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Algebras of operators on Hilbert space, $C^*-$algebras, von Neumann algebras, non-commutative geometry
1
vote
Accepted
Definition of Radon measure on Takesaki's first volume
Making no claims of originality, one possible proof can be obtained by combining Example 4.60, Lemma 5.11, and Lemma 3.14 in arXiv:2005.05284.
This shows that for any Radon measure its algebra of equi …
2
votes
Accepted
Continuous surjection between spectra of commutative von Neumann algebras
Is it true that π maps clopen sets into clopen sets?
This is true if and only if the inclusion $V_1→V_2$ is a morphism of von Neumann algebras, i.e., its image is closed in the ultraweak topology.
S …
26
votes
8
answers
3k
views
Bimodules in geometry
Grothendieck's approach to algebraic geometry in particular tells us to treat all rings as rings of functions
on some sort of space. This can also be applied outside of scheme theory (e.g., Gelfand-N …
2
votes
Hochschild/cyclic homology of von Neumann algebras: useless?
I am surprised that nobody mentioned the book by Sinclair and Smith “Hochschild Cohomology of von Neumann algebras” so far.
If I remember it correctly, they claim that nobody knows whether there is a …
21
votes
3
answers
3k
views
Noncommutative smooth manifolds
Connes defined a noncommutative analog of a closed oriented Riemannian spin^c manifold using spectral triples.
Using his definition it is unclear how to separate the smooth structure from the metric. …
7
votes
Accepted
Questions about Maharam's classification theorem
The spaces $[0,1]$, $[0,1]^2$, and $S^1$ are all isomorphic as measurable spaces, including their sets of measure 0, as required by the Gelfand-type duality for measurable spaces.
For instance, the is …
13
votes
Accepted
Making sense of "every non-commutative algebra has its own internal time evolution (aka a on...
Given any von Neumann algebra $M$, we can define its noncommutative $\def\L{{\cal L}} \L^p$-spaces $\L^p(M)$ for any $\def\C{{\bf C}} p∈\C$ such that $\Re p≥0$.
Here I use the notation $\L^p:={\rm L}^ …
5
votes
Accepted
Free extension of algebra for an operad
This result is true and is due to Spitzweck, Berger–Moerdijk, Fresse, and Elmendorf–Mandell.
A complete set of references can be found around Proposition 5.7
in the paper https://arxiv.org/abs/1410.56 …
37
votes
5
answers
4k
views
Reference for the Gelfand duality theorem for commutative von Neumann algebras
The Gelfand duality theorem for commutative von Neumann algebras states that the following three categories are equivalent:
(1) The opposite category of the category of commutative von Neumann algebra …
6
votes
Accepted
Reference for the Gelfand duality theorem for commutative von Neumann algebras
As shown in the paper Gelfand-type duality for commutative von Neumann algebras, the following categories are equivalent.
The category CSLEMS of compact strictly localizable enhanced measurable spac …
5
votes
1
answer
333
views
One-parameter semigroups of bimodules
Suppose M is a von Neumann algebra.
Consider a monoidal category of bimodules over M.
Here a bimodule is a Hilbert space with two normal representations of M.
The monoidal structure is given by Connes …
4
votes
Accepted
On existence of certain operators in von Neumann algebra
This is false.
Consider, for example, the case of M being the von Neumann algebra
of bounded complex-valued functions on an infinite countable set I.
It acts on the Hilbert space of square-summable fu …
20
votes
0
answers
827
views
Can we define spectral triples using the language of rigged Hilbert spaces?
The traditional mathematical approach to quantum mechanics,
as developed by von Neumann, is based on Hilbert spaces and unbounded self-adjoint operators.
Another approach, which more closely resembles …
2
votes
Regarding Haagerup $L^{P}$ spaces
How the norm on L^{P} space related to weight φ?
The L^p-spaces and their norms are independent of the choice of the weight φ.
See, for instance, the exposition by Yamagami in “Algebraic Aspects …
4
votes
Why are ultraweak *-homomorphisms the `right' morphisms for von Neumann algebras (and say, n...
A von Neumann algebra is a $C^*$-algebra $A$ that admits a predual,
i.e., a Banach space $A_*$ such that there is an isomorphism $A\to(A_*)^*$.
A morphism of von Neumann algebras is a morphism of $C^ …