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Homotopy theory, homological algebra, algebraic treatments of manifolds.
35
votes
2
answers
5k
views
Why should have Peter May worked with CGWH instead of CGH in "The Geometry of Iterated Loop ...
This is a follow-up to Dan Ramras' answer of this question.
The following correction can be found in the errata to The Geometry of Iterated Loop space (Page 484 here).
The weak Hausdorff rather t …
26
votes
2
answers
2k
views
Are there geometrically formal manifolds, which are not rationally elliptic?
Formality of a space is meant in the sense of Sullivan, i.e. a space $X$ is called formal, if its commutative differential graded algebra of piecewise linear differential forms $(A_{PL}(X),d)$ is weak …
18
votes
1
answer
1k
views
Is the restriction map for embeddings of manifolds with boundary a fibration?
Let $M$ and $W$ be smooth manifolds (possibly with boundary) and $V\subseteq W$ a submanifold. We have a map between embedding spaces
$$Emb(W,M)\rightarrow Emb(V,M)$$ given by restriction.
Richard Pa …
14
votes
2
answers
2k
views
Reference Request: Compact manifolds with boundary have the homotopy type of a CW-complex
Let $M$ be a compact manifold (possibly non-smooth) manifold with boundary $\partial M$.
Is the inclusion $\partial M\hookrightarrow M$ homotopy equivalent to the inclusion of a subcomplex into a CW- …
13
votes
Is the Hurewicz theorem ever used to compute abelianizations?
The mapping class group of a smooth manifold $M$ is the group of all its self diffeomorphisms up to isotopy, i.e. $\pi_0(\operatorname{Diff}(M))\cong \pi_1(B\operatorname{Diff}(M))$.
A large portion …
13
votes
Which stable homotopy groups are represented by parallelizable manifolds?
Repeating the first part of Oscar's answer and elaborating on comments by Chris and Panagiotis, here is a down-to-earth argument in all cases:
The cases $n=1,3,7$ are fine, since the stable stems are …
13
votes
Accepted
On the state of the art on closed $(n-1)$-connected $2n$ manifolds
The classification problem of smooth oriented closed $(n-1)$-connected $2n$-manifolds for $n\ge3$ splits into three parts.
Classify smooth almost closed compact oriented $(n-1)$-connected $2n$-manifo …
12
votes
1
answer
712
views
Homotopy spheres with vanishing and non-vanishing $\alpha$-invariant
I'm unsure whether this question is appropriate for mathoverflow, so feel free to criticize.
All manifolds are closed, smooth and have dimensions $n\ge 5$.
The Atiyah-Shapiro-Bott-Orientation gives …
11
votes
What are examples when the equality of some invariants is good enough in algebraic topology?
Stiefel-Whitney numbers detect (unoriented) bordism classes and together with Pontryagin numbers, they determine oriented bordism classes.
Ranicki's total surgery obstruction of a finite $n$-dimensio …
11
votes
Accepted
Mapping class groups in high dimension
Let me assume that M is at least 5-dimensional.
Sullivan's proof only uses surgery theory and properties of O(n) that also hold for Top(n), so the answer to your first question is yes.
Regarding your …
11
votes
Accepted
Characteristic classes of non-linear sphere bundles
For many values of $n$, the answer to both questions is no. Since the fundamental groups of $BX$ and $B\mathrm{Diff}(S^n)$ are finite for $n\ge5$ (This uses that $\pi_0\mathrm{Diff}_\partial(D^n)$ is …
11
votes
4
answers
1k
views
Topological Grothendieck Construction
Let $C$ be a small category and $F\colon C^{op}\rightarrow Set$ a functor. The Grothendieck construction is the category $F\wr C$ with objects being pairs $(c,x)$ where $c$ is a object of $C$ and $x\i …
8
votes
cohomology of BG, G compact Lie group
Just for completeness, here's another argument without spectral sequences via rational homotopy theory.
Recall a theorem of Hopf, which states that the rational cohomology of a path-connected H-space …
8
votes
1
answer
635
views
Reference Request: Grouplike Algebras over the little $n$-cubes operad are $n$-fold loop spaces
In Geometry of the iterated loop space, Peter May proved his famous recognition theorem, which is, in a simple form, stated on page 3 as the following.
There exist $\Sigma$-free operads $\mathcal{ …
6
votes
Accepted
Naive G-spectrum representing geometric equivariant cobordism
Since my comment answered Emanuele Dotto's answer, I post it as an answer:
Stefan Schwede discusses equivariant bordism in his book project about global homotopy theory in detail.