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The Cauchy-Schwarz inequality states $|\langle x,y \rangle |\leq ||x||\cdot ||y||.$ Use this tag for questions related to the CS inequality and its applications.
9
votes
How to prove that $1/ ((y+z) x^4) + 1/ ((z+x) y^4) + 1/ ((x+y) z^4) \geq 3/2$ for $x, y, z>0...
$\newcommand\tH{\tilde H}$This problem is one of real algebraic geometry, which can be solved purely algorithmically. In Mathematica, such algorithms are implemented by Reduce and similar commands.
He …
5
votes
A probabilistic angle inequality
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6
votes
Accepted
A probabilistic angle inequality
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6
votes
Accepted
A moment inequality
This inequality is false in general, by homogeneity considerations. Indeed, it can be rewritten as $L(x)\ge R(x)$, where $L(x):=\left(\chi(0)\chi(2)-\chi(1)^{2}\right)\left(\chi(4)\chi(2)-\chi(3)^{2}\ …
6
votes
Accepted
Prove inequality: $2\Big[ \sum_{k=0}^{n} (k+1) a_k \Big]^2 -\Big[1+ \sum_{k=0}^{n} a_k \Big]...
A counterexample is given by the following conditions: $n=185$,
$$a_k=\sum_{j=k}^n b_j,\quad b_j:=\frac{c_j}{j+1},
\quad c_j:=\frac{1000}7\,1(j=47)+\frac{302}7\,1(j=185).$$
Indeed, then $a_0\ge\cdots …
6
votes
Accepted
An inequality involving a sum of power terms
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3
votes
Is it possible to find $f$ such that : $f$ is absolutely integrable, $f'$ is absolutely inte...
Indeed, disjoint tiny smooth spikes, of small heights and even much-much smaller widths, will do.
Let $K\in C^\infty(\mathbb R)$ be such that $K\ge0$, $K(x)=0$ if $|x|>1/2$, and $a:=K(1/3)-K(0)\ne0 …
6
votes
Accepted
Good upper bound for a certain sum
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$
Of course, without further assumptions on the $e_t$'s, no good bound can be given. However, looking at your examples, it appears that you are primarily interested in situat …
5
votes
Accepted
The inequality $\int^\infty_0 (\sin(rt)r^3/\sinh^2(r)) dr\leq cte^{-At}$
This is to complement the answer by Carlo Beenakker by showing that
$$I(t)\le\pi^4 te^{-\pi t}\tag{1}\label{1}$$
for real $t\ge0$, where $I(t)$ is the integral in question.
Indeed, according to Carlo …
4
votes
Accepted
Cauchy-Schwarz-like inequality with a power $p$ term
$\newcommand\th\theta\newcommand\R{\mathbb R}$This is false for any real $p>2$ (actually, this is false for any real $p>1$ such that $p\ne2$).
Indeed, if this were true, then, by continuity, we could …
5
votes
Accepted
Good upper-bound for $\mathbb E[|X-np|^r]$ where $X \sim \text{Binomial}(n,p)$ and $r \ge 1$
By the main result of the paper Exact Rosenthal-type bounds, we have
$$E|X-np|^r\le c^r E|\Pi_\lambda-\lambda|^r
$$
for real $r\in(2,\infty)\setminus(3,4)\setminus(4,5)$, where real $c>0$ and $\lambd …
1
vote
An alternative proof of Bayesian Cramer-Rao
Perhaps, the following re-arrangement of the argument will help remove the mystery of the choice of $g(x,y)=\frac{\partial}{\partial x} \ln f(x,y)=\frac{f'_x(x,y)}{f(x,y)}$, where $f:=f_{X,Y}$ and ${} …
1
vote
Accepted
Tight sublinear estimates for a triple partial binomial summation
This conjecture does not hold even in the case $\gamma=\gamma'=1/2$.
Indeed, consider the values of $\ell,t,k$ such that
$$|\ell-n/2|\ll\sqrt n,\ |t-n/2|\ll\sqrt n,\ |k-t/2|\ll\sqrt n,$$
where $A\l …
1
vote
Properties of a function $C_\ell(\ell)$ which checks an inequality in ideal case (decreasing...
It is not enough to assume that $Y=C_l$ is decreasing in $l$.
Indeed, if your inequality were true for all such $Y$, then its non-strict version would be true for all constant $Y$, say for $Y=1$ for a …
4
votes
Accepted
Is there a tight lower bound for the expectation of the product of two positive valued rando...
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Let us present the exact lower bound on $EXY$ in terms of $\mu_1:=\mu_X$, $\mu_2:=\mu_Y$, $\si_1:=\si_X$, $\si_2:=\si_ …