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9 votes
2 answers
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Elementary end extensions of models of Peano Arithmetic in uncountable languages

A well-known theorem of Mills asserts that there is a model of Peano Arithmetic $M$ in an uncountable language such that $M$ has no elementary end extension (e.e.e.). I ask whether every complete ...
shahram's user avatar
  • 1,403
8 votes
3 answers
427 views

Uncountable model of bounded arithmetic with an elementary end extension

Theorem 1.53 (3) in page 227 of Hajek and Pudlak's book, Metamathematics of First-Order Arithmetic, says: Theorem. If $M$ is a countable model of $I\Delta_{0}$ such that $M$ has a proper elementary ...
shahram's user avatar
  • 1,403
7 votes
1 answer
198 views

A well-behaved $A$ that is almost contained in every element of some filter for a countable arithmetically closed family $\mathfrak X$

The question has relevance for constructing Scott sets with certain extra desirable properties. Suppose that $\mathfrak X$ is a countable arithmetically closed family of subsets of $\mathbb N$: ...
Victoria Gitman's user avatar
10 votes
3 answers
618 views

If an oracle Turing machine halts with every infinite arithmetic oracle, can it fail to halt with some non-arithmetic oracle?

Let $e$ be an index of an oracle Turing machine program and $k$ be some natural number. Let us say that a subset of $\mathbb N$ is arithmetic if it is definable in the model $\langle \mathbb N,+,\cdot,...
Victoria Gitman's user avatar
7 votes
1 answer
701 views

Has Ribet's theorem been proved using only finite powers of primes?

Ribet proved the Serre epsilon conjecture using $p$-adic Galois representations (http://math.berkeley.edu/~ribet/Articles/invent_100.pdf). Can someone show how to replace all use of $p$-adics in ...
Colin McLarty's user avatar
39 votes
3 answers
3k views

Why do stacked quantifiers in PA correspond to ordinals up to $\epsilon_0$?

I am trying to understand why induction up to exactly $\epsilon_0$ is necessary to prove the cut-elimination theorem for first-order Peano Arithmetic; or, as I understand, equivalently, why the length ...
Eliezer Yudkowsky's user avatar
0 votes
1 answer
495 views

Infinite board games: sentences about

As a unified approach if we have an ( read any) infinite board game described as $\mathcal{G}$ using a particular axiom set A.. can a sentence be devised in A which automatically answers the basic ...
ARi's user avatar
  • 851
3 votes
2 answers
353 views

Reference request: Minimal Axiomatizations of PA over (+,x,<=).

Many years ago, when I was still a high school student, I came up with a certain first-order axiomatization of PA over the signature (+, x, ≤). Out of nostalgia, I've decided to clean up what I ...
Vladimir Sotirov's user avatar
57 votes
2 answers
7k views

What arithmetic information is contained in the algebraic K-theory of the integers

I'm always looking for applications of homotopy theory to other fields, mostly as a way to make my talks more interesting or to motivate the field to non-specialists. It seems like most talks about ...
David White's user avatar
  • 30.3k
27 votes
1 answer
678 views

Decidability of equality of expressions built using 1,+,-,*,/,^

Consider expressions built using number $1$, arithmetical operators $+, -, *, /$ and exponentiation ^ (in case of multiple values, the principal value is assumed, the same way as it implemented in ...
Zakharia Stanley's user avatar
11 votes
1 answer
433 views

Does any lower bound on proofs of FLT improve Shepherdson 1965?

In 1965 Shepherdson proved that FLT is independent of the fragment of PA that uses only open induction and signature $0,S,+\times$. Indeed $2x+1\neq 2y$ is independent of that fragment. Schmerl ...
Colin McLarty's user avatar
12 votes
1 answer
976 views

What metatheory proves $\mathsf{ACA}_0$ conservative over PA?

Simpson's book shows $\mathsf{ACA}_0$ is conservative over $\mathsf{PA}$ in the natural way by model theory using definable subsets. Of course, $\mathsf{ACA}_0$ being conservative over PA is ...
Colin McLarty's user avatar
2 votes
2 answers
1k views

Are there non-commutative models of arithmetic which have a prime number structure?

