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Non-commutative rings and algebras, non-associative algebras, universal algebra and lattice theory, linear algebra, semigroups. For questions specific to commutative algebra (that is, rings that are assumed both associative and commutative), rather use the tag ac.commutative-algebra.

6 votes
Accepted

Chirality of octonion algebras

Perhaps this is more a question about the Fano plane than about the (real) octonions. Notice that the automorphism group of the Fano plane is the simple group $\operatorname{GL}(3, \mathbb{F}_2) \cong …
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4 votes
Accepted

Subfields of division rings of degree $2$ which are not invariant

(This is basically a more detailed version of Eoin's comment.) I assume that you are considering division algebras over a field $k$, i.e., $Z(A) = k$. If $B$ is a subalgebra of dimension $2$ of $A$, t …
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7 votes

An algebra map between Hopf algebras that does not commute with the counit

Such a map can certainly exist. For instance, take the $k$-algebra $G = k \times k$, with $$ \begin{aligned} &\Delta(1,0) = (1,0) \otimes (1,0) + (0,1) \otimes (0,1), \\ &\Delta(0,1) = (1,0) \otimes ( …
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4 votes

Group representation with algebra structure

A classification is too much to hope for, but the representation theory tells you whether such an algebra structure can exist: if $V$ is your $G$-representation, then an algebra product corresponds to …
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1 vote
2 answers
229 views

Invertibility of all left multiplication maps in non-unital rings

Suppose that $R$ is a ring, not necessarily commutative nor associative. Assume that for every non-zero $a \in R$, the left multiplication map $$ \lambda_a \colon R \to R \colon x \mapsto ax $$ is inv …
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12 votes

Applications of Jordan algebras

They turn up quite often in the study of (exceptional) linear algebraic groups. The most famous instance of this is the fact that algebraic groups of type $F_4$ are precisely the automorphism groups o …
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2 votes

Tits-Kantor-Koecher construction for Jordan algebra of symmetric bilinear form

This is contained in Jacobson's Blue Book (Structure and Representations of Jordan Algebras, AMS Colloquium Publications, 1968), as Exercise 1 on p. 342, for arbitrary fields, and with no assumptions …
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3 votes
2 answers
919 views

Skew fields inside quaternion division algebras

Suppose that $Q$ is a quaternion division algebra with center $k$, where $k$ is an arbitrary commutative field (let's say with $\operatorname{char}(k) \neq 2$ if necessary). Assume that $D$ is an arbi …
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12 votes
1 answer
1k views

Divisibility and factorization in rings that are not integral domains

In my course notes for an undergraduate course "Algebra I", I wrote at the point when I'm introducing the notion of divisibility in rings (in a section on unique factorization): We want to study f …
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3 votes

Heisenberg-type groups over rings with involution

I wasn't aware of the paper by Abe that you mention, but I have used the group $A$ that you described in the case where $R$ is an octonion division algebra, in order to describe the rank one forms of …
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2 votes

polarization/linearization as in jordan forms

The principle of polarizing is given by what you wrote yourself in the third paragraph. If $p$ is a homogeneous polynomial of degree $n$, then: The clearest formulation is to take $p(x+ \lambda y) …
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5 votes
3 answers
1k views

adjoint of multiplication operator in a commutative algebra

Dan Popescu asked me the following question, and since I'm not an expert I'm throwing his question on MO. Suppose that $A$ is a finite-dimensional vector space over an ordered field $k$ with $\operat …
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12 votes

Simplest examples of rings that are not isomorphic to their opposites

Here is an explicit example of a central simple algebra over $\mathbb{Q}$ not isomorphic to its opposite (which is merely a detailed example of what Pete explained). First take a cubic cyclic Galois …
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6 votes

Cayley-Dickson form of a quaternion

I believe there is a good reason why mathematicians don't use the terminology "simplex-part" and "perplex-part": they are not canonical! Indeed, algebraically there is no way to distinguish the elemen …
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3 votes
1 answer
303 views

ABA-product of matrices and length of chains of principal inner ideals

Let $k$ be a field, $p,q$ positive integers, and let $R$ be the space of $(p \times q)$-matrices over $k$, and $S$ be the space of $(q \times p)$-matrices over $k$. For every matrix $A \in R$, we defi …
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