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${\rm SL}_2(\mathbb C)$-equivariant K-theory of $\mathbb C P^1$

Consider the action of ${\rm SL}_2(\mathbb C)$ on $\mathbb C P^1$ induced by the action of 2×2 matrices on 2-vectors. Is it true that $K^{{\rm SL}_2(\mathbb C)}(\mathbb C P^1)$ is $\mathbb C[t,t^{-1}]$...
Yellow Pig's user avatar
  • 2,964
1 vote
0 answers
111 views

Unique Hausdorff topology on trivial vector bundle?

Question: Is there a Hausdorff topology other than the product topology on $X\times \mathbb{C}^n$, that turns $(X\times \mathbb{C}^n, \mathrm{pr}_1)$ into a vector bundle, where $\mathrm{pr_1}$ ...
PHmath's user avatar
  • 11
1 vote
0 answers
240 views

Smooth version of the splitting principle

Inspried by this MO question A manifold whose tangent space is a sum of line bundles and higher rank vector bundles we pose the following question as a possible smooth version of the splitting ...
Ali Taghavi's user avatar
4 votes
0 answers
110 views

category of vector bundles with connections and its K-theory

For the category of Hermitian vector bundles with unitary connections, an object is (of course) a Hermitian vector bundle with a Hermitian metric and a unitary connection $(E, g^E, \nabla^E)$. For ...
Ho Man-Ho's user avatar
  • 1,173
0 votes
1 answer
203 views

Equivariant sheaves on $\mathbb P^1$

Let $K(\mathbb P^1)$ be the Grothendieck group of sheaves on $\mathbb P^1$. I want to show that the map $K^{{\rm PGL}(2)\times \{\pm 1\}}(\mathbb P^1) \to K(\mathbb P^1)$ is not onto. I read somewhere ...
Yellow Pig's user avatar
  • 2,964
7 votes
0 answers
270 views

The Todd class and Weyl's character formula

Let $\mathfrak{g}$ be a finite-dimensional complex semi-simple Lie algebra. Fix a Cartan sub algebra $\mathfrak{h} \subset \mathfrak{g}$ and let $R \subset \mathfrak{h}^{\ast}$ denote the root system. ...
AmorFati's user avatar
  • 1,379
4 votes
1 answer
457 views

Pullback of complex vector bundles along a retraction of compact Hausdorff spaces: a direct proof instead?

Consider a pointed compact Hausdorff space $(X,x_0)$ and a closed pointed subspace $i:A\subset X$ such that there exists a continuous map $r:X\rightarrow A$ such that $r|_A=\text{Id}_A$. Set $$q:(X,...
user avatar
1 vote
0 answers
68 views

Metric and connection on virtual bundles

Let $E=[E^+]-[E^-]$ be an element of the Grothendieck group $K(X)$ of a compact Kahler manifold $X$. Does it exist a way to define more "geometric" structures on $E\in K(X)$ such that a ...
BinAcker's user avatar
  • 789
6 votes
1 answer
752 views

Locally trivializing a G vector bundle?

In §1.6 of Atiyah's K-theory, he defines the notion of a $G$-(vector)-bundle, which is a sort of "equivariant vector bundle" with respect to a finite group action. More specifically, let $G$ ...
Nikhil Sahoo's user avatar
  • 1,225
2 votes
0 answers
141 views

Definition of odd topological K-theory using circles

I wanted to check whether the following characterization of odd complex topological $K$-theory is correct (reposted from Math.SE). Let $X$ be a compact Hausdorff space. Then $K^{-1}(X)$ can be defined ...
geometricK's user avatar
  • 1,903
9 votes
1 answer
514 views

K-theory on finite-dimensional (possibly not finite) CW complexes

I am trying to understand why (at least my most elementary understanding of) topological K-theory breaks down for non-compact things (which I have seen asserted in various places). In particular, as ...
Nikhil Sahoo's user avatar
  • 1,225
1 vote
0 answers
132 views

A possible kind of $K$ theory via comparison of sphere bundles associated to given vector bundles

Let $E$ be a vector bundle on a topological space $X$.Thanks to Allen Hatcher's book "Vector Bundles and K theory", the construction of sphere bundle $S(E)$ can be done without any inner ...
Ali Taghavi's user avatar
5 votes
0 answers
132 views