Peano Arithmetic (PA) models have a prime number structure and commutativity of addition and multiplication. Presburger arithmetic (PrA) models of arithmetic have addition without multiplication and ...
user avatar
9 votes
1 answer
1k views

ERA, PRA, PA, transfinite induction and equivalences

I'm quite sure I don't understand very well the links between proof theoretical ordinals of theories, the axioms of transfinite induction and the objects a theory can prove to exist. For instance I'm ...
Primitive Recursive Fab's user avatar
0 votes
2 answers
2k views

Gödel, Escher, Bach: b is a power of 10. [closed]

I’d like to verify if my formula correctly expresses that a number is a power of $ 10 $, using the $ \sf{TNT} $ language provided by Hofstadter in his famous book Gödel, Escher, Bach: An Eternal ...
almahed's user avatar
1 vote
3 answers
3k views

Why Does Induction Prove Multiplication is Commutative?

Andrew Boucher's General Arithmetic (GA2) is a weak sub-theory of second order Peano Axioms (PA2). GA has second order induction and a single successor axiom: $$\forall x \forall y \forall z\bigr((Sx=...
Russell Easterly's user avatar
0 votes
0 answers
315 views

Definitions for Oddness

In the thread Even Xor Odd Infinities I defined odd models of Modular Arithmetic (MA) as models satisfying the axioms of MA and two first order statements. Even XOR Odd Infinities? $O1) \forall x(x=0 ...
Russell Easterly's user avatar
12 votes
1 answer
1k views

Is an ultrafinitist Hilbert's program doomed?

Hilbert's program is popularly understood as an attempt to justify infinitary mathematics with a finitary consistency proof. Godel's Second Theorem is usually considered as showing this is not ...
abo's user avatar
  • 1,974
20 votes
3 answers
2k views

Can FPA really prove its consistency?

I will ask the question first and then explain. QUESTION: FPA can prove its own consistency in the Godelian sense. But can it really prove its consistency? FPA is a multi-sorted first-order theory,...
abo's user avatar
  • 1,974
6 votes
3 answers
1k views

Provability in Second-Order Arithmetic without the Successor Axiom

Consider second-order Peano Arithmetic Z2, i.e. the two-sorted first-order theory with induction and comprehension. Remove the assumption about the totality of the successor relationship (the ...
abo's user avatar
  • 1,974
6 votes
2 answers
929 views

First-order vs second-order provability

Modular Arithmetic (MA) has the same axioms as first order Peano Arithmetic (PA) except ∀x(Sx≠0) is replaced with ∃x(Sx=0). Let MA2 be the second-order variation, with second-order induction. ...
abo's user avatar
  • 1,974
30 votes
2 answers
3k views

Even XOR Odd Infinities?

Modular Arithmetic (MA) has the same axioms as first order Peano Arithmetic (PA) except $\forall x (Sx \ne 0)$ is replaced with $\exists x(Sx = 0)$. (http://en.wikipedia.org/wiki/Peano_axioms#First-...
Russell Easterly's user avatar
2 votes
0 answers
84 views

Seeking name for an order raising operator in Higher Order Arithmetic.

Any class $X$ of order $j$ in HOA is in bijection with the order $j+1$ class built up from singletons $\{x\}$ of natural numbers $x$ just the way that $X$ is built up from the numbers $x$. And of ...
Colin McLarty's user avatar
8 votes
1 answer
545 views

How arithmetical is algebraic exponentiation?

Suppose $K$ is an exponential real closed field, i.e. there is an isomorphism, say exp, between the additive group of $K$ and the multiplicative group of its positive elements. Assume further that $Z$ ...
M Carl's user avatar
  • 521
2 votes
0 answers
223 views

Is this fragment of arithmetic on $p^{-\infty} {\mathbb Z}$ decidable?

