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13 votes
3 answers
1k views

Can ultraproducts avoid all "factor structures"?

This came up in the comments to an answer of Joel's. Suppose $\mathcal{M}_i$ ($i\in I$) are elementarily equivalent structures in the same fixed signature and $\mathcal{U}$ is an ultrafilter on $I$. ...
Noah Schweber's user avatar
13 votes
0 answers
252 views

Intuitionistic proofs of propositional formulae versus natural transformations between finite sets

The setup: Given a formula $\varphi$ of intuitionistic propositional logic (i.e., made from the connectors $\Rightarrow$, $\land$, $\lor$, $\top$ and $\bot$ from propositional variables $A,B,C,\ldots$)...
Gro-Tsen's user avatar
  • 32.5k
13 votes
0 answers
387 views

On sentences true in all finite groups (revisited)

Let $w$ be a group word with variables $\bar x, \bar y$, where $\bar x=(x_1,\dots ,x_m)$ and $\bar y=(y_1,\dots ,y_n).$ I am interested in the following questions. (1) Is the sentence $(\forall\bar ...
owb's user avatar
  • 893
13 votes
1 answer
565 views

Long chains of amorphous cardinalities

An amorphous set is an infinite set that cannot be partitioned into 2 infinite subsets. An amorphous cardinality is the cardinality of an amorphous set. Working in $\sf ZF$, it is consistent that ...
Ynir Paz's user avatar
  • 576
13 votes
1 answer
438 views

Is this notion of finiteness closed under unions?

This was asked and bountied at MSE without success. Throughout, we work in $\mathsf{ZF}$. Say that a set $X$ is $\Pi^1_1$-pseudofinite if for every first-order sentence $\varphi$, if $\varphi$ has a ...
Noah Schweber's user avatar
13 votes
1 answer
524 views

How much determinacy do you need for second order arithmetic to be as strong as ZFC?

From Wikipedia (I couldn't find the original source): $\text{ZFC} + \{\text{there are $n$ Woodin cardinals: $n$ is a natural number}\}$ is conservative over $\text{Z}_2$ with projective determinacy. ...
Christopher King's user avatar
13 votes
3 answers
796 views

How to make countably closed forcing "nice" without choice

When working over a model $V$ of $ZFC$, countably closed forcings are extremely nice: If $\mathbb{P}$ is countably closed, then $V[G]$ has no new $\omega$-sequences of elements of $V$. In ...
Noah Schweber's user avatar
13 votes
3 answers
1k views

Which ordinals can be proof-theoretic ordinals of a reasonable theory?

When talking to a friend recently he asked a question - are there any reasonable first-order theories which have proof theoretic ordinal equal to small or large Veblen ordinal? I have then extended ...
Wojowu's user avatar
  • 28.2k
13 votes
4 answers
2k views

Set-Theoretic Issues/Categories

It is a major bummer that one cannot strictly speaking talk about the category of all categories without saying "it is not really a category, since the morphisms between objects may form a class" and "...
nerses's user avatar
  • 131
13 votes
1 answer
561 views

Iterating Neeman's forcing

In the paper, "Forcing with sequences of models of two types," (MR3201836), Neeman claims that, using a supercompact and a weakly compact above, one can force with his pure side conditions ...
Monroe Eskew's user avatar
  • 18.6k
13 votes
1 answer
472 views

Real numbers with given complexity

This may be an easy question or it may be related to a well known open problem in Computer Science. Let $\alpha>0$. We say that $\alpha$ is computed in time $T(n)$ if there is a Turing machine ...
user avatar
13 votes
1 answer
988 views

What is the proof-theoretic ordinal of PA + Con(PA), PA + Con(PA + Con(PA)) etc., and why?

I seem to remember having read that the proof-theoretic ordinal (sup of ordinals the theory can prove well-ordered) of $\mathsf{PA} + \mathsf{Con}(\mathsf{PA})$ is the same as that of $\mathsf{PA}$, ...
Benya's user avatar
  • 151
13 votes
0 answers
345 views

Can you define a probability measure on the set of countable transitive models of ZFC?

