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4 votes
0 answers
162 views

Can this theory of dyadic rationals prove that multiplying by three is the same as summing thrice?

(This question arose from a discussion with Jade Vanadium about a theory of dyadic rationals.) Let $T$ be the 2-sorted FOL theory with sorts $ℕ,ℚ$ and constant-symbols $0,1$ and binary function-...
user21820's user avatar
  • 2,912
34 votes
2 answers
2k views

What is the logical status of the sentence combining the ideas of Löb and Rosser, "this sentence is provable before any proof of its negation"?

Logicians are familiar with the variety of self-referential sentences expressible in the language of arithmetic: The Gödel sentence, "this sentence is not provable", which indeed is not ...
Joel David Hamkins's user avatar
2 votes
2 answers
294 views

Can we use remote provability to prove the first incompleteness theorem sans $\omega$-consistency?

Let $\mathcal g_1$ denote the usual Godel sentence defined as: $$ \mathcal g_1 \iff \neg\exists x:\operatorname {Proof}_T(x, \ulcorner \mathcal g_1 \urcorner)$$ Lets suppose that $\sf T$ is ...
Zuhair Al-Johar's user avatar
6 votes
0 answers
407 views

Can Set Theory be turned into Infinite Arithmetic?

The following system I'd label as "Infinite Arithmetic" is simply an endeavor to extend second order arithmetic to the infinite ordinal world, and extending with it the representation of ...
Zuhair Al-Johar's user avatar
3 votes
0 answers
206 views

Independence and truth in PA

By $\textbf{PA}$ I will mean the usual first-order Peano Arithmetic. I will denote an element of $\mathbb{N}$ by $n$, and by $[n]$ I will denote the corresponding term in the language of $\textbf{PA}$:...
jg1896's user avatar
  • 3,318
2 votes
1 answer
194 views

Do these two provability theories over PA differ in consistency strength?

This posting is related to the answer to this question. Lets extend the language of $\sf PA$ with a monadic symbol "$\vdash$", add to the formula formation rules, the rule: if $(\phi)$ is a ...
Zuhair Al-Johar's user avatar
1 vote
2 answers
231 views

Does strong provability imply syntactical provability?

This posting is related to the answer to this question. Lets extend the language of $\sf PA$ with a monadic symbol "$\vdash$", add to the formula formation rules, the rule: if $(\phi)$ is a ...
Zuhair Al-Johar's user avatar
1 vote
0 answers
129 views

Is set theory interpretable in infinite primitive recursive arithmetic?

In A Formalization of the Theory of Ordinal Numbers, Takeuti interprets $\sf ZFC$ in a first order theory extending first order arithmetic to the infinite ordinal realm, while at the same time ...
Zuhair Al-Johar's user avatar
32 votes
11 answers
11k views

Is PA consistent? do we know it?

1) (By Goedel's) One can not prove, in PA, a formula that can be interpreted to express the consistency of PA. (Hopefully I said it right. Specialists correct me, please). 2) There are proofs (...
6 votes
0 answers
192 views

How to show that $\omega^\omega$ is well-founded in PA?

By induction on $n$ variables I can show that for any meta-natural number $n$, PA proves well-foundedness of $\omega^n$. However it is well known that PA proves well-foundedness of $\omega^\omega$ ...
SmileLee's user avatar
  • 101
6 votes
1 answer
232 views

Interpretation of $ZFC^-$ in 2nd order Peano arithmetic

Let $Z_2^-$ be the 2nd order Peano arithmetic without the schema of Countable Choice. It has been known, since 1960s at least, that $ZFC^-$ (without the power set) admits an interpretation in $Z_2$ ...
Vladimir Kanovei's user avatar
7 votes
0 answers
110 views

How tightly are decidability and "induction-completeness" linked?

It is known that there are a number of expansions of the structure $\mathfrak{N}:=(\mathbb{N};+)$ which are decidable (= have computable theories); one such example is the expansion by a predicate ...
Noah Schweber's user avatar
9 votes
0 answers
210 views

Is there an Arithmetized Completeness theorem for intuitionistic theories?