Let $p$ be a prime number. Consider the abelian group $p^{-\infty} {\mathbb Z} = \bigcup p^{-n} {\mathbb Z}$ consisting of rational numbers whose denominator is a power of $p$, under addition. View $...
Marty's user avatar
  • 13.3k
7 votes
1 answer
414 views

Is there an $E_1$-definition of primality?

Here, $E_1$ denotes the set of arithmetic formulas starting with a bounded existential quantifier, followed by a quantifier-free formula. Is there an $E_1$-formula $\phi$ such that $\phi(n)$ holds iff ...
M Carl's user avatar
  • 521
9 votes
1 answer
898 views

Does higher order arithmetic interpret the axiom of choice?

By second order arithmetic I mean the axiomatic theory $Z_2$, that is Peano arithmetic extended by second order variables with the full comprehension axiom, and not defined semantically using power ...
Colin McLarty's user avatar
3 votes
2 answers
624 views

Models of the natural numbers in ultrapowers in the universe.

Our question arises from wondering about the systems of natural numbers in models ZFC + Con(ZFC) and ZFC + $\neg$Con(ZFC). In thinking of the systems of natural numbers of these models, we came to ...
user avatar
8 votes
2 answers
2k views

Axiom to exclude nonstandard natural numbers

In Peano Arithmetic, the induction axiom states that there is no proper subset of the natural numbers that contains 0 and is closed under the successor function. This is intended to rule out the ...
David Wasserman's user avatar
3 votes
1 answer
405 views

Godel 's Ladder: Undecidable PI_N sentences for N =2, 3, ......

After Godel's groundbreaking results, a plethora of $\Pi_1^0$ undecidable arithmetical sentences have been found by many authors. But what about $\Pi_n^0$ for $n=2,3,.....$ ? There are, to my ...
Mirco A. Mannucci's user avatar
12 votes
2 answers
973 views

Z_2 versus second-order PA

These days, Peano Arithmetic ($PA$) refers to the first-order version of the axioms, where induction is only over formulas referring to natural number variables. Peano's original version of the ...
David Roberts's user avatar
  • 35.5k
1 vote
3 answers
996 views

Applicability of Deduction theorem to Primitive recursive arithmetic [closed]

Hello. I already asked the question here. The main point is that I tried to prove in Primitive recursive arithmetic (PRA) the totality of the Ackerman function, and I found, that the single thing ...
eugepros's user avatar
4 votes
2 answers
743 views

NNO = (first order) PA

Recall the definition of a Natural Numbers Object in a topos, and the first order axioms for Peano Arithmetic. I am more familiar with the first definition than the second, so I cannot tell from the (...
David Roberts's user avatar
  • 35.5k
5 votes
2 answers
2k views

How many models of Peano arithmetic are isomorphic to the standard model and how many models of Peano arithmetic are non-standard?

I am currently writing a paper on non-standard models of Peano arithmetic and I am having trouble finding references or information that discuss the relative sizes of how many models of Peano ...
Samuel Reid's user avatar
  • 1,441
7 votes
4 answers
912 views

Reference Request: Non-Standard Models of PA

I am attempting to write an expository paper on non-standard models of PA that is accesible to students taking an introductory graduate course in mathematical logic (covering Godel's incompleteness ...
Samuel Reid's user avatar
  • 1,441
25 votes
4 answers
3k views

What can be proven in Peano arithmetic but not Heyting arithmetic?

Hi. I'll confess from the start to not being a logician. In fact this question came up not from research but during a discussion with a friend about whether the classical proof that $\sqrt{2}$ is ...
Brad Rodgers's user avatar
  • 2,151
12 votes
4 answers
931 views

Parameters in arithmetic induction axiom schemas

The induction schema of Peano Arithmetic is standardly given as the universal closure of $\phi(0)\land \forall x (\phi(x)\rightarrow \phi(x+1)) \rightarrow \forall x\phi(x)$. However, since the ...
Marian's user avatar
  • 313
2 votes
3 answers
552 views

Generalizations of PA and its standard and non-standard models

Consider Peano's axioms — in its first-order version and without addition and multiplication — with its single injective function $S$: $(\forall x) \neg Sx = 0$ $\Big(\phi(0)\ \ \&\ \...
Hans-Peter Stricker's user avatar
22 votes
5 answers
1k views

What is the spectrum of possible cofinality types for cuts in an ordered field? Or in a model of the hyperreals? Or in a nonstandard model of arithmetic?

