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Questions about abstract measure and Lebesgue integral theory. Also concerns such properties as measurability of maps and sets.
2
votes
a measure convolution equation
Choosing properly the Gaussian (e.g. $e^{-π\vert x\vert^2}$) and the normalization for the Fourier transform, your equation becomes
$$
\hat f(\xi)=e^{-π\vert \xi\vert^2}\hat \mu(\xi).
$$
This implies …
2
votes
Does a weaker condition than vanishing derivative imply a function being constant?
$f$ is a continuous function thus can be considered as a distribution. For $\phi\in C^1_c(0,1)$, we have
$$
\langle f',\phi\rangle=-\int_{\mathbb R} f(x) \phi'(x) dx=\lim_{\epsilon \rightarrow 0}
\int …
0
votes
Can a nowhere differentiable function preserve measurability?
Take $\Psi$ as the standard Cantor function: $\Psi(x)=0$ for $x\le 0$,
$\Psi(x)=1$ for $x\ge 1$, continuous, nondecreasing, constant on each connected component of the complement of the Cantor ternar …
6
votes
About the definition of Borel and Radon measures
Let $(X,\mathcal M, \mu)$ be a measure space, where $\mu$ is a positive measure and $X$ is topological space. Let $\mathcal B$ the Borel $\sigma$-algebra on $X$.
The measure $\mu$ is called a Borel m …
2
votes
Fractal set $E$ such that the indicator function $\mathbf{1}_E$ is BV
An open subset $E$ of $\mathbb R^{N}$ such that $\mathbf 1_E$ belongs to $BV$ is said to be with "finite perimeter" and this implies that
$$
\mathcal H^{N-1}(\partial E)<+\infty,
$$
where $\mathcal H …
15
votes
2
answers
3k
views
Radon-Nikodym theorem for non-sigma finite measures
Let $(X,\mathcal M, \mu)$ be a measured space where $\mu$ is a positive measure.
Let $\lambda$ be a complex measure on $(X,\mathcal M)$. When $\mu$ is sigma-finite, the Radon-Nikodym theorem provides …
4
votes
Accepted
Boundedness of a singular integral operator on $L^p(\mathbb{R})$, $1<p<\infty$
We have with $\chi\in C^\infty_c(\mathbb R)$, equal to $1$ near 0,
$$
\frac{1}{\sinh t}=\frac{\chi(t)}{\sinh t}+\frac{1-\chi(t)}{\sinh t}.
$$
The second function belongs to $L^1$ and Young's inequalit …
1
vote
Show that the absolute value of this function is twice differentiable except on a set of Leb...
Let $h:\mathbb R\rightarrow \mathbb R$ continuous such that the second distribution derivative $h''$ is continuous and bounded. We define
$$
\rho(x)=\vert{h(x)}\vert^{\frac{1}{2}}+\vert{h'(x)}\vert,
$ …
1
vote
Accepted
Support of functions in Fourier domain
No. You may ask the same equivalent question for a function in $L^2$. A function $u$ belongs to $L^2$ means measurability and
$$
\int \vert u(x) \vert^2 dx<+\infty,
$$
which implies
$
\lim_{R\rightarr …
22
votes
Pullback measures
A simple-minded answer. The push forward of a measure is a triviality: take a measure space $(X,\mathcal M, \mu)$ and a mapping
$f:X\rightarrow Y$. Then defining $\mathcal N=${$B\subset Y, f^{-1}(B)\ …
1
vote
For what nonnegative measures $\mu$ does $\mu*e^{-|\cdot|}\in L^{\infty}$?
Let $(X,\mathcal M)$ be a measurable space and let $\lambda$ be a complex measure on $(X,\mathcal M)$. The total variation $\vert \lambda\vert$ is a positive measure on $(X,\mathcal M)$ with a finite …
2
votes
Accepted
Meaning of Alberti rank-one theorem
Let $X=\sum_ja_j(x)\frac{\partial }{\partial x_j}$ be a $BV$ vector field in an open subset of $\mathbb R^n.$ Alberti's theorem says that
$$
DX_s=(\frac{\partial a_j }{\partial x_k})_{1\le j,k\le n}= …
3
votes
Accepted
$f \in L^p(\mathbb{R}^2)$ for all $p \geq 1$, and $f$ has zero integral. What can we say abo...
Let $f$ be in $L^1(\mathbb R^n)$, then $\hat f$ belongs to $L^\infty(\mathbb R^n)$ and is (uniformly) continuous with $\lim_{\vert \xi\vert\rightarrow +\infty} \hat f(\xi)=0$: this is the Riemann-Leb …
1
vote
Riemann-Liouville integral of $f$ is zero implies $f =0$ a.e
Let $H=\mathbf 1_{\mathbb R^+}$ be the Heaviside function and let us define $g$ by
$
g(x)=H(x) x^{-1/2}.
$
We note that $g$ is homogeneous with degree $-1/2$ and thus its Fourier transform is homogene …