It is well known that the set of hereditarily countable sets $H(\omega_1)$ —or, if you prefer, $H_{\omega_1}$— has cardinality $2^{\aleph_0}$, and I understand that every countable ...
Pedro Sánchez Terraf's user avatar
13 votes
1 answer
1k views

What ccc forcings add a Suslin tree?

In a comment to Miha's question in Forcing PFA with ccc forcing, I suggested that if such situation is even possible, it might be achieved by screwing with PFA by some ccc forcing (e.g. adding a Cohen ...
Asaf Karagila's user avatar
  • 39.8k
13 votes
1 answer
672 views

Forcing PFA with ccc forcing

Is it consistent (from suitable large cardinals) that there is a ccc poset which forces PFA? This seems quite implausible to me. If we could force PFA via ccc forcing, the ground model would have to ...
Miha Habič's user avatar
  • 2,389
13 votes
5 answers
1k views

"Let $x \in A$", beginning a proof of "$\forall x \in A$ ...", if A were empty [closed]

I work at a four-year teaching school, where we pride ourselves on teaching pure math, proof, and a rather obsessive carefulness of work. Recently I have been criticized for saying that "Let $x \in A$...
Coward's user avatar
  • 139
12 votes
1 answer
780 views

Does every countable set of Turing degrees have an upper bound, without AC?

It is easy to see that every countable collection of sets $A_n\subseteq\mathbb{N}$ has an upper bound in the Turing degrees, since we can just take a copy of their disjoint sum $\oplus_n A_n=\{\langle ...
Joel David Hamkins's user avatar
12 votes
1 answer
794 views

Is Girard's LU just an embedding of classical and intuitionistic logic into linear logic?

This question is about Girard's system LU, presented in his paper On the unity of logic. Girard starts by giving a "modal" sequent calculus with two zones of both hypotheses and consequents, $\Gamma;\...
Mike Shulman's user avatar
  • 66.8k
12 votes
1 answer
1k views

Is an ultrafinitist Hilbert's program doomed?

Hilbert's program is popularly understood as an attempt to justify infinitary mathematics with a finitary consistency proof. Godel's Second Theorem is usually considered as showing this is not ...
abo's user avatar
  • 1,974
12 votes
6 answers
2k views

Uses of bisimulation outside of computer science.

Bisimulation is one of the most important ideas of theoretical computer science. I was wondering whether bisimilarity is used/known outside of computer science/modal logic? I am aware that it ...
supercooldave's user avatar
12 votes
0 answers
357 views

Undetermined copy/diagonalize games without CH

This question was the motivation behind an earlier question of mine; having thought about it some more, that question seems nontrivial and the connection is actually pretty tenuous anyways, so I've ...
Noah Schweber's user avatar
12 votes
0 answers
721 views

Diagonal lemma from recursion theorem?

Does Gödel's diagonal lemma follow from Kleene's recursion theorem? I believe the converse is true, by an argument like the following. Let e ↦ θe be a bijection between ω and ...
Cole Leahy's user avatar
  • 1,081
12 votes
2 answers
583 views

Do there exist acyclic simple groups of arbitrarily large cardinality?

Recall that a group $G$ is acyclic if its group homology vanishes: $H_\ast(G; \mathbb Z) = 0$. Equivalently, $G$ is acyclic iff the space $BG$ is acyclic, i.e. $\tilde H_\ast(BG;\mathbb Z) = 0$. In ...
Tim Campion's user avatar
12 votes
1 answer
744 views

Is the following construction of the 0-Hecke monoid (well) known?

Let W be a Coxeter group with Coxeter generators S. The corresponding 0-Hecke monoid H(W) has generating set S, the braid relations of W and the relations that each element of S is an idempotent. If ...
Benjamin Steinberg's user avatar
12 votes
2 answers
429 views

Trading Choice for Comprehension (or Replacement)

This question is basically a request for clarification about a remark made by Sam Sanders in a comment to another question: IIUC what he's saying, there are statements that can be proved either with a ...
Gro-Tsen's user avatar
  • 32.5k
12 votes
1 answer
863 views

Probability that a Turing machine is universal?

