Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 13972

Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.

3 votes

Reference request: $\operatorname{Sym}^2_0(T^*M) \simeq \Lambda_- \otimes \Lambda_+$

There is also a quick abstract proof via representation theory: $S^2_0(\mathbb{R}^4)$ is a 9-dimensional representation of $\mathrm{SO}(4)/\{\pm I_4\}\simeq \mathrm{SO}(3)\times\mathrm{SO}(3)$ and, h …
Robert Bryant's user avatar
5 votes
Accepted

Asymptotic parametrization for negatively curved surfaces

As asked, the answer to the question is 'no'. The simply-connected cover $f:\mathbb{R}^2\to S$ of Sherck's first surface $S$ (which is defined in $\mathbb{R}^3$ by the equation $\mathrm{e}^{z} \cos x …
Robert Bryant's user avatar
3 votes
Accepted

How badly does the geodesic exponential map fail to be $C^2$ on Finsler manifolds

Note: I am making the standard assumptions in Finsler geometry, i.e., that $F:TM\to\mathbb{R}$ is smooth away from the zero section and $F$ is 'strictly convex'. Although $\partial_i\partial_j\exp^k_ …
Robert Bryant's user avatar
17 votes

When are these base spaces isomorphic?

Here's a perhaps more serious example: There is a compact $4$-manifold that fibers over both $\mathbb{RP}^3$ and $(S^1\times S^2)/\mathbb{Z}_2$ where, in each case, the fibers are circles. (The $\ma …
Robert Bryant's user avatar
6 votes
Accepted

Nontrivial extension of the action of complex hyperbolic group $H$ on $\mathbb{C}$

The group $H$ acts transitively and primitively on $\mathbb{C}=\mathbb{R}^2$. ('Primitive' means that $H$ preserves no nontrivial foliation.) It's a consequence of the classification of transitive pr …
Robert Bryant's user avatar
13 votes

Isometry group of a left-invariant Riemannian metric on $\mathrm{SU}(2)$

The $\sigma_i$ as defined above satisfy $\mathrm{d}\sigma_i = -2\,\sigma_j\wedge\sigma_k$ when $(i,j,k)$ is an even permutation of $(1,2,3)$. For later use, let $E_i$ be the dual (left-invariant) fram …
Robert Bryant's user avatar
10 votes
Accepted

Understanding exterior differential systems

Here's an expansion of my comment that the natural formulation of this problem as an EDS is on the coframe bundle $\pi: P\to M$, which, I hope, will be helpful. Also, because it will match my usual n …
Robert Bryant's user avatar
11 votes

A manifold whose tangent space is a sum of line bundles and higher rank vector bundles

Remark: I assume that you want $A$ to be a non-trivial bundle. Otherwise, of course, any parallelizable compact manifold would be an example. In particular, any compact Lie group would be an exampl …
Robert Bryant's user avatar
1 vote

Characterization of bi-Hermitian structures with equal Lee forms

There are probably too many such $(M,g,I_+,I_-)$ to really expect a 'classification'. For instance, consider the case when a complex manifold $(M,I_+)$ has real dimension $4$, and the $I_+$-holomorphi …
Robert Bryant's user avatar
4 votes

Unitary transformations of Vandermonde matrices forms a smooth manifold?

The answer is 'not always', in particular, not when $(n,r)=(2,3)$. The image is obviously is a smooth manifold when $n=0$, for then the image in $\mathbb{R}^{(n+1)r}=\mathbb{R}^r$ is the sphere $\Sigm …
Robert Bryant's user avatar
6 votes
Accepted

Systems of (hyperbolic) 2nd order PDEs with lower order constraints

Yes, there is a standard procedure to analyze such systems, essentially, it is Cartan's method of prolongation combined with his theory of involutive systems. There are other approaches as well, but …
Robert Bryant's user avatar
5 votes

Frobenius theorem and the size of integral manifold

Your equations are equivalent to the $1$-form equations $$ \mathrm{d}f = X_0(f,g)\,\mathrm{d}s + Y_0(f,g)\,\mathrm{d}t \quad \text{and}\quad \mathrm{d}g = X_1(f,g)\,\mathrm{d}s + Y_1(f,g)\,\mathrm{ …
Robert Bryant's user avatar
14 votes
Accepted

How to learn intrinsic torsion

General $G$-structures are not usually treated in textbooks, other than the basic definitions, so it's not surprising that there would be few if any textbooks that treat the intrinsic torsion of $G$-s …
Robert Bryant's user avatar
6 votes

Commutative/ symmetric second covariant derivative

If the second covariant derivative of every vector field $Z$ is symmetric in the sense that $\nabla(\nabla Z)$ (which is a section of $TM\otimes T^*M\otimes T^*M$) is a section of the sub bundle $TM\o …
Robert Bryant's user avatar
1 vote
Accepted

Exterior differential systems on compact three-manifolds and Cartan-Kähler theory

In their comments to my first answer, the OP has clarified that they did not mean to regard the metric $h$ as a given, but, rather, an output of the problem of prescribing coframings by specifying the …
Robert Bryant's user avatar

1
2 3 4 5
33
15 30 50 per page