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8 votes
1 answer
677 views

Infinite series and sum of two squares

Consider the following infinite sequence $a(n)$ generated by $$\sum_{n\geq0} a(n)q^n =\frac{\sum_{k\geq0}F(2k+1)q^{\binom{k+1}2}}{\sum_{k\geq0} q^{\binom{k+1}2}}$$ where the $F(2k+1)$ are the odd ...
T. Amdeberhan's user avatar
2 votes
1 answer
215 views

Representing positive integers $n$ by binary forms $n=ax^2+by^2$, $a\geq 0$, $b\geq 0$

In there a finite set of $(a_k,b_k)\in\mathbb{Q}_{\geq 0}\times \mathbb{Q}_{\geq 0}$ so that any $n\in \mathbb{Z}_{>0}$ can be written as $n=a_k x^2+b_k y^2$ for some $k$ ? This is related to ...
Dima Pasechnik's user avatar
1 vote
1 answer
182 views
+50

On a probabilistic integer factorization algorithm given bounds for one prime factor

We got a probabilistic integer factorization algorithm and experimental evidence with large integers given bounds for one factor. Let $D \ge 2$ be real number and let $p,q$ be primes and $N=pq$. ...
joro's user avatar
  • 25.4k
1 vote
0 answers
267 views

Are there connections between Calabi-Yau manifolds and number theory?

I am interested in understanding whether there are any significant connections between Calabi-Yau manifolds and number theory. Calabi-Yau manifolds are central objects in algebraic geometry and string ...
Abdullah M Al-jazy's user avatar
3 votes
1 answer
123 views

Reference request: ray class group as quotient of finite ideles

Let $K$ be a number field, and write $\mathbb{A}_{K,f}^\times$ for the group of finite ideles of $K$. That is $$ \mathbb{A}_{K,f}^\times = \{(u_v)_v \in \prod_{v \nmid \infty} K_v^\times : v(u_v) = 0 \...
Sebastian Monnet's user avatar
-3 votes
1 answer
195 views

Bounding a number-theoretic integral

Find a good upper bound on $$\int_1^T\frac{\zeta'(s)}{\zeta(s)\zeta(1-s)}X^sdt,$$ where $s=c+it$ for a constant $c>1$ and $X>0$ is a parameter. If needed, we can assume RH. My attempt here is ...
charlie_beck's user avatar
1 vote
0 answers
45 views

Proper Pisot n-tuples

Recall that x is a Pisot number if it is real and x>1, while all of its conjugates have magnitude less than 1. Then $\{(x)^k\}$ (where $\{\cdot\}$ is the fractional part of x) approaches 0 ...
ericf's user avatar
  • 680