I choose a Turing machine T with n states and an input tape at random. What can be proven about the probability P_A(n) that it is not decidable whether T will halt for a particular input? What can be ...
twiz's user avatar
  • 187
12 votes
1 answer
1k views

Testing whether $e^x+ax^2+bx+c$ has a zero

What is the simple test with exponential polynomials to determine whether $$f(x)=e^x+ax^2+bx+c$$ has a positive zero? This was prompted by the question about discriminants here. We have an ineffective ...
user avatar
12 votes
1 answer
584 views

"Set theory" founded on lists rather than sets

On a computer, sets are often represented rather "indirectly / implicitly", e.g. in terms of some properties that they or their members satisfy. But some sets can be represented more "directly / ...
Robin Saunders's user avatar
12 votes
1 answer
482 views

Is there a useful measure of density of decidable sentences in PA?

Essential undecidability of PA says every complete extension of PA includes a non r.e. set of new "axioms," all undecidable in PA.  In that sense lots of sentences of PA are undecidable in ...
Colin McLarty's user avatar
12 votes
6 answers
3k views

Can you do math without knowing how to count?

Are there mathematical theories that do not use intuitive integers? [That is, do not use integers to write statements.] Can you propose a theory that describes natural integers, without using ...
Dattier's user avatar
  • 4,074
12 votes
1 answer
475 views

Stone duality for the algebra of Boolean functions such that $f(\top,\dots,\top) = \top$, or: What does the presheaf topos on $FinSet_\ast$ classify?

$\newcommand\FinSet{\mathit{FinSet}}\newcommand\FinBool{\mathit{FinBool}}\newcommand\FreeFinBool{\mathit{FreeFinBool}}\newcommand\Set{\mathit{Set}}\newcommand\Psh{\mathit{Psh}}$It's well-known that ...
Tim Campion's user avatar
12 votes
2 answers
778 views

Why "adding" a single extender cannot give an L-like inner model for say, a strong cardinal?

The constructible universe $L$ is too thin for large cardinals greater than measurable. To build $L$-like inner models for large cardinal, it is natural to think about "adding" the evidences into the ...
Ruizhi Yang's user avatar
12 votes
1 answer
486 views

The strength of "There are no $\Pi^1_1$-pseudofinite sets"

For $\Gamma$ a set of second-order sentences in the empty language, say that a set $X$ is $\Gamma$-pseudofinite if $X$ is infinite but for every sentence $\varphi\in\Gamma$ which is satisfied in every ...
Noah Schweber's user avatar
12 votes
1 answer
429 views

The scope of a "strong Cantor-Bernstein" property

This question is of course related to this earlier MO question, but I don't believe is answered by the posts there. My favorite proof of the Cantor-Schroeder-Bernstein theorem actually establishes ...
Noah Schweber's user avatar
12 votes
1 answer
695 views

A new cardinality living in every forcing extension?

I'm broadly interested in notions of "generic presentability" - when a given object exists in every forcing extension of the universe by some fixed forcing, at least up to the appropriate ...
Noah Schweber's user avatar
12 votes
1 answer
556 views

Building the real from Dedekind finite sets

It is well known that the real numbers can be countable union of countable sets by starting with GCH and taking a finite support permutations while collapsing all of $\aleph_n$ for natural $n$. The ...
Holo's user avatar
  • 1,676
12 votes
1 answer
296 views

Can the cardinal $2^{\aleph_0}$ be order-embedded in ${\cal P}(\omega)/(\text{fin})$?

For $A,B\in{\cal P}(\omega)$ we say $A\subseteq^* B$ if $A\setminus B$ is finite (that is, $A$ is "almost contained" in $B$). We write $A\simeq_{\text{fin}} B$ if $A\subseteq^* B$ and $B\...
Dominic van der Zypen's user avatar
12 votes
1 answer
1k views

Can there be only one (uncountable transitive model of ZFC)?

