Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 1465

Topology of cell complexes and manifolds, classification of manifolds (e.g. smoothing, surgery), low dimensional topology (e.g. knot theory, invariants of 4-manifolds), embedding theory, combinatorial and PL topology, geometric group theory, infinite dimensional topology (e.g. Hilbert cube manifolds, theory of retracts).

3 votes

Fundamental group of the complement of a codimension two submanifold

To your first question, the answer is yes. Take a $k$-component trivial link in $S^n$, i.e. the boring, linear embedding $$\sqcup_k S^{n-2} \to S^n$$ that is the boundary of a linear embedding $$\sqcu …
Ryan Budney's user avatar
  • 44.4k
2 votes

Handle decompositions subordinate to an open cover

If you call the standard $n$-simplex $\Delta^n$, i.e. $$\Delta^n = \{ (x_0, x_1, \cdots, x_n) : x_i \geq 0 \forall i, \sum_i x_i = 1\}$$ then the function $\phi : \Delta^n \to \mathbb R$ given by $\ph …
Ryan Budney's user avatar
  • 44.4k
5 votes

Equivalence of knotted spheres in $S^4$

$\DeclareMathOperator{\Diff}{Diff}$ The answer is "yes modulo some small potatoes". There is one case where the answer is a simple no: if $K$ and $K'$ are mirror images of each other you can have a di …
Ryan Budney's user avatar
  • 44.4k
2 votes
Accepted

Numerical computation of the second Vassiliev invariant, and the permutation $(1 3 4 2)$

This is not a full answer to your question, but it gives some information. The expression (1) is an integral version of the Polyak-Viro formula for the type-2 invariant, described here: https://academ …
Ryan Budney's user avatar
  • 44.4k
9 votes

Why/does 'low-dimension' topology end with dimension 4?

There are of course ways to construct difficult problems in high-dimensional manifold theory. One of the ways high-dimensional manifold theory differs strongly from low-dimensional manifold theory i …
Ryan Budney's user avatar
  • 44.4k
14 votes
Accepted

Isotopic diffeomorphisms of the sphere

This is Cerf's pseudoisotopy-implies-isotopy theorem. Cerf's result is true in high dimensions, while it's independently known in a low-dimensional range. In dimension $2$ it goes back to the Earle–E …
Ryan Budney's user avatar
  • 44.4k
3 votes

Lie group framing and framed bordism

Lie group framing is a reference to the group action. A Lie group $G$ acts on the left of $G$ by the map $$(g,h) \longmapsto gh.$$ Similarly there are actions on the right, and conjugation actions, e …
Ryan Budney's user avatar
  • 44.4k
9 votes

Generalization of the sphere theorem in dimension at least 4

I have a thread on the co-dimension $1$ generalization of Dehn's Lemma for 4-manifolds: A problem/conjecture related to 4-manifolds that deserves a name. What name does it deserve? My pair of papers w …
Ryan Budney's user avatar
  • 44.4k
5 votes
Accepted

How to get a presentation of the mapping class group of the $n$-punctured sphere

$\DeclareMathOperator\Diff{Diff}\DeclareMathOperator\Emb{Emb}\DeclareMathOperator\fix{fix}$There's a variety of ways to do this. If you take "mapping class group" to mean "isotopy classes of diffeomo …
Ryan Budney's user avatar
  • 44.4k
2 votes

Handle attachment information from Morse function and triangulation

Near a critical point $p$ of a genuine Morse function you have the local model $$f(x) = f(p) + x_1^2 + \cdots + x_i^2 - x_{i+1}^2 - \cdots - x_n^2$$ Just below the height of $p$, your attaching sphere …
Ryan Budney's user avatar
  • 44.4k
6 votes
Accepted

Is there a geometric interpretation of the second derivative of the Alexander polynomial at ...

Given a knot in $S^3$, think of it as an embedding $$f : S^1 \to S^3.$$ The configuration space of $5$ distinct points in $S^3$ is denoted $C_5(S^3)$, this is a $15$-dimensional manifold and it consis …
Ryan Budney's user avatar
  • 44.4k
4 votes
Accepted

Does every simply connected, orientable, non-compact, 3-manifold embed in $\mathbb{R}^3$?

When the manifold is the universal cover of a compact $3$-manifold $M$ (to begin with, lets say without boundary) then you construct the embedding by hands, using geometrization. In your question let …
Ryan Budney's user avatar
  • 44.4k
2 votes

How to find the JSJ decomposition in the plumbing tree model of a graph manifold?

Given that all your ingredient manifolds are Seifert-fibered, your JSJ decomposition is going to be a subset of the separating tori in your plumbing construction, i.e. corresponding to your edges, if …
Ryan Budney's user avatar
  • 44.4k
1 vote

applications of Sard's to differential topology

It's been a long time, but isn't your suggestion roughly Whitney's original approach to this problem? I don't have Whitney's papers in front of me but this is roughly how I think his arguments went. …
Ryan Budney's user avatar
  • 44.4k
7 votes
Accepted

Is a spin structure on a knot complement the same thing as an orientation of the knot?

Is the theorem true? There is an non-natural bijection. There is no natural bijection. A link exterior is homotopy-equivalent to a $2$-complex, so a trivialization of the tangent bundle over the $2$ …
Ryan Budney's user avatar
  • 44.4k

1
2 3 4 5
12
15 30 50 per page