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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions
10
votes
Accepted
Can all three numbers $\ n\ \ n^2-1\ \ n^2+1\ $ be fine (as opposed to coarse)?
$n = 2673$ has largest prime factor $11$ whose cube is $1331$.
$n^2 - 1 = 7144928$ has largest prime factor $191$ whose cube is $6967871$.
$n^2 + 1 = 7144930$ has largest prime factor $61$ whose cube …
0
votes
Is there a general way to solve this modular equation?
$$\sum_{k=0}^{N-1} 3^k \, 2^{-L_{k+1}} \equiv 1 \pmod{3^N}$$
is equivalent to a series of equations modulo powers of $3$:
$$\begin{eqnarray*}
2^{-L_1} &\equiv& 1 \pmod{3} \\
3 \cdot 2^{-L_2} &\equiv& …
4
votes
upper bound for the number of integer solutions of a special equation
Hint: it's always worth checking the Online Encyclopedia of Integer Sequences.
For $r=3$ the values of $N$ are the sequence A002426. There's a wealth of literature references, a number of comments whi …
4
votes
Non-trivial solution to $\sum^{n}_{i=1}\sum^{n}_{j=1,j\ne i}(x_{i})^{(x_j)}=(\sum^{n}_{i=1}x...
Split $x_i$ into $z$ zeroes and a partition of $n$ into $k$ (non-zero) parts, $\lambda_j$. Then your equality can be rewritten as $$z(z-1) + kz + \mathop{\sum\sum}_{i \neq j} \lambda_i^{\lambda_j} = n …
4
votes
Accepted
Periodic Gauss hypergeometric function
Gauss' contiguous relations provide a basis for finding a linear relationship between three functions of the form ${}_2F_1(a+k, b+l, c+m, z)$, henceforth $\mathbf{F}\left(\begin{matrix}a+k, b+l \\ c+m …
3
votes
Accepted
A combinatorial game with seemingly curious arithmetic properties
Consider the case where $(0,0)$ and $(0,1)$ are winning (i.e. P) positions. There's a biphasic structure.
Let $\operatorname{off}_w(b) = 3 \lfloor \frac b2 \rfloor + (b \bmod 1)$. Then if $w < \operat …
20
votes
Accepted
Splitting the integers from $1$ to $2n$ into two sets with products as close as possible
Original question
Is this sequence strictly increasing?
No.
n difference smaller half
16 16753029012720 [3, 5, 6, 7, 9, 10, 11, 13, 15, 18, 19, 21, 25, 27, 29, 30]
17 10176199188480 [4, 6, 7, 8 …
2
votes
Question for averaging the overall quantities by averaging a part
A brief comment on notation: "can be averaged by" is a reflexive partial order. I shall use the notation $a \succeq b$ to indicate that $a$ can be averaged by $b$, and save $\geq$ for the usual total …
7
votes
Accepted
Numbers $m$ for which coefficients of the polynomial $p(m,x)$ are relatively prime
Counterexample: $463 \in b(n)$ (it's a prime and $464 = 2^4 \cdot 29$ is not squarefree), but $463 \not \in a(n)$ because it's a factor of the GCD of the coefficients of $p(463, x)$.
3
votes
Accepted
"Radical" Catalan numbers?
If $s(n)$ is the largest integer such that $s(n)^2 \mid \binom{2n}{n}$, then the main result of Sárközy, A. (1985). On divisors of binomial coefficients, I. Journal of Number Theory, 20(1), 70-80 is
…
5
votes
Accepted
The exact number of points within a circle of radius r centered on a lattice point in a hexa...
By identifying the lattice points with numbers of the form $x - y\omega$, $\omega = e^{2\pi i / 3}$, $x, y \in \mathbb{Z}$, we find that we want to count Diophantine solutions to $x^2 + xy + y^2 \le r …
3
votes
Accepted
A similar relationship between the generic cubic and the Lehmer quintic?
The map $s(r) = \frac{n+2 + nr - r^2}{1 + (n+2)r}$ cyclically permutes the roots. This map is given in [2], and I found it through the reference in [1]. It turns out to give the correct order.
Explici …
1
vote
Getting a bound on the coefficients of the factor polynomial
The review Bounds on Factors of $\mathbb{Z}[x]$ by John Abbott gives various such bounds and shows that none of them is strictly better than the others.
4
votes
Question in a paper by Erdős on divisibility properties of central binomial coefficient
The $n_i$ are any sequence of distinct integers, indexed by $i$. The point is that if $R = r^{kl}$ then $R$ is a power of $p$, so any sum of distinct powers of $R$ is a 0-1 number in base $p$; and sym …
12
votes
Accepted
Egyptian fraction of a number in the interval (0.5,1)
Suppose this is known for all Egyptian fractions with minimal representation in $k$ fractions. Then if there's a counterexample in $k+1$ fractions $\frac{1}{n_1} + \frac{1}{n_2} + \cdots \frac{1}{n_{k …