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2 votes
0 answers
192 views

Can PA be acyclically complete?

Any formula $\phi$ in the first order language of arithmetic is to be called acyclic if and only if we can associate with it an acyclic undirected graph whose nodes are the variable symbols occurring ...
Zuhair Al-Johar's user avatar
2 votes
1 answer
194 views

Do these two provability theories over PA differ in consistency strength?

This posting is related to the answer to this question. Lets extend the language of $\sf PA$ with a monadic symbol "$\vdash$", add to the formula formation rules, the rule: if $(\phi)$ is a ...
Zuhair Al-Johar's user avatar
1 vote
2 answers
231 views

Does strong provability imply syntactical provability?

This posting is related to the answer to this question. Lets extend the language of $\sf PA$ with a monadic symbol "$\vdash$", add to the formula formation rules, the rule: if $(\phi)$ is a ...
Zuhair Al-Johar's user avatar
12 votes
1 answer
482 views

Is there a useful measure of density of decidable sentences in PA?

Essential undecidability of PA says every complete extension of PA includes a non r.e. set of new "axioms," all undecidable in PA.  In that sense lots of sentences of PA are undecidable in ...
Colin McLarty's user avatar
11 votes
2 answers
379 views

Can singular long models require less than PA?

Say that a long model is an $\mathfrak{A}\models\mathsf{I\Sigma_1}$ such that $\mathfrak{A}$ has strictly greater cardinality than each of its proper initial segments (in the case $\vert\mathfrak{A}\...
Noah Schweber's user avatar
9 votes
0 answers
210 views

Is there an Arithmetized Completeness theorem for intuitionistic theories?

For classical theories, Henkin's completeness proof can be arithmetized. This leads to the result that for classical theories $T$ and $S$ if $\sigma$ is a formula enumerating $S$ in $T$ then $S \leq T ...
Spencer Woolfson's user avatar
10 votes
2 answers
600 views

Is diamond consistent with 2nd order PA?

If $T$ is a theorem of ZF which says something only about reals, then one may want to prove $T$ using a theory like 2nd order PA or related theories like ZFC$^-$ or GBC$^-$ (minus accounts for the ...
Vladimir Kanovei's user avatar
3 votes
0 answers
283 views

What is the meaning and proof of Harvey Friedman’s ultrafinite incompleteness sentence?

On page 7 of his paper “Adventures in Incompleteness”, Harvey Friedman states the following: IN ANY LONG ENOUGH SEQUENCE $x_1,...,x_n$ FROM $\{1,2,3\}$, SOME $(x_i,...,x_{2i})$ IS A SUBSEQUENCE OF ...
Keshav Srinivasan's user avatar
2 votes
0 answers
79 views

Which sets of natural numbers are "lambda-analytic"?

Begin with a bit of notation. Let $t = t_0, \ldots, t_d$ be a finite sequence of real numbers. Define $$\lambda^t(x) = x^{t_0} \log(x)^{t_1} \log(\log(x))^{t_2} \cdots.$$ for all real numbers $x \in ...
Marty's user avatar
  • 13.3k
1 vote
0 answers
118 views

Which real functions benefit from the Fundamental Theorem of Interval Analysis?

I'm reading Introduction to Interval Analysis, by Moore, Baker & Cloud and complementing it with Global Optimization using Interval Analysis, by Hansen & Walster. Theorem 5.1 - Fundamental ...
Lost in Traslations's user avatar
8 votes
3 answers
1k views

Dedekind-Peano axioms, but numbers have at most one successor

One can consider a variant of the Dedekind-Peano axioms in which one replaces the assumption that every number has exactly one successor by the assumption that every number has at most one successor, ...
James Propp's user avatar
  • 19.7k
5 votes
1 answer
148 views

Does visible nonstandardness imply visible ill-foundedness?

For $X\subseteq\mathfrak{M}\models \mathsf{TA}$, say that $X$ is $\mathfrak{M}$-disruptive iff there is some formula $\varphi$ in the language of arithmetic + a new unary predicate symbol $U$ such ...
Noah Schweber's user avatar
2 votes
0 answers
137 views

Can we extend the projectively extended real line with a single number that stands for division of zero by zero?

