Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
Theory and applications of probability and stochastic processes: e.g. central limit theorems, large deviations, stochastic differential equations, models from statistical mechanics, queuing theory.
5
votes
Matrices over $\mathbb{F}_p$ that have nonzero determinant under any element permutation
Let's try an easy case: $n=2$. If the matrix has entries $a,b,c,d$ we need $ab - cd$, $ac-bd$ and $ad-bc$ to all be nonzero. In particular if $b,c,d$ are all nonzero there are
at most $3$ forbidden …
4
votes
Accepted
Scheduling "parent talks" at school
To restate the question in probabilistic language, each of the $n$ chldren's parents independently and with uniform probabilities chooses a $k$-element subset of $[n]$; say $X_i$ is the choice of chil …
16
votes
Accepted
For positive definite $A,B$ why does $AB+BA$ tend to be positive definite?
$\text{tr}(AB+BA) = 2 \operatorname{tr}(A^{1/2} B A^{1/2}) > 0$, so that may produce some bias toward positive eigenvalues. In particular if you generate your "random" matrices in such a way that the …
2
votes
Are the first 4 statistical moments independent?
If you're talking about the moments of a real-valued random variable, they are not independent in the sense that they are related by inequalities, e.g. $\mathbb E[X^2] \ge \mathbb E[X]^2$.
3
votes
The covariance matrix of quadratic form, without normal assumption
Why would you think normality is not needed? Consider the $1$-dimensional case: the left side is a constant times the variance of $x^2$, which depends on the $4$'th moment; it is not just a function …
4
votes
Grand-canonical Gibbs measure for continuous systems
The configuration space is the disjoint union of $\Lambda^N$ for each nonnegative integer $N$. You can
take the Borel $\sigma$-algebra on each of these (or Lebesgue if you prefer, but you're unlikely …
13
votes
Accepted
Is there a systematic theory for Gibbs measures (better if on Hilbert spaces)?
Any probability measure $\mu_1$ absolutely continuous with respect to $\mu_1$ can be written as a Gibbs measure if you allow $G$ to take values $\pm \infty$. If the density is bounded above and below …
0
votes
Accepted
Brownian motion and Durret book
Yes: assuming $B_t$ is a random variable, $T$ is also a random variable, and the inf is done pointwise with respect to the sample space.
1
vote
On exponential distributions and dot products
I'm assuming you mean $a, b, c, d$ to be independent exponential random variables with rate parameters $\lambda_1, \lambda_1, \lambda_2, \lambda_2$.
I find that $(ac+bd)/(c+d)$ has mean $\lambda_1^{- …
3
votes
Accepted
Computationally random bitstreams and normalcy
Let $s$ be a computationally random bitstring. Consider $\tilde{s}$
defined by $\tilde{s}(2n) = \tilde{s}(2n+1) = s(n)$. Then $\tilde{s}$ should also be computationally random, but it does not contai …
3
votes
Solution of a 2D Recurrence sequence
If $P_k(t) = \sum_{m=0}^k a_{m,k-n} t^m$ is the generating function of an ascending antidiagonal, we have
$$P_k(t) = \frac{t^k-t}{t-1} + \frac{1+t}{2} P_{k-1}(t), \ P_0(t) = 0 $$
and this can be solv …
1
vote
Estimating expectation of a slightly strange sum
It is possible to take random variables $X_k$ and the corresponding $W_k$
so $\mathbb E[X_k] \to \infty$ while $\mathbb E[W_k]/\mathbb E[X_k] \to 0$. For example, consider
$X = N$ with probability …
0
votes
Accepted
Using common samples to numerically estimate pairwise equality of three random variables
Your two estimators $c_{XY}/n$ and $c_{XZ}/n$ are unbiased estimators of $P(X=Y)$ and $P(X=Z)$ respectively. They are not independent, however. Whether that is "acceptable" might depend on what you' …
0
votes
Left tail of convex combinations of $\chi_1^2$
Let $X = \sum_{i=1}^n a_i Z_i^2$. If $m = \min(a_1,\ldots,a_n)$ and $M = \max(a_1,\ldots,a_n)$, we have $m A \le X \le M A$ where $A$ has $\chi^2$ distribution with $n$ degrees of freedom. Thus
$$\ …
1
vote
Accepted
Properties of Cameron Martin Space
1) To see that $K^{1/2}(H)$ is dense in $H$: if not, there is some nonzero $v$ orthogonal to it. But since $K^{1/2}$ is self-adjoint, that says $0 = (K^{1/2})^* v = K^{1/2} v$, and then $K v = K^{1/2 …