Riemannian version of topological $K$-theory

Let $X$ be a compact Hausdorff space.Put $Vec(X)$, the space of all real (or complex) vector bundles over $X$.We put also $Vec_g(X)$, the space of all Riemannian vector bundles over $X$, that is the ...
Ali Taghavi's user avatar
5 votes
1 answer
251 views

Equivalence of families indexes of Fredholm operators

Let $F=F(H,H)$ be the space of bounded Fredholm operators in a Hilbert space $H$ with topology inherited from the norm operator topology, and let $X$ be a compact topological space. For a continuous ...
Rodrigo Dias's user avatar
25 votes
1 answer
839 views

Vector bundles on $\mathbb{A}^n / G$

Let $G$ be a finite group acting linearly on $\mathbb{A}^n$. Do we expect algebraic vector bundles on $X := \mathbb{A}^n/G$ to be trivial? Here by the quotient I mean the singular scheme, not the ...
Evgeny Shinder's user avatar
1 vote
1 answer
142 views

A kind of isomorphicity of vector bundles

Let $X$ be a connected topological space. Let $E$ be a $k$ dimensional sub vector bundle of the trivial vector bundle $X\times \mathbb{R}^n$. Then $E$ defines an idempotent with trace $k$ in $M_n(C(X))...
Ali Taghavi's user avatar
10 votes
1 answer
374 views

Computing K-theory for cellular vector bundles

One of the most computationally convenient properties of singular cohomology $X \mapsto H^\bullet(X;\mathbb{Z})$ is the fact that one can extract it from a good cover $\{U_i\}$ of $X$ via Cech ...
Vidit Nanda's user avatar
  • 15.5k
4 votes
0 answers
81 views

Minimum rank of inverse complex vector bundles

When considering vector bundles (real or complex) over a compact manifold, i know about the existence of inverse bundles. That is, if $\xi$ is a vector bundle over $M$, then there is a bundle $\nu$ ...
Reb's user avatar
  • 261
9 votes
1 answer
336 views

Positive cones in K-groups

Let $X$ be a topological space or a scheme, and let $K^0(X)$ be $K$-group of vector bundles of $X$. One may ask when an element $x$ of $K^0(X)$ is represented by an actual vector bundle, and not just ...
Grisha Papayanov's user avatar
3 votes
0 answers
214 views

Vector fields on quasi-spheres

In 1962, Adams proved that there do not exist $\rho(n)$ linearly independent vector fields on the sphere $S^{n-1}$, where $\rho(n)$ is the Hurwitz-Radon number. I wonder if this is still true in the ...
Arimakat's user avatar
  • 333
0 votes
0 answers
171 views

Surjectivity of the Albanese map of the moduli space of stable vector bundles

I have a naive question:(I saw that it is related to relative K-theory of Hodge-Deligne and also Nadel-Chern-Weil theory ) Let $\mathcal M (r, d)$ be the moduli space of stable vector bundles of rank ...
1984's user avatar
  • 189
8 votes
1 answer
544 views

Question regarding the paper by Atiyah, Bott and Shapiro: alternative description of K-theory

In Atiyah, Bott, and Shapiro - Clifford modules (journal, MSN), the authors discuss the alternative description of K-theory in terms of sequences of vector bundles. I would like to understand the ...
truebaran's user avatar
  • 9,330
4 votes
1 answer
157 views

Geometric Motivation for Hilbert $C^*$-Bimodules

I'm trying to get an understanding of Hilbert $C^*$-bi-modules from a geometric point of view. As is well-known, we have that i) Commutative unital $C^*$-algebras correspond to compact Hausdorff ...
Ago Szekeres's user avatar
5 votes
0 answers
130 views

Alternative description of $K$-theory of locally compact spaces using sequences of bundles

In this paper Aityah, Bott and Shapiro give an alternative definition of (relative) $K$-theory groups $K(X,Y)$ using sequences of bundles (this group is denoted by $L_n(X,Y)$ where $n$ is the length ...
truebaran's user avatar
  • 9,330
4 votes
0 answers
220 views

Splitting principle for real vector bundles with $w_i=0$, $0<i<2^r$

Is the following true/known? Let $E$ be a (real) vector bundle over a compact CW-complex $X$. Suppose that $w_i(E)=0$ for $0<i<2^r$. Then there exist a space $Y$ and a map $f\colon Y\to X$ ...
Semen Podkorytov's user avatar
7 votes
2 answers
805 views

What are some applications of virtual vector bundles?

