Skip to main content

All Questions

Filter by
Sorted by
Tagged with
4 votes
0 answers
69 views

is a 4-connected planar graph still Hamiltonian after removing an edge?

We know that 4-connected planar graphs are Hamiltonian(by the known Tutte Theorem). Additionally, Thomas and Yu [1] proved that removing two vertices from a 4-connected planar graph still preserves ...
Licheng Zhang's user avatar
5 votes
1 answer
271 views

Approximation of Hamiltonian cycles

Let's define the $\texttt{MinHalfSimpCycle}$ search problem: Given $G=(V, E)$ a complete, undirected graph with weights on the edges. We want a simple cycle in $G$ (each vertex appears in it at most ...
Redbull's user avatar
  • 53
1 vote
0 answers
65 views

Has there been progress on Hamiltonicity in 4-connected claw-free graphs with a constant maximum degree?

In 1984, Matthews and Sumner [1] conjectured that every 4-connected claw-free graph is Hamiltonian, and this conjecture is still wide open. I would like to know if there has been any progress on this ...
Licheng Zhang's user avatar
0 votes
0 answers
86 views

Uniqueness of compatible cycle decomposition for Eulerian trail

Fleischner mentions in his article Uniqueness of maximal dominating cycles in 3-regular graphs and of hamiltonian cycles in 4-regular graphs about the uniqueness of compatible cycle decomposition that ...
False Equivalence's user avatar
5 votes
2 answers
191 views

Number of Hamiltonian cycles on 24-cell graph

I asked Wolfram Alpha for the number of Hamiltonian cycles on the 24-cell graph. https://www.wolframalpha.com/input?i=number+of+hamiltonian+cycles+on+24-cell+graph It answers 114.9 billion but doesn't ...
Etienne's user avatar
  • 53
1 vote
0 answers
93 views

15-game graph contains a Hamiltonian path ? Lovász conjecture for groupoids, loops, quasigroups , etc?

Typically Cayley graphs are defined for groups and generators sets S. But basically one only needs some set S and another set V and partially defined operation SxV->V, then one defines graph with ...
Alexander Chervov's user avatar
4 votes
1 answer
228 views

Probability problem in Sheehan's conjecture

As my first math project, I have been working on Sheehan's Conjecture and am stuck for weeks. I wonder if I am at a dead end. Sheehan's Conjecture states that every Hamiltonian 4-regular simple graph ...
Daniel Liu's user avatar
1 vote
0 answers
61 views

A generalized/set hamiltonian cycle problem on directed graphs

So this problem originally stems from the asymmetric generalized/set TSP problem, where I am interested in asking the question which or how many edges I can delete while maintaining feasability. The ...
whiterock's user avatar
  • 111
0 votes
0 answers
52 views

Are there 4-connected planar non-hamilton multi-graphs?

Tutte proved the famous result: Every planar 4-connected graph has a hamiltonian cycle. But I read in Section 111.6.5 on book Eulerian Graphs and Related Topics that the author Herbert Fleischner ...
Licheng Zhang's user avatar
5 votes
0 answers
127 views

Do uniquely Hamiltonian graphs have cycles of a sufficiently long length?

Let $C$ be a Hamiltonian cycle of a graph $G$. Call an edge $e$ of $G$ a chord if $e\not\in C$. Let each edge of $C$ be weighted $1$ and each chord be weighted $2$. The weight of a path or cycle of ...
kabenyuk's user avatar
  • 673
0 votes
0 answers
36 views

A class of directed graph, when their minimal polynomial of the adjacency matrix matches the characteristic polynomial

We consider an unweighted directed simple graph, $G$, with a Hamiltonian cycle. Q. Assume that the adjacency matrix of $G$ is non-singular. Do the characteristic and minimal polynomials of the ...
ABB's user avatar
  • 4,058
0 votes
0 answers
65 views

Cycles in Kneser graphs with three vertices forming triangles

Consider the Kneser graphs $G=K(n,k)$. Is it possible to list how many even cycles, or, at the least, existence of an even cycle of a given order in $G$, such that any three consecutive vertices form ...
vidyarthi's user avatar
  • 2,089
1 vote
1 answer
92 views

Existence of a strongly regular vertex ordering on cubic graphs

Definition: Let $G=(V,E)$ be a cubic (i.e. $3$-regular) graph, and $<$ a total order on $V$. For $v\in V$ let $v^\downarrow$ denote the set of nodes $w\in V$ such that $w<v$, and let $\alpha(v) =...
BHT's user avatar
  • 191
9 votes
2 answers
2k views

Is this graph Hamiltonian?

