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3 votes
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Schatten norm estimate of spatially truncated resolvent of Laplacian

Consider the operator $-\Delta$ on $L^2(\mathbb R^d)$. In my studies I stumbled upon operators of the form $$1_{\Gamma_n} (-\Delta -z)^{-1} 1_{\Gamma_m},$$ where $1_{\Gamma_m}$ denotes multiplication ...
user271621's user avatar
2 votes
0 answers
52 views

On distributions and kernels

Let $U\subset\mathbb{R}^{d}$ be an open set and consider $X=\mathbb{R}\times U$. Now, lets consider a smooth (regular) kernel $k_{A}\in C^{\infty}(X\times X)$ and corresponding continuous operator $A:...
G. Blaickner's user avatar
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2 votes
0 answers
79 views

One-dimensional integral equation uniquely solvable?

I recently met a question similar to this one and I would like to post it here, because I basically found nothing: We define the (possibly unbounded) integral operator $T:D(T) \subset C_0(\mathbb{R}) ...
BaoLing's user avatar
  • 329
1 vote
0 answers
125 views

Convergence of solutions of the volterra integral equation with convergent kernels

Consider the following Volterra integral equation $$ g(t) = \int_0^t K_n(t,s)w_n(s) ds $$ where g(t) and K_n(t,s) are continuous and $K_n(t,s)\geq K_{n+1}(t,s)$ for all $t,s$. Moreover, $K_n(t,s)$ ...
user155214's user avatar
0 votes
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145 views

Why is this function in $L^1$?

I had a question about a claim made in the paper "Group Invariant Scattering" and why it is true. Consider the function $h_j(x) = 2^{nj}\psi(2^jx)$, where $\psi$ is a function such that $\...
Bobo's user avatar
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