K-theory gives a nice way to define vector bundles that don't actually exist. For example, given a singular variety $Y$ embedded into a smooth variety $X$ we can define the virtual normal bundle as $$ ...
54321user's user avatar
  • 1,716
4 votes
1 answer
354 views

Natural extension homomorphism and wrong-way maps in K-theory

Let $X \subset Y$ be two smooth manifolds. To the inclusion $I:X \to Y$ corresponds the so called wrong-way map in $K-theory$ $i_!:K(X) \to K(Y)$. It is constructed as follows: to the inclusion $X \...
truebaran's user avatar
  • 9,330
2 votes
2 answers
124 views

Invertible (isometric) sections of certain hom bundles over sphere

Assume that we have a vector bundle $E$ over $S^n$. Is there a continuous family of invertible linear maps $T_x:E_x \to E_{-x}$? Here continuity has the obvious meaning as soon as ...
Ali Taghavi's user avatar
3 votes
0 answers
287 views

Basic Question: K-theory of a sphere bundle

Does anyone know how to compute the topological K-theory of the unit tangent bundle for a compact connected Riemann surface of genus greater than one? Thank you very much in advance.
Jacopo Bassi's user avatar
2 votes
1 answer
266 views

Are these vector bundles, trivial bundle?

We identify the vector space tensor product $\mathbb{R}^{m} \otimes \mathbb{R}^{n}$ with $\mathbb{R}^{mn}$ Let $X$ be the space of all non zero simple tensors $X=\{a\otimes b \mid a\in \...
Ali Taghavi's user avatar
5 votes
1 answer
293 views

Reference for $E_{\infty}$-ness of the Chern Character

I would like a reference/proof for the fact that the Chern character map: $$KU_{\mathbb{Q}} \rightarrow H\mathbb{Q}[u, u^{-1}]$$ is an $E_{\infty}$-ring map. Thank you in advance!
Elden Elmanto's user avatar
9 votes
1 answer
327 views

Closed formulas for topological K-theory?

Let $X$ be a compact manifold. I'm interested in whether any of the following cases admits a general closed formula for (complex)-$K$-theory. Let $E$ be a complex vector bundle with a given line ...
Saal Hardali's user avatar
  • 7,789
4 votes
1 answer
353 views

Isomorphism classes of differential rank $k$ vectors bundles over $S^q$ [closed]

Could anybody provide a motivated sketch of why the isomorphism classes of the differentiable rank $k$ real vector bundles over the sphere $S^q$ are given by$$\text{Vect}_k(S^q) \simeq \pi_{q - 1}(\...
M.S.'s user avatar
  • 369
3 votes
1 answer
323 views

self-Whitney sum of the canonical vector bundle on Grassmannians

Let $G_{k}(\mathbb{R}^N)$ be the Grassmannian manifold consisting of $k$-subspaces in $\mathbb{R}^N$. There is a canonical $k$-dimensional vector bundle $$ \gamma_{k,N}: \mathbb{R}^k\longrightarrow E(...
Shiquan Ren's user avatar
  • 1,990
6 votes
2 answers
981 views

Relative Characteristic classes

A pair of vector bundles over a base space $X$ is a pair $(E,F)$ where $E$ is a vector bundle over $X$ and $F$ is a sub-bundle of $E$. Two pairs $(E_{1},F_{1})$ and $(E_{2}, F_{2})$ are ...
Ali Taghavi's user avatar
5 votes
1 answer
403 views

covering map from spheres to projective spaces and the associated vector bundle

Let $S^n$ be the $n$-sphere and consider a $2$-sheeted covering $$ S^n\longrightarrow\mathbb{R}P^n. $$ We have an associated vector bundle $$ \xi: \mathbb{R}^2\longrightarrow S^n\times_{\mathbb{Z}/2}\...
Quan's user avatar
  • 519
7 votes
1 answer
434 views

classifying maps of Whitney sums of vector bundles

For an $n$-dimensional vector bundle $\xi$ with structure group $G\leq O(n)$ over a $CW$-complex $B$, we have a classifying map up to homotopy $$ f(\xi): B\longrightarrow BG, $$ $f(\xi)\in [B;BG]$, ...
Quan's user avatar
  • 519
12 votes
2 answers
2k views

Is every vector bundle over a noncompact finite-dimensional manifold a summand of a trivial bundle?

