Skip to main content

All Questions

Filter by
Sorted by
Tagged with
1 vote
2 answers
2k views

Real solutions to underdetermined system of polynomial equations

I have the system of multi-variable polynomial (quadratic) equations with real coefficients. The number of equations is given scales as $K$ and the number of unknowns goes as $K^2$. So for for large $...
9 votes
3 answers
3k views

Why are divisible abelian groups important?

I just quote wikipedia: "Divisible groups are important in understanding the structure of abelian groups, especially because they are the injective abelian groups." I am asking for detail ...
-1 votes
2 answers
671 views

Do Gorenstein rings necessarily have a finite projective dimension (as a module over itself)? [closed]

Do Gorenstein rings necessarily have finite projective dimensions?
9 votes
1 answer
792 views

Reconstructing a polynomial from resultants

I am trying to compute a monic polynomial $f(x)$ with integer coefficients and known degree $d$. I am given $n$ pairwise coprime polynomials $g_1(x),\ldots,g_n(x)$, also with integer coefficients, ...
1 vote
2 answers
2k views

The structure of the module of Kähler differentials of R[[x]] over R

It seems that $\Omega_{R[[x]]/R}^1$ is rather big. For example, take $R$ to be the rational numbers. We can see that $\Omega_{R((x))/R}^1$ is a $R((x))$-vector space of infinite rank. As by results ...
2 votes
1 answer
980 views

Spectral sequence for Ext

Why is $H^p(X, \mathcal{E}xt^q(F, I))=0$ for $p>0$ and $I$ an injective sheaf and $F$ an arbitrary sheaf? I'm trying to check the hypothesis in the grothendieck spectral sequence applied to the ...
7 votes
2 answers
542 views

Does every nontrivial sheaf of rings have a maximal ideal?

Let $R$ be a sheaf of rings on a topological space $X$. Assume $R \neq 0$. Does then $R$ have a maximal ideal? So this is a spacified analogon of the theorem, that every nontrivial ring has a maximal ...
5 votes
2 answers
689 views

Irreducible components of quotients of Cohen-Macaulay rings of the "correct" dimension

Suppose $R$ is a Cohen-Macaulay ring. It is well known that if $I$ is an ideal of $R$ generated by $n$ elements, and $I$ has codimension $n$, then $R/I$ is also Cohen-Macaulay. Now suppose that $I$ ...
3 votes
2 answers
2k views

Extension problem

As I understand, if $0\rightarrow A\rightarrow X\rightarrow B\rightarrow 0$ is a short exact sequence of abelian groups, $\mbox{Ext }_{\mathbb{Z}}^{1}(B,A)$ gives all the isomorphism classes of what ...
2 votes
2 answers
420 views

Homological dimensions of module

$(A,\mathfrak{m})$ a Noetherian local ring, $M\neq 0$ a finitely generated $A$-module. As I understand, $\mbox{Ext }^{j}(A/\mathfrak{m}, M) = 0$ for $j<\mbox{depth }(M)$ and for $j>\mbox{inj. ...
14 votes
3 answers
2k views

Intuition for Model Theoretic Proof of the Nullstellensatz

I recently read the model-theoretic proof of the Nullstellensatz using quantifier elimination (see www.msri.org/publications/books/Book39/files/marker.pdf). I'm convinced that the Nullstellensatz is ...
4 votes
2 answers
2k views

Non-finite version of Nakayama's lemma?

Let $A$ be a local ring with nilpotent maximal ideal $\mathfrak{m}$ (i.e., some power of $\mathfrak{m}$ vanishes), and $M$ an $A$-module (not necessarily finitely generated). Let $\bar{S}\subset M/\...
2 votes
0 answers
797 views

How can I prove R[x] is integrally closed iff R is integrally closed ? (R: integral domain) [closed]

$R$ is a integral domain. How can I prove $R[x]$ is integrally closed iff $R$ is integrally closed?
13 votes
1 answer
2k views

Can an infinite commutative ring have a finite (but nonzero) number of non-nilpotent zero-divisors?

By a theorem of Ganesan, if a commutative ring not a domain has only finitely many zero-divisors, then the ring must be finite. (There are analogous results for non-commutative rings.) There are ...
2 votes
0 answers
348 views

How much can we say about the number of nilpotents in a finite local commutative ring?

