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Smooth manifolds and smooth functions between them. For manifolds with additional structure, see more specific tags, such as [riemannian-geometry]. For more topological aspects, see [differential-topology].
2
votes
Accepted
Any reference including a coordinate free proof of the inverse function theorem?
A coordinate-free proof of the inverse function
theorem in the finite-dimensional case
is provided by Theorem 19.6 in "Topological Geometry"
by Ian R. Porteous.
In general, the cited book is an expos …
10
votes
How to classify the algebras C^∞(M)?
How can we characterize the algebras (at least within all the C^∞(M)'s), that come from compact manifolds?
An algebra of the form C^∞(M) corresponds to a compact manifold if and only if all of it …
3
votes
smooth Gelfand-duality
The functor from the category of smooth manifolds to to the category of real algebras
that sends a manifold M to C^∞(M) is fully faithful, hence it is an equivalence
of categories of smooth manifolds …
9
votes
Accepted
To what extent differentiable mappings of an affine line into a manifold determine its diffe...
This is true for infinitely differentiable curves: if a map sends smooth curves to smooth curves, then it is smooth, by a theorem of Boman from 1967:
Jan Boman. Differentiability of a Function and of …
11
votes
When (why) did we allow manifolds to be non-Hausdorff and/or non-second countable?
The étale space construction produces non-Hausdorff and nonparacompact spaces (e.g., smooth manifolds)
in many practical examples that have nothing to do with algebraic geometry.
The étale space is …
9
votes
Accepted
Delta distribution on manifolds
We can give a complete classification of (candidates for) delta-distributions on a smooth manifold $M$ at point $p$.
Specifically, a delta-distribution is a smooth linear functional on the space of sm …
10
votes
Accepted
How to show that $\text{Man}(M,\mathbb{R}^n)\cong \mathbb{R}\text{-Alg}(C^\infty(\mathbb{R}^...
The proof of this fact is available in modern textbooks.
For example, see Theorem 7.16 in Jet Nestruev's Smooth Manifolds and Observables (Second Edition, 2020).
In fact, the cited book contains a lot …
7
votes
Atlas of a manifold as a Sheaf
An atlas is a sheaf on the site of cartesian spaces (the site with objects R ), such that ...
One can certainly define smooth manifolds in such terms.
The cartesian site has finite-dimensional …
5
votes
Accepted
Metrics on derived smooth manifolds
As far as I am aware, there is nothing in the literature that
treats Riemannian or pseudo-Riemannian metrics on derived smooth manifolds.
However, there is an extensive treatment of symplectic structu …
8
votes
Results in “generalised smooth spaces” that did not hold in the case of smooth manifolds
There are many such results.
Consider some smooth manifolds M and N.
The internal hom Hom(M,N) is a sheaf on smooth manifolds.
We can compute its tangent bundle,
and it turns out that the tangent spac …
13
votes
Accepted
Is a manifold paracompact? Should it be?
every group can be declared a Lie group if one allows the more general definition since one is permitted to have an uncountable number of connected components.
A manifold is paracompact if and o …
15
votes
2
answers
1k
views
Is there a citeable reference for star-shaped open subsets of R^n being diffeomorphic to R^n?
A folk theorem says that star-shaped open subsets of R^n are diffeomorphic to R^n.
Is there a citeable reference for a proof of this result?
For the sake of being definite, let's say that
“citeable” m …
11
votes
1
answer
446
views
Does every smooth map of rank at most d factor through a d-manifold?
Suppose $d≥0$, $m≥0$, $n≥0$, and $\def\R{{\bf R}} f\colon \R^m→\R^n$ is a smooth map
whose rank at any point of $\R^m$ is at most $d$.
Here and below, smooth means infinitely differentiable.
Can we fi …
3
votes
1
answer
222
views
Can elements of Weil algebras be detected by maps into truncated symmetric algebras?
Recall that a Weil algebra is a finite-dimensional real unital algebra that admits exactly one homomorphism to R.
Such algebras form the basis of the Weil approach to differential geometry, pioneered …
10
votes
0
answers
740
views
Can any smooth triangulation of a smooth manifold be blurred?
For the purposes of this question, let's say that a blurring
of a smooth triangulation $T$ of a smooth manifold $X$
is a smooth homotopy $h\colon [0,1] \times X \to X$ such that $h_0=\operatorname{id} …