If we work within $\hat{\mathbb R} = \mathbb R \cup \{\infty\}$, i.e. one point compactification of the real line. We extend $<$ relation on $\mathbb R$ to $\hat <$ defined as: $ x \ \hat{<} \...
Zuhair Al-Johar's user avatar
6 votes
1 answer
232 views

Interpretation of $ZFC^-$ in 2nd order Peano arithmetic

Let $Z_2^-$ be the 2nd order Peano arithmetic without the schema of Countable Choice. It has been known, since 1960s at least, that $ZFC^-$ (without the power set) admits an interpretation in $Z_2$ ...
Vladimir Kanovei's user avatar
3 votes
1 answer
140 views

Can we always know if an algebraic rule over the reals is preserved over the extended reals or not?

Recall a prior posting titled Is there an effective way to generalize this approach of affinely extending the number line?, and especially the accepted answer given to it. So we are working in $\sf ...
Zuhair Al-Johar's user avatar
3 votes
0 answers
210 views

Self-referential Quinean proof of Löb's Theorem

Given its relevance for Open-source game theory, Dr. Andrew Critch asks the following about provability logic: We conjecture that Löb’s Theorem can be proven without the use of the modal fixed point $...
Martín S's user avatar
  • 421
1 vote
1 answer
213 views

Is there an effective way to generalize this approach of affinely extending the number line?

The general approach here is a follow up of the approach outlined in a prior posting on extending the projectively extended real line. In particular arithmetic operators break down to ternery ...
Zuhair Al-Johar's user avatar
-2 votes
1 answer
369 views

Is this extension of the projectively extended real line, consistent?

This posting has been Edited. The edited material shall be noted. The projectively extended real line $\hat {\mathbb R}= \mathbb R \cup \{\infty\}$ is one system which allows division by zero! Yet it ...
Zuhair Al-Johar's user avatar
7 votes
1 answer
262 views

What is known about first order logic of $\mathbb{N}$ with + and a unary predicate?

In "Weak Second-Order Arithmetic and Finite Automata", Büchi claims that the first order theory of $\mathbb{N}$ with + and a predicate for recognizing powers of 2 ($Pw_2$) is expressively ...
TomKern's user avatar
  • 429
32 votes
2 answers
3k views

Do we expect that sufficiently large computable ordinals settle every question of arithmetic?

I came across a post by Ron Maimon on physics.SE that makes what seems to me to be a very interesting conjecture I've never seen before about what it would take to settle every question of arithmetic. ...
Qiaochu Yuan's user avatar
10 votes
5 answers
2k views

What is the canonical way to extend Peano's axioms to the set of all integers?

My first idea on how to do this would be: $0\in\mathbf Z$ $\forall x\in\mathbf Z,Sx\in\mathbf Z\land Px\in\mathbf Z$ $P$ and $S$ are injective $\forall x\in\mathbf Z,PSx=SPx=x$ some induction axiom ...
user avatar
34 votes
2 answers
2k views

What is the logical status of the sentence combining the ideas of Löb and Rosser, "this sentence is provable before any proof of its negation"?

Logicians are familiar with the variety of self-referential sentences expressible in the language of arithmetic: The Gödel sentence, "this sentence is not provable", which indeed is not ...
Joel David Hamkins's user avatar
1 vote
0 answers
117 views

Can this type theory interpret second order arithmetic?

Language: multi-sorted first order logic with equality and membership, where for each natural $t$ there is a set $x^t$ of sort $t$. Equality "$=$" only occurs between variables of the same ...
Zuhair Al-Johar's user avatar
6 votes
1 answer
278 views

A "negative" standard system

For $\mathcal{M}$ a (countable) nonstandard model of $\mathsf{PA}$, let $\mathsf{SS}(\mathcal{M})$ be the set of sets of natural numbers coded by elements of $\mathcal{M}$. There are various ways to ...
Noah Schweber's user avatar
32 votes
2 answers
3k views

Can we interpret arithmetic in set theory, with exactly PA as the ZFC provable consequences?

There are many interpretations of arithmetic in set theory. The Zermelo interpretation, for example, begins with the empty set and applies the singleton operator as successor: $$0=\{\ \}$$ $$1=\{0\}$$ ...
Joel David Hamkins's user avatar
0 votes
0 answers
152 views

What is the strength of allowing multiple predecessor numbers?

