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On the blending of real/complex analysis with number theory. The study involves distribution of prime numbers and other problems and helps giving asymptotic estimates to these.

7 votes

Primes in arithmetic progression $a \pmod q$

Given a fixed $a$ and $q$, this should be true for sufficiently large $n$ by the explicit versions of Dirichlet's theorem on arithmetic progressions. We cannot prove that this is true for every $n$. T …
JoshuaZ's user avatar
  • 6,969
7 votes

Set and bounded gap

The set $S$ is very likely finite. It is unclear if you intend for $a$, $b$, $c$ and $d$ to be positive. If you don't assume that $a$, $b$, $c$ and $d$ are positive, then $n!$ has such a representati …
JoshuaZ's user avatar
  • 6,969
7 votes
0 answers
152 views

Recovering basic information about perfect numbers from a Dirichlet series

The following question is inspired mostly by this question, answer and the comment by Wojowu there A naive approach to understanding odd perfect numbers is to make a Dirichlet series where the $n$th o …
JoshuaZ's user avatar
  • 6,969
4 votes
Accepted

Bounds for the number of prime numbers less than the Euler's factor, the radical and the gre...

Since we have good asymptotics for $\pi(n)$ by the prime number theorem (and can get good explicit bounds on that from Rosser and Schoenfeld's work as well as later work such as that by Dusart) this q …
JoshuaZ's user avatar
  • 6,969
12 votes

What are the consequences of an ineffective proof of the Riemann Hypothesis?

One would have an ineffective but strengthened version of the Prime Number Theorem. A consequence of this would be there need to be some $\epsilon>0$ such that there's no zero in the strip with real …
JoshuaZ's user avatar
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7 votes
Accepted

The equivalent proposition of Legendre's conjecture

Your conjecture for sufficiently large $n$ is implied by Cramer's conjecture. In general though, conjectures like this unless they are coming from some specific application aren't that interesting. It …
JoshuaZ's user avatar
  • 6,969
3 votes
Accepted

A conjecture about an inequality that involve Ramanujan primes

Not a complete answer, but a bit too long for a comment: Conjecture 1 is very likely to be very difficult if true. The corresponding conjecture for general primes is open. Let $p_n$ be the $n$th prime …
JoshuaZ's user avatar
  • 6,969
3 votes
Accepted

References of research papers which lead to starting of Sieve Theory

Sieve theory as such is generally considered to have started with Brun's 1915 and 1919 papers. The titles are "Über das Goldbachsche Gesetz und die Anzahl der Primzahlpaare" and ""La série $1/5+1/7+1/ …
11 votes

Heuristic argument for the Riemann Hypothesis

There have been some good answers already given but I want to note another aspect, namely a heuristic involving the Möbius function. Let $\mu(n)$ be the Möbius function. The Riemann Hypothesis is equi …
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2 votes

What work can be done to study the solutions of $\varphi\left(x^{\sigma(x)}\sigma(x)^x\right...

In general, problems involving the composition of multiplicative functions are very hard to analyze. I don't see any specific way to approach this problem, and I'm skeptical that this is likely to be …
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10 votes
Accepted

Error term in Mertens' third theorem

There's been a lot of work on unconditional results of this sort. Rosser and Schoenfeld showed in a 1962 paper that one can take $$\dfrac{e^{-\gamma}}{\log x} \left(1- \frac{1}{2\log^2 x} \right) < …
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  • 6,969
2 votes
Accepted

Odd perfect numbers having as prime factors exclusively Mersenne primes and Fermat primes

This should be provable by standard although laborious methods. What follows is a proof sketch (I have not checked all the computational details but this method should work). We recall a few basic fac …
JoshuaZ's user avatar
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10 votes
Accepted

A weaker version of the Brocard's Conjecture

Theorem: For any constant $c$ there are infinitely many primes $p_k$ such that there are at least $c$ primes between $p_k^2$ and $p_{k+1}^2$. Proof: Fix a $c$. Assume that for sufficiently large $k$ …
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2 votes
Accepted

Sum of divisors of Stirling numbers of the second kind

Conjecture 2 seems to be true. If $n \geq 2$ then $$\frac{1}{2}(k^2+k+2)k^{n-k-1}-1 \leq \left\{{n \atop k}\right\} \leq \frac{1}{2}{n \choose k} k^{n-k} < 2^n k^{n-k}. $$ (Inequalities from Here.) …
JoshuaZ's user avatar
  • 6,969
3 votes

Bounds for two arithmetic functions, when one assumes that $n$ are odd perfect numbers

As far as I'm aware, we don't have any substantially non-trivial bounds on the behavior of $\psi(n)$ when $n$ is an odd perfect number. We can at least prove the following but none of these are diffi …
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  • 6,969

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