A commutative ring is local if it has a single maximal ideal. If the ring is finite, this implies that all elements are either units or nilpotents. Further, all finite local rings have prime power ...
20 votes
1 answer
3k views

On a theorem of Jacobson

In a comment to an answer to a MO question, in which Bill Dubuque mentioned Jacobson's theorem stating that a ring in which $X^n=X$ is an identity is commutative (theorem which has shown up on MO ...
4 votes
0 answers
179 views

Global dimensions of orders over non-Gorenstein centers

This question concerns the following Lemma 4.2 in this paper by Van den Bergh: Lemma: Let $R$ be local, normal Gorenstein ring of dimension $d$. Suppose $M$ is a reflexive $R$ module such that $A=\...
6 votes
2 answers
2k views

Cardinality of maximal linearly independent subset

M a finitely generated module over a commutative ring A. I can't think of an example of two maximal linearly independent subsets of M having different cardinality. I know that they all have the same ...
5 votes
2 answers
2k views

Is there a non-projective flat module over a local ring?

Is there a non-projective flat module over a local ring? Here I assume the ring is commutative with unit.
13 votes
0 answers
496 views

Are the supports of $Ext^i(M,N)$ eventually periodic?

Let $R$ be a Noetherian, commutative ring and $M,N$ be finitely generated $R$-modules. Question: Do the sets of minimal primes of $\text{Ext}^i_R(M,N)$ (for a fixed pair of $M,N$) become periodic ...
9 votes
3 answers
1k views

Vector spaces with natural bases

Sergeib's question asks about vector spaces without a natural basis. Actually, I would claim (apparently in accord with many comments and answers to Sergeib's question ) that this is the default ...
1 vote
0 answers
534 views

Integral element in the quotient of a polynomial ring

Hello, I'm writting a "report" (to learn) on algebraic geometry, and was looking to write a proof for the following statement : Theorem : Let $K$ be an algebraically closed field and $C_1, C_2 \...
11 votes
1 answer
1k views

The associated prime ideals of $Ext^i_R(M,N)$

If R is a commutative noetherian ring, M and N are modules with M finite. It is well known in commutative algebra that $AssHom_R(M,N)=Supp(M)\cap Ass(N)$. But I want to know whether there is a ...
2 votes
1 answer
1k views

For which rings does there exist an invertible Vandermonde matrix?

Suppose $R$ is a commutative ring, and $S \subset R^{n\times n}$ is an $R$-module. We are given $H_0,\dots,H_n \in R^{n\times n}$, and we know that for all $r \in R$, $$H_0 + r H_1 + \dots r^n H_n \in ...
5 votes
4 answers
388 views

Familiar equations in more general settings

What equations, or results about equations, generalize in interesting ways from number theory or geometry to more abstract settings? The motivating example for this question was as follows: ...
4 votes
1 answer
914 views

Elements of trace zero in a field extension

Let $K=F_q$ and $F=F_{q^3}$, define the set A={$x \in F$ : $Tr_{F/K} (x)=0$}. Is it true that for every $x \in A$ there are $y,z \in A$ such that $x=yz$?
2 votes
0 answers
165 views

Ideals weak equivalence and "finite" equivalence

Let $R$ be an order in a number field. Two $R$-ideals $I$ and $J$ are weak equivalent if there exist (necessarily invertible) ideals $X$ and $Y$ such that $I X=J$ and $J Y=I$. This is equivalent to ...
0 votes
1 answer
630 views

Useless question on rank

What is the rank of $A^{n}$ if A is the zero ring? It's clearly not $n$ as many careless authors claim, since it's not even invariant. I don't think it's 0 either because it does have a linearly ...
7 votes
2 answers
1k views

Is the category of affine schemes (over a fixed field) Cartesian closed?

This is probably a trivial question, but I don't see the answer, and I haven't found it on Wikipedia, nLab, nor MathOverflow. Let $\text{ComAlg}$ denote the category whose objects are commutative ...
1 vote
1 answer
219 views

Name for a module with only one associated prime

In EGA IV2, Def. 3.2.4, Grothendieck defines a quasicoherent sheaf over a locally Noetherian scheme to be "irredondant" if it has a unique associated point. Presumeably, a module over a Noetherian ...
16 votes
1 answer
2k views

Does ZF prove that all PIDs are UFDs?

Main Question: Does ZF (no axiom of choice) prove that every Principal Ideal Domain is a Unique Factorization Domain? The proofs I've seen all use dependent choice. Minor Questions: Does ZF + ...
11 votes
2 answers
470 views

Localizing at the primitive polynomials?

