Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 1345

The study of differentiable manifolds and differentiable maps. One fundamental problem is that of classifying manifolds up to diffeomorphism. Differential topology is what Poincaré understood as topology or “analysis situs”.

7 votes
Accepted

Smooth map between oriented manifolds

This follows from a result of Hopf (see the exposition of Epstein). By this result, one may assume that there is a disk $D\subset N$ such that $f^{-1}(D)$ is $d$ disks mapping diffeomorphically to $D$ …
Ian Agol's user avatar
  • 68.9k
2 votes
Accepted

Reference request and prerequisites for understanding the Sphere Theorem and the Loop Theore...

On Marc Lackenby’s webpage you can find notes on 3-manifold topology (Michaelmas 1999). The proof of the loop theorem in Chapter 9 uses special hierarchies (instead of Papakyriakopoulos’ towers) follo …
Ian Agol's user avatar
  • 68.9k
7 votes

Embedded 2-tori in $S^1\times S^4$

I think this is true (homotopy implies isotopy). Consider a generic smooth torus embedding $f: T^2 \to S^1\times S^4$, then the projection to $S^1$ gives a circle-valued Morse function on $T^2$. Becau …
Ian Agol's user avatar
  • 68.9k
7 votes
Accepted

Does every triangulable manifold have a vertex-transitive triangulation?

There exists many closed connected hyperbolic 3-manifolds $M$ with trivial symmetry group, and hence trivial mapping class group. $M$ cannot be homeomorphic to a simplicial complex $\tau$ which admits …
Ian Agol's user avatar
  • 68.9k
6 votes

Doubles of 2-handlebodies

A hyperbolic 4-manifold has zero signature and hence is null-cobordant. However there exist hyperbolic 4-manifolds with trivial isometry group, and hence which cannot be a double of a 2-handlebody (su …
Ian Agol's user avatar
  • 68.9k
5 votes

Classification of surface bundles over surfaces

For a), when $\chi(F)<0$ $F$-bundles over $B$ are classified by maps $\pi_1(B)\to Mod(F)$, where $Mod(F)$ is the mapping class group of $F$. This boils down to the fact that $Diff_0(F)$ is contractibl …
Ian Agol's user avatar
  • 68.9k
4 votes
Accepted

Compact closed aspherical manifolds with vanishing second homology in all the covering spaces

I think that the answer to this question is unknown in general. If one had a closed aspherical manifold with this property, then it could not contain a Baumslag-Solitar subgroup since such a group has …
Ian Agol's user avatar
  • 68.9k
4 votes

Under what conditions can an orientable Riemannian 3-manifold be defined implicitly?

This is too long for a comment. If you want $0$ to be a regular value of $f$, then this should be possible iff there is a smooth isometric embedding to $R^n$ with trivial normal bundle (for any dimens …
Ian Agol's user avatar
  • 68.9k
9 votes
Accepted

When can a surface in a 3-manifold be isotoped off a knot?

Let’s assume that the manifold $M$ is irreducible and orientable and the surface $S$ is orientable. This is to avoid 1-sided surfaces. First let’s assume that the surface $S$ is fully compressible. T …
Ian Agol's user avatar
  • 68.9k
18 votes
Accepted

Very particular kind of 4-manifolds. Classification

There are plenty of such manifolds, but as Danny indicates in his answer, there is not a known classification. Take any acyclic group $G$ with a finite aspherical 2-complex $C$ with $\pi_1(C)=G$. Then …
Ian Agol's user avatar
  • 68.9k
6 votes
Accepted

Irreducibility of 3-manifolds with (non)empty boundary

You're asking how reducibility/irreducibility behaves under drilling and filling. I think you've captured the essence of drilling: if a link is "sphere busting" in a reducible manifold (meets every es …
Ian Agol's user avatar
  • 68.9k
8 votes
Accepted

Realizing Morse functions on $S^2$ as height functions

Any Morse function on $S^2$ may be realized by an embedding $S^2\hookrightarrow \mathbb{R}^3 \to \mathbb{R}$. For a Morse function $F:S^2\to \mathbb{R}$, take the equivalence relation with equivalence …
Ian Agol's user avatar
  • 68.9k
43 votes

Is differential topology a dying field?

I don't think differential topology is a dying field. I'll interpret this as the classification of smooth manifolds and, more broadly, maps between them (immersions, embeddings, diffeomorphism group …
Ian Agol's user avatar
  • 68.9k
47 votes

Parallelizability of the Milnor's exotic spheres in dimension 7

The tangent bundle to a smooth structure on $S^7$ is classified by a map $S^7 \to G_7(R^{\infty})$. By the exact sequence for a fibration for the fiber bundle $O(7)\to V_7(R^\infty)\to G_7(R^\infty)$, …
Ian Agol's user avatar
  • 68.9k
4 votes

Classification of oriented vector bundles of rank 5 over closed oriented 5-manifolds

I don't know how to answer this question completely, but I'll make some observations. The oriented vector bundles over $M$ are classified by homotopy classes of maps $f:M\to \tilde{G}_5$, the orient …
Ian Agol's user avatar
  • 68.9k

15 30 50 per page