In the notes of Vector Bundles and K-theory by Prof Allen Hatcher, on page 12 he proved a Proposition that for each vector bundle $E\to B$ with $B$ compact hausdorff there exists a vector bundle $E'\...
Anubhav Mukherjee's user avatar
4 votes
1 answer
507 views

A question on complex line bundle over $S^{2}$

Consider the trivial bundle $\epsilon_{2}=S^{2}\times \mathbb{C}^{2}$ with the standard Hermitian inner product $<(a,b), (c,d)>=a\bar{c}+b\bar{d}$. Assume that $\ell$ is a sub line bundle of ...
Ali Taghavi's user avatar
7 votes
1 answer
485 views

Non trivial rank 2 holomorphic vector bundles in complex dimensions greater than or equal 2

Does every compact complex manifold of complex dimension greater than or equal two possess a nontrivial rank 2 holomorphic vector bundle?
Hamed's user avatar
  • 1,236
1 vote
1 answer
331 views

realization map for K-theory of spheres

Let $\overset{\sim}{K}(X)$ and $\overset{\sim}{KO}$ denote the reduced stable isomorphic classes of complex and real bundles over X and $\rho$ be the realization map. We know that $\overset{\sim}{K}(\...
Prateep's user avatar
  • 141
1 vote
1 answer
322 views

A (possible) equivalent relation on the space of vector bundles

Edit: According to the essential comment of Alex Degtyarev, we revise the question as follows; Assume that $\alpha$ and $\beta$ are two oriention preserving automorphism of Lie groups $O(n)$ and $...
Ali Taghavi's user avatar
7 votes
2 answers
1k views

Cancellation and splitting theorems for vector bundles etc over schemes

It is not too hard, in the theory of vector bundles over manifolds (or nice topological spaces, say locally contractible with finite covering dimension), to arrive at a splitting theorem. This ...
David Roberts's user avatar
  • 35.5k
1 vote
0 answers
261 views

Two questions on canonical line bundle over $\mathbb{C}P^{n}$

The canonical line bundle over $\mathbb{C}P^{n}$ is denoted by $\ell_{n}$. It is well known that: $$(\ell_{1}\otimes \ell_{1})\oplus1 \simeq\ell_{1}\oplus\ell_{1}$$ Both sides are isomorphic ...
Ali Taghavi's user avatar
5 votes
2 answers
624 views

Topological K-theory for commutative C*-algebras

It is in some sense folklore that given two arbitrary abelian groups $G,H$ one can find a $C^*$ algebra $A$ such that $K_0(A)=G$ and $K_1(A)=H$. My question is the following: what is known in the case ...
truebaran's user avatar
  • 9,330
4 votes
1 answer
282 views

Is there a geometric interpretation of Johnson-Wilson E(n) analogous to vector bundles for K-theory?

I am reading Ravenel's Localization with Respect to Certain Periodic Homology Theories where he states; For $n\ge2$, the spectra E(n) represent periodic homology theories which at present have ...
Gabriel Angelini-Knoll's user avatar
1 vote
1 answer
128 views

Integration from vector bundles

Let $(E,M,p)$ be a smooth n dimensional vector bundle. Then $(TE,TM,Dp)$ is a 2n dimensional vector bundle. We restrict this bundle to $M\subset TM$. We denote this restricted bundle by $F$, as a ...
Ali Taghavi's user avatar
4 votes
1 answer
447 views

Totally non parallelizable manifold

Does there exist a manifold M which all iterated tangent bundles are non parallelizable manifolds? That is$ M, TM , T^2(M), \ldots ,T^n(M)\ldots$ are non parallelizable manifold? What is ...
Ali Taghavi's user avatar
2 votes
2 answers
247 views

Preimage of $1 \in H^n(M^n)$ under Chern character

Let $M$ be a closed, oriented manifold of dimension $n$. We know that the Chern character induces an isomorphism $K^\ast(M) \otimes \mathbb{Q} \cong H^\ast(M; \mathbb{Q})$ and now I was wondering how ...
AlexE's user avatar
  • 2,998
7 votes
0 answers
369 views

Does the suspension isomorphism $K_1(A) \to K_0(SA)$ descend from a more refined invariant?

If $A$ is a C*-algebra, denote its minimal unitization by $\tilde A$ and its suspension by $SA$, thought of as all continuous $a:[0,1] \to A$ with $a(0)=a(1)=0$. The unitized suspension $\widetilde{SA}...
Michael's user avatar
  • 662