For any UFD $R$, the concept of a primitive polynomial (gcd of the coefficients is 1) makes sense in $R[x]$. The product of two primitive polynomials is primitive (Gauss's Lemma), and certainly 1 is a ...
4 votes
0 answers
1k views

Associative binary operations on natural numbers

Which are all the associative binary operations on natural numbers ? Certain results in this regard can be found in arxiv:math/0508215. It appears that such associative operations cannot grow too fast....
5 votes
3 answers
4k views

How to prove these two rings are not isomorphic

In fact, it is a simple problem. I just want to know whether there are some interesting proof. $Z[x_1, x_2, ......, x_{n^2-1}]$ and $Z[y_{11}, ......, y_{1n}, y_{21}, ......, y_{nn}]/(det(y_{ij})-1))...
13 votes
3 answers
6k views

Ranks of free submodules of free modules [duplicate]

Possible Duplicate: Atiyah-MacDonald, exercise 2.11 The following question came up during tea today. Let $R$ be a commutative ring with an identity and let $M \subset R^n$ be a submodule. ...
5 votes
0 answers
437 views

Primary decomposition for non-affine schemes

I will call a (nonzero) ring primary if every zero divisor is nilpotent. (This implies that the prime spectrum is irreducible, although the converse does not hold.) An irreducible scheme I will call ...
6 votes
1 answer
376 views

Checking locally whether a homomorphism is a localization

All rings below are commutative with $1$. Suppose $A\subset B$ is a subring and that $A\rightarrow A'$ is a faithfully flat ring homomorphism. [You may assume the rings are actually ${\mathbb C}$-...
3 votes
2 answers
2k views

Finitely-generated algebra over Z

Let A be an artin ring which is also a finitely generated algebra over Z. Show that $|A|<\infty$. If A would have been a field then I know how to prove it. I know that A is a product of local ...
9 votes
1 answer
2k views

Symmetric polynomials theorem

Hello all, I would appreciate comments on the following question: A main theorem of symmetric functions might be formulated: Let k be a field of char. 0. Then $k[x_1,...,x_n]^{S_n} = k[s_1,...,s_n]$,...
12 votes
0 answers
529 views

A commutative monoid associated with a finite abelian group

Let $M$ be a finite abelian group, and denote by $e_m$, for $m \in M$, the canonical basis of $\mathbb{Z}^M$. For $m, n \in M$ define elements $v_{m,n} \in \mathbb{Z}^M/\langle e_0\rangle$ as $$ v_{m,...
6 votes
2 answers
610 views

What is the set of possible values of the degree of the sum of two algebraic numbers with fixed degrees?

This question is related to Degree of sum of algebraic numbers and algebraic numbers of degree 3 and 6, whose sum has degree 12. In this last question I asked a very special case of the following ...
1 vote
1 answer
262 views

$\omega$-monoids

Does the notion of $\omega$-monoid exist, analogous to the notions of $\omega$-groupoid and $\omega$-category? If so, some references would be appreciated. This is an attempted rephrasing of question:...
3 votes
3 answers
1k views

question about tensor of two fields

Let $k$ be a field, $L$, $H$ extension fields of $k$, and $G=L\otimes_k H$. I wonder why (I want to know the proof but I can't find) the prime ideal of $G$ must be maximal, and its properties: a) if $...
3 votes
1 answer
3k views

Isomorphism between direct sum of modules

Let $M$, $N$ be two modules over ring $A$. If $M\oplus M\cong N\oplus N$, can we conclude $M\cong N$? In the case that $M$, $N$ are completely decomposable (e.g. finite-length module by Krull-Schmidt ...
2 votes
0 answers
234 views

Flatness of module

$A\rightarrow B$ a ring homomorphism, $N$ a $B$-module which is flat over $A$. $\mathfrak{q}\subset B$ a prime ideal, $\mathfrak{p}\subset A$ its contraction in $A$. Then is it true that $N_{\mathfrak{...
2 votes
0 answers
333 views

Localization of module

M an A-module, $S\subset A$ a multiplicative subset. Is it possible for $S^{-1}M$ to have an $S^{-1}A$-module structure satisfying $\frac{a}{1}\cdot\frac{m}{1}=\frac{am}{1}$ other than the "usuall" ...
3 votes
2 answers
335 views

Gaps in Dimension Polynomials

There are several notions of rank/dimension defined on differential fields. However, we do not have a reasonable way to estimate these typically ordinal valued invariants. Especially, we do now know a ...
1 vote
0 answers
268 views

Rational map defined over K leads to algebra question

Hello, Concrete algebraic question : Let $K$ be a perfect field, $\bar{K}$ a fixed algebraic closure and let $f \in \bar{K}[x_1,\ldots,x_n]$. I was wondering when there exists another polynomial (non-...
13 votes
2 answers
5k views

Primitive element theorem without building field extensions

Is there are nice way to prove the primitive element theorem without using field extensions? The primitive element theorem says that if $x$ and $y$ are algebraic over $F$ and $y$ is separable over $F$...
0 votes
1 answer
2k views

Dimension of tensor product of modules

$A\rightarrow B$ a ring homomorphism of Noetherian rings, where $A$ is local. $M$, $N$ finitely generated and nonzero $A$- and $B$- modules, respectively. Then I seem to get $\mbox{dim}_ {B}(M\...

1
116 117
118
119 120
122