If we have a theory of numbers, pairs of numbers, and sets of those, and axiomatize that the relation $<$ on numbers is both extensional and well founded, then this theory would prove all PA axioms ...
Zuhair Al-Johar's user avatar
0 votes
1 answer
150 views

Reflection schema

Peano Arithmetic consists of axioms $P_1, P_2, \ldots P_7$ plus first order classical logic. Let us call this theory $T$. This theory has its unprovable Gödel’s sentence $G$ such that $$ G\...
Newberry's user avatar
11 votes
0 answers
476 views

Which sentences are "irreducibly" self-referential over $\mathsf{PA}$?

Previously asked at MSE. Below, all sentences/formulas are in the language of arithmetic, and for simplicity we conflate numbers with numerals and sentences with Godel numbers. Say that a sentence $\...
Noah Schweber's user avatar
7 votes
1 answer
358 views

Proving short consistency: can we do better than brute force search?

This is a minor variation of a question originally asked on MSE by user779130 and bountied by me, without success. Throughout, "length" refers to the number of symbols, not lines, in a proof....
Noah Schweber's user avatar
11 votes
2 answers
967 views

How much induction does a p-adic valuation need?

Recently I learned a nice constructive proof of the irrationality of $\sqrt{2}$, which uses the 2-adic valuation of an integer: the count of how many times a number is divisible by 2. The valuation ...
David Roberts's user avatar
  • 35.5k
3 votes
0 answers
165 views

Why is the proof of decidability of arithmetic (Theorem 2.1) in Hamkins & Lewis (2000) enough?

Recently, I was reading the paper "Infinite Time Turing Machines" by Hamkins & Lewis. And one of the first theorems (Theorem 2.1) is about decidability of arithmetic. The proof is quite ...
Jeremy's user avatar
  • 31
0 votes
1 answer
256 views

Is there a non-standard model of PA computable with infinitary computation?

By the Tennenbaum's theorem, there are no non-standard countable models of Peano Arithmetic that are computable using Turing machines. What about models of infinitary computation like infinite time ...
Jozef Mikušinec's user avatar
4 votes
0 answers
198 views

Is there a simple proof of consistency of EA?

Let $\mathsf{EA}+\mathsf{CE}$ be elementary arithmetic with cut elimination theorem. Is there a simple (1-)consistency proof of $\mathsf{EA}$ over $\mathsf{EA}+\mathsf{CE}$? I think that a naïve ...
Alwe's user avatar
  • 178
4 votes
1 answer
439 views

Alternative proof of Tennenbaum's theorem

The standard proof of Tennenbaums's theorem uses the existence of recursively enumerable inseparable sets and is presented e.g. in Kaye [1, 2], Smith [3]. In the following, $\mathcal{M}$ will always ...
Léreau's user avatar
  • 211
5 votes
1 answer
283 views

Which arithmetical sentences have no counterexamples in the sense of Kreisel?

It is a well-known fact that given a first-order sentence $\psi$ in prenex normal form $\forall x_1 \exists y_1 \forall x_2 \exists y_2 \dots \forall x_n \exists y_n \theta(x_1,\dots,x_n,y_1,\dots,y_n)...
James E Hanson's user avatar
16 votes
1 answer
532 views

Are there signatures escaping from Tennenbaum's Theorem?

By Tennenbaum's Theorem all recursive models of $\mathsf{PA}$ are isomorphic to the standard model. And by a result of Wilmer this holds even for models of the theory $\mathsf{IE}_1\subseteq \mathsf{I}...
Fedor Pakhomov's user avatar
2 votes
1 answer
147 views

Representation of the equality relation between hereditarily finite sets in weak set theories

Consider General Set Theory ($ \mathsf { GST } $) axiomatized by the following. Axiom of Extensionality: The sets $ x $ and $ y $ are the same set if they have the same members: $$ \forall x \forall ...
Mohsen Shahriari's user avatar
4 votes
1 answer
377 views

Does ACA prove categoricity of the reals?

