g)$ by two Dehn twists

This is addressed in §3.5.2 of Farb and Margalit's Primer on Mapping Class Groups. The subgroups of mapping class groups generated by two Dehn twists $T_a,T_b$ are one of: $\mathbb{Z}$ if the curves …
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4 votes
Accepted

Examples of finite polyhedra with finitely generated simple fundamental group

As suggested in the comments, what you are asking for is essentially the presentation complex of a finitely presented, infinite, simple group. Thus it suffices to exhibit a presentation for such a gro …
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5 votes

HNN decomposition of finite rank free group over infinite rank subgroups

You haven't quite given the full strength of Swarup's result, which is what makes it so useful: moreover, $H_2$ and $tHt^{-1}$ are conjugate into $J_2$. The geometric interpretation is that a natural …
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5 votes
Accepted

Does length spectrum determine a hyperbolic 3-manifold? What if we also know holonomies?

I think your questions are answered by this paper of Leininger, McReynolds, Neumann and Reid. In their terminology, your first question is asking about manifolds with equal length sets, and your seco …
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3 votes

From topological actions on $\mathbb{R}^3$ to isometric actions

My earlier attempt at an answer was a bit of a mess -- let me have another go. The hypotheses of the question introduce several technical difficulties, but I'm unsure which are crucial and which can b …
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