For classical theories, Henkin's completeness proof can be arithmetized. This leads to the result that for classical theories $T$ and $S$ if $\sigma$ is a formula enumerating $S$ in $T$ then $S \leq T ...
Spencer Woolfson's user avatar
17 votes
3 answers
3k views

Did Edward Nelson accept the incompleteness theorems?

Edward Nelson advocated weak versions of arithmetic (called predicative arithmetic) that couldn't prove the totality of exponentiation. Since his theory extends Robinson arithmetic, the incompleteness ...
BPP's user avatar
  • 675
11 votes
2 answers
967 views

How much induction does a p-adic valuation need?

Recently I learned a nice constructive proof of the irrationality of $\sqrt{2}$, which uses the 2-adic valuation of an integer: the count of how many times a number is divisible by 2. The valuation ...
David Roberts's user avatar
  • 35.5k
2 votes
0 answers
75 views

Can all the strongly provable theorems of $\sf PA+\neg Con(PA)$ be captured in an effective manner through alternative kind of provability?

If we extend $\sf PA$ with the following axiom asserting its own inconsistency: Inconsistency: $\exists x: \operatorname {Proof}_{\sf PA} (x, \ulcorner 0=1 \urcorner)$ For short denote this axiom by $\...
Zuhair Al-Johar's user avatar
3 votes
0 answers
283 views

What is the meaning and proof of Harvey Friedman’s ultrafinite incompleteness sentence?

On page 7 of his paper “Adventures in Incompleteness”, Harvey Friedman states the following: IN ANY LONG ENOUGH SEQUENCE $x_1,...,x_n$ FROM $\{1,2,3\}$, SOME $(x_i,...,x_{2i})$ IS A SUBSEQUENCE OF ...
Keshav Srinivasan's user avatar
7 votes
1 answer
262 views

What is known about first order logic of $\mathbb{N}$ with + and a unary predicate?

In "Weak Second-Order Arithmetic and Finite Automata", Büchi claims that the first order theory of $\mathbb{N}$ with + and a predicate for recognizing powers of 2 ($Pw_2$) is expressively ...
TomKern's user avatar
  • 429
5 votes
1 answer
148 views

Does visible nonstandardness imply visible ill-foundedness?

For $X\subseteq\mathfrak{M}\models \mathsf{TA}$, say that $X$ is $\mathfrak{M}$-disruptive iff there is some formula $\varphi$ in the language of arithmetic + a new unary predicate symbol $U$ such ...
Noah Schweber's user avatar
19 votes
3 answers
2k views

Is platonism regarding arithmetic consistent with the multiverse view in set theory?

A "truth" platonist for arithmetic believes, given a statement in the language of arithmetic, that the problem whether the statement is true has a definite answer. Prof. Hamkins has argued for a ...
AEWARG's user avatar
  • 261
-2 votes
1 answer
369 views

Is this extension of the projectively extended real line, consistent?

This posting has been Edited. The edited material shall be noted. The projectively extended real line $\hat {\mathbb R}= \mathbb R \cup \{\infty\}$ is one system which allows division by zero! Yet it ...
Zuhair Al-Johar's user avatar
3 votes
1 answer
140 views

Can we always know if an algebraic rule over the reals is preserved over the extended reals or not?

Recall a prior posting titled Is there an effective way to generalize this approach of affinely extending the number line?, and especially the accepted answer given to it. So we are working in $\sf ...
Zuhair Al-Johar's user avatar
5 votes
3 answers
1k views

Are there first-order statements that second order PA proves that first order PA does not?

Are there first-order statements that second order PA proves that first order PA does not? Is this known one way or the other? Could you share an example? (edit: to clarify, by 'second order PA' I don'...
pathway's user avatar
  • 117
1 vote
1 answer
213 views

Is there an effective way to generalize this approach of affinely extending the number line?

The general approach here is a follow up of the approach outlined in a prior posting on extending the projectively extended real line. In particular arithmetic operators break down to ternery ...
Zuhair Al-Johar's user avatar
16 votes
2 answers
1k views

How special is first-order $\mathsf{PA}$?

