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Questions about partial differential equations of hyperbolic type. Often used in combination with the top-level tag ap.analysis-of-pdes.

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Why don't we study hyperbolic equations as elliptic and parabolic equations?

Why we do not study such estimates for hyperbolic equations? Because they are false. Now: you may ask "why are they false?" This is a fairly deep question, and answers often involve discussion of p …
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8 votes
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Looking for references to study $U^p$ and $V^p$ spaces

You can take a look at Herbert Koch's contribution in Koch, Herbert; Tataru, Daniel; Vişan, Monica, Dispersive equations and nonlinear waves. Generalized Korteweg-de Vries, nonlinear Schrödinger, wave …
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7 votes
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Preservation of metric signature in Cauchy problem for the Einstein equations

The dynamic metric is the metric for the quasidiagonal system; and so for self consistency the solution can only be proven to exist (and be unique) when the metric (i.e. the solution itself) is hyper …
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7 votes
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Uniqueness of solution of the wave equation

Since I haven't been able to track down Selberg's lecture notes since he moved to Bergen, and since the proof of the result I mentioned in this comment is super-short anyway, let me just include a pro …
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6 votes
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Finite speed propagation by finite energy method

For an equation that is actually hyperbolic, this is well-known. Here are some classical references: Lars Garding, Cauchy's Problem for Hyperbolic Equations (1958) Jean Leray, Hyperbolic Differenti …
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6 votes
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Existence of a solution for a quasilinear hyperbolic system of PDEs with many state variables

Okay, so I would write your equations instead in the following form: $$ \partial_t u_i + v_i(t) \cdot \nabla u_i = b_i (t, \vec{x}, \vec{u}) $$ This is a system of transport equations and so can actua …
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6 votes
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Quasilinear wave equations without (weak) null conditions and conjectures

What you've found is basically "survivor bias", so it helps for me to describe a bit where the null conditions came about. Assertion 1: Quasilinear partial differential equations, in general, are too …
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5 votes

Decay estimates for wave and Klein-Gordon equation in "generic" curved backgrounds

A longish bunch of remarks: there's a big leap that doesn't make sense between your question and your motivation. On the maximally extended Schwawrzschild solution there is no decay to the wave equat …
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5 votes

Boundary conditions for Klein-Gordon equation

There are a few things that can be said about this, and it depends on how one "approaches" infinity. Wave equations satisfy conservation of energy. Let $$E(t) = \int_{\{t\} \times \mathbb{R}^d} |\par …
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5 votes

Decay estimate on wave equation

The key is to estimate the integral (where $g\in C^\infty_c(\mathbb{R}^3)$ by assumption) $$\tag{A} \iint_{|x - y| = t} g(y)~ dS_y \lesssim \iiint_{|x-y| \geq t} |D g|~dy. $$ Once this estimate is fou …
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5 votes
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A problem about closed 2-forms on Minkowski space

Your question can be equivalently phrased as: Given a closed two-form $F$ on $\mathbb{R}^4$, is it always possible to find a Lorentzian metric on $\mathbb{R}^4$ such that $\delta F = 0$. Then t …
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5 votes
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On a nonlinear wave equation

By replacing $\phi$ by $-\phi$ you can set $\alpha$ to be positive (or negative, if you wish). By replacing $\phi$ by $\lambda \phi$ you can rescale away $\alpha$. So you can set $\alpha$ to be either …
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5 votes
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Maximum principle for hyperbolic PDEs

Fundamentally, the classical maximum principles for second order elliptic PDEs are based on the simple facts that The Hessian of a function at a local maximum is positive semidefinite. The full contr …
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4 votes
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Wave equation in $ \Omega\times(0,T) $

Strichartz estimates on domains is a difficult problem! First: on bounded domains you cannot have any global in time Strichartz estimates. This is because of the presence of standing waves. (Set initi …
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4 votes
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wave equation with vanishing trace at infinity

If $q$ is not signed, then in general the solution need not be unique. The question of uniqueness can be reduced to the case where $f \equiv 0$. In this case, the constant $0$ function obviously solve …
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