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Non-commutative rings and algebras, non-associative algebras, universal algebra and lattice theory, linear algebra, semigroups. For questions specific to commutative algebra (that is, rings that are assumed both associative and commutative), rather use the tag ac.commutative-algebra.

5 votes

Algebraic theorems with no known algebraic proofs

Okninski proved that $M$ is a monoid and $K$ is a field of characteristic $0$ such that the monoid algebra $KM$ is von Neumann regular, then $M$ is locally finite using analytic methods. No algebraic …
Benjamin Steinberg's user avatar
3 votes

Examples of combinatorial problems where the only known solutions, or most "natural" solutio...

Many special cases of the Černý conjecture in automata theory have been proved using linear algebra, or really representations of monoids, that do not have known combinatorial proofs. The conjecture …
LSpice's user avatar
  • 12.9k
7 votes
Accepted

True or false? Every left or right cancellative, duo semigroup is cancellative

Here is a right cancellative duo monoid that is not cancellative. Let $A$ be a free abelian group of countable rank with basis $e_0,e_1,\ldots$. Let $\Phi\colon A\to A$ be the endomorphism given by $ …
Benjamin Steinberg's user avatar
4 votes

If a semigroup embeds into a group, then is it a subdirect product of groups?

I seem to be late to this game, but since you asked for a reference request here is one which also gives a more elementary example which has interesting properties in its own right. The reference is P …
Benjamin Steinberg's user avatar
14 votes
Accepted

Pairs of matrices for which traces of powers are independent of the order

If you look at the book of Radjavi on Simultaneous Triangularization it is shown that a semigroup of complex matrices which satisfies your trace property is simultaneously triangularizable, and so the …
Benjamin Steinberg's user avatar
3 votes

What is known about finite dimensional modules over the nilCoxeter algebra?

@DaveBenson, has already given a beautiful answer to this question. I just wanted to point out that a number of the things he says (although not his full computation of the dimension of the Ext-algeb …
Benjamin Steinberg's user avatar
3 votes
Accepted

Every homomorphism between (rational) Puiseux monoids is multiplication by a non-negative ra...

This seems to be Corollary 4 of the paper Morio Sasaki, Takayuki Tamura, Positive rational semigroups and commutative power joined cancellative semigroups without idempotent Czechoslovak Mathematical …
Benjamin Steinberg's user avatar
3 votes
Accepted

Minimal ideals and subalgebras of semisimple algebras

For a not necessarily unital ring $R$, a left $R$-module $S$ is simple if $RS\neq 0$ and $S$ has no proper submodule. A simple right module is defined dually. For a not necessarily unital ring the f …
Benjamin Steinberg's user avatar
3 votes
Accepted

How is the classification of groups extensions by $H^2$ related to Yoneda Ext?

As I mentioned in my comment above, Gruenberg gave a direct bijection between $\operatorname{Ext}^1_{\mathbb ZG}(I_G,A)$ and group extensions $1\to A\to H\to G\to 1$. The details can be found in eith …
LSpice's user avatar
  • 12.9k
5 votes

Congruences that aren't "finite from above"

On a ring or group all congruences are parafinite. Partition into the kernel and the complement of the kernel.
Benjamin Steinberg's user avatar
10 votes
Accepted

An algebra with more than one Frobenius algebra structure

If $A$ is a Frobenius $K$-algebra and $\lambda\colon A\to K$ is a Frobenius form, then the Frobenius forms are the mappings of the form $a\mapsto \lambda(ua)$ with $u$ a unit of $A$. One way to see th …
Benjamin Steinberg's user avatar
1 vote
Accepted

Semigroup algebras with one dimensional center

Let me answer what goes on with bands. I'll assume the band is a monoid for simplicity. I think everything works so long as the band is unital but this can get messier to describe. Details of wha …
Benjamin Steinberg's user avatar
10 votes
Accepted

Do rational group algebras have an outer automorphism?

This conjecture was proved in Feit, Walter; Seitz, Gary M. On finite rational groups and related topics. Illinois J. Math. 33 (1989), no. 1, 103–131. The proof relies on the classification since this …
Benjamin Steinberg's user avatar
6 votes
Accepted

When is semigroup algebra local?

Question 1 either has a trivial answer or it is answered in my paper (with coauthors). REPRESENTATION THEORY OF FINITE SEMIGROUPS, SEMIGROUP RADICALS AND FORMAL LANGUAGE THEORY depending on what you …
Benjamin Steinberg's user avatar
1 vote

Hopf algebra of representative k-valued functions of an abstract group

This question is not well formulated because you don't define $R(G)$. Also it is not clear to me what you want to know,since your "if" clause has no "then" clause. I assume you mean the Hopf algebra o …
Benjamin Steinberg's user avatar

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