Let $G$ be a simple $2$-connected graph with $m+n$ vertices ($n>m \geq 3$) with degree sequence $(m-1)^m$, $(n-1)^n$; that is, $G$ is degree-equivalent to two disjoint cliques $K_m$, $K_n$ of ...
Valentin Brimkov's user avatar
2 votes
0 answers
112 views

Constructing Hamiltonian circuits in acyclic digraphs

Any directed graph $G$ lacking cycles can acquire a Hamiltonian circuit through the addition of a sufficient number of edges. Q. Is there a method to minimize the addition of edges to achieve a ...
ABB's user avatar
  • 4,058
5 votes
1 answer
119 views

Sufficient condition for a Hamilton cycle $C$ in a planar triangulation $G$ s.t. every triangle in $G$ has an edge in $C$

Let $G$ be a $k$-connected planar triangulation ($k\geq 4$) and let $C$ be a Hamilton cycle of $G$. Then: Which conditions would be sufficient to assure that every triangle of $G$ has at least one ...
Jose Antonio Martin H's user avatar
4 votes
0 answers
234 views

How many 20-vertex 2-connected 5-regular non-Hamiltonian graphs are there?

As for the question in title, I attempted to use nauty to obtain them, but it has been running on my computer for nearly three days without producing any results. <...
Licheng Zhang's user avatar
2 votes
2 answers
64 views

Does $(\omega, E)$ with the cycle condition have an $\omega$-path?

Let $G = (V,E)$ be a simple, undirected graph. We say that $v\neq w\in V$ lie on a common cycle if there is an integer $n\geq 3$ and an injective graph homomorphism $f: C_n\to V$ such that $v,w\in \...
Dominic van der Zypen's user avatar
13 votes
1 answer
1k views

Generalisation of this circular arrangement of numbers from $1$ to $32$ with two adjacent numbers being perfect squares

I posted this question on MSE, and failed to get the type of answer I wanted. That's why I would like to post it here and wait for the experts to reply. Here's the link to the MSE post, which I ...
Sayan Dutta's user avatar
3 votes
2 answers
725 views

The perfect matching problem of planar graph

We know that connectivity is closely related to the Hamiltonian of planar graphs. The most famous result is the Tutte theorem. Theorem (Tutte, 1956). A 4-connected planar graph has a Hamiltonian ...
Licheng Zhang's user avatar
0 votes
0 answers
62 views

Clique sizes of generalized Kneser graphs

Are there known bounds for clique size in generalized Kneser graphs $KG(n,k,t)=K(n,k,t-1)$, the graph formed by distinct $k$ subsets of $n$ set so that two subsets with at most $t$ elements in common ...
vidyarthi's user avatar
  • 2,089
3 votes
1 answer
104 views

Edge coloring of a graph on alternating groups

Let $G$ be the Cayley graph on the alternating group $A_n\,n\ge4$ with generating set $$S=\begin{cases}\{(1,2,3),(1,3,2),\\(1,2,\ldots,n),(1,n,n-1,\ldots,2)\}, &n\ \text{odd}\\ \{(1,2,3),(1,3,2),\\...
vidyarthi's user avatar
  • 2,089
2 votes
2 answers
234 views

Decompose complete directed graph with n vertices into n edge-disjoint cycles with length n−1

I want to know how to decompose a complete directed graph with $n$ nodes into $n$ edge-disjoint cycles with length $n-1$. I found this result was proved in Bermond and Faber - Decomposition of the ...
chunma's user avatar
  • 21
2 votes
1 answer
138 views

Two ears polygon in a maximal planar hamiltonian graph

Given a maximal planar graph (+6vertices) without separating triangles. Then it can have many Hamilton cycles°. Such a cycle divides the graph into two triangulated polygons. Is it always possible to ...
P.Labarque's user avatar
6 votes
2 answers
304 views

Hamiltonian path in bike-lock graph with $1$ known digit

Motivation. My youngest son has a bike lock with dials, and he forgot the unlocking combination completely, except that he remembered that digit $0$ appeared somewhere in the combination. So it was my ...
Dominic van der Zypen's user avatar
2 votes
1 answer
495 views

Is every $k$-edge connected $k$-regular graph Hamiltonian?