It is an immediate consequence of Cohen's forcing that if there is one countable transitive model of $\sf ZFC$, then there are many of them. Even if all of these models are of the same height, there ...
Asaf Karagila's user avatar
  • 39.8k
12 votes
1 answer
448 views

Comparing generic versions of $\mathbb{R}$

This question was previously asked and bountied at MSE, unsuccessfully. I'm currently interested in the behavior of cardinalities in generic extensions of models of $\mathsf{ZF+\neg AC}$, and ...
Noah Schweber's user avatar
12 votes
1 answer
834 views

Transfinitely extending $\sf PA$ — can we get stronger than $\sf ZFC$?

Let $\sf PA$ denote the theory of natural numbers with constants $(0, 1)$ and binary operators $(+,\times)$ based on the first-order predicate calculus with equality, having the following axioms, ...
Vladimir Reshetnikov's user avatar
12 votes
1 answer
512 views

What is the "iterated definability" limit of first-order logic?

Roughly speaking, given a set-sized logic $\mathcal{L}$ let $\mathcal{L}'$ be gotten by adding to $\mathcal{L}$ the ability to quantify over $\mathcal{L}$-definable relations. (The details are a bit ...
Noah Schweber's user avatar
12 votes
2 answers
490 views

Conflating reals and sets of countable ordinals "nicely"

It is consistent with ZFC that $2^{\aleph_1}=2^{\aleph_0}$. This can be gotten easily via forcing; more interestingly, it is a direct consequence of forcing axioms (which also set this value at $\...
Noah Schweber's user avatar
12 votes
1 answer
681 views

Can there be a small complete category in ZF?

It's a ZFC theorem of Freyd, any small complete category is a preorder. Freyd's theorem continues to hold in any Grothendieck topos. But Hyland showed it fails in some elementary toposes. I don't ...
Tim Campion's user avatar
11 votes
1 answer
812 views

Set-theoretic geology: controlled erosion?

I have to say that after the two last posts by Timothy Chow on Forcing I got so intrigued that I am trying to rethink the little I know about this formidable chapter of mathematics. I have also to add ...
Mirco A. Mannucci's user avatar
11 votes
5 answers
6k views

Finding minimal or canonical expressions for Boolean truth tables

This is not an urgent question, but something I've been curious about for quite some time. Consider a Boolean function in n inputs: the truth table for this function has 2n rows. There are uses of ...
Rhubbarb's user avatar
  • 524
11 votes
2 answers
574 views

Identifying a group without 2-torsion

Suppose we have a finitely presented group $G$ with solvable word problem. (For instance, the command RWSGroup in Magma terminates giving us a finite [but possibly gigantic] rewrite system.) Is there ...
Pace Nielsen's user avatar
  • 18.7k
11 votes
2 answers
483 views

The "strong" measure number

Beyond measure zero we have yet another measure-y notion of smallness: strong measure zero. A set $S\subseteq\mathbb{R}$ is strong measure zero if, for any $f:\mathbb{N}\rightarrow\mathbb{R}_{>0}$, ...
Noah Schweber's user avatar
11 votes
3 answers
946 views

When is $\mathbb{L}$-rank definable in inner models of $\mathbb{V} = \mathbb{L}$?

Suppose $\mathbb{V} = \mathbb{L}$ and there is a countable transitive model $\mathbb{M}$ of $ZFC$. Let $\rho$ be the $\mathbb{L}$-rank, i.e. for all $a \in \mathbb{V}$, $\rho(a) = $the least $\alpha$...
Danielle Ulrich's user avatar
11 votes
1 answer
452 views

A weak form of countable choice

Let $\Omega$ be the set/type of truth values. We're using constructive logic. Define $AC_{0, 0} = \forall P : \mathbb{N}^2 \to \Omega, (\forall n \in \mathbb{N}, \exists m \in \mathbb{N}, P(n, m)) \to ...
Mark Saving's user avatar
11 votes
2 answers
720 views

Is there a modern account of Veblen functions of *several* variables?

Veblen $\phi$ functions extend the $\xi \mapsto \phi(\xi) := \omega^\xi$ and the $\xi \mapsto \phi(1,\xi) := \varepsilon_\xi$ functions on the ordinals by repeatedly taking fixed points (I won't ...
Gro-Tsen's user avatar
  • 32.5k

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