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Algebraic and geometric theory of quadratic forms and symmetric bilinear forms, e.g., values attained by quadratic forms, isotropic subspaces, the Witt ring, invariants of quadratic forms, the discriminant and Clifford algebra of a quadratic form, Pfister forms, automorphisms of quadratic forms.

5 votes

About the solutions of $ \dfrac{x^p - y^p}{x - y} = a^2+pb^2 $

Friday, June 28. I found a nice exposition by David Savitt https://pi.math.cornell.edu/~web401/steve.gauss17gon.pdf from which this is page 32 David A. Cox, in Galois Theory, gives an account of Gau …
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1 vote

Automorphism groups in class sets of ternary lattices

I put lots of references at http://zakuski.math.utsa.edu/~kap/ I've got an early version working. At first I thought it would be just class number one or two. The six coefficients $a,b,c,d,e,f$ ref …
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3 votes

A cubic equation, and integers of the form $a^2+32b^2$

details, details. From $x$ odd and $$ x^4-32x-16 = (x^2 + 4)^2 - 2(2x+4)^2. $$ we see that $x^4-32x-16$ is not divisible by any prime $q \equiv 3,5 \pmod 8.$ That is, $x^2 + 4$ is also odd. Nex …
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2 votes

Integers $8k+3>0$ not represented by $2x^2+4y^2+4yz+9z^2$ over the integers

First things first, all the relevant numbers really are represented by $x^2 + 2 y^2 + 32 z^2.$ See http://zakuski.math.utsa.edu/~kap/Kap_Jagy_Schiemann_1997.pdf for regular ternaries. From my giant …
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3 votes

Integers representable as binary quadratic forms

you don't seem to be mentioning Gauss composition. You have a genus of forms, equivalent to $\langle 1,8,27 \rangle,$ then $\langle 3,8,9 \rangle,$ then $\langle 9,8,3 \rangle.$ These are convenient …
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0 votes

Binary quadratic forms order four in the form class group not having desired coefficients

Finally made an exhaustive program, finds stubborn order four forms; ran it up to absolute value of discriminant 2500. 144: < 5, 4, 8> STUBBORN 144: < 4, 0, 9> 144: < 1, 0, 36> 144 …
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4 votes

Modular forms and number of representations by binary quadratic forms

The coefficient $w$ in theorem 64 is usually $2,$ but is $4$ for discriminant $-4,$ then $6$ for discriminant $-3$
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2 votes

Proof that $x^2 + y^2 - z^2$ is universal

As the others point out, there is no knowing about the earliest this was written down. For example, the notion of regularity of a ternary form is due to Dickson, but universality is an easier concept …
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1 vote

Solving a pair of ternary quadratic form equations

Part of this is finding the primitive integer null vectors of an indefinite ternary quadratic form $f(x,y,z).$ Mordell points out that these occur in a finite number of parametrizations. The process y …
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0 votes

Simple conjecture about rational orthogonal matrices and lattices

This is from papers about 1940 by Gordon Pall, one with B. W. Jones. I'm looking for statements about things being primitive, especially odd/even. Found it, also in "Rational Automorphs," in order to …
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4 votes

When does $axy+byz+czx$ represent all integers?

I have figured out some things; it is much quicker, as far as computing, to find a way for the Hessian matrix of the ternary quadratic form, is to have it represent the (two by two) Hessian of the for …
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13 votes

When does $axy+byz+czx$ represent all integers?

Just so you know, one of Dickson's students (A. Oppenheim) finished classifying (indefinite) universal ternaries; the final family is $xy - M z^2.$ Page 161 in Modern Elementary Theory of Numbers. You …
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7 votes

Difference of two sums of two squares

Sure. Demand $a \geq b \geq 0$ as well as $c,d \geq 0.$ Then map $$ (a,b,c,d) \mapsto (25a+11b+24c+13d, 11a-b+11c, 24a+11b+23c+13d, 13a + 13 c+d) $$
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4 votes

Evaluating a binary quadratic form at convergents

The item you want is the neighbor method, a version of continued fractions. I learned this from Buell, Binary Quadratic Forms. It is also in a 1929 Introduction by Dickson, and a book by Matthews I've …
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1 vote

Solutions to the Diophantine equation $x^2+3y^2+3z^2=n$

well, here is the same information when the target number has a factor of 2 or 3. The ratio pair (12,4) is evidently repeated, the two cases are $1,10 \pmod {12}.$ Oh, note that multiples of $9$ are …
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