A graph $G$ is Hamiltonian if there is a Hamiltonian cycle in $G$. Suppose $G$ is a $k$-edge connected $k$-regular graph with $k>1$. Does this ensure that $G$ is Hamiltonian? If not, how about ...
Cyriac Antony's user avatar
1 vote
3 answers
6k views

Which are good algorithms for finding Hamiltonian path (not necessarily a circle) up to now?

I am not expertise in graph theory. So have to ask this question here. The term "good" means that the algorithms should be efficient for general undirected simple connected graphs with a higher ...
Licheng Wang's user avatar
8 votes
2 answers
598 views

Orthogonal Hamiltonian cycles in (n x n x n) grids

Let $C_n$ be a cubical $n \times n \times n$ subset of the integer lattice, so consisting of $n^3$ vertices. I am interested in special Hamiltonian cycles in $C_n$, special in the sense that (a) each ...
Joseph O'Rourke's user avatar
7 votes
3 answers
2k views

"Gray code" for building teams

Motivation. In a team of $n$ people, we had the task to build subteams of a fixed size $k<n$ such that every day, $1$ person of the subteam is replaced by another person in the team, but not in the ...
Dominic van der Zypen's user avatar
1 vote
1 answer
100 views

Is there a monograph or review of Hamiltonian cycles of graphs (or long cycles of graphs)?

In graph theory, a Hamiltonian cycle is a cycle that visits each vertex exactly once. Hamiltonian cycle has a long history, and I have followed some articles. We can find plenty of examples of ...
Licheng Zhang's user avatar
2 votes
1 answer
106 views

Hamiltonian path in divisibility graph

Let $\mathbb{N}$ denote the set of positive integers, and consider the graph $(\mathbb{N}, E)$ where a set $\{a,b\}$ of two distinct positive integers belongs to $E$ if there is an integer $k>1$ ...
Dominic van der Zypen's user avatar
15 votes
2 answers
2k views

What is the smallest uniquely hamiltonian graph with minimum degree at least 3?

I would like to know more about uniquely hamiltonian graphs with minimum vertex degree at least 3, and in particular what is the smallest one. (Recall that a graph is hamiltonian if it has a cycle ...
Gordon Royle's user avatar
  • 12.7k
3 votes
0 answers
108 views

Hamiltonian path in $\{0,1\}^n$ with rotations and bit-flip in position 0

We consider any non-negative integer as an ordinal, that is $0=\emptyset$ and $n=\{0,\ldots,n-1\}$ for every positive integer. Let $\{0,1\}^n$ denote the set of $\{0,1\}$-vectors of length $n$. Define ...
Dominic van der Zypen's user avatar
3 votes
0 answers
70 views

Hamilton cycles in Cayley graphs: between Rapaport-Strasser and Fleischner

A well-known question of Rapaport-Strasser asks whether every finite connected Cayley graph has a Hamilton cycle. Fleischner's Theorem implies that if $S$ is the generating set of such a Cayley graph $...
Agelos's user avatar
  • 1,936
6 votes
0 answers
164 views

Hamilton cycles in random graphs with just enough connectivity

What is the asymptotic probability that $G$ has a Hamilton cycle if $G$ is a random $n$ vertex $\frac{4}{3}n$ edge graph, with minimum degree 2 and without degree 2 vertices at distance 1 or 2 to each ...
Dmytro Taranovsky's user avatar
-1 votes
2 answers
200 views

Path of length $n$ but no Hamilton cycle [closed]

What is an example of a simple graph $G = (\{1,\ldots,n\}, E)$, where $n\in\mathbb{N}$ is a positive integer, with the following properties? There is a path in $G$ of length $n$, every vertex has at ...
Dominic van der Zypen's user avatar
7 votes
7 answers
3k views

Efficient Hamiltonian cycle algorithms for graph classes

Generally speaking, finding a Hamiltonian cycle is NP-Hard and so tough. But if $G=L(H)$ is the line graph of $H$, then we can reduce the problem of finding a Hamiltonian cycle in $G$ to finding an ...
Felix Goldberg's user avatar
-1 votes
1 answer
96 views

Hamiltonian $\mathbb{Z}$-paths in connected countably infinite vertex-transitive graphs [closed]

A simple, undirected graph $G=(V,E)$ is said to be vertex-transitive if for all $a,b\in V$ there is a graph isomorphism $\varphi:G\to G$ such that $\varphi(a) = b$. If $G = (\omega, E)$ is vertex-...
Dominic van der Zypen's user avatar
5 votes
0 answers
154 views

How to construct 4-regular graphs with few Hamiltonian decompositions?