This is a modified version of a question which was asked and bountied at MSE without success. Below, "$\mathsf{PA}$" refers to first-order Peano arithmetic. There are various "...
Noah Schweber's user avatar
1 vote
0 answers
118 views

Which real functions benefit from the Fundamental Theorem of Interval Analysis?

I'm reading Introduction to Interval Analysis, by Moore, Baker & Cloud and complementing it with Global Optimization using Interval Analysis, by Hansen & Walster. Theorem 5.1 - Fundamental ...
Lost in Traslations's user avatar
16 votes
1 answer
532 views

Are there signatures escaping from Tennenbaum's Theorem?

By Tennenbaum's Theorem all recursive models of $\mathsf{PA}$ are isomorphic to the standard model. And by a result of Wilmer this holds even for models of the theory $\mathsf{IE}_1\subseteq \mathsf{I}...
Fedor Pakhomov's user avatar
7 votes
1 answer
341 views

Can this weakish system of arithmetic express multiplication for second-sort numbers?

Consider a 2-sorted first-order logic with equality (for first-sort entities). The first sort consists of numbers, the second sort (which will be capitalized) of unary functions. There is one constant,...
abo's user avatar
  • 1,974
2 votes
0 answers
79 views

Which sets of natural numbers are "lambda-analytic"?

Begin with a bit of notation. Let $t = t_0, \ldots, t_d$ be a finite sequence of real numbers. Define $$\lambda^t(x) = x^{t_0} \log(x)^{t_1} \log(\log(x))^{t_2} \cdots.$$ for all real numbers $x \in ...
Marty's user avatar
  • 13.3k
68 votes
4 answers
12k views

Nelson's program to show inconsistency of ZF

At the end of the paper Division by three by Peter G. Doyle and John H. Conway, the authors say: Not that we believe there really are any such things as infinite sets, or that the Zermelo-Fraenkel ...
Andreas Thom's user avatar
  • 25.5k
54 votes
1 answer
3k views

In the two-person Killing the Hydra game, what is the winning strategy?

My question is which player has a winning strategy in the two-player version of the Killing the Hydra game? In their amazing paper, Kirby, Laurie; Paris, Jeff, Accessible independence results for ...
Joel David Hamkins's user avatar
3 votes
0 answers
210 views

Self-referential Quinean proof of Löb's Theorem

Given its relevance for Open-source game theory, Dr. Andrew Critch asks the following about provability logic: We conjecture that Löb’s Theorem can be proven without the use of the modal fixed point $...
Martín S's user avatar
  • 421
0 votes
0 answers
73 views

Least number principle for IOpen fragment of Peano Arithmetic

Is it possible to prove the least number principle in IOpen fragment of Peano Arithmetic, i.e. having induction only for Open formulas?
Viipuri's user avatar
  • 19
6 votes
1 answer
278 views

A "negative" standard system

For $\mathcal{M}$ a (countable) nonstandard model of $\mathsf{PA}$, let $\mathsf{SS}(\mathcal{M})$ be the set of sets of natural numbers coded by elements of $\mathcal{M}$. There are various ways to ...
Noah Schweber's user avatar
2 votes
0 answers
137 views

Can we extend the projectively extended real line with a single number that stands for division of zero by zero?

If we work within $\hat{\mathbb R} = \mathbb R \cup \{\infty\}$, i.e. one point compactification of the real line. We extend $<$ relation on $\mathbb R$ to $\hat <$ defined as: $ x \ \hat{<} \...
Zuhair Al-Johar's user avatar
21 votes
2 answers
1k views

Is factorial definable using a $\Delta_0$ formula?

The factorial function is primitive recursive, and therefore definable by a $\Sigma_1$ formula. Is it also definable by a $\Delta_0$ formula (i.e. bounded quantifiers)? If not, why?
Yoni Zohar's user avatar
7 votes
1 answer
358 views

Proving short consistency: can we do better than brute force search?

This is a minor variation of a question originally asked on MSE by user779130 and bountied by me, without success. Throughout, "length" refers to the number of symbols, not lines, in a proof....
Noah Schweber's user avatar
16 votes
2 answers
2k views

Could Kronecker accept a proof of Goodstein's theorem?

