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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions
25
votes
Polynomial representing all nonnegative integers
After thinking about this problem for a bit using rather a naive approach, looking at regions where f grows faster than quadratically (as mentioned in Qiaochu's attempt), it certainly appears that obt …
2
votes
Does Weyl's Inequality prove equidistribution?
This response is in answer to David's further question about whether it is possible to bound the rate at which SN/N tends to zero, as he was wanting to use Weyl's inequality to do.
This is not possibl …
7
votes
1
answer
373
views
Bounding the growth of rational bivariate polynomials from below
The following question is an attempt to find a lower bound for the value of a polynomial at integer points. It is something that I originally thought about while trying to understand how it would be p …
4
votes
A heuristic for the density of solutions to Diophantine equations
Searching including the key phrases "Hardy-Littlewood circle method" and "singular series", as suggested by the other answers, turned up some interesting references which shed light on the question an …
13
votes
3
answers
2k
views
A heuristic for the density of solutions to Diophantine equations
Let $f\in\mathbb{Z}[X_1,\ldots,X_n]$ be a Diophantine equation which, for the purposes of this question, I will assume is homogeneous and nonsingular on $\mathbb{R}^n\setminus\{0\}$ (so that $\nabla f …
7
votes
Is there a finite set of primes such that if K over Q is completely split at all those prime...
No. In fact, given a finite set of primes $S=\lbrace p_1,p_2,\ldots,p_n\rbrace$, we can find a finite extension $K$ of $\mathbb{Q}$ in which elements of $S$ decompose in any way that we like. That is, …
23
votes
Accepted
A question of Erdős on equidistribution
The statement was shown to be false by J. Bourgain in a paper published in 1988 (Almost Sure Convergence and Bounded Entropy, doi:10.1007/BF02765022). Well before either Harman's 1997 book and the 200 …
26
votes
Why should I believe the Mordell Conjecture?
I'm not an expert here, but reading J.S.Milne's notes on elliptic curves (available from his website), I noticed the following statement.
ASIDE 2.4 There is a heuristic
explanation for Mordell’s …
19
votes
Upper bounds for the sum of primes up to $n$
It is not difficult to calculate upper bounds on $s(n)$ from bounds on the prime counting function $\pi(n)$. Just use integration by parts,
$$
s(n) = \int_0^n x\,d\pi(x) = n\pi(n) - \int_0^n\pi(x)\,dx …
22
votes
Accepted
Have all numbers with "sufficiently many zeros" been proven transcendental?
I don't know of a paper proving the result, but I can prove it for you now. In fact, the methods in the paper you link generalize to an arbitrary base $g\gt2$. The authors of the paper don't seem to t …
32
votes
Accepted
are there infinitely many triples of consecutive square-free integers?
To expand on the answer in my comment, the proportion of integers $a$ for which $4a+1,4a+2,4a+3$ are all squarefree is $\prod_{p\not=2}(1-3/p^2)$, with the product taken over all odd primes $p$. As th …
8
votes
Accepted
Meromorphic continuation of a Dirichlet series associated to an irrational number
Yes, the conjecture is true -- $\zeta_\theta(s)$ extends to a meromorphic function on $\mathbb{C}$ for all real quadratic irrationals $\theta$ with poles at $s=2$, $s=1$ and in the infinite set of ver …
3
votes
Accepted
Limit connected with a periodic function
No, convergence does not hold for all irrational $x$. I posted a full answer to the question at math.stackexchange and I'll summarize the result here.
There are uncountably many values of $x$ for whi …
15
votes
Two questions about finiteness of ideal classes in abstract number rings
To answer Question 1: Yes, there do exist integrally closed abstract number rings with infinite class group.
By factorization of ideals, for $R$ to be an abstract number ring it is enough that it is …
3
votes
Does Weyl's Inequality prove equidistribution?
I made the following attempt to prove the result using Weyl's inequality, which failed. It only manages to show that $\liminf S_N/N\to0$. However, as mentioned in Benoît's answer, with a little bit mo …