I am interested to know the full range of possibilities for the cofinality type of cuts in an ordered field and in other structures, such as nonstandard models of arithmetic. Definitions. ...
Joel David Hamkins's user avatar
8 votes
1 answer
897 views

Nelson natural number objects in a topos (say)

Nelson's predicative arithmetic (survey article) is a very weak system of arithmetic extending Robinson's $Q$ (Wikipedia). We can have natural number objects in a topos, or even a merely finitely ...
David Roberts's user avatar
  • 35.5k
4 votes
2 answers
924 views

Natural numbers of great kolmogorov complexity

Before I ask my question, let me give you a mini-preamble: in 2006, during an animated discussion on feasibility, ultrafinitism, and what else on FOM, I introduced (informally, and to speak the tuth, ...
Mirco A. Mannucci's user avatar
6 votes
3 answers
1k views

Set theory inside arithmetics via the Ackermann yoga

Among the basic results of logic which, simple as they are, never fail to intrigue me, is Ackermann's interpretation of ZF-Infinity in PA (see for refs this MO question and here for an excellent ...
Mirco A. Mannucci's user avatar
21 votes
5 answers
2k views

Alternative Arithmetics

Although, beyond any doubts, $ZFC$ is by and large the predominantly accepted theory of sets, there have been a few attempt to establish some serious competitors in town. I just quote two of them (...
Mirco A. Mannucci's user avatar
32 votes
11 answers
11k views

Is PA consistent? do we know it?

1) (By Goedel's) One can not prove, in PA, a formula that can be interpreted to express the consistency of PA. (Hopefully I said it right. Specialists correct me, please). 2) There are proofs (...
3 votes
1 answer
437 views

Axiomatizations of complete theories

This question was motivated by this recent question by Ricky Demer. In his paper $\Pi^0_1$ classes and Boolean combinations of recursively enumerable sets, Carl Jockusch showed that there is no ...
François G. Dorais's user avatar
10 votes
2 answers
2k views

The different Branches of Arithmetic

... "and then the different branches of Arithmetic-- Ambition, Distraction, Uglification, and Derision." (Alice in Wonderland, chapter IX: the Mock Turtle's story) As a child I wondered for ...
Pietro Majer's user avatar
  • 60.6k
18 votes
3 answers
2k views

Is Robinson Arithmetic biinterpretable with some theory in LST?

Let ZFC$^{\text{fin}}$ be ZFC minus the axiom of infinity plus the negation of the axiom of infinity. It is well-known that ZFC$^{\text{fin}}$ is biinterpretable with Peano Arithmetic. In this sense ...
Adam's user avatar
  • 3,267
7 votes
1 answer
694 views

Implication of Polignac's conjecture on prime distribution in models of PA

Polignac's conjecture (PC) is that there exists infinitely many pairs of consecutive prime numbers that are a distance $d$ apart for some natural number $d$. The twin prime conjecture is the ...
Jason's user avatar
  • 2,762
0 votes
2 answers
998 views

Is division considered the mathematical dual of multiplication? [closed]

I'm doing a bit of research for a tech presentation that touches on the subject of mathematical duality. (To be clear, my presentation is not on mathematics or duality, but mentions duality in passing....
Judah Himango's user avatar
3 votes
0 answers
343 views

example just slightly better than the greedy construction

Roth's theorem provides an estimate for the largest size of a nonaveraging subset of $\lbrace 1,2, \ldots ,n \rbrace$ (a set of integers is nonaveraging if it does not contain any nontrivial three-...
Ewan Delanoy's user avatar
  • 3,595

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