A famous result of Goodstein asserts that the Goodstein sequence of integers terminates. For a precise statement and a short proof, see https://en.wikipedia.org/wiki/Goodstein%27s_theorem. A well ...
Piotr Hajlasz's user avatar
25 votes
4 answers
3k views

What can be proven in Peano arithmetic but not Heyting arithmetic?

Hi. I'll confess from the start to not being a logician. In fact this question came up not from research but during a discussion with a friend about whether the classical proof that $\sqrt{2}$ is ...
Brad Rodgers's user avatar
  • 2,151
4 votes
1 answer
439 views

Alternative proof of Tennenbaum's theorem

The standard proof of Tennenbaums's theorem uses the existence of recursively enumerable inseparable sets and is presented e.g. in Kaye [1, 2], Smith [3]. In the following, $\mathcal{M}$ will always ...
Léreau's user avatar
  • 211
11 votes
0 answers
476 views

Which sentences are "irreducibly" self-referential over $\mathsf{PA}$?

Previously asked at MSE. Below, all sentences/formulas are in the language of arithmetic, and for simplicity we conflate numbers with numerals and sentences with Godel numbers. Say that a sentence $\...
Noah Schweber's user avatar
43 votes
1 answer
3k views

Do the analogies between metamathematics of set theory and arithmetic have some deeper meaning?

By "formal analogies" between the metamathematics of $\mathsf{ZFC}$/set theory and $\mathsf{PA}$(=Peano Arithmetic)/first order arithmetic, I mean facts such as the following: We are considering a ...
Gro-Tsen's user avatar
  • 32.5k
12 votes
2 answers
868 views

The inconsistency of Graham Arithmetics plus $ \forall n, n < g_{64}$

As you all know, Ronald Graham just passed away. He is famous for many fabulous contributions to finite combinatorics, and much much more, but perhaps none of them is as popular as the infamous ...
Mirco A. Mannucci's user avatar
11 votes
2 answers
1k views

Why is there a need for ordinal analysis?

Consider the Peano axioms. There exists a model for them (namely, the natural numbers with a ordering relation $<$, binary function $+$, and constant term $0$). Therefore, by the model existence ...
user3730940's user avatar
11 votes
2 answers
442 views

Are all generalized Scott sets realized as generalized standard systems?

Below, I've focused on PA when lots of other theories would do. If replacing PA with a different theory leads to a more answerable question, feel free to do so. The standard system of a nonstandard ...
Noah Schweber's user avatar
10 votes
1 answer
630 views

Is $\mathsf{R}$ axiomatizable by finitely many schemes?

Recall that $\mathsf{R}$ is the theory of arithmetic consisting of the quantifier-free theory of $(\mathbb{N};+,\times,0,1,<)$ together with, for each $k\in\mathbb{N}$, the sentence $$\forall x[(\...
Noah Schweber's user avatar
4 votes
1 answer
377 views

Does ACA prove categoricity of the reals?

$\def\f#1{\text{#1}}$Does $\f{ACA}$ prove that any two internally complete ordered fields are isomorphic? Here internal completeness is expressed roughly as "every sequence of reals with an upper ...
user21820's user avatar
  • 2,912
0 votes
1 answer
256 views

Is there a non-standard model of PA computable with infinitary computation?

By the Tennenbaum's theorem, there are no non-standard countable models of Peano Arithmetic that are computable using Turing machines. What about models of infinitary computation like infinite time ...
Jozef Mikušinec's user avatar
10 votes
1 answer
807 views

Why can't we embed Tarski's truth in PA?

I recently learned that ZFC can prove $Con(PA)$ because it can give a model of PA, but I'm not given the technical details. (My teacher thinks it is too obvious to even mention.) What plagues me is ...
Paul Sohn's user avatar
  • 171
18 votes
1 answer
3k views

Existence of a model of ZFC in which the natural numbers are really the natural numbers

I know that, from compactness theorem, one can prove that there are models of first order arithmetic in which there is some "number" which is not a successor of zero, in the sense that it is strictly ...
display llvll's user avatar

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