A Hamiltonian decomposition of a finite simple graph is a partition of its edge set so that each partition class forms a Hamiltonian cycle. This is only possible if the graph is $2k$-regular. ...
M. Winter's user avatar
  • 13.6k
3 votes
0 answers
76 views

Hamiltonian cycles in Cayley graph on alternating group

Let $G=\operatorname{Cay}(A_n,S)$ be the Cayley graph on the Alternating group $A_n\quad n\ge4$ with generating set $S=\{(1,2,3),(1,2,4),\ldots,(1,4,2),(1,3,2)\}$. One Hamiltonian cycle in $G$ for $n=...
vidyarthi's user avatar
  • 2,089
1 vote
2 answers
186 views

Hamiltonian cycle in $S_n$ with transpositions

For any set $X$, let $[X]^2=\{\{a,b\}:a\neq b \in X\}$. If $n\in\mathbb{N}$ is a positive integer, let $S_n$ denote the collection of bijections $\varphi:\{0,\ldots,n-1\}\to\{0,\ldots,n-1\}$. Let $E_n\...
Dominic van der Zypen's user avatar
1 vote
1 answer
120 views

How to construct a hamilton-connected cubic graph? Is it possible?

If we are given a large integer $k$, can we construct a hamiltonian-connected $n$-vertex graph for every even $n\geq k$ such that all its vertices are of degree 3? Is there any reference concerning ...
Xin Zhang's user avatar
  • 1,190
14 votes
1 answer
1k views

Are all cubic graphs almost Hamiltonian?

Call a graph $G$ $n$-almost-Hamiltonian if there is a closed walk in $G$ that visits every vertex of $G$ exactly $n$-times. So a Hamiltonian graph is $n$-almost-Hamiltonian for all $n$. Are all ...
user101010's user avatar
  • 5,349
5 votes
1 answer
279 views

Infinitely many counterexamples to Nash-Williams's conjecture about hamiltonicity?

Question from 2013 gives one counterexample to Nash-Williams's conjecture about hamiltonicity of dense digraphs. Later, we found tens of counterexamples on more than 30 vertices and believe there are ...
joro's user avatar
  • 25.4k
2 votes
1 answer
298 views

Opposite-nearest neighbor algorithm vs. nearest neighbor algorithm

Take the traveling salesman problem, but with three slight twists: You can choose a different start vertex for each of the two algorithms. Each path from one vertex to another is of unique, arbitrary ...
Zixun Tau's user avatar
3 votes
1 answer
234 views

Counting cycle vertex covers on hypercube

Let $Q_n$ be the $n$-dimensional hypercube graph. How many vertex cycle covers exist on $Q_n$? (Presumably the best we can hope for are upper and lower bounds.) To be clear, a single "vertex cycle ...
Bill Bradley's user avatar
  • 3,979
9 votes
2 answers
2k views

"Gray code" of all permutations

Informally asking, can we step through all permutations of the set $\{1,\ldots,n\}$ by just using transpositions? More formally: For any $n\in\mathbb{N}$ let $[n] = \{1,\ldots,n\}$ and let $S_n$ be ...
Dominic van der Zypen's user avatar
12 votes
1 answer
424 views

Quantitatively characterizing the failure of the converse of Dirac's theorem

First, I am an undergraduate so I apologize if this is trivial and certainly understand if it is closed immediately. I am currently in a combinatorics and graph theory class and recently we have ...
1729's user avatar
  • 221
12 votes
1 answer
2k views

Hobbled rook tour – Hamiltonian cycle on square grid

Consider a square grid of even side length ($2n \times 2n$). It is easy to see that there must exist a Hamiltonian cycle on the corresponding grid graph. Such a cycle is called balanced if the number ...
John's user avatar
  • 121
2 votes
1 answer
321 views

Extending perfect matchings into Hamiltonian cycles

Let $G$ be a simple cubic graph which has a Hamiltonian circuit $C$. In general, it is not possible to find a second Hamiltonian circuit which contains all the chords of $C$. For example, the Wagner ...
EGME's user avatar
  • 1,018