$\def\f#1{\text{#1}}$Does $\f{ACA}$ prove that any two internally complete ordered fields are isomorphic? Here internal completeness is expressed roughly as "every sequence of reals with an upper ...
user21820's user avatar
  • 2,912
7 votes
0 answers
284 views

Generic behavior of "polynomialish" models of $\mathsf{Q}$

(This question was originally asked and bountied at MSE - with different notation, some more explicit arguments, and topology in place of forcing.) Suppose $\mathcal{R}=(R_i)_{i\in\mathbb{N}}$ is a ...
Noah Schweber's user avatar
5 votes
0 answers
318 views

$\Sigma_n$-complete sets in the Levy hierarchy

Recall that a set $A \subseteq \mathbb N$ is (many-one, Turing) $\Sigma_n$-complete if it's $\Sigma_n$ and any other $\Sigma_n$ set (many-one, Turing) reduces to it. This definition actually makes ...
Corey Bacal Switzer's user avatar
4 votes
0 answers
105 views

Computably saturated Skolem hulls of Morley sequences in $\mathsf{PA}$

Recall that a model $M$ of a first-order theory $T$ (in a computable language $\mathcal{L}$) is computably saturated if for every finite tuple $\bar{a} \in M$ and every computable partial type $\Sigma(...
James E Hanson's user avatar
0 votes
1 answer
270 views

What is the smallest countable limit ordinal in which 'lost melodies' occur

The question is in the title. This question is in response to the following paragraph found at the end of Prof. Hamkins' answer to my MathOverflow question, Are ITTM's necessary to compute Turing's &...
Thomas Benjamin's user avatar
7 votes
1 answer
341 views

Can this weakish system of arithmetic express multiplication for second-sort numbers?

Consider a 2-sorted first-order logic with equality (for first-sort entities). The first sort consists of numbers, the second sort (which will be capitalized) of unary functions. There is one constant,...
abo's user avatar
  • 1,974
7 votes
0 answers
102 views

How similar can a model of $I\Delta_0$ be to the intersection of all of its definable cuts?

Let $M$ be a model of $I\Delta_0$. Recall that a definable cut is a definable (possibly with parameters) subset $I$ of $M$ that is non-empty, downwards closed, and closed under successor. If we ...
James E Hanson's user avatar
3 votes
0 answers
160 views

Is anything known about $\Delta_n$ bounding?

For a class $\Gamma \in \{ \Sigma_n, \Pi_n, \Delta_n \}$ in the arithmetical hierarchy, we can consider the induction, bounding, and least number principles for $\Gamma$: $\mathsf{I}\Gamma$ is $\big[ ...
Jordan Barrett's user avatar
2 votes
1 answer
198 views

Can $\mathsf{RCA}_0$ prove that every nonempty c.e. set $A \subseteq \mathbb{N}$ has a least element?

In other words, can $\mathsf{RCA}_0$ prove that for every function $f\colon \mathbb{N} \to \mathbb{N}$, there is $b \in \mathbb{N}$ such that $$ \exists k \in \mathbb{N},\ f(k) = b\quad \land\quad \...
Jordan Barrett's user avatar
3 votes
0 answers
146 views

Does Robinson arithmetic interpret a Kripke model of the double negation translation of $\mathsf{I}\Delta_0 + \mathrm{Exp}$?

It is a well-known fact that while while Robinson arithmetic can interpret surprisingly strong theories, it cannot interpret $\mathsf{I}\Delta_0 + \mathrm{Exp}$, i.e., Peano arithmetic with induction ...
James E Hanson's user avatar
6 votes
0 answers
428 views

Proof of Tennenbaum's Theorem by McCarty

Tennenbaum's Theorem in its usual form states that for any countable non-standard model $M$ of PA there is no way to code the elements of $M$ as natural numbers such that either the addition or ...
Léreau's user avatar
  • 211
13 votes
1 answer
437 views

What is the proof-theoretic ordinal of bare $\mathsf{NFU}$?

On the Stanford Encyclopedia of Philosophy article on alternative axiomatic set theories, it is stated without reference that bare $\mathsf{NFU}$ (i.e., $\mathsf{NFU}$ without the axiom of infinity) ...
James E Hanson's user avatar
3 votes
1 answer
148 views

Consistency and consistency strength of certain special cuts in $I\Delta_0$

Recall that $I\Delta_0$ is the theory in the language of arithmetic that consists of the axioms of $\mathsf{PA}$ with induction restricted to $\Delta_0$ formulas (i.e., formulas where all quantifiers